I have a main tkinter window that can take up to a few seconds to load properly. Because of this, I wish to have a splash screen that shows until the init method of the main class has finished, and the main tkinter application can be shown. How can this be achieved?
Splash screen code:
from Tkinter import *
from PIL import Image, ImageTk
import ttk
class DemoSplashScreen:
def __init__(self, parent):
self.parent = parent
self.aturSplash()
self.aturWindow()
def aturSplash(self):
self.gambar = Image.open('../output5.png')
self.imgSplash = ImageTk.PhotoImage(self.gambar)
def aturWindow(self):
lebar, tinggi = self.gambar.size
setengahLebar = (self.parent.winfo_screenwidth()-lebar)//2
setengahTinggi = (self.parent.winfo_screenheight()-tinggi)//2
self.parent.geometry("%ix%i+%i+%i" %(lebar, tinggi, setengahLebar,setengahTinggi))
Label(self.parent, image=self.imgSplash).pack()
if __name__ == '__main__':
root = Tk()
root.overrideredirect(True)
progressbar = ttk.Progressbar(orient=HORIZONTAL, length=10000, mode='determinate')
progressbar.pack(side="bottom")
app = DemoSplashScreen(root)
progressbar.start()
root.after(6010, root.destroy)
root.mainloop()
Main tkinter window minimum working example:
import tkinter as tk
root = tk.Tk()
class Controller(tk.Frame):
def __init__(self, parent):
'''Initialises basic variables and GUI elements.'''
frame = tk.Frame.__init__(self, parent,relief=tk.GROOVE,width=100,height=100,bd=1)
control = Controller(root)
control.pack()
root.mainloop()
EDIT: I can use the main window until it has finished loading using the .withdraw() and .deiconify() methods. However my problem is that I cannot find a way to have the splash screen running in the period between these two method calls.
a simple example for python3:
#!python3
import tkinter as tk
import time
class Splash(tk.Toplevel):
def __init__(self, parent):
tk.Toplevel.__init__(self, parent)
self.title("Splash")
## required to make window show before the program gets to the mainloop
self.update()
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
self.withdraw()
splash = Splash(self)
## setup stuff goes here
self.title("Main Window")
## simulate a delay while loading
time.sleep(6)
## finished loading so destroy splash
splash.destroy()
## show window again
self.deiconify()
if __name__ == "__main__":
app = App()
app.mainloop()
one of the reasons things like this are difficult in tkinter is that windows are only updated when the program isn't running particular functions and so reaches the mainloop. for simple things like this you can use the update or update_idletasks commands to make it show/update, however if the delay is too long then on windows the window can become "unresponsive"
one way around this is to put multiple update or update_idletasks command throughout your loading routine, or alternatively use threading.
however if you use threading i would suggest that instead of putting the splash into its own thread (probably easier to implement) you would be better served putting the loading tasks into its own thread, keeping worker threads and GUI threads separate, as this tends to give a smoother user experience.
Related
I'm working on a tkinter GUI in Python to produce error messages in a new window. When running the code as shown below, the error noise plays, then it pauses for several seconds before opening the window. If I comment out the line with winsound, it opens it just fine.
import tkinter as tk
import winsound
class Error_Window:
def __init__(self, txt):
self.root = tk.Tk()
self.root.title("Error")
self.lbl = tk.Label(self.root, text=txt)
self.lbl.pack()
winsound.PlaySound("SystemExit", winsound.SND_ALIAS)
self.root.mainloop()
I suspect that it may be due to the error noise playing in full before reaching the mainloop command. One solution to this could be running the sound in a separate thread, but I've heard multithreading with tkinter should be avoided. Any tips on getting it to open smoothly at the same time as the noise is played?
Try this, the reason why it does that is the whole program is should we say in ONE THREAD/ MAIN THREAD so it would do first or execute first the sound then pop up the window. I think there's no problem with working with threads in tkinter just like what #jasonharper said
import tkinter as tk
import winsound
import threading
class Error_Window:
def __init__(self, txt):
self.root = tk.Tk()
self.root.title("Error")
self.lbl = tk.Label(self.root, text=txt)
th = threading.Thread(target=self.__play_sound,args=[])
th.start()
self.lbl.pack()
self.root.mainloop()
def __play_sound(self):
winsound.PlaySound("SystemExit", winsound.SND_ALIAS)
Error_Window("Hi")
I wrote a small application using python 3 and tkinter. Testing every widget, even though there are not many of them feels daunting so I wanted to write a couple of automated tests to simplify the process. I read some other question that seemed relevant to this problem but none fit my needs. Right now I'm doing the testing in a very simple manner - I invoke the command for every widget and manually click through it to see if it works. It does make things a bit faster, but I constantly run into some problems - i.e. I can't automatically close popup windows (like showinfo) even with using libraries to simulate keyboard clicks (namely pynput). Is there an efficient approach for testing applications using tkinter?
Here is the code I use right now:
import tkinter as tkinter
import unittest
from mygui import MyGUI
class TKinterTestCase(unittest.TestCase):
def setUp(self):
self.root = tkinter.Tk()
def tearDown(self):
if self.root:
self.root.destroy()
def test_enter(self):
v = MyGUI(self.root)
v.info_button.invoke()
v.close_button.invoke()
v.btnOut.invoke()
if __name__ == "__main__":
unittest.main()
I don't know much about unittest but I found a workaround to close popup dialogs like showinfo during the tests. The idea is to use keyboard event to invoke the button of the dialog. But since the app is waiting for the user to close the popup dialog, we need to schedule in advance the keyboard event using after:
self.root.after(100, self.root.event_generate('<Return>'))
v.button.invoke()
Full example
import tkinter
from tkinter import messagebox
import unittest
class MyGUI(tkinter.Frame):
def __init__(self, master, **kw):
tkinter.Frame.__init__(self, master, **kw)
self.info_button = tkinter.Button(self, command=self.info_cmd, text='Info')
self.info_button.pack()
self.quit_button = tkinter.Button(self, command=self.quit_cmd, text='Quit')
self.quit_button.pack()
def info_cmd(self):
messagebox.showinfo('Info', master=self)
def quit_cmd(self):
confirm = messagebox.askokcancel('Quit?', master=self)
if confirm:
self.destroy()
class TKinterTestCase(unittest.TestCase):
def setUp(self):
self.root = tkinter.Tk()
self.root.bind('<Key>', lambda e: print(self.root, e.keysym))
def tearDown(self):
if self.root:
self.root.destroy()
def test_enter(self):
v = MyGUI(self.root)
v.pack()
self.root.update_idletasks()
# info
v.after(100, lambda: self.root.event_generate('<Return>'))
v.info_button.invoke()
# quit
def cancel():
self.root.event_generate('<Tab>')
self.root.event_generate('<Return>')
v.after(100, cancel)
v.quit_button.invoke()
self.assertTrue(v.winfo_ismapped())
v.after(100, lambda: self.root.event_generate('<Return>'))
v.quit_button.invoke()
with self.assertRaises(tkinter.TclError):
v.winfo_ismapped()
if __name__ == "__main__":
unittest.main()
I am creating a gui application using Tkinter, which imports other pieces of code stored in external .py files which contain time consuming functions. What I want to do is have a progressbar on my gui window which gets updated according to some function running in my imported script.
Gui script example:
#gui script
import tkinter
from tkinter import ttk
from somefile import somefunc
progcomp = ttk.Progressbar(root, orient='horizontal', length=200, mode = 'determinate', maximum=100)
somefunc()
External function example:
#somefile.py
def somefunc():
for i in range(1000):
#dosomething
#update progressbar of gui script
My actual code is too long to show in a question like this, so I chose to represent it as simply as possible. My question is, is this possible or will I have to change the infrastructure to accomplish?
You could use threading to implement this. Below is a very rough example of this.
threaded_task.py
import threading
import time
class ThreadedTask(threading.Thread):
def __init__(self, progress):
threading.Thread.__init__(self)
self.progress = progress
def run(self):
for i in range(100):
self.progress.step(1) # Update progress bar
time.sleep(1) # Simulate long running process
main.py
from tkinter import *
from tkinter import ttk
from threaded_task import ThreadedTask
root = Tk()
progcomp = ttk.Progressbar(root, orient='horizontal', length=200, mode = 'determinate', maximum=100)
progcomp.grid()
task = ThreadedTask(progcomp)
task.start()
root.mainloop()
I want to create a GUI module that I can import in my main program without having to import tkinter there, letting just the module handle everything. Here's how I imagine that it might work:
main.py
import gui as g
def update():
#Update the GUI with new Data from this main program
GUI = g.gui()
gui.after(1000, update)
gui.mainloop()
gui.py
import tkinter as tk
class viewer(tk.Frame):
#Some variables
def __init__(self, parent):
tk.Frame.__init(self, parent)
self.parent = parent
self.initialize(400, 100)
def initialize(self, width, height):
#Initialize some widgets, place them on grid, etc
def start(self):
#Do some other stuff, make a main window, configurations, etc
print('Started!')
Edit: "Don't ask for opinion"
How do I make this work?
import tkinter as tk
import gui as g
root = tk.Tk()
GUI = g.gui(root)
GUI.after(1000, update)
GUI.mainloop()
The above is what I don't want.
I used a workaround that seemed plausible to me:
main.py
import gui
GUI = gui.start()
GUI.after(1000, update)
GUI.mainloop()
gui.py
import tkinter as tk
def start():
root = tk.Tk()
run = viewer(root) # <- The class provided above
return run
I created a simple tkinter app, where have used two threads. Their task is to write numbers to widgets such as label and text. One thread is triggered by button (click event) and second is executed as a background thread.
import Tkinter as tk
from ttk import *
from Tkconstants import *
import threading, thread, time
def tl1(text,counter):
while True:
text.insert(END,counter)
counter += 1
time.sleep(2)
def tl2(label,counter):
while True:
label['text'] = counter
counter += 1
time.sleep(1)
class mainWindow():
def __init__(self, master):
self.master = master
self._initLayout()
def _initLayout(self):
#button
self.button = tk.Button(self.master, text="thread1_start", command = self._task1)
self.button.pack()
#label
self.label = tk.Label(self.master)
self.label.pack()
#text
self.text = tk.Text(self.master, width=30)
self.text.pack()
def _task1(self):
t1 = thread.start_new_thread(tl1,(self.text,1))
def _task2(self):
t2 = thread.start_new_thread(tl2,(self.label,1000))
class App(tk.Tk):
def __init__(self):
tk.Tk.__init__(self)
self.mainWindow = mainWindow(self)
self.mainWindow._task2() #background_thread
app = App()
app.mainloop()
In this manner everything works fine, but if we change the background thread to display results on text widget, the whole app freezes.
Why background thread works fine communicating with label but causes problems with text widget? Is there any way to run it properly?
Tkinter isn't thread safe. You can only access widgets from the thread that created them. Your threads will need to put data on a thread-safe queue, and your GUI thread will need to poll the queue.
In your particular case you don't need threads at all. You can use the tkinter after method to run code periodically.