I have a file info.txt, and I want to show content when I click on Info.
import sys
from PyQt5.QtWidgets import QMainWindow, QTextEdit, QAction, QApplication, QMessageBox
from PyQt5.QtGui import QIcon
file=open("info.txt","r")
data=file.read()
class Example(QMainWindow):
def showdialog(self):
msg = QMessageBox()
msg.setIcon(QMessageBox.Information)
msg.setText(data)
msg.setWindowTitle("Info")
msg.show()
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
textEdit = QTextEdit()
self.setCentralWidget(textEdit)
sourceAction = QAction(QIcon('info.png'), 'More informations', self)
sourceAction.setShortcut('Ctrl+I')
sourceAction.setStatusTip('More info')
self.statusBar()
sourceAction.triggered.connect(self.showdialog)
menubar = self.menuBar()
fileMenu = menubar.addMenu('&About')
fileMenu.addAction(sourceAction)
sourceAction.triggered.connect(self.showdialog)
toolbar = self.addToolBar('Exit')
toolbar.addAction(sourceAction)
self.setGeometry(300, 300, 350, 250)
self.setWindowTitle('Summoner info')
self.show()
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
sys.exit(app.exec_())
file.close()
The message box doesn't show the content of the file info.txt and almost instantly disappear.
You're defining showdialog as a method of your class Example.
This
sourceAction.triggered.connect(showdialog)
however, looks for showdialog in the local and global namespace - where it isn't defined.
Instead, connect the signal to the the method:
sourceAction.triggered.connect(self.showdialog)
Plus, you'll also have to take at least self as a parameter in your method. I've also added an msg.show() call - your messagebox will otherwise not become visible.
def showdialog(self):
msg = QMessageBox(self) # use self as parent here
# and/or keep a reference to the messagebox
self.messageBox = msg
# etc...
# actually show the message box:
msg.show()
EDIT: Added self as parent for the messagebox - so it's not recycled.
Related
I am new to PyQt and Qt at all and I have a problem with window rendering or updating or how to call it. Problem is that when I call QWidget.show(), none of added components after are displayed. Here is a simple code, where in init(), there is called self.show(). First QLabel item is displayed and the second one is not. What am I doing wrong?
Code:
from PyQt6.QtWidgets import QApplication, QWidget, QLabel
import sys
class MyGui(QWidget):
box = {}
def __init__(self) -> None:
super().__init__()
self.setFixedSize(200, 400)
self.setStyleSheet("background-color:#000000")
self.box["top"] = QLabel(self)
self.box["top"].setFixedSize(200, 200)
self.box["top"].setStyleSheet("background-color:red")
self.box["top"].move(0,0)
self.show()
self.box["botom"] = QLabel(self)
self.box["botom"].setFixedSize(200, 200)
self.box["botom"].setStyleSheet("background-color:green")
self.box["botom"].move(0,200)
if __name__ == "__main__":
app = QApplication(sys.argv)
my_app = MyGui()
my_app.show()
try:
sys.exit(app.exec())
except SystemExit:
print("Closing window..")
Screenshots of GUI window:
With self.show()
Without self.show()
I have two windows (App.py and ChildApp.py) and .ui files for both with same name.
App.py:
import sys
from PyQt4 import QtCore, QtGui, uic
from ChildApp import ChildApp
qtCreatorFile = "App.ui" # Enter file here.
Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)
class App(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
Ui_MainWindow.__init__(self)
self.setupUi(self)
self.message = None
self.child_window = ChildApp()
self.pushButton.clicked.connect(self.sendMessage)
def sendMessage(self):
self.message = self.lineEdit.text()
self.child_window.show()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
window = App()
window.show()
sys.exit(app.exec_())
ChildApp.py:
import sys
from PyQt4 import QtCore, QtGui, uic
qtCreatorFile = "ChildApp.ui" # Enter file here.
Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)
class ChildApp(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self):
QtGui.QMainWindow.__init__(self)
Ui_MainWindow.__init__(self)
self.setupUi(self)
self.pushButton.clicked.connect(self.alertmessage)
def alertmessage(self):
message = "test"
self.label.setText("Message : "+message)
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
window = ChildApp()
window.show()
sys.exit(app.exec_())
In Main.py file I have a variable self.message.
When I click on the button "Do something with text", text in the textbox is assigned to self.message and the child window is opened.
Now in the child window, when I click on button "Show message", the method alertmessage() is called, where it sets message = "text".
This variable message must be assigned to value of self.message from MainApp.py.
Please help
Thank you
Call the child that way:
self.child_window = ChildApp(parent=self)
Define the child app this way:
class ChildApp(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent):
self.parent = parent
you can use the parent variables through self.parent.whatever
It must work, but I wouldn't advise this because you are not supposed to know the fields of the parent form the child.
I don't think you can get local data from the parent. I would do the following:
Use a signal to update the child when the text is changed in the lineEdit:
self.lineEdit.textChanged.connect(self.updateChild)
Add this function in the main window:
def updateChild(self):
self.child_window.setMessage(self.lineEdit.text())
and keep the variable self._message updated in the child window:
def setMessage(self, message):
self._message=message
so that whenever you need this variable, it is up to date
I want to add startup window that when I click button, it will open another window and close current window. For each window, it has seperated UI which created from Qt Designer in .ui form.
I load both .ui file via uic.loadUiType(). The first window(first UI) can normally show its UI but when I click button to go to another window, another UI (second UI) doesn't work. It likes open blank window.
Another problem is if I load first UI and then change to second UI (delete that Class and change to another Class, also delete uic.loadUiType()), the second UI still doesn't work (show blank window)
Please help... I research before create this question but can't find the answer.
Here's my code. How can I fix it?
import sys
from PyQt5.QtWidgets import QApplication, QWidget
from PyQt5.QtGui import QIcon
from PyQt5 import uic
#load both ui file
uifile_1 = 'UI/openPage.ui'
form_1, base_1 = uic.loadUiType(uifile_1)
uifile_2 = 'UI/mainPage.ui'
form_2, base_2 = uic.loadUiType(uifile_2)
class Example(base_1, form_1):
def __init__(self):
super(base_1,self).__init__()
self.setupUi(self)
self.startButton.clicked.connect(self.change)
def change(self):
self.main = MainPage()
self.main.show()
class MainPage(base_2, form_2):
def __int__(self):
super(base_2, self).__init__()
self.setupUi(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
ex.show()
sys.exit(app.exec_())
First you have an error, you must change __int__ to __init__. To close the window call the close() method.
import sys
from PyQt5.QtWidgets import QApplication, QWidget
from PyQt5.QtGui import QIcon
from PyQt5 import uic
#load both ui file
uifile_1 = 'UI/openPage.ui'
form_1, base_1 = uic.loadUiType(uifile_1)
uifile_2 = 'UI/mainPage.ui'
form_2, base_2 = uic.loadUiType(uifile_2)
class Example(base_1, form_1):
def __init__(self):
super(base_1,self).__init__()
self.setupUi(self)
self.startButton.clicked.connect(self.change)
def change(self):
self.main = MainPage()
self.main.show()
self.close()
class MainPage(base_2, form_2):
def __init__(self):
super(base_2, self).__init__()
self.setupUi(self)
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
ex.show()
sys.exit(app.exec_())
I am trying to write a PyQt5 application that does the following:
Creates and opens a Main Window. The MainWindow has a function that opens a QFileDialog window.
Function to open QFileDialog can be triggered in two ways (1) from a file menu option called 'Open' (2) automatically, after the Main window is shown.
My problem is that I haven't found a way to get the QfileDialog to automatically open (2) that doesn't cause the application to hang when the main window is closed. Basic example of code can be found below:
import sys
from PyQt5.QtWidgets import (QApplication, QMainWindow, QMenuBar, QWidget,
QHBoxLayout, QCalendarWidget, QScrollArea, QFileDialog, QAction, QFrame)
from PyQt5.QtGui import QIcon
from PyQt5.QtCore import Qt
class MainWindow(QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.openAction = QAction(QIcon('/usr/share/icons/breeze/places/64/folder-open.svg'), 'Open', self)
self.openAction.triggered.connect(self.openDialog)
self.menubar = QMenuBar(self)
fileMenu = self.menubar.addMenu('&File')
fileMenu.addAction(self.openAction)
self.event_widgets = EventWidgets(self)
self.setMenuBar(self.menubar)
self.setCentralWidget(self.event_widgets)
def openDialog(self):
ics_path = QFileDialog.getOpenFileName(self, 'Open file', '/home/michael/')
class EventWidgets(QWidget):
def __init__(self, parent):
super(EventWidgets, self).__init__(parent)
self.initUI()
def initUI(self):
self.calendar = QCalendarWidget(self)
self.frame = QFrame()
self.scrollArea = QScrollArea()
self.scrollArea.setWidget(self.frame)
horizontal_box = QHBoxLayout()
horizontal_box.addWidget(self.calendar)
horizontal_box.addWidget(self.scrollArea)
self.setLayout(horizontal_box)
if __name__ == '__main__':
app = QApplication(sys.argv)
app_window = MainWindow()
app_window.showMaximized()
app_window.openDialog()
sys.exit(app.exec_())
Code has been tested on KDE Neon and Arch Linux, both have same issue.
I can get round this issue by handling the close event of the Main Window manually - i.e. adding this function to MainWindow:
def closeEvent(self, event):
sys.exit()
But I am not sure a) why this is necessary b) if it is best practice.
I tried your code on macOS Sierra and it works as it's supposed to. However I would propose a different approach to solve your problem.
What you could do is to implement the showEvent() function in your MainWindow class, which is executed whenever a widget is displayed (either using .show() or .showMaximized()) and trigger your custom slot to open the QFileDialog. When doing this you could make use of a single shot timer to trigger the slot with some minimal delay: the reason behind this is that if you simply open the dialog from within the showEvent(), you will see the dialog window but not the MainWindow below it (because the QFileDialog is blocking the UI until the user perform some action). The single shot timer adds some delay to the opening of the QFileDialog, and allows the MainWindow to be rendered behind the modal dialog. Here is a possible solution (not that I made some minor changes to your code, which you should be able to easily pick up):
import sys
from PyQt5 import QtCore
from PyQt5 import QtWidgets
class MainWindow(QtWidgets.QMainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.openAction = QtWidgets.QAction('Open', self)
self.openAction.triggered.connect(self.openDialog)
menuBar = self.menuBar()
fileMenu = menuBar.addMenu('&File')
fileMenu.addAction(self.openAction)
self.event_widgets = EventWidgets(self)
self.setCentralWidget(self.event_widgets)
def showEvent(self, showEvent):
QtCore.QTimer.singleShot(50, self.openDialog)
#QtCore.pyqtSlot()
def openDialog(self):
ics_path = QtWidgets.QFileDialog.getOpenFileName(self, 'Open file', '/Users/daniele/')
class EventWidgets(QtWidgets.QWidget):
def __init__(self, parent):
super(EventWidgets, self).__init__(parent)
self.calendar = QtWidgets.QCalendarWidget(self)
self.frame = QtWidgets.QFrame()
self.scrollArea = QtWidgets.QScrollArea()
self.scrollArea.setWidget(self.frame)
horizontal_box = QtWidgets.QHBoxLayout()
horizontal_box.addWidget(self.calendar)
horizontal_box.addWidget(self.scrollArea)
self.setLayout(horizontal_box)
if __name__ == '__main__':
app = QtWidgets.QApplication(sys.argv)
app_window = MainWindow()
app_window.showMaximized()
sys.exit(app.exec_())
I'm new to PyQt5 and I've got an error (pythonw.exe not working anymore) with the following code:
import sys
from PyQt5.QtWidgets import QWidget, QPushButton, QApplication
from PyQt5.QtCore import QCoreApplication
class Example(QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
qbtn = QPushButton('Quit', self)
qbtn.clicked.connect(self.q)
qbtn.resize(qbtn.sizeHint())
qbtn.move(50, 50)
self.setGeometry(300, 300, 250, 150)
self.setWindowTitle('Quit button')
self.show()
def q():
print('test')
sys.exit()
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
app.exec_()
First it works, but only until I push the "quit" button. Then the error message pops up.
If I put the q() function outside the class (and change "self.q" into "q") it works fine.
What's the problem?
Thanks in advance.
Windows 7
Python 3.4.3 (x86)
PyQt 5.5.1 (x86)
that's because when q() is inside the class it's expects a compulsory argument as the first parameter, this is usually called self and is passed for you implicitly by python when you're calling the method (q() not q(self)). just as you've done with the initUI method in your class, when you put it outside the class, it's just a normal function and not a method again (function in a class), so it's fine to define the function without self
import sys
from PyQt5.QtWidgets import QWidget, QPushButton, QApplication
from PyQt5.QtCore import QCoreApplication
class Example(QWidget):
def __init__(self):
super().__init__()
self.initUI()
def initUI(self):
qbtn = QPushButton('Quit', self)
qbtn.clicked.connect(self.q)
qbtn.resize(qbtn.sizeHint())
qbtn.move(50, 50)
self.setGeometry(300, 300, 250, 150)
self.setWindowTitle('Quit button')
self.show()
def q(self):
print('test')
sys.exit()
if __name__ == '__main__':
app = QApplication(sys.argv)
ex = Example()
app.exec_()