I'm trying to access some data from a public source, however I have trouble getting the module fileio to work despite installing it with pip. Here's my code:
from fileio import read
import gzip
odffn = 'test-data/Level1_IC59_data_Run00115150_Part00000000.odf.gz'
f = gzip.open(odffn)
ev = read(f)
hit_dist = list()
while ev :
# do some analysis with the event
hit_dist.append(len(ev.hits))
# get the next event
ev = read(f)
import pylab
pylab.hist(hit_dist,30,range=(0,1000), log=True, histtype='step')
pylab.title('IceCube Hit Distribution')
pylab.xlabel('nhit')
pylab.savefig('nhits.png')
And I get the following error:
from fileio import read
ModuleNotFoundError: No module named 'fileio'
However, I already checked using the pip installer,
python -m pip install fileio
And I get the module is already installed. I don't think it's a problem with the PATH since it works well with all the other models (i.e. numpy), so I'm not really sure what could be the problem. I appreciate in advance any insight.
I looked in pip for fileio and from what I can see, this doesn't appear to be a legitimate package. When installed from pip it doesn't install any importable Python modules or packages. All it does it create a skeleton directory under site-packages.
I think you should step back and re-evaluate what this code is doing:
from fileio import read
import gzip
odffn = 'test-data/Level1_IC59_data_Run00115150_Part00000000.odf.gz'
f = gzip.open(odffn)
ev = read(f)
hit_dist = list()
This seems fine (ignoring the import from fileio), up until the line: ev = read(f). What is the purpose of using this function to read the file object that gzip returns? That object has its own set of read methods that should be able to do the job:
import gzip
odffn = 'test-data/Level1_IC59_data_Run00115150_Part00000000.odf.gz'
f = gzip.open(odffn)
lines = f.readlines()
Assuming this is a text file, that should read the whole thing into a list of strings, one per line. You can also buffer it:
buf_size = 100
buf = f.read(buf_size)
while buf:
<do something with 1-100 characters of input>
buf = f.read(buf_size)
or buffer whole lines:
line_buf = f.readline()
while line_buf:
<do something with a line of input>
line_buf = f.readline()
I'm on a Debian GNU/Linux computer, working with Python 2.7.9.
As a part of my job, I have been making python scripts that read inputs in various formats (e.g. Excel, Csv, Txt) and parse the information to more standarized files. It's not my first time opening or working with Excel files.
There's a particular file which is giving me problems, I just can't open it. When I tried with xlrd (version 0.9.3), it gave me the following error:
xlrd.open_workbook('sample.xls')
XLRDError: Unsupported format, or corrupt file: BOF not
workbook/worksheet: op=0x0009 vers=0x0002 strm=0x000a build=0 year=0
-> BIFF21
I tried to investigate the matter on my own, found a couple of answers in StackOverflow but I couldn't open it anyway. This particular answer I found may be the problem (the second explanation), but it doesn't include a workaround: https://stackoverflow.com/a/16518707/4345659
A tool that could conert the file to csv/txt would also solve the problem.
I already tried with:
xlrd
openpyxl
xlsx2csv (the shell tool)
A sample file is available here:
https://ufile.io/r4m6j
As a side note, I can open it with LibreOffice Calc and MS Excel, so I could eventually change it to csv that way. The thing is, I need to do it all with a python script.
Thanks in advance!
It seems like MS Problem. The xls file is very strange, maybe you should contact xlrd support.
But I have a crazy workaround for you: xls2ods. It works for me even though xls2csv doesn't (SiC!).
So, install catdoc first:
$sudo apt-get install catdoc
Then convert your xls file to ods and open ods using pyexcel_ods or whatever you prefer. To use pyexcel_ods install it first using pip install pyexcel_ods.
import subprocess
from pyexcel_ods import get_data
file_basename = 'sample'
returncode = subprocess.call(['xls2ods', '{}.xls'.format(file_basename)])
if returnecode > 0:
# consider to use subprocess.Popen if you need more control on stderr
exit(returncode)
data = get_data('{}.ods'.format(file_basename))
print(data)
I'm getting following output:
OrderedDict([(u'sample',
[[u'labo',
u'codfarm',
u'farmacia',
u'direccion',
u'localidad',
u'nom_medico',
u'matricula',
u'troquel',
u'producto',
u'cant_total']])])
Here is a kludge I would use:
Assuming you have LibreOffice on Debian, you could either convert all your *.xls files into *.csv using:
import os
os.system("libreoffice --headless --convert-to csv *.xls")
#or use os.call
... and then work consistently with csv.
Or you could convert only the corrupted file(s) when needed using a try/except block:
import os
try:
xlrd.open_workbook('sample.xls')
except XLRDError:
os.system("libreoffice --headless --convert-to csv sample.xls")
# mycsv = open("sample.csv", "r")
# for line in mycsv.readlines():
# ...
# ...
OBS: Keep LibreOffice closed while running the script.
Alternatively there are other tools out there to do the conversion. Here is one (which I have not tested): https://github.com/dilshod/xlsx2csv
If you are targeting windows, if you have Excel installed, and if you are familiar with Excel VBA, you will have a quick solution using the comtypes package:
http://pythonhosted.org/comtypes/
You will have direct access to Excel by its COM interfaces.
This code open an xls file and saves it as a cvs file, using the comtypes package:
import comtypes.client as cl
progId = "Excel.Application.15"
xl = cl.CreateObject(progId)
wb = xl.Workbooks.Open(r"C:\Users\aUser\Desktop\thermoList.xls")
wb.SaveAs(r"C:\Users\aUser\Desktop\thermoList.csv",FileFormat=6)
xl.DisplayAlerts = False
xl.Quit()
I could not test it with "sample.xls" which is corrupt.
Your could try with another file.
You might need to adjust the progId according to your version of Excel.
It's a file format issue. I'm not sure what file type is it but it's not Excel. I just open and saved the file with sample2.xls name and compare the types:
How are you creating this file?
If you need to get the words as a list of strings:
text_file = open("sample.xls", "r")
lines = text_file.read().replace(chr(200), '').replace(chr(0), '').replace(chr(1), '').replace(chr(5), '').replace(chr(2), '').replace(chr(3), '').replace(chr(4), '').replace(chr(6), '').replace(chr(7), '').replace(chr(8), '').replace(chr(9), '').replace(chr(10), '').replace(chr(12), '').replace(chr(15), '').replace(chr(16), '').replace(chr(17), '').replace(chr(18), '').replace(chr(49), '').replace('Arial', '')
for line in lines.split(chr(128)):
print(line)
the output:
The file you provided is corrupted, so there is no way for other responders to test it and recommend a good solution. And exception you posted confirming that.
As a solution you can try to debug some things, please see some steps below:
You mentioned you tried the xlrd library. Try to check if your xlrd module is upto date by executing this:
Python 2.7.9
>>> import xlrd
>>> xlrd.__VERSION
update to the latest official version if needed
Try to open any other *.xls file and see if it works with Python version you're using and current library.
Check module documentation it's pretty good, and there are some different things described how to use this module on various platforms( Win vs. Linux)http://xlrd.readthedocs.io/en/latest/dates.html
You always can rich out to the community (there is still a chance that you might be getting into some weird state or bug) the link is here https://github.com/python-excel/xlrd/issues
Hope that helps.
Unable to open your Excel either. Just as yadayada said, I think it is the problem of data source. If you really want to figure out the reason, I suggest you ask questions about the excel instead of python.
It's always work for me with any xls or xlsx files:
def csv_from_excel(filename_xls, filename_csv):
wb = xlrd.open_workbook(filename_xls, encoding_override='YOUR_ENCODING_HERE (f.e. "cp1251"')
sh = wb.sheet_by_index(0)
your_csv_file = open(filename_csv, 'wb')
wr = unicodecsv.writer(your_csv_file)
for rownum in xrange(sh.nrows):
wr.writerow(sh.row_values(rownum))
your_csv_file.close()
So, i don't work directly with excel file before convert them to csv. Mb it will help you
Why do I receive this warning message every time I run my code? (below). Is it possible to get rid of it? If so, how do I do that?
My code:
from openpyxl import load_workbook
from openpyxl import Workbook
wb = load_workbook('NFL.xlsx', data_only = True)
ws = wb.active
sh = wb["Sheet1"]
ptsDiff = (sh['J127'].value)
print ptsDiff
The code works but I get this warning message:
Warning (from warnings module):
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/openpyxl/reader/worksheet.py", line 320
warn(msg)
UserWarning: Unknown extension is not supported and will be removed
This error happens when openpyxl cannot understand/read an extension (source). Here is the list of built-in extensions openpyxl currently knows that is doesn't support:
Conditional Formatting
Data Validation
Sparkline Group
Slicer List
Protected Range
Ignored Error
Web Extension
Slicer List
Timeline Ref
Also see the Worksheet extension list specification.
Try to add single quotes to your data_only parameter like this:
wb = load_workbook('NFL.xlsx', data_only = **'True'**)
This works for me.
Using python 3.5 under Anaconda3, Excel 2016, Windows10 -- I had the same problem initially with an xlsx file. Tried to make it into a csv and did not work. What worked was: select the entire spreadsheet, copy on a Notepad, select the notepad text, paste in a new spreadsheet, save as xslx. It looks like any extra formatting would result in a warning.
It is already listed in the first answer what is wrong with it If you only want to get rid of the error that is given in red for some reason. You can go to the file location of the error and # the line where is says warn(msg) this will stop the error being displayed the code still works fine in my experience.I am not sure if this will work after compiled but this should work in the same machine.
PS:I had the same error and this is what I did because I though it could be confusing for the end user
PS:You can use a try and except error catcher too but this is quicker.
I am practicing with openpyxl and I'm working on an Excel file called 'test.xlsx'. The file only has 3 columns and 7 rows. The .xlsx file was created with LibreOffice.
When I run...
>>> #! python3
>>> import openpyxl
>>> wb = openpyxl.load_workbook('test.xlsx')
>>> sheet = wb.get_sheet_by_name('Sheet1')
>>> sheet.get_highest_column()
1025
The returned value should be 3.
A quick Google search suggested I run:
>>> sheet.calculate_dimension()
and got the return value:
'A1:AMK7'
This should only be 'A1:C7'.
I remember reading that LibreOffice could be part of the problem to this.
However, I can't switch to MSOffice, and I hate OpenOffice.
Is there suggestion on how I could fix this, or work around it?
Thanks!
It sounds like you're using older versions of LibreOffice and openpyxl. LibreOffice did used to set a default value of "A1:AMK7" for the dimensions but it version 5 doesn't seem to be doing that any more. openpyxl used to rely on the dimensions tag when reading files but hasn't done this for a while. Please try using openpyxl 2.3-b2
import xlrd
wb = xlrd.open_workbook("file.xls")
wb.sheet_names()
sh = wb.sheet_by_index(0)
for item in sh.col(0):
value = unicode(item.value)
if value.startswith("cheap"):
print value
when i trying this code, interpritator return me:
AttributeError: 'module' object has no attribute 'open_workbook'
whats wrong? in all manuals typeed this code!
The most likely explanation is that you've accidentally created your own xlrd.py file that is being found before the real one.
The solution is to find the imposter and delete it. Try import xlrd; print xlrd.__file__ to find the culprit :-)
P.S. You will need to delete both the .py file and its .pyc cached version.