This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Python regular expression not matching
(3 answers)
Closed 6 years ago.
In the following code, I expect the program to print "Match", because "\D+\d" matches the "x4" part of the string. But it does not print anything. What is the problem?
import re
pattern = r"\D+\d"
if re.match(pattern, "1x4"):
print("Match");
Thanks
Your assumption that re.match can match anywhere inside a string is wrong.
https://docs.python.org/2/library/re.html#re.RegexObject.match
If zero or more characters at the beginning of string match this regular expression, return a corresponding MatchObject instance. Return None if the string does not match the pattern; note that this is different from a zero-length match.
Use re.search() instead.
Related
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How do I match any character across multiple lines in a regular expression?
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How to extract an IP address from an HTML string?
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Closed 3 years ago.
When applying regex to a multiline string, I realize the regex may be correct according to rubular.com. The problem is that somehow it is not working against multiline text. Question is, I attempted to do "item.strip()" and no change in behavior.
s = """ #if route rate 230.207.200.1', '', '
(50.50.50.11,230.207.200.1)', """
for item in s:
match = re.findall(r'([0-9].[0-9].[0-9].[0-9],.........)', s)
if match:
print('match')
Do you have any line ending matching or dot character in there?
Try setting the flags to either re.DOTALL or re.MULTILINE, for example:
re.findall(r'...', s, flags=re.DOTALL)
This question already has answers here:
Regex plus vs star difference? [duplicate]
(9 answers)
Python regular expression pattern * is not working as expected
(2 answers)
Closed 4 years ago.
import re
real_comp = re.compile(r'[0-9]*')
real_comp.search('+123i').group()
Out[7]: ''
I am expecting the the result as "123", but it returns empty.
What's wrong?
You'll need another quantifier, namely a +:
import re
real_comp = re.compile(r'([0-9]+)')
print(real_comp.search('+123i').group())
Which yields
123
Otherwise the regex engine reports a match before the very first consumed char ( [0-9]* is always true).
This question already has answers here:
Matching all words except one
(8 answers)
Regex: match everything but a specific pattern
(6 answers)
Closed 4 years ago.
I'm very new to regex and I've looked but haven't found the syntax I'm looking for.
I want to match any word (including foobar), but not foo. However, everythimg I've found catches foobar with foo.
What's the correct way to do this? I'm working in Python, if that matters
(?!^foo$)^\w+$
This is a negative look ahead (?!), saying don't match the word foo, but match any other word.
^ and $ assert the start and end of the string, respectively. \w+ means match one or more of any word character.
And an example:
https://regex101.com/r/nfxyso/2
This question already has answers here:
Regular expression to return text between parenthesis
(11 answers)
Regular expression to extract text between square brackets
(15 answers)
Closed 4 years ago.
I am trying to find anything between [ and ] Here is what I have so far and isn't working. I am aware that I can use string.find("[") to get the positions but I am trying to get better at using regex.
string = '[12/Aug/2000:06:29:11 -]'
pattern = re.compile(r'[\[][.][\]]')
matches = pattern.finditer(string)
for match in matches:
print(match)
This question already has answers here:
What is the difference between re.search and re.match?
(9 answers)
Closed 5 years ago.
I want to get userid from url like:
http://space.bilibili.com/1950746/#!/channel/detail?cid=1757&order=&page=1
and it should be like 1950746.
And here is the code:
url='http://space.bilibili.com/1950746/#!/channel/detail?cid=1757&order=&page=1'
b=userid=re.match(r'\d{7}', url)
print(b)
The result is None.
Using re.match gives an implicit ^ at the beginning of the string. Use re.search to find anywhere in string.