Develop Reference

How to compare two tables and identify a specific type of row to be returned?

I have two tables with relatively different data.
the photos table is a table with all the relevant meta data for photos such as user_id, photo_id, datetime, name, etc.
I have another table ratings that holds liked/disliked data for each respective photo. The columns in this table would have rater_id(for the person rating the picture), photo_id, and the rating (like/dislike).
The user would be presented a picture (at random) and then pick whether they liked it or not. Every time the image is loaded/presented it would have to be something that they have not yet rated.
What I'm trying to do is return a photo_id where the user has not yet rated it.
I've thought of using join or union, but I'm having difficulty understanding how to best use those (or any other solution) for this application. Where my confusion lies is how I can compare the ratings table against the photos table, to only return the photos that have not been rated by rater_id.
Sample data
photos table
id | photo_id
-------------------------
1 | photo_123
2 | photo_456
3 | photo_432
4 | photo_642
-------------------------
ratings table
id | photo_id | rater_id | rating
---------------------------------
1 | photo_123 | user2 | 1
2 | photo_456 | user2 | 1
3 | photo_123 | user1 | 1
4 | photo_642 | user2 | 1
--------------------------------
Sample Result: return photo_432 for user2 because it has not yet had a rating in ratings table

The canonical way would be not exists:
select p.*
from photos p
where not exists (select 1
from ratings r
where r.photo_id = p.id and
r.rater_id = #rater
)
order by rand()
limit 1;
There are more efficient ways to get a random row back if the table is big.

Trouble with SQL join, where, having clause

I'm having trouble understanding how to make a query that will show me 'the three most popular articles' in terms of views ('Status: 200 OK').
There are 2 tables I'm currently dealing with.
A Log table
An Articles table
The columns in these tables:
Table "public.log"
Column | Type | Modifiers
--------+--------------------------+--------------------------------------------------
path | text |
ip | inet |
method | text |
status | text |
time | timestamp with time zone | default now()
id | integer | not null default nextval('log_id_seq'::regclass)
Indexes:
and
Table "public.articles"
Column | Type | Modifiers
--------+--------------------------+-------------------------------------------------------
author | integer | not null
title | text | not null
slug | text | not null
lead | text |
body | text |
time | timestamp with time zone | default now()
id | integer | not null default nextval('articles_id_seq'::regclass)
Indexes:
.
So far, I've written this query based on my level and current understanding of SQL...
SELECT articles.title, log.status
FROM articles join log
WHERE articles.title = log.path
HAVING status = “200 OK”
GROUP BY title, status
Obviously, this is incorrect. I want to be able to pull the three most popular articles from the database and I know that 'matching' the 200 OK's with the "article title" will show or count in for me one "view" or hit. My thought process is like, I need to determine how many times that article.title=log.path (1 unique) shows up in the log database (with a status of 200 OK) by creating a query. My assignment is actually to write a program that will print the results with "[my code getting] the database to do the heavy lifting by using joins, aggregations, and the where clause.. doing minimal "post-processing" in the Python code itself."
Any explanation, idea, a tip is appreciated all of StackOverflow...

Perhaps the following is what you have in mind:
SELECT
a.title,
COUNT(*) AS cnt
FROM articles a
INNER JOIN log l
ON a.title = l.path
WHERE
l.lstatus = '200 OK'
GROUP BY
a.title
ORDER BY
COUNT(*) DESC
LIMIT 3;
This would return the three article titles having the highest status 200 hit counts. This answer assumes that you are using MySQL.

Python ,SQLAlchemy, get id from database

I want to make a Python (SQLAlchemy) program that takes the ID from a table according to a value.
For example, I have a table like this :
-------------------------------
| ID | Name |
-------------------------------
| 1 | Paul |
-------------------------------
| 2 | Paul |
-------------------------------
| 3 | John |
-------------------------------
And I want to retrieve the IDs where the name is Paul.
The code I was doing was something like this :
list = session.query(Table).filter_by(Name='Paul')
list_id = []
for tuple in list :
list_id.append(tuple.id)
for id in list_id :
print(id)
Is there any much easier solution?
Thanks!

You don't need the intermediate list to 'hold' the id, if you only use them once, just iterate directly over the query.
for row in session.query(Table).filter_by(Name='Paul'):
print(row.ID)
If you only need the ID, you can arrange for your query to return only that:
for ID in session.query(Table.ID).filter_by(Name='Paul'):
print(ID)

How to rewrite Raw SQL Query (MySQL) with Django ORM query?

How to rewrite next Raw SQL Query (MySQL) with Django ORM query?
mysql> select author_id,
count(*) c
from library_books
group by author_id
having c>2
limit 3;
+---------------+----+
| author_id | c |
+---------------+----+
| 0 | 39 |
| 1552 | 17 |
| 1784 | 8 |
+---------------+-----

First, annotate an author queryset with the number of books.
from django.db.models import Count
authors = Author.objects.annotate(num_books=Count('librarybook')
You haven't shown your Django models, so I've had to guess that 'librarybook' is the correct name for the reverse relationship.
Then filter on the num_books to find authors with more than two books.
authors = Author.objects.annotate(num_books=Count('librarybook').filter(num_books__gt=2)
Finally, slice the queryset to limit it to 3 results.
authors = Author.objects.annotate(num_books=Count('librarybook').filter(num_books__gt=2)[:3]
You can then loop through the resulting authors and access the number of books.
for author in authors:
print author.name, author.num_books

Django group by id then select max timestamp

It might be a redundant question, but I have tried previous answers from other related topics and still can't figure it out.
I have a table Board_status looks like this (multiple status and timestamp for each board):
time | board_id | status
-------------------------------
2012-4-5 | 1 | good
2013-6-6 | 1 | not good
2013-6-7 | 1 | alright
2012-6-8 | 2 | good
2012-6-4 | 3 | good
2012-6-10 | 2 | good
Now I want to select all records from Board_status table, group all of them by board_id for distinct board_id, then select the latest status on each board. Basically end up with table like this (only latest status and timestamp for each board):
time | board_id | status
------------------------------
2013-6-7 | 1 | alright
2012-6-4 | 3 | good
2012-6-10 | 2 | good
I have tried:
b = Board_status.objects.values('board_id').annotate(max=Max('time')).values_list('board_id','max','status')
but doesn't seem like it is working. Still give me more than 1 record per board_id.
Which command should I use in Django to do this?

An update, this is the solution I use. Not the best, but it works for now:
b=[]
a = Board_status.objects.values('board_id').distinct()
for i in range(a.count()):
b.append(Board_status.objects.filter(board_id=a[i]['board_id']).latest('time'))
So I got all board_id, store into list a. Then for each board_id, do another query to get the latest time. Any better answer is still welcomed.

How will it work? You neither have filter nor distinct to filter out the duplicates. I am not sure if this can be easily done in a single django query. You should read more on:
https://docs.djangoproject.com/en/dev/ref/models/querysets/#django.db.models.query.QuerySet.distinct
https://docs.djangoproject.com/en/1.4/topics/db/aggregation/
If you can't do it in 1 raw sql query, you can't do it with an OR mapper either as it's built on top of mysql (in your case). Can you tell me how you would do this via raw SQL?