I am attempting to parse the below XML file but having difficulty getting a specific element value. I am trying to specify element 'Item_No_2' to get the related value <v>2222222222</v> but am unable to do it using get.element('Item_No_2'). Am I using the get.element value incorrectly?
XML File:
<?xml version="1.0" encoding="utf-8"?>
<?xml-stylesheet type="text/xsl" href="Data.xsl"?>
<abc>
<md>
<mi>
<datetime>20160822020003</datetime>
<period>3600</period>
<it>Item_No_1</it>
<it>Item_No_2</it>
<it>Item_No_3</it>
<it>Item_No_4</it>
<it>Item_No_5</it>
<it>Item_No_6</it>
<it>Item_No_7</it>
<ovalue>
<v>1111111111</v>
<v>2222222222</v>
<v>3333333333</v>
<v>4444444444</v>
<v>5555555555</v>
<v>6666666666</v>
<v>7777777777</v>
</ovalue>
</mi>
</md>
</abc>
My Code:
from xml.etree.ElementTree import parse
doc = parse('test.xml').getroot()
for element in doc.findall('md/mi/'):
print(element.text)
for element in doc.findall('md/mi/ovalue/'):
print(element.text)
The current output gets them separately but I can't seem to understand how to call a specific element value.
Output:
20160822020003
3600
Item_No_1
Item_No_2
Item_No_3
Item_No_4
Item_No_5
Item_No_6
Item_No_7
1111111111
2222222222
3333333333
4444444444
5555555555
6666666666
7777777777
Tried this but did not work:
for element in doc.findall('md/mi/ovalue/'):
print(element.get('Item_No_1'))
There is no Item_No_1 at the elements that are found by doc.findall('md/mi/ovalue/').
I think what you may try to do is get both lists
items = [e.text for e in doc.findall('md/mi/it')]
values = [e.text for e in doc.findall('md/mi/ovalue/v')]
Then find the index of the string 'Item_No_1' from items, and then index into values with that number.
Alternatively, zip the two lists together and check when you find one element.
for item,value in zip(doc.findall('md/mi/it'), doc.findall('md/mi/ovalue/v')):
if item.text == 'Item_No_1':
print(value.text)
There might be a better way, but those are the first ways that come to mind
Related
<?xml version="1.0" encoding="utf-8"?>
<export_full date="2022-03-15 07:01:30" version="20160107">
<items>
<item code="A1005" image="https://www.astramodel.cz/images/A/800x600/A1005.jpg" imageDate="2014-04-08" name="Uhlíková tyčka 0.6mm (1m)" brandId="32" brand="ASTRA" czk="89.00" eur="3.50" czksmap="89.00" eursmap="3.50" hasPrice="true" created="2014-01-09" changed="" new="false" stock="true" date="" stock2="true" date2="" stock3="high" date3="" discontinued="false" weight="0.001" length="0.001" width="0.001" height="1.000" recycling_fee="">
<descriptions>
<description title="Charakteristika" order="1"><p>Tyč z uhlíkových vláken kruhového průřezu ø0.6 mm v délce 1 m. Hmotnost 0,3 g</p></description>
</descriptions>
</item>
I have a an XML file which is significantly large however I am trying to count the total number of items and try to type the name attribute of each item, above you can see of how each individual item with its tags looks like.I do get a number when trying to print the total item count however I'm not sure if I'm going about it the right way and in terms of name attributes I am getting nothing so far, please help.
import xml.etree.ElementTree as ET
tree = ET.parse('export_full.xml')
root = tree.getroot()
test = [elem.tag for elem in root.iter("item")]
print(len(test))
for item in root.iter('./item[#name]'):
print(item.attrib)
To evaluate an XPath expression use findall() function. Note the "item" elements are children of "items" element so need to add 'items' to the XPath if using an absolute path otherwise use ".//item[#name]".
for item in root.findall('./items/item[#name]'):
print(item.attrib)
If you want it iterate over all items and add the name attribute to a list.
items = [elem.get('name') for elem in root.iter("item")]
print(len(items), items) # print count of items and list of names
If XML is huge then you can benefit by doing an incremental parse of the XML using iterparse() function.
Example below iterate overs the XML and if tag is 'item' then print its 'name' attribute. You can add whatever logic you want to check.
count = 0
for _, elem in ET.iterparse('export_full.xml'):
if elem.tag == 'item':
print(elem.get('name')) # print out just the name
count += 1
# print(elem.attrib) # print out all attributes
print(count) # display number of items
i'm triying to extract from xml file (GPX) all informations related to the waypoints of my gpx file with lxml library.
there is a subset of my gpx file.
<?xml version="1.0"?>
<gpx
version="1.0"
creator="GPSBabel - http://www.gpsbabel.org"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.topografix.com/GPX/1/0"
xsi:schemaLocation="http://www.topografix.com/GPX/1/0 http://www.topografix.com/GPX/1/0/gpx.xsd">
<time>2006-01-23T02:00:28Z</time>
<trk>
<name>08-JAN-06 02</name>
<trkseg>
<trkpt lat="-33.903422356" lon="151.175565720">
<ele>19.844360</ele>
<time>2006-01-08T06:45:07Z</time>
</trkpt>
</trkseg>
</trk>
</gpx>
i can get point latitude and longitude by:
node.get("lon") and node.get("lat")
but when i try to get time with :
for element in root:
if element.tag=="{http://www.topografix.com/GPX/1/0}time":
time=str(element.text)
i get finally for example this kind of results
(1.45,32.12,'')
a blank value for time how can i solve this
I'm assuming there is a </trk> and a </trkseg> tag that's supposed to be at the end of what you posted, or else this would be kind of malformed.
I'm going to write this out in a very verbose way. First, let's assume you've got an lxml object containing your xml-- we'll call it tree.
First define your namespace, if necessary:
ns = {'gpx': 'http://www.topografix.com/GPX/1/0'}
I like using XPath queries. If you try a query like tree.xpath('//trk') and get an undefined namespace error, try again by specifying a namespace argument-- you have to prefix your xpath expressions with the key, like tree.xpath('//gpx:trk', namespaces=ns)
Now you want to get a list of all your trk objects:
trk_objects = tree.xpath('//gpx:trk', namespaces=ns)
This will return a list of them or an empty list if there are no trk tags.
Then you want to iterate through them (I'm assuming there's only one trkseg tag per trk tag, and that you need to use the name space):
for trk in trk_objects:
# xpath queries aways return a list of objects
lat_objects = trk.xpath('./gpx:trkseg/gpx:trkpt/#lat', namespaces=ns)
if lat_objects:
lat = lat_objects[0].text
lon_objects = trk.xpath('./gpx:trkseg/gpx:trkpt/#lon', namespace=ns)
if lon_objects:
lon = lon_objects[0].text
time_objects = trk.xpath('./gpx:trkseg/gpx:time', namespace=ns)
if time_objects:
time = time_objects[0].text
I would like to crawl a specific element of an HTML page that is inside an unordered list. Sometimes, this element is present, sometimes it isn't. If the element is present, I want to select the second paragraph in the respective list item.
Example:
<div class="testdiv">
<ul class="ullist">
<li><p>random element 1</p><p>value</p></li>
<li><p>random element 2</p><p>value</p></li>
<li><p>element_to_select</p><p>wanted_value</p></li>
<li><p>random element 4</p><p>value</p></li>
</ul>
</div>
For the HTML above, I first want to check if 'element_to_select' is present, and if yes, get wanted_value.
I have tried the following (rather naive) approach:
soup_parsed = BeautifulSoup(global_html.encode('utf-8'), 'html.parser')
index_of_wanted_element = self.index_containing_substring([str(s) for s in soup_parsed.find_all("p")], "element_to_select")
wanted_element_paragraph = soup_parsed.find_all("p")[index_of_wanted_element+1]
wanted_value_string = str(wanted_element_paragraph).replace("<p>","").replace("</p>","")
in which index_containing_substring finds the index of the wanted string in a list.
Is this possible in Python, e.g., using BeautifulSoup, Xpath, etc.?
The idea is to get the element_to_select element by text, check if it is not None and, if not, get the next p sibling element:
element_to_select = soup.find("p", text="element_to_select")
if element_to_select is not None:
next_element = element_to_select.find_next_sibling("p")
print(next_element.get_text())
I'm using ElementTree findall() to find elements in my XML which have a certain tag. I want to turn the result into a list. At the moment, I'm iterating through the elements, picking out the .text for each element, and appending to the list. I'm sure there's a more elegant way of doing this.
#!/usr/bin/python2.7
#
from xml.etree import ElementTree
import os
myXML = '''<root>
<project project_name="my_big_project">
<event name="my_first_event">
<location>London</location>
<location>Dublin</location>
<location>New York</location>
<month>January</month>
<year>2013</year>
</event>
</project>
</root>
'''
tree = ElementTree.fromstring(myXML)
for node in tree.findall('.//project'):
for element in node.findall('event'):
event_name=element.attrib.get('name')
print event_name
locations = []
if element.find('location') is not None:
for events in element.findall('location'):
locations.append(events.text)
# Could I use something like this instead?
# locations.append(''.join.text(*events) for events in element.findall('location'))
print locations
Outputs this (which is correct, but I'd like to assign the findall() results directly to a list, in text format, if possible;
my_first_event
['London', 'Dublin', 'New York']
You can try this - it uses a list comprehension to generate the list without having to create a blank one and then append.
if element.find('location') is not None:
locations = [events.text for events in element.findall('location')]
With this, you can also get rid of the locations definition above, so your code would be:
tree = ElementTree.fromstring(myXML)
for node in tree.findall('.//project'):
for element in node.findall('event'):
event_name=element.attrib.get('name')
print event_name
if element.find('location') is not None:
locations = [events.text for events in element.findall('location')]
print locations
One thing you will want to be wary of is what you are doing with locations - it won't be defined if location doesn't exist, so you will get a NameError if you try to print it and it doesn't exist. If that is an issue, you can retain the locations = [] definition - if the matching element isn't found, the result will just be an empty list.
i have a xml with following data. i need to get value of and all other attribute. i return a python code there i get only first driver value.
My xml :
<volume name="sp" type="span" operation="create">
<driver>HDD1</driver>
<driver>HDD2</driver>
<driver>HDD3</driver>
<driver>HDD4</driver>
</volume>
My script:
import xml.etree.ElementTree as ET
doc = ET.parse("vol.xml")
root = doc.getroot() #Returns the root element for this tree.
root.keys() #Returns the elements attribute names as a list. The names are returned in an arbitrary order
root.attrib["name"]
root.attrib["type"]
root.attrib["operation"]
print root.get("name")
print root.get("type")
print root.get("operation")
for child in root:
#print child.tag, child.attrib
print root[0].text
My output:
sr-query:~# python volume_check.py aaa
sp
span
create
HDD1
sr-queryC:~#
I am not get HDD2, HDD3 and HDD4. How to itirate through this xml to get all values? Any optimized way? I think any for loop can do that but not familiar with Python.
In your for loop, it should be
child.text
not
root[0].text