Develop Reference

Using Selenium to accept a splash page

When I load the my site as shown below, a splash screen appears to confirm I am 21 years of age. I am trying to load the element to click yes, but I am unable to bypass the age verification screen.
My approach was to load the page. Add a sleep time, find the element and click Yes. However it wont work.
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
time.sleep(5)
element= driver.find_element_by_xpath('//*[#id="enter"]')
element.click()
Error received.
selenium.common.exceptions.NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"//*[#id="enter"]"}
So either my find.element is off or my time.sleep is not helping with the splash page.

It seems the problem is that the pop-up is in an iframe.
This code appears to do the trick
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
from selenium.common.exceptions import NoSuchElementException
from selenium.webdriver import ActionChains
import time
driver = webdriver.Chrome('/usr/local/bin/chromedriver')
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
# xpath of iframe
frame_xpath = '/html/body/div[5]/div/div/div/div/iframe'
wait = WebDriverWait(driver, 10)
# wait until iframe appears and select iframe
wait.until(EC.frame_to_be_available_and_switch_to_it((By.XPATH, frame_xpath)))
# select button
xpath = '//*[#id="enter"]'
time.sleep(2)
element= driver.find_element_by_xpath(xpath)
ActionChains(driver).move_to_element(element).click(element).perform()
referencing This answer on Stack Overflow

You need to switch to the frame, check the below code
driver.get('https://seelbachs.com/products/sagamore-spirit-cask-strength-rye-whiskey')
sleep(5)
driver.switch_to.frame(driver.find_element_by_xpath("//iframe[contains(#id,'fancyboxAge-frame')]"))
OR
#Using the explicitWait
WebDriverWait(driver,10).until(EC.frame_to_be_available_and_switch_to_it((By.XPATH,"//iframe[contains(#id,'fancyboxAge-frame')]")))
element= driver.find_element_by_xpath('//*[#id="enter"]')
element.click()
import
from time import sleep
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.support.wait import WebDriverWait

Unable to select element from Dropdown that hides - Python Selenium

I'm trying to get to the results page of a search but I have to first click on the dropdown option to complete the search. When I do this manually, the dropdown hides if I do not click on it right as it appears, when I code it, I get a the following error:
ElementNotInteractableException: Message: Element <div id="_esgratingsprofile_autocomplete-results-container" class="autocomplete-results-container msci-ac-search-data-dropdown"> could not be scrolled into view
This is my code so far, you can visit the url and see how it is yourself as well:
from selenium.webdriver import Firefox
from selenium.webdriver.support.ui import Select
from selenium.webdriver.firefox.options import Options
opts = Options()
opts.set_headless()
assert opts.headless
browser = Firefox(options=opts)
browser.get('https://www.msci.com/esg-ratings')
search_form = browser.find_element_by_id('_esgratingsprofile_keywords')
search_form.send_keys('MSFT')
browser.find_element_by_xpath("//div[#id='_esgratingsprofile_autocomplete-results-container']/ul[#id='ui-id-1']/li[#class='msci-ac-search-section-title ui-menu-item']").click()
I looked through many other answers but they didnt seem to deal with the case where the dropdown was not a directly clickable element or where it hides if you dont click on it right away. Any help is appreciated.

Try the below code, This code is working for me. Let me know if it shows any error.
from selenium import webdriver
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver import ActionChains
from selenium.webdriver.common.by import By
driver = webdriver.Chrome()
driver.maximize_window()
wait = WebDriverWait(driver, 5)
action = ActionChains(driver)
driver.get("https://www.msci.com/esg-ratings")
Drop_Down = driver.find_element_by_xpath('//*[#id="_esgratingsprofile_keywords"]')
Drop_Down.send_keys("MSFT")
# Select the First Result from the search.
Result = wait.until(
EC.presence_of_element_located((By.XPATH, "//div[contains(#class,'autocomplete-results-container')]/ul/li[1]")))
action.move_to_element(Result).click().perform()

Selenium clicks next button instead of back button

Trying to scrape this webpage for prices, and I need the prices to be in US dollars, so it is currency I understand. However, when I initially load the URL, it gives the prices in multiple seemingly random currencies. I found that I could change this by clicking the next button, and then the back button, but when I tried to automate this, it did not work. Instead, running this code clicks the next button twice, rather than clicking it once, waiting for five seconds, and then clicking the back button. Here is the code that I am currently using that can replicate this problem.
from selenium import webdriver
driver = webdriver.Chrome(r'C:\Users\Hank\Desktop\chromedriver_win32\chromedriver.exe')
driver.get('https://steamcommunity.com/market/listings/440/Unusual%20Old%20Guadalajara')
from selenium.webdriver.common.by import By
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.support.ui import WebDriverWait as wait
from selenium.webdriver.support.expected_conditions import presence_of_element_located
from selenium.webdriver.common.action_chains import ActionChains
from selenium.webdriver.support import expected_conditions as EC
from selenium.common.exceptions import StaleElementReferenceException
import time
time.sleep(5)
action = ActionChains(driver)
next_button=wait(driver, 10).until(EC.element_to_be_clickable((By.ID,'searchResults_btn_next')))
action.move_to_element(next_button).click().perform()
time.sleep(5)
back_button=wait(driver, 10).until(EC.element_to_be_clickable((By.ID,'searchResults_btn_prev')))
action.move_to_element(back_button).click().perform()
Thanks, your time and help is greatly appreciated. Please direct me to a relevant question if this one has already been answered somewhere else.

You don't need ActionChains class, it's works by .click() method.
Try following code:
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
driver = webdriver.Chrome(r'C:\Users\Hank\Desktop\chromedriver_win32\chromedriver.exe')
driver.get('https://steamcommunity.com/market/listings/440/Unusual%20Old%20Guadalajara')
wait = WebDriverWait(driver, 20)
next_button = wait.until(EC.element_to_be_clickable((By.ID,'searchResults_btn_next')))
next_button.click()
time.sleep(5)
back_button = wait.until(EC.element_to_be_clickable((By.ID,'searchResults_btn_prev')))
back_button.click()
But note, time.sleep(5) is bad way, you can use other way, ex : wait until the second page element appear.
Or instead of time.sleep(...) in this case, you can use this code:
wait.until(EC.invisibility_of_element_located((By.CSS_SELECTOR,'.pagebtn.disabled')))
The above is the disable previous button since you landing in the first pagination, and will gone when you arrieve on second pagination. Use .invisibility_of_element_located, it will more efficient.

Login Button can not be found with selenium

https://www.sevenonemedia.de/tv/programm/programmwochen
Here I want to login:
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
import time
options = Options()
chrome_path = "T:/Markus/WebScrapingExample/Chromedriver/chromedriver.exe"
driver = webdriver.Chrome(executable_path=chrome_path,chrome_options=options)
driver.set_window_size(1280, 720)
time.sleep(5)
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
driver.find_element_by_id("_58_login").send_keys("name")
driver.find_element_by_id("_58_password").send_keys("pw")
driver.find_element_by_xpath('//*[#id="sign-in-button"]').click()
ElementNotInteractableException: element not interactable
(Session info: chrome=78.0.3904.97)
This is my error
Id is there. Why does this happen?

This page contains duplicate of element with ID sign-in-button. If your selector points to more than one element, driver always takes the first from the top of the DOM one which is not interactable in this case. You must refer to the second element with this id. Try this selector for "Sign in" button:
//*[#id="aheadcustom_p_p_id_58"]//button

hi first things you should not give your password to all of the stackoverflow community :)
you can't click on the button because there is a popup at the bottom of the page and you have to click on it first for selenium it's hidding your button
last is that the totality of your code ?
if yes you forgot
driver = webdriver.Firefox() #or any other webdriver
you have not create driver without this line
EDIT !!
it wasn't working with only the modification above but with this one its good
from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.by import By
import time
time.sleep(5)
driver = webdriver.Firefox()
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
driver.find_element_by_id("_58_login").send_keys("login")
driver.find_element_by_id("_58_password").send_keys("pssd")
driver.find_element_by_xpath("/html/body/div[1]/div/div/div[2]/a").click()
driver.find_element_by_css_selector("#_58_fm > fieldset:nth-child(1) > div:nth-child(6) > button:nth-child(1)").click()
this work :)
sometime css selector a safer and work better

To click on the Login button you have to induce WebDriverWait for the element_to_be_clickable() and you can use either of the following solutions:
Using XPATH:
driver.get("https://www.sevenonemedia.de/tv/programm/programmwochen")
WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//input[#title='Anmelden' and not(contains(#name,'INSTANCE'))]"))).send_keys("a.mai#mediaplus.com")
driver.find_element_by_xpath("//input[#title='Passwort' and not(contains(#name,'INSTANCE'))]").send_keys("Edidaten17")
driver.find_element_by_xpath("//input[#title='Passwort' and not(contains(#name,'INSTANCE'))]//following::button[1]").click()
Note : You have to add the following imports :
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC
Browser Snapshot:

The problem is that your button locator isn't unique on the page. It finds two buttons, the first of which is not visible which causes the ElementNotInteractableException.
The simple fix is to use the CSS selector below
#main-content #sign-in-button
That will find only the button you want. So your last few lines of code would be
driver.find_element_by_id("_58_login").send_keys("name")
driver.find_element_by_id("_58_password").send_keys("pw")
driver.find_element_by_css_selector('#main-content #sign-in-button').click()

sleep(1)
login_box = driver.find_element_by_name('login')
login_box.click()
this is for facebook login button, just inspect the website and see the id/name/type to make your code automate to work properly

Selenium Python using ActionChains

The code I have opens a website and using actionChains, it right clicks on the desktop which brings up a menu. I now need to do 3 more things with actionChains. I need to hover over the item that says Save Page WE and then click an item on the sub-menu that pops up and then hit the enter button. Can anyone show me how to do this? Thanks
from selenium import webdriver
from selenium.webdriver import ActionChains
fp = webdriver.FirefoxProfile('/Users/Jake/AppData/Roaming/Mozilla/Firefox/Profiles/emjx467y.default-1524932841911')
driver = webdriv[enter link description here][1]er.Firefox(fp)
driver.get('http://www.tradingview.com/screener')
element = driver.find_element_by_link_text('Screener')
actionChains = ActionChains(driver)
actionChains.context_click(element).perform()

By using this line : actionChains.context_click(element).perform() , you are trying to right click on Screener menu. But the ideal behavior should be to be hover on it and select one options out of 3.
I'm selecting Forex Screener, you can select any one as per your requirement.
For hover over you can try this code :
actionChains.move_to_element(element).perform()
Full code would be like this :
driver.get("http://www.tradingview.com/screener")
wait = WebDriverWait(driver,40)
driver.find_element_by_css_selector("span[class*='tv-header__dropdown-wrap--noarrow'] span[class$='lang-icon--current-lang']").click()
wait.until(EC.element_to_be_clickable((By.XPATH, "//span[text()='English (UK)']/parent::a"))).click()
element = driver.find_element_by_link_text('Screener')
actionChains = ActionChains(driver)
actionChains.move_to_element(element).perform()
wait.until(EC.element_to_be_clickable((By.LINK_TEXT, "Forex Screener"))).click()
Make sure to import these :
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from selenium.webdriver.common.action_chains import ActionChains