I am trying to upload files using django forms and save those files in the database itself.
I have been able to save the link of the file in database and save the file itself in a directory which i specified in Media_root.Can you please help me and tell me what can i change in my code so that files are saved in the database.
here is my code:
models.py
from django.db import models
class Document(models.Model):
docfile = models.FileField(upload_to='documents/%Y/%m/%d')
forms.py
from django import forms
class DocumentForm(forms.Form):
docfile = forms.FileField(
label='Select a file',
)
views.py
from django.shortcuts import render_to_response
from django.template import RequestContext
from django.http import HttpResponseRedirect
from django.core.urlresolvers import reverse
from .models import Document
from .forms import DocumentForm
def list(request):
# Handle file upload
if request.method == 'POST':
form = DocumentForm(request.POST, request.FILES)
if form.is_valid():
newdoc = Document(docfile = request.FILES['docfile'])
newdoc.save()
# Redirect to the document list after POST
return HttpResponseRedirect(reverse('upload.views.list'))
else:
form = DocumentForm() # A empty, unbound form
# Load documents for the list page
documents = Document.objects.all()
# Render list page with the documents and the form
return render_to_response(
'list.html',
{'documents': documents, 'form': form},
context_instance=RequestContext(request)
)
def index(request):
return render_to_response('index.html')
app\urls.py
from django.conf.urls import patterns, include, url
from django.conf import settings
from django.conf.urls.static import static
from django.views.generic import RedirectView
from django.contrib import admin
# admin.autodiscover()
urlpatterns = patterns('',
(r'^upload/', include('upload.urls')),
(r'^$', 'upload.views.index'),
(r'^admin/', include(admin.site.urls)),) + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
project\urls.py
from django.conf.urls import patterns, include, url
urlpatterns = patterns('upload.views',
url(r'^$', 'list', name='list'),
url(r'^list/$', 'list', name='list'),)
Django provides BinaryField that lets you store any binary data, including file contents.
Please do note that the documentation also says:
Although you might think about storing files in the database, consider that it is bad design in 99% of the cases. This field is not a replacement for proper static files handling.
If you'd rather not store the files on your web server's file system, you can explore other options such as Amazon S3 or just an FTP server. Have a look at the django-storages library, it provides a nice bunch of options.
Related
I hope someone could maybe help me, please :
I am quite new to Django and currently trying to implement a simple login/logout for a test page.
However, for some reasons, the Django does not generate the name of application in the href (so where it should be xxxx/main/register, it is only xxx/register).
But when I put the app name manually in the href in Pycharm, it generates it two times (so it becomes xxx/main/main/register).
So for this:
Logout
I got this url:
http://127.0.0.1:8000/logout/
If I write this:
Logout
I got this url:
http://127.0.0.1:8000/main/main/logout/
But I need to get this:
http://127.0.0.1:8000/main/logout/
It worked before, but from one minute to another, it suddenly stopped directing to the good path. And django does the same thing with every links in my site.
main/urls.py:
from django.urls import path
from . import views
app_name = 'main' # here for namespacing of urls.
urlpatterns = [
path("", views.homepage, name="homepage"),
path("register/", views.register, name="register" ),
path("logout/", views.logout_request, name="logout"),
]
main/views.py:
from django.shortcuts import render, redirect
from django.http import HttpResponse
from .models import Tutorial
from django.contrib.auth.forms import UserCreationForm, AuthenticationForm
from django.contrib.auth import logout, authenticate, login
from django.contrib import messages
def homepage(request):
return render(request = request,
template_name='main/home.html',
context = {"tutorials":Tutorial.objects.all})
def register(request):
if request.method == "POST":
form = UserCreationForm(request.POST)
if form.is_valid():
user = form.save()
username = form.cleaned_data.get('username')
messages.success(request, f"New account created: {username}")
login(request, user)
return redirect("main:homepage")
else:
for msg in form.error_messages:
messages.error(request, f"{msg}: {form.error_messages[msg]}")
else:
form = UserCreationForm
return render(request = request,
template_name='main/register.html',
context={"form":form})
def logout_request(request):
logout(request)
messages.info(request, "Logged out successfully!")
return redirect("main:homepage")
mysite/urls.py:
from django.contrib import admin
from django.urls import include, path
urlpatterns = [
path('polls/', include('polls.urls')),
path('main/', include('main.urls')),
path('admin/', admin.site.urls),
path('tinymce/', include('tinymce.urls')),
]
The behaviour you observe has nothing to do with Django, it's a basic html feature: in the first case you're using an absolute path (=> starting with a slash) for your href, in the second one you're using a relative path (NOT starting with a slash) so it's resolved relatively to the current url path whatever it is. You'd have the very same issue with plain static HTML.
This being said, in Django, you should never hardcode urls, but use the {% url <name> %} template tag (or the django.utils.reverse() function in Python code) instead, so you can change your urls in the urls.py files without breaking anything.
<a href="{% url 'logout' %}">
Use the name in href tag that will work.
You should use the url name in the template. It should solve the problem. Like this:
Logout
Or with namespacing:
Logout
I am newbie Django dev, I have a bit problem about urls config. I want to make url http://localhost:8000/user-auth/register/
In my project, there is user_auth app with below urls:
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^register$', views.register),
]
In register this url within urls in my site:
from django.conf.urls import include, url
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
url(r'^polls/', include('polls.urls')),
url(r'^user-auth/', include('user_auth.urls')),
]
In my view user_auth/views.py:
from django.shortcuts import render
from django.http import HttpResponse
from .forms import RegisterForm
def register(request):
if request.method == 'POST':
response = HttpResponse()
response.write("<h1>Thanks for registering</h1></br>")
response.write("Your username:" + request.POST['username'])
response.write("Your email" + request.POST['email'])
return response
registerForm = RegisterForm()
return render(request, 'user_auth/register.html', {'form':registerForm})
In my user_auth/forms.py
from django import forms
class RegisterForm(forms.Form):
username = forms.CharField(label='Username', max_length=100)
password = forms.CharField(widget=forms.PasswordInput)
email = forms.EmailField(label='Email')
When I access to the link http://localhost:8000/user-auth/register/, the console announce "Not Found: /user-auth/register/". I dont know reason why and where. Could you please help me on this problem?. Tks
Well, this question has been asked by many users, and I have tried some of the resolution provided in the query, but that doesn't seem to resolve my issue, maybe I am doing some other mistake.
I am trying to create a simple user registration/login/logout forms
SchoolnSkill ---Project name, and below is the SchoolnSkill/url details:-
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^admin/', admin.site.urls),
url(r'^user_info/', include('user_info.urls')),
]
user_info--App name, and the user_info/url details are below:-
from django.conf.urls import url
from . import views
urlpatterns = [
# url(r'^$', views.index, name='index'),
url(r'^registration/', views.UserFormView, name='registration')
]
My views.py output is as below:-
from django.shortcuts import render, redirect
from django.views.generic.edit import CreateView, UpdateView, DeleteView
from django.core.urlresolvers import reverse_lazy
from django.contrib.auth import authenticate, login
from django.views import generic
from .models import Registration
from django.views import View
from .forms import UserForm
class UserFormView(View):
#from_class = UserForm
template_name = 'user_info/registration_form.html'
#dispaly blank form, new user coming to the website
def get(self, request):
form = self.UserForm(None)
return render(request, self.template_name, {'form':form})
def post(self, request):
form = self.UserForm(request.POST)
if form.is_valid():
user = form.save(commit=False)
username = form.cleaned_data['username']
password = form.cleaned_data['password']
user.set_password(password)
user.save()
form.py content as below:
from django.contrib.auth.models import User
from django import forms
from django.forms import ModelForm
class UserForm(forms.ModelForm):
password = forms.CharField(widget =forms.PasswordInput)
class Meta:
model = User
fields = ['username', 'email', 'password']
I am using below versions:
Python 3.6
Django 1.11.3
Spyder IDE
I am pretty sure that am doing something silly.
Please help.
below is the error message:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/user_info/
Using the URLconf defined in SchoolnSkill.urls, Django tried these URL patterns, in this order:
^admin/
^user_info/ ^registration/ [name='registration']
The current path, user_info/, didn't match any of these.
as you are using class based view you need to add as_view in the url
so
change this in user_info url to
urlpatterns = [
url(r'^registration/', views.UserFormView.as_view(), name='registration')
]
So, I'm trying to create a table filled with contacts in Python/Django. When I attempt to run the program, I get the above error message ("ImportError: Could not import 'edit_contact'. The path must be fully qualified.")
Here is the views.py I'm using:
from contacts.models import Contact
#, Address, Telephone
from django.http import HttpResponse, HttpResponseRedirect
from django.shortcuts import render_to_response, get_object_or_404, render
from django.template import Context, loader
from django.forms.models import inlineformset_factory
from django.template import loader, Context, RequestContext
from django.core.urlresolvers import reverse
from django.contrib.auth.decorators import login_required
# Create your views here.
def index(request):
#return HttpResponse("Hey! You can see contacts here!")
contact_list = Contact.objects.all().order_by('last_name')
return render_to_response('contacts/index.html', {'contact_list': contact_list},
RequestContext(request))
def detail(request, contact_id):
c = get_object_or_404(Contact, pk=contact_id);
def new_contact(request):
print "new_contact"
#AddressInlineFormSet = inlineformset_factory(Contact,
if request.method == "POST":
form = ContactForm(request.POST)
if form.is_valid():
contact = form.save()
return HttpResponseRedirect(reverse('contacts.views.detail', args=(contact.pk,)))
else:
form = ContactForm()
return render_to_response("contacts/form.html",{
"form": form,
}, RequestContext(request))
def edit_contact(request, contact_id):
contact = Contact.objects.get(pk=contact_id)
if request.method == "POST":
form = ContactForm(request.POST, instane=contact)
if form.is_valid():
form.save()
return HttpResponseRedirect(reverse('contacts.views.detail', args=(contact.pk,)))
else:
form = ContactForm(instance = contact)
return render_to_response("contacts/form.html", {
"form": form,
}, RequestContext(request))
This is the urls.py:
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^(?P<contact_id>\d+)/$', 'detail', name='contactdetailsurl'),
url(r'^new/$', 'new_contact', name='newcontacturl'),
url(r'^(?P<contact_id>\d+)/edit/$','edit_contact', name='editcontacturl'),
]
And the error is pointing to this line in my site_base.html file:
<li id="tab_first"><a href="
{% url contacts.views.index %}
"><i class="icon-book"></i> Contacts</a></li>
Let me know if you need any more info. Thanks!
The error is telling you that you should use the full path to the view, for example 'contacts.views.edit_contact' (assuming the app is called contacts).
However, using strings in your URL patterns is deprecated in Django 1.8, and not supported in Django 1.10+. You should using callables instead. You are already using the callable views.index for your index URL pattern.
I would convert the rest of your URL patterns as follows:
urlpatterns = [
url(r'^$', views.index, name='index'),
url(r'^(?P<contact_id>\d+)/$', views.detail, name='contactdetailsurl'),
url(r'^new/$', views.new_contact, name='newcontacturl'),
url(r'^(?P<contact_id>\d+)/edit/$', views.edit_contact, name='editcontacturl'),
]
I'm using django's auth module to handle the user login, logout and registration in my website.
The problem is that when I register a new user, I new to redirect to another url, and then, since the model is created but doesn't automatically log in, I need to navigate to /login/ and log in manually.
I would like my site to do this automatically. By that I mean that:
You click on the register button in home.html. You fill in the form and submit it.
The website AUTOMATICALLY creates the new user model, logs you in and redirects you to home.html with the user logged in.
Urls.py looks like this:
from django.conf.urls import include, url, patterns
from django.contrib import admin
from django.conf import settings
from django.conf.urls.static import static
from django.contrib.auth import views as auth_views
from django.contrib.auth.forms import UserCreationForm
from browse.views import UserCreate
urlpatterns = patterns('',
url(r'',include('browse.urls')),
url(r'^$', 'browse.views.home_page', name='home'),
url(r'^admin/', include(admin.site.urls)),
url(r'^login/$', auth_views.login, {'template_name': 'browse/login.html'}),
url(r'^register/$', UserCreate.as_view(
template_name='browse/register.html',
form_class=UserCreationForm,
success_url='/register/'
)),
url(r'^logout/$', 'browse.views.logout_view', name='logout'),
url(r'^', include('django.contrib.auth.urls')),
) + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
and views.py looks like this:
from django.shortcuts import render, redirect
from django.views.generic.edit import CreateView
from browse.models import Pattern
from django.contrib.auth.models import User
from django.contrib.auth import logout, login
class PatternCreate(CreateView):
model = Pattern
fields = ['name','description','license', 'xcheme', 'pictures', 'video']
class UserCreate(CreateView):
model = User
def post(self, request):
return login(request, User.objects.get(username=request.POST['username']))
def home_page(request):
return render(request, 'browse/home.html')
def pattern_detail(request, pk):
pattern = Pattern.objects.get(pk=pk)
return render(request, 'browse/pattern_detail.html', {'pattern': pattern})
def logout_view(request):
logout(request)
return redirect('/')
As you can see, when you GET /register/ the register form is rendered. When I POST to /register/, I want to execute the view as normally AND then add:
def post(self, request):
return login(request, User.objects.get(username=request.POST['username']))
But It looks like I'm overriding the default view instead of adding to it, because the model doesn't get saved, since I get this error:
Exception Value:
User matching query does not exist.
How can I fix it?
Thank you so much beforehand.
Okay, it was a really dumb question. Luckily, I could figure it out:
def post(self, request):
super(UserCreate, self).post(request)
login_username = request.POST['username']
login_password = request.POST['password1']
created_user = authenticate(username=login_username, password=login_password)
login(request, created_user)
return redirect('/')
All I had to do is call super() and the parent function is executed. Then, my code executes.