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Can multiple table be formed from a condition in dataframe in python?

I have a dataset:
list1 list2
0 [1,3,4] [4,3,2]
1 [1,3,2] [0,4,6]
2 [4,5,8] NA
3 [6,3,7] [8,2,3]
Is there a process where i can find the count of the common term for- each of the index,
Expected output:
intersection_0, it will compare 0 of list1 with each of list2 and give output, intersection_1 which will compare 1 of list1 with each of list2
Expected_output:
Intersection_0 intersection_1 intersection_2 intersection_3
1 2 1 1
1 0 1 1
0 0 0 0
1 2 0 1
For intersection i was trying:
df['intersection'] = [len(set(a).intersection(b)) for a, b in zip(df1.list1, df1.list2)]
Is there a better way or faster way to achieve this? Thank you in advance

The double loop would go like this:
intersections = []
for l2 in df['list2']:
intersection = []
for l1 in df['list1']:
try:
i = len(np.intersect1d(l1,l2))
except:
i = 0
intersection.append(i)
intersections.append(intersection)
out = (pd.DataFrame(intersections))
Output:
0 1 2 3
0 2 2 1 1
1 1 0 1 1
2 0 0 0 0
3 1 2 1 1

Python inner loop and outer loop with counter to iterate over list

I have specific issue where, im trying to find solution on inner loop(execute 3 time) and continue outer to process rest of the list in for loop:
strings = ['A','A','A','A','A','A','A','A','A','A','B','B','B','B','B','B','B','B','B','B',\
'A','A','A','A','A','A','A','A','A','A','B','B','B','B','B','B','B','B','B','B']
i=0
for string in strings:
global i
if string == 'A':
while i < 3:
print(string, i)
i+=1
if i==3: continue
elif string== 'B':
while i < 3:
print(string,i)
i+=1
if i==3: continue
# print(string)
Current result:
A 0
A 1
A 2
Expected to have continued over list once the inner loop complete and process from next:
A 0
A 1
A 2
B 0
B 1
B 2
A 0
A 1
A 2
B 0
B 1
B 2

If I understand correctly the logic, you could use itertools.groupby to help you form the groups:
variant #1
from itertools import groupby
MAX = 3
for k,g in groupby(strings):
for i in range(min(len(list(g)), MAX)):
print(f'{k} {i}')
print()
variant #2
from itertools import groupby
MAX = 3
for k,g in groupby(strings):
for i,_ in enumerate(g):
if i >= MAX:
break
print(f'{k} {i}')
print()
output:
A 0
A 1
A 2
B 0
B 1
B 2
A 0
A 1
A 2
B 0
B 1
B 2
variant #3: without import
prev = None
count = 0
MAX = 3
for s in strings:
if s == prev:
if count < MAX:
print(f'{s} {count}')
count += 1
elif prev:
count = 0
print()
prev = s

Skip particular repetition in nested foor loop - Python

for k in range(8):
for i in range(2): #number of columns
for j in range(4): #number of row
print(k,j,i)
I want an output like this. no repetition of first for loop
k,j,i
-----
0 0 0
1 1 0
2 2 0
3 3 0
4 0 1
5 1 1
6 2 1
7 3 1
How I will achieve this?

Normally i would do
for i in range(8):
print(i, i%4, i%2)
Output:
0 0 0
1 1 1
2 2 0
3 3 1
4 0 0
5 1 1
6 2 0
7 3 1
But to reproduce your exact output:
for i in range(8):
print(i, i%4, int(i>3))
Output:
0 0 0
1 1 0
2 2 0
3 3 0
4 0 0
5 1 1
6 2 1
7 3 1

You can use if statements to say things like if k == 7 or something along those lines. This will only allow it to loop the first loop before moving on to the second loop.

Other answers have shown similar ways to produce your exact output, but this is another way to do it, and this would still work if you wanted the number of rows to be more than 8 and you wanted i to keep increasing
for i in range(8):
print(i, i%4, i//4)
I hope this is useful, sorry if it isn't

Looking at i and j, you have the cartesian product of {0,1} and {0,1,2,3}. You can compute that with itertools.product(range(2), range(4)), then use enumerate to number them for your k value.
from itertools import product
for k, (i, j) in enumerate(product(range(2), range(4))):
print(k, j, i)
Earlier arguments to product vary more slowly than later arguments.

"How to unevenly iterate over two lists"

I cannot find a solution for this very specific problem I have.
In essence, I have two lists with two elements each: [A, B] and [1,2]. I want to create a nested loop that iterates and expands on the second list and adds each element of first list after each iteration.
What I want to see in the end is this:
A B
1 A
1 B
2 A
2 B
1 1 A
1 2 A
2 1 A
2 2 A
1 1 B
1 2 B
2 1 B
2 2 B
1 1 1 A
1 1 2 A
...
My problem is that my attempt at doing this recursively splits the A and B apart so that this pattern emerges (note the different first line, too):
A
1 A
2 A
1 1 A
1 2 A
2 1 A
2 2 A
1 1 1 A
1 1 2 A
...
B
1 B
2 B
1 1 B
1 2 B
2 1 B
2 2 B
1 1 1 B
1 1 2 B
...
How do I keep A and B together?
Here is the code:
def second_list(depth):
if depth < 1:
yield ''
else:
for elements in [' 1 ', ' 2 ']:
for other_elements in list (second_list(depth-1)):
yield elements + other_elements
for first_list in [' A ', ' B ']:
for i in range(0,4):
temp=second_list(i)
for temp_list in list(temp):
print temp_list + first_list

I would try something in the following style:
l1 = ['A', 'B']
l2 = ['1', '2']
def expand(l1, l2):
nl1 = []
for e in l1:
for f in l2:
nl1.append(f+e)
yield nl1[-1]
yield from expand(nl1,l2)
for x in expand(l1, l2):
print (x)
if len(x) > 5:
break
Note: the first line of your output does not seem to be the product of the same rule, so it is not generated here, you can add it, if you want, manually.
Note2: it would be more elegant not to build the list of the newly generated elements, but then you would have to calculate them twice.

Python: Change row and colum in a matrix

matrix = []
for index, value in enumerate(['A','C','G','T']):
matrix.append([])
matrix[index].append(value + ':')
for i in range(len(lines[0])):
total = 0
for sequence in lines:
if sequence[i] == value:
total += 1
matrix[index].append(total)
unity = ''
for i in range(len(lines[0])):
column = []
for row in matrix:
column.append(row[1:][i])
maximum = column.index(max(column))
unity += ['A', 'C', 'G', 'T'][maximum]
print("Unity: " + unity)
for row in matrix:
print(' '.join(map(str, row)))
OUTPUT:
Unity: GGCTACGC
A: 1 2 0 2 3 2 0 0
C: 0 1 4 2 1 3 2 4
G: 3 3 2 0 1 2 4 1
T: 3 1 1 3 2 0 1 2
With this code I get this matrix but I want to form the matrix like this:
A C G T
G: 1 0 3 3
G: 2 1 3 1
C: 0 4 2 1
T: 2 2 0 3
A: 3 1 1 2
C: 2 3 2 0
G: 0 2 4 1
C: 0 4 1 2
But I don't know how. I hope someone can help me. Thanks already for the answers.
The sequences are:
AGCTACGT
TAGCTAGC
TAGCTACG
GCTAGCGC
TGCTAGCC
GGCTACGT
GTCACGTC

You're needing to do a transpose of your matrix. I've added comments in the code below to explain what has been changed to make the table.
matrix = []
for index, value in enumerate(['A','C','G','T']):
matrix.append([])
# Don't put colons in column headers
matrix[index].append(value)
for i in range(len(lines[0])):
total = 0
for sequence in lines:
if sequence[i] == value:
total += 1
matrix[index].append(total)
unity = ''
for i in range(len(lines[0])):
column = []
for row in matrix:
column.append(row[1:][i])
maximum = column.index(max(column))
unity += ['A', 'C', 'G', 'T'][maximum]
# Tranpose matrix
matrix = list(map(list, zip(*matrix)))
# Print header with tabs to make it look pretty
print( '\t'+'\t'.join(matrix[0]))
# Print rows in matrix
for row,unit in zip(matrix[1:],unity):
print(unit + ':\t'+'\t'.join(map(str, row)))
The following will be printed:
A C G T
G: 1 0 3 3
G: 2 1 3 1
C: 0 4 2 1
T: 2 2 0 3
A: 3 1 1 2
C: 2 3 2 0
G: 0 2 4 1
C: 0 4 1 2

I think that the best way is to convert your matrix to pandas dataframe and to then use transpose function.
https://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.transpose.html