I have a XML file downloaded from Wordpress that is structured like this:
<wp:postmeta>
<wp:meta_key><![CDATA[country]]></wp:meta_key>
<wp:meta_value><![CDATA[Germany]]></wp:meta_value>
</wp:postmeta>
my goals is to look through the XML file for all the country keys and print the value. I'm completely new to the XML library so I'm looking where to take it from here.
# load libraries
# importing os to handle directory functions
import os
# import XML handlers
from xml.etree import ElementTree
# importing json to handle structured data saving
import json
# dictonary with namespaces
ns = {'wp:meta_key', 'wp:meta_value'}
tree = ElementTree.parse('/var/www/python/file.xml')
root = tree.getroot()
# item
for item in root.findall('wp:post_meta', ns):
print '- ', item.text
print "Finished running"
this throws me a error about using wp as a namespace but I'm not sure where to go from here the documentation is unclear to me. Any help is appreciated.
Downvoters please let me know how I can improve my question.
I don't know XML, but I can treat it as a string like this.
from simplified_scrapy import SimplifiedDoc, req, utils
xml = '''
<wp:postmeta>
<wp:meta_key><![CDATA[country]]></wp:meta_key>
<wp:meta_value><![CDATA[Germany]]></wp:meta_value>
</wp:postmeta>
'''
doc = SimplifiedDoc(xml)
kvs = doc.select('wp:postmeta').selects('wp:meta_key|wp:meta_value').html
print (kvs)
Result:
['<![CDATA[country]]>', '<![CDATA[Germany]]>']
I'm trying to create a function which counts words in pptx document. The problem is that I can't figure out how to find only this kind of tags:
<a:t>Some Text</a:t>
When I try to: print xmlTree.findall('.//a:t'), it returns
SyntaxError: prefix 'a' not found in prefix map
Do you know what to do to make it work?
This is the function:
def get_pptx_word_count(filename):
import xml.etree.ElementTree as ET
import zipfile
z = zipfile.ZipFile(filename)
i=0
wordcount = 0
while True:
i+=1
slidename = 'slide{}.xml'.format(i)
try:
slide = z.read("ppt/slides/{}".format(slidename))
except KeyError:
break
xmlTree = ET.fromstring(slide)
for elem in xmlTree.iter():
if elem.tag=='a:t':
#text = elem.getText
#num = len(text.split(' '))
#wordcount+=num
The way to specify the namespace inside ElementTree is:
{namespace}element
So, you should change your query to:
print xmlTree.findall('.//{a}t')
Edit:
As #mxjn pointed out if a is a prefix and not the URI you need to insert the URI instead of a:
print xmlTree.findall('.//{http://tempuri.org/name_space_of_a}t')
or you can supply a prefix map:
prefix_map = {"a": "http://tempuri.org/name_space_of_a"}
print xmlTree.findall('.//a:t', prefix_map)
You need to tell ElementTree about your XML namespaces.
References:
Official Documentation (Python 2.7): 19.7.1.6. Parsing XML with Namespaces
Existing answer on StackOverflow: Parsing XML with namespace in Python via 'ElementTree'
Article by the author of ElementTree: ElementTree: Working with Namespaces and Qualified Names
I am parsing xml with python using xmltodict. But i am getting following error ,
xml.parsers.expat.ExpatError: mismatched tag: line 2890, column 2
Here is my code ,
import xmltodict
import urllib2
url="url here"
data=xmltodict.parse(urllib2.urlopen(url).read())
print data
I have also tried using etree
Here is the code ,
import urllib2
import lxml.etree as ET
print 'Started Execution here'
url="url here"
xmldata = urllib2.urlopen(url).read()
root = ET.fromstring(xmldata)
print 'Done'
print root
It is also giving me error,
lxml.etree.XMLSyntaxError: Opening and ending tag mismatch: ClinicID line 54 and Type, line 55, column 14
I know there is problem in xml .
My question is that is there is any way to read the xml with all the nodes except that caused error ?
I receive xml strings from an external source that can contains unsanitized user contributed content.
The following xml string gave a ParseError in cElementTree:
>>> print repr(s)
'<Comment>dddddddd\x08\x08\x08\x08\x08\x08_____</Comment>'
>>> import xml.etree.cElementTree as ET
>>> ET.XML(s)
Traceback (most recent call last):
File "<pyshell#4>", line 1, in <module>
ET.XML(s)
File "<string>", line 106, in XML
ParseError: not well-formed (invalid token): line 1, column 17
Is there a way to make cElementTree not complain?
It seems to complain about \x08 you will need to escape that.
Edit:
Or you can have the parser ignore the errors using recover
from lxml import etree
parser = etree.XMLParser(recover=True)
etree.fromstring(xmlstring, parser=parser)
I was having the same error (with ElementTree). In my case it was because of encodings, and I was able to solve it without having to use an external library. Hope this helps other people finding this question based on the title. (reference)
import xml.etree.ElementTree as ET
parser = ET.XMLParser(encoding="utf-8")
tree = ET.fromstring(xmlstring, parser=parser)
EDIT: Based on comments, this answer might be outdated. But this did work back when it was answered...
This code snippet worked for me. I have an issue with the parsing batch of XML files. I had to encode them to 'iso-8859-5'
import xml.etree.ElementTree as ET
tree = ET.parse(filename, parser = ET.XMLParser(encoding = 'iso-8859-5'))
See this answer to another question and the according part of the XML spec.
The backspace U+0008 is an invalid character in XML documents. It must be represented as escaped entity and cannot occur plainly.
If you need to process this XML snippet, you must replace \x08 in s before feeding it into an XML parser.
None of the above fixes worked for me. The only thing that worked was to use BeautifulSoup instead of ElementTree as follows:
from bs4 import BeautifulSoup
with open("data/myfile.xml") as fp:
soup = BeautifulSoup(fp, 'xml')
Then you can search the tree as:
soup.find_all('mytag')
This is most probably an encoding error. For example I had an xml file encoded in UTF-8-BOM (checked from the Notepad++ Encoding menu) and got similar error message.
The workaround (Python 3.6)
import io
from xml.etree import ElementTree as ET
with io.open(file, 'r', encoding='utf-8-sig') as f:
contents = f.read()
tree = ET.fromstring(contents)
Check the encoding of your xml file. If it is using different encoding, change the 'utf-8-sig' accordingly.
After lots of searching through the entire WWW, I only found out that you have to escape certain characters if you want your XML parser to work! Here's how I did it and worked for me:
escape_illegal_xml_characters = lambda x: re.sub(u'[\x00-\x08\x0b\x0c\x0e-\x1F\uD800-\uDFFF\uFFFE\uFFFF]', '', x)
And use it like you'd normally do:
ET.XML(escape_illegal_xml_characters(my_xml_string)) #instead of ET.XML(my_xml_string)
A solution for gottcha for me, using Python's ElementTree... this has the invalid token error:
# -*- coding: utf-8 -*-
import xml.etree.ElementTree as ET
xml = u"""<?xml version='1.0' encoding='utf8'?>
<osm generator="pycrocosm server" version="0.6"><changeset created_at="2017-09-06T19:26:50.302136+00:00" id="273" max_lat="0.0" max_lon="0.0" min_lat="0.0" min_lon="0.0" open="true" uid="345" user="john"><tag k="test" v="Съешь же ещё этих мягких французских булок да выпей чаю" /><tag k="foo" v="bar" /><discussion><comment data="2015-01-01T18:56:48Z" uid="1841" user="metaodi"><text>Did you verify those street names?</text></comment></discussion></changeset></osm>"""
xmltest = ET.fromstring(xml.encode("utf-8"))
However, it works with the addition of a hyphen in the encoding type:
<?xml version='1.0' encoding='utf-8'?>
Most odd. Someone found this footnote in the python docs:
The encoding string included in XML output should conform to the
appropriate standards. For example, “UTF-8” is valid, but “UTF8” is
not.
I have been in stuck with similar problem. Finally figured out the what was the root cause in my particular case. If you read the data from multiple XML files that lie in same folder you will parse also .DS_Store file.
Before parsing add this condition
for file in files:
if file.endswith('.xml'):
run_your_code...
This trick helped me as well
lxml solved the issue, in my case
from lxml import etree
for _, elein etree.iterparse(xml_file, tag='tag_i_wanted', unicode='utf-8'):
print(ele.tag, ele.text)
in another case,
parser = etree.XMLParser(recover=True)
tree = etree.parse(xml_file, parser=parser)
tags_needed = tree.iter('TAG NAME')
Thanks to theeastcoastwest
Python 2.7
In my case I got the same error. (using Element Tree)
I had to add these lines:
import xml.etree.ElementTree as ET
from lxml import etree
parser = etree.XMLParser(recover=True,encoding='utf-8')
xml_file = ET.parse(path_xml,parser=parser)
Works in pyhton 3.10.2
What helped me with that error was Juan's answer - https://stackoverflow.com/a/20204635/4433222
But wasn't enough - after struggling I found out that an XML file needs to be saved with UTF-8 without BOM encoding.
The solution wasn't working for "normal" UTF-8.
The only thing that worked for me is I had to add mode and encoding while opening the file like below:
with open(filenames[0], mode='r',encoding='utf-8') as f:
readFile()
Otherwise it was failing every time with invalid token error if I simply do this:
f = open(filenames[0], 'r')
readFile()
this error is coming while you are giving a link . but first you have to find the string of that link
response = requests.get(Link)
root = cElementTree.fromstring(response.content)
I tried the other solutions in the answers here but had no luck. Since I only needed to extract the value from a single xml node I gave in and wrote my function to do so:
def ParseXmlTagContents(source, tag, tagContentsRegex):
openTagString = "<"+tag+">"
closeTagString = "</"+tag+">"
found = re.search(openTagString + tagContentsRegex + closeTagString, source)
if found:
start = found.regs[0][0]
end = found.regs[0][1]
return source[start+len(openTagString):end-len(closeTagString)]
return ""
Example usage would be:
<?xml version="1.0" encoding="utf-16"?>
<parentNode>
<childNode>123</childNode>
</parentNode>
ParseXmlTagContents(xmlString, "childNode", "[0-9]+")
I'm building a simple web-based RSS reader in Python, but I'm having trouble parsing the XML. I started out by trying some stuff in the Python command line.
>>> from xml.dom import minidom
>>> import urllib2
>>> url ='http://www.digg.com/rss/index.xml'
>>> xmldoc = minidom.parse(urllib2.urlopen(url))
>>> channelnode = xmldoc.getElementsByTagName("channel")
>>> channelnode = xmldoc.getElementsByTagName("channel")
>>> titlenode = channelnode[0].getElementsByTagName("title")
>>> print titlenode[0]
<DOM Element: title at 0xb37440>
>>> print titlenode[0].nodeValue
None
I played around with this for a while, but the nodeValue of everything seems to be None. Yet if you look at the XML, there definitely are values there. What am I doing wrong?
For RSS feeds you should try the Universal Feed Parser library. It simplifies the handling of RSS feeds immensly.
import feedparser
d = feedparser.parse('http://www.digg.com/rss/index.xml')
title = d.channel.title
This is the syntax you are looking for:
>>> print titlenode[0].firstChild.nodeValue
digg.com: Stories / Popular
Note that the node value is a logical descendant of the node itself.