Calling a subset of a dataset - python

x_train = train['date_x','activity_category','char_1_x','char_2_x','char_3_x','char_4_x','char_5_x','char_6_x',
'char_7_x','char_8_x','char_9_x','char_10_x',.........,'char_27','char_29','char_30','char_31','char_32','char_33',
'char_34','char_35','char_36','char_37','char_38']
y = y_train
x_test = test['date_x','activity_category','char_1_x','char_2_x','char_3_x','char_4_x','char_5_x','char_6_x',
'char_7_x','char_8_x','char_9_x','char_10_x','char_1_y','group_1','char_1_y','char_2_y','char_3_y', 'char_4_y','char_5_y','char_6_y','char_7_y',
'char_8_y','char_9-y','char_10_y', ...........,'char_29','char_30','char_31','char_32','char_33',
'char_34','char_35','char_36','char_37','char_38']
train.iloc([0:17,19:38])
After trying to slice columns with train([0:17,19:38)], I resorted to data entry of all column names. A pretty cumbersome way of doing this, but I am only getting what I call with 19:38. I am getting Key error message for doing it the first way, by calling the column names.

As suggested by #AndrasDeak
Consider the pd.DataFrame train
train = pd.DataFrame(np.arange(1000).reshape(-1, 20))
Then use the suggestion like this
train.iloc[np.r_[0:17, 19:38]]

Related

How do i make my data 1-dimensional? - neural network

When I output this below code through some other functions (sigmoid/weight functions etc). I get the output that my data 'must be one dimensional'.
The data is from a csv that is 329 X 31, I have split this as I need the first column as my 'y' value, and then the remaining 30 columns and all its rows will be my 'x'. How do I go about making this 1 dimensional for my functions?
Is this section of code where I process my data even the issue? could it be an issue from a later functional call? im new to python so im not sure what the issue could be caused by, I was wondering if I converted my data into an array correctly.
df = pd.read_csv('data.csv', header=None)
#splitting dataframe into 70/30 split
trainingdata = df.sample(frac=0.7)
testingdata = df.drop(trainingdata.index)
#splitting very first column to 'y' value
y = trainingdata.loc[:,0]
#splitting rest of columns to 'X' value
X = trainingdata.loc[:,1:]
#printing shape for testing
print(X.shape, y.shape)
if I understand your question correctly, you can flatten the array using the flatten(), or you can use reshape() for more information, read the documentation
y=y.flatten()
print(y.ndim)
doc

ValueError: could not convert string to float <ipython-input-5-1a15d1ec0505> in <module>()

I am trying to implement KNN but when i transform X_train and X_test it gives error, I am new please any help regarding this.
scaler = StandardScaler()
X_train = scaler.fit_transform(X_train)
X_test = scaler.transform(X_test)
It gives error "could not convert string to float"
what to do?
The first thing I do when I see an error like this is to check my inputs. If you're getting a "could not convert string to float" error, you probably have a non-numeric string somewhere in your inputs (because it looks like this KNN function only takes numbers as input).
I'm assuming X_train and X_test are dataframes--try running the following for each column in your dataframe:
for i in range(len(X_train.columns)):
try:
[float(j) for j in X_train[X_train.columns[i]]]
print(X_train.columns[i],' is all-numeric')
except:
pass
Whichever column doesn't print when you run this is the one you need to look at and see if you can clean up the non-numeric entries in that column.
Edit: if you have a column of only non-numeric strings (for example, "Iris-setosa","Iris-versicolor", etc), you will have to convert them into numbers or Dummy Variable columns for the purposes of the KNN function.
Edit 2: Whoooops. I wrote bad code. Fixed it.

Scikit Learn - Combining output of TfidfVectorizer and OneHotEncoder - dimensionality

I am currently developing a machine learning algorithm for ticket classification that combines a Title, Description and Customer name together to predict what team a ticket should be assigned to but have been stuck for the past few days.
Title and description are both free text and so I am passing them through TfidfVectorizer. Customer name is a category, for this I am using OneHotEncoder. I want these to work within a pipeline so have them being joined with a column transformer where I can pass in an entire dataframe and have it be processed.
file = "train_data.csv"
train_data= pd.read_csv(train_file)
string_features = ['Title', 'Description']
string_transformer = Pipeline(steps=[('tfidf', TfidfVectorizer()))
categorical_features = ['Customer']
categorical_transformer = Pipeline(steps=[('OHE', preprocessing.OneHotEncoder()))
preprocessor = ColumnTransformer(transformers = [('str', string_transformer, string_features), ('cat', categorical_transformer, categorical_features)])
clf = Pipeline(steps=[('preprocessor', preprocessor),('clf', SGDClassifier())]
X_train = train_data.drop('Team', axis=1)
y_train = train_data['Team']
clf.fit(X_train, y_train)
However I get an error: all the input array dimensions except for the concatenation axis must match exactly.
After looking into it, print(OneHotEncoder().fit_transform(X_train['Customer'])) on its own returns an error: Expected 2d array got 1d array instead.
I believe that OneHotEncoder is failing as it is expecting an array of arrays (a pandas dataframe), each being length one containing the customer name. But instead is just getting a pandas series. By converting the series to a dataframe with .to_frame() the printed output now seems to match what is outputted by the TfidfVectorizer and the dimensions should match.
Is there a way I can modify OneHotEncoder in the pipeline so that it accepts the input as it is in 1 dimension? Or is there something I can add to the pipeline that will convert it before it's passed into OneHotEncoder? Am I right in that this is the reason for the error?
Thanks.
I believe the problem lies in the fact that you're giving two columns to the TfIdfVectorizer (which is thus converted to a DataFrame). This will not work: TfIdfVectorizer expects a list of strings. So an immediate solution (and therefore a check of whether this is in fact the source of the problem), is changing this line to: string_features = 'Description'. Note this is not a list, it just a string. Therefore the Series is passed to the TfIdfVectorizer, and not the DataFrame.
If you would like to combine both string columns, you could either
concatanenate the strings, so you keep one column (which is the easiest), or
Fit two different TfIdfVectorizers, which is more complex but might perform better. See for instance Computing separate tfidf scores for two different columns using sklearn
Should this not solve your problem, I would advise you to share some sample data so we can actually test what is happening.
I believe the difference between your perceived error and the actual pipeline lies in the fact that you're giving it X_train['Customer'] (again a Series), but in the actual pipeline you're giving it X_train[['Customer']] (a DataFrame).

Getting ValueError: y contains new labels when using scikit learn's LabelEncoder

I have a series like:
df['ID'] = ['ABC123', 'IDF345', ...]
I'm using scikit's LabelEncoder to convert it to numerical values to be fed into the RandomForestClassifier.
During the training, I'm doing as follows:
le_id = LabelEncoder()
df['ID'] = le_id.fit_transform(df.ID)
But, now for testing/prediction, when I pass in new data, I want to transform the 'ID' from this data based on le_id i.e., if same values are present then transform it according to the above label encoder, otherwise assign a new numerical value.
In the test file, I was doing as follows:
new_df['ID'] = le_dpid.transform(new_df.ID)
But, I'm getting the following error: ValueError: y contains new labels
How do I fix this?? Thanks!
UPDATE:
So the task I have is to use the below (for example) as training data and predict the 'High', 'Mod', 'Low' values for new BankNum, ID combinations. The model should learn the characteristics where a 'High' is given, where a 'Low' is given from the training dataset. For example, below a 'High' is given when there are multiple entries with same BankNum and different IDs.
df =
BankNum | ID | Labels
0098-7772 | AB123 | High
0098-7772 | ED245 | High
0098-7772 | ED343 | High
0870-7771 | ED200 | Mod
0870-7771 | ED100 | Mod
0098-2123 | GH564 | Low
And then predict it on something like:
BankNum | ID |
00982222 | AB999 |
00982222 | AB999 |
00981111 | AB890 |
I'm doing something like this:
df['BankNum'] = df.BankNum.astype(np.float128)
le_id = LabelEncoder()
df['ID'] = le_id.fit_transform(df.ID)
X_train, X_test, y_train, y_test = train_test_split(df[['BankNum', 'ID'], df.Labels, test_size=0.25, random_state=42)
clf = RandomForestClassifier(random_state=42, n_estimators=140)
clf.fit(X_train, y_train)
I think the error message is very clear: Your test dataset contains ID labels which have not been included in your training data set. For this items, the LabelEncoder can not find a suitable numeric value to represent. There are a few ways to solve this problem. You can either try to balance your data set, so that you are sure that each label is not only present in your test but also in your training data. Otherwise, you can try to follow one of the ideas presented here.
One of the possibles solutions is, that you search through your data set at the beginning, get a list of all unique ID values, train the LabelEncoder on this list, and keep the rest of your code just as it is at the moment.
An other possible solution is, to check that the test data have only labels which have been seen in the training process. If there is a new label, you have to set it to some fallback value like unknown_id (or something like this). Doin this, you put all new, unknown IDs in one class; for this items the prediction will then fail, but you can use the rest of your code as it is now.
you can try solution from "sklearn.LabelEncoder with never seen before values" https://stackoverflow.com/a/48169252/9043549
The thing is to create dictionary with classes, than map column and fill new classes with some "known value"
from sklearn.preprocessing import LabelEncoder
le = LabelEncoder()
suf="_le"
col="a"
df[col+suf] = le.fit_transform(df[col])
dic = dict(zip(le.classes_, le.transform(le.classes_)))
col='b'
df[col+suf]=df[col].map(dic).fillna(dic["c"]).astype(int)
If your data are pd.DataFrame I suggest you this simple solution...
I build a custom transformer that integer maps each categorical feature. When fitted you can transform all the data you want. You can compute also simple label encoding or onehot encoding.
If new unseen categories or NaNs are present in new data:
1] For label encoding, 0 is a special token reserved for mapping these cases.
2] For onehot encoding, all the onehot columns are zeros in these cases.
class FeatureTransformer:
def __init__(self, categorical_features):
self.categorical_features = categorical_features
def fit(self, X):
if not isinstance(X, pd.DataFrame):
raise ValueError("Pass a pandas.DataFrame")
if not isinstance(self.categorical_features, list):
raise ValueError(
"Pass categorical_features as a list of column names")
self.encoding = {}
for c in self.categorical_features:
_, int_id = X[c].factorize()
self.encoding[c] = dict(zip(list(int_id), range(1,len(int_id)+1)))
return self
def transform(self, X, onehot=True):
if not isinstance(X, pd.DataFrame):
raise ValueError("Pass a pandas.DataFrame")
if not hasattr(self, 'encoding'):
raise AttributeError("FeatureTransformer must be fitted")
df = X.drop(self.categorical_features, axis=1)
if onehot: # one-hot encoding
for c in sorted(self.categorical_features):
categories = X[c].map(self.encoding[c]).values
for val in self.encoding[c].values():
df["{}_{}".format(c,val)] = (categories == val).astype('int16')
else: # label encoding
for c in sorted(self.categorical_features):
df[c] = X[c].map(self.encoding[c]).fillna(0)
return df
Usage:
X_train = pd.DataFrame(np.random.randint(10,20, (100,10)))
X_test = pd.DataFrame(np.random.randint(20,30, (100,10)))
ft = FeatureTransformer(categorical_features=[0,1,3])
ft.fit(X_train)
ft.transform(X_test, onehot=False).shape
This is in fact a known bug on LabelEncoder : BUG for fit_transform ... basically you have to fit it and then transform. It will work fine ! A suggestion is to keep a dictionary of your encoders to each and every column so that in the inverse transform you are able to retrieve the original categorical values.
I'm able to mentally process operations better when dealing in DataFrames. The approach below fits and transforms the LabelEncoder() using the training data, then uses a series of pd.merge joins to map the trained fit/transform encoder values to the test data. When there is a test data value not seen in the training data, the code defaults to the max trained encoder value + 1.
# encode class values as integers
import numpy as np
import pandas as pd
from sklearn.preprocessing import LabelEncoder
encoder = LabelEncoder()
encoder.fit(y_train)
encoded_y_train = encoder.transform(y_train)
# make a dataframe of the unique train values and their corresponding encoded integers
y_map = pd.DataFrame({'y_train': y_train, 'encoded_y_train': encoded_y_train})
y_map = y_map.drop_duplicates()
# map the unique test values to the trained encoded integers
y_test_df = pd.DataFrame({'y_test': y_test})
y_test_unique = y_test_df.drop_duplicates()
y_join = pd.merge(y_test_unique, y_map,
left_on = 'y_test', right_on = 'y_train',
how = 'left')
# if the test category is not found in the training category group, then make the
# value the maximum value of the training group + 1
y_join['encoded_y_test'] = np.where(y_join['encoded_y_train'].isnull(),
y_map.shape[0] + 1,
y_join['encoded_y_train']).astype('int')
encoded_y_test = pd.merge(y_test_df, y_join, on = 'y_test', how = 'left') \
.encoded_y_test.values
I found an easy hack around this issue.
Assuming X is the dataframe of features,
First, we need to create a list of dicts which would have the key as the iterable starting from 0 and the corresponding value pair would be the categorical column name. We easily accomplish this using enum.
cat_cols_enum = list(enumerate(X.select_dtypes(include = ['O']).columns))
Then the idea is to create a list of label encoders whose dimension is equal to the number of qualitative(categorical) columns present in the dataframe X.
le = [LabelEncoder() for i in range(len(cat_cols_enum))]
Next and the last part would be fitting each of the label encoders present in the list of encoders with the unique values of each of the categorical columns present in the list of dicts respectively.
for i in cat_cols_enum: le[i[0]].fit(X[i[1]].value_counts().index)
Now, we can transform the labels to their respective encodings using
for i in cat_cols_enum:
X[i[1]] = le[i[0]].transform(X[i[1]])
This error comes when transform function getting any new value for which LabelEncoder try to encode and because in training samples, when you are using fit_transform, that specific value did not present in the corpus. So there is a hack, whether use all the unique values with fit_transform function if you are sure that no new value will come further, or try some different encoding method which suits on the problem statement like HashingEncoder.
Here is the example if no further new values will come in testing
le_id.fit_transform(list(set(df['ID'].unique()).union(set(new_df['ID'].unique()))))
new_df['ID'] = le_id.transform(new_df.ID)
I also encountered the exact same error and was able to fix it.
my array: [[63, 1, 'True' , 1850000000.0, 61666.67]]
When I used the following code, the error occurred
pa_ = preprocessing.LabelEncoder()
pa_.fit([True,False])
data[:,2] = pa_.transform(data[:,2])
The reason for the error was that the true value into array was of string type
And I set boolean. i changed bool type to string Thus, the error was fixed
fit(['True','False'])
I hope my answer be helpful
I hope this helps someone as it's more recent.
sklearn uses the fit_transform to perform the fit function and transform function directing on label encoding.
To solve the problem for Y label throwing error for unseen values, use:
from sklearn.preprocessing import LabelEncoder
le = LabelEncoder()
le.fit_transform(Col)
This solves it!
I used
le.fit_transform(Col)
and I was able to resolve the issue. It does fit and transform both. we dont need to worry about unknown values in the test split

How to convert dataframe to 1D array ?

First of all apologies. I am very new to pandas, scikit learn and python. So I am sure I am doing something silly. Let me give a little background.
I am trying to run KNeighborsClassifier from scikit learn (python)
Following is my strategy
#Reading the Training set
data = pd.read_csv('Path_TO_File\\Train_Set.csv', sep=',') # reading CSV File
X = data[['Attribute 1','Attribute 2']]
y = data['Target_Column'] # the output is a Dataframe of single column with many rows
neigh = KNeighborsClassifier(n_neighbors=3)
neigh.fit(X,y)
Next I try to read Test data
test = pd.read_csv('PATH_TO_FILE\\Test.csv', sep=',')
t = test[['Attribute 1','Attribute 2']]
pred = neigh.predict(t)
actual = test['Target_Column']
Next I try to check the accuracy by following function which is throwing error.
accuracy=neigh.score(actual,pred)
ERROR: ValueError: could not convert string to float: N
I checked actual and pred both and they are of following data type and content
actual
Out[161]:
Target_Column
0 Y
1 N
:
[614 rows x 1 columns]
pred
Out[162]:
array(['Y', 'N', .....'N'], dtype=object)
N.B : pred has 614 values.
I tried to convert "actual" variable to 1D array I might be able to execute the function however, I am not successful.
I think I need to do following two things, however, was not able to do so (after googling it)
1) Convert actual into 1Dimen array
2) Making a transpose of the 1Dimen array since the pred has 614 columns.
Please let me know how to correct the function.
Thanks in advance !
Raj
Thanks Vivek and Thornhale
Indeed I was doing two wrong things.
As pointed by you guys, I should have been using 1, 0 in stead of Y,
N.
I was giving wrong parameters to the function score. It should be
accuracy=neigh.score(t, actual) , where t is test feature set and
actual is test label information.
You could convert your series which is what you get when you do "test[COLUMN_NAME]" into an array like so:
actual = np.array(test['Target_Column'])
To then reshape an np array, you would emply this command:
actual.reshape(1, 612) # <- Could be the other way around as well.
Your main issue though is that your Series needs to be boolean (as in 0,1).

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