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Python2.7 chat using sockets and select module(non-blocking code)

Hi i have an exercise to build with sockets select and msvcrt, server and clients of mltiplie chat(the server and the clients need to be built non-blocking) that every client will send message and the server will send the message to all the clients except the one who sent it, the server:
import socket
import select
IP = "192.168.1.154"
port = 123
default_buffer_size = 1024
open_client_sockets = []
messages_to_send = []
def send_waiting_messages(wlist):
for message in messages_to_send:
(client_sock, data) = message
if client_sock in wlist:
for sock in open_client_sockets:
if sock is not client_sock:
sock.send(data)
messages_to_send.remove(message)
def main():
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.bind((IP, port))
sock.listen(5)
print("The server is on and waiting for client...")
while True:
rlist, wlist, xlist = select.select([sock] + open_client_sockets, open_client_sockets, [])
for current_socket in rlist:
if current_socket is sock:
(new_socket, addr) = sock.accept()
open_client_sockets.append(new_socket)
else:
data = current_socket.recv(default_buffer_size)
if data == "":
open_client_sockets.remove(current_socket)
print("Connection with client closed")
else:
messages_to_send.append((current_socket, 'Hello ' + data))
send_waiting_messages(wlist)
if __name__ == '__main__':
main()
Building the server wasnt hard because it was guided(if it was not guided i would never got this code working) by the book but i have problem building the client and the main reason is that i dont understand how select.select works, couldn't find answer that will simplify enough this module for me.
this is what i did with the client:
import socket
import select
import msvcrt
IP = "192.168.1.154"
port = 123
sockets = []
def write():
pass
def main():
sock = socket.socket()
sock.connect((IP, port))
while True:
rlist, wlist, xlist = select.select(sockets, sockets, [])
for current_socket in rlist:
if current_socket is sock:
data = current_socket.recv(1024)
print(data)
else:
sockets.append(current_socket)
write()
if __name__ == '__main__':
main()
This probably shows you that I have low understanding of the module select and the exercise actually. I saw some threads that has similar question but I understand nothing from them so I realy need good explantion.
In conclusion I realy am lost...

select takes as parameters a list of sockets to wait for readablity, a list of sockets to wait for writability, and a list of sockets to wait for errors. It returns lists of ready to read, ready to write, and error sockets. From help:
>>> help(select.select)
Help on built-in function select in module select:
select(...)
select(rlist, wlist, xlist[, timeout]) -> (rlist, wlist, xlist)
Wait until one or more file descriptors are ready for some kind of I/O.
The first three arguments are sequences of file descriptors to be waited for:
rlist -- wait until ready for reading
wlist -- wait until ready for writing
xlist -- wait for an ``exceptional condition''
If only one kind of condition is required, pass [] for the other lists.
A file descriptor is either a socket or file object, or a small integer
gotten from a fileno() method call on one of those.
The optional 4th argument specifies a timeout in seconds; it may be
a floating point number to specify fractions of seconds. If it is absent
or None, the call will never time out.
The return value is a tuple of three lists corresponding to the first three
arguments; each contains the subset of the corresponding file descriptors
that are ready.
*** IMPORTANT NOTICE ***
On Windows, only sockets are supported; on Unix, all file
descriptors can be used.
So to fix your client, you need to add the socket you opened (sock) to the sockets list. Your write function can then be called if your socket is ready to be written.
In write, use msvcrt.kbhit() to test for characters typed. You can't just use input because it will block. Then read the character if one has been typed. Collect up the characters until you hit enter, then build a message and write it to the socket. Something like:
message = []
def write(sock):
if msvcrt.kbhit():
c = msvcrt.getche()
if c == '\r':
data = ''.join(message)
print 'sending:',data
sock.sendall(data)
message.clear()
else:
message.append(c)

Looking for help in making my socket messenger send instantaneously in Python

Im sure there are easier ways with particular python modules, but for an assignment I need to create a program that can act as a client/server. As of right now I have it working to the point of only being able to send a message if the reciever has responded. I need it to just send and appear on the respective client/server terminal when enter is pressed. Any help would be greatly appreciated!
These are pictures of what happens as of now
https://i.stack.imgur.com/T9CsJ.png
import sys
import socket
import getopt
def usage(script_name):
print('Usage: py' + script_name + '-l' +' <port number>' + '[<server>]')
def sockObj():
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
return sock
def serversockConn(serversocket,port):
serversocket.setsockopt(socket.SOL_SOCKET,socket.SO_REUSEADDR,1)
# bind the serversocket to address
serversocket.bind(('',int(port)))
# enable a server to accept connections
serversocket.listen(5)
# wait for a connection and accept it
sock,addr = serversocket.accept()
return sock
def connToServersock(sock,server, port):
# connect to a serversocket
if server:
sock.connect((server, int(port)))
else:
sock.connect(('localhost', int(port)))
return sock
if __name__ == '__main__':
## get the command line arguments
try:
options, non_option_args = getopt.getopt(sys.argv[1:],'l')
except getopt.GetoptError as err:
print(err)
sys.exit(2)
#check if '-l' is present in command line agrument
serverSide = False
for opt,arg in options:
if opt == "-l":
serverSide = True
# port number
port = non_option_args[0]
# server address
server = None
hostLen = len(non_option_args)
if hostLen == 2:
server = non_option_args[1]
# create a communicator object, and make a connection between server and client
# server
if serverSide:
serversocket = sockObj()
sock = serversockConn(serversocket,port)
# client
else:
sock = sockObj()
sock = connToServersock(sock,server,port)
while True:
## read a message from standard input
message = sys.stdin.readline().encode()
if len(message) != 0:
sock.send(message)
return_msg = sock.recv( 1024 )
if return_msg:
print("Message recieved: " + return_msg.decode())
else:
print("Other side shut down")
else:
try:
sock.shutdown(socket.SHUT_WR)
sock.close()
except:
pass

I think your issue is that there are two places in your event loop where you block:
message = sys.stdin.readline().encode()
Here, you block until the user has pressed return -- during this time, your program is unable to respond to any data received over the network, because it is blocked waiting for data from stdin.
... and:
return_msg = sock.recv( 1024 )
Here, you are waiting for data to be received from the network -- during this time, your program is unable to respond to any data received from stdin, because it is blocked waiting for data from the network.
The behavior you'd ideally like to have is for your program to wait for both stdin and network traffic simultaneously -- i.e. have it block until either the user has pressed return, or some network data has been received, whichever comes first.
The easiest way to achieve that behavior is to use select(); its purpose is to block until at least one of several file descriptors is ready to be acted on. (Note, however, that Windows does not support using select() on stdin, so if your program needs to run under Windows you will probably have to spawn a second thread instead).
To implement the event loop using select(), add import select to the top of your script, then replace your event loop with something like this instead:
while True:
## block here until either sock or sys.stdin has data ready for us
readable, writable, exceptional = select.select([sock, sys.stdin], [], [])
if sys.stdin in readable:
## read a message from standard input
message = sys.stdin.readline().encode()
if len(message) != 0:
sock.send(message)
if sock in readable:
## read a message from the network
try:
return_msg = sock.recv( 1024 )
if (return_msg):
print("Message received: " + return_msg.decode())
else:
print("Other side shut down")
break
except:
print("recv() threw an exception")
break

Using one socket in UDP chat using threading

I am working on UDP chat which should be listening and being able to send message any time using only one socket. Example, I will have the chat program done, I will open it first time, then second time and I must be able to communicate over UDP from both programs, simply each program has only one opened socket.
My two threads are for listening, which is deamon thread, because I want it to listen to new messages nonstop, and my other is sending the messages, which is just like a normal thread.
First of all, my problem is that it looks like my threads are blocking each other, because if I run the program, I only get output from the first thread I start.
Second problem is that I am not sure if my sending function or the entire class is written properly, or if there is something missing or incorrect.
Thanks in advance. Btw, I am new into python and I am using python 3, just to make it clear.
import socket
import threading
import logging
import time
from sys import byteorder
class Sending():
def __init__(self, name, tHost, tPort):
self.name = name
self.host = tHost
self.port = tPort
def set_name(self, name):
self.name = name
def send(self, name, tHost, tPort, msgType, dgramSize):
logging.debug('Starting send run')
message = input('Enter message: ')
data = bytearray()
data.extend( (name.encode('utf-8'), message.encode('utf-8'), msgType.to_bytes(1, byteorder = 'little')) )
#data.extend(message.encode(encoding='utf_8'))
self.sock.sendto(bytearray(data), (tHost, tPort))
def run(self):
th2 = threading.Thread(name = 'send', target=self.send('username', 'localhost', 8001, 1, 1400))
th2.start()
class Receiving():
def __init__(self, host, port):
self.host = host
self.port = port
def create_socket(self, host, port):
logging.debug('Starting socket')
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind((host, port))
#print ('socket ready')
time.sleep(5)
while True:
data, addr = sock.recvfrom(1500)
print('Prijata:' + data + addr)
def run(self):
th1 = threading.Thread(name = 'rec', target=self.create_socket('localhost', 8000))
th1.setDaemon(True)
th1.start()
if __name__ == '__main__':
#print ('running')
rec = Receiving('localhost', 8000)
send = Sending('username', 'localhost', 8001)
send.run()
rec.run()

Congrats on your introduction to Python! It looks like you're using Python 3, and in future questions it's helpful if you are explicit about which version you're using because there are minor but program-breaking incompatibilities in some code (including this code!).
I found a few errors in your program:
The most major issue - as Trevor Barnwell says, you're not calling threading.Thread quite correctly. The target= argument needs to be a callable object (i.e. function), but in this case it should just be a reference to the function. If you add brackets to the function, self.create_socket(host, port) as you have above, it actually runs the function immediately. As Trevor explained, your Sending.send() method was called early, but additionally there was a similar bug in Receiving. Because Receiving.create_socket() creates an infinite loop, it never returns program execution. While the console output looks correct to the user, the actual program execution has never made it to running the listener in a separate thread.
bytearray.extend() takes an iterable of ints, what you're passing right now is a tuple of byte objects.
In Sending.send() you call self.sock, but you never assign self.sock a value, so it fails.
Sending.run() only runs Sending.send() one time. After completing input for the user, it immediately exits, because the program has finished.
If you're looking for an in-depth, project based introduction to Python appropriate for an experienced programmer (including an exercise very similar to this question on basic sockets, and another on threading), I highly recommend you check out Wesley Chun's "Core Python Applications Programming". The most recent edition (3rd) has a lot of Python 2 code, but it's easily portable to Python 3 with some minor work on the reader's part.
I tried to modify your code as little as possible to get it working, here it is:
import socket
import threading
import logging
import time
class Sending():
def __init__(self, name, tHost, tPort, target):
self.name = name
self.host = tHost
self.port = tPort
self.target_port = target
self.sock = self.create_socket()
def create_socket(self):
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind((self.host, self.port))
return sock
def set_name(self, name):
self.name = name
def send_loop(self):
while True:
logging.debug('Starting send run')
message = input('Enter message: ')
data = bytearray()
data.extend(message.encode('utf-8'))
self.sock.sendto(bytearray(data), (self.host, self.target_port))
def run(self):
th2 = threading.Thread(name='send', target=self.send_loop)
th2.start()
class Receiving():
def __init__(self, host, port):
self.host = host
self.port = port
def create_socket(self):
logging.debug('Starting socket')
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind((self.host, self.port))
print ('socket ready')
time.sleep(5)
while True:
data, addr = sock.recvfrom(1500)
print('\nPrijata:' + data.decode('utf-8') + str(addr))
def run(self):
th1 = threading.Thread(name='rec', target=self.create_socket)
print("Made it here")
th1.daemon = True
th1.start()
return
if __name__ == '__main__':
print('running')
rec = Receiving('localhost', 8000)
send = Sending('username', 'localhost', 8001, 8000)
rec.run()
send.run()

The threads are not blocking each other. send is called before a thread is even created.
th2 = threading.Thread(name = 'send', target=self.send('username', 'localhost', 8001, 1, 1400))
This line makes a call to send at:
self.send('username', 'localhost', 8001, 1, 1400)
I think you meant to do this:
th2 = threading.Thread(
target=self.send
args=('username', 'localhost', 8001, 1, 1400))
That way a thread will start that calls send on the next line.
Two other things:
You will want to loop in your functions because the thread terminates once the function does.
I think you mean raw_input instead of input

python multithreading server

I am new to networking programming and python.
I am trying to figure out how to run different jobs at the server side.
For example, I want one function to create connections for incoming clients but in the same time I can still do some administration work from the terminal.
My code is as below but it doesn't work:
Edited: it doesn't work means it will get stuck in the init_conn() function
Like:
starting up on localhost port 8887
Thread: 0 Connected with 127.0.0.1:48080
# waiting
I am looking into SocketServer framework but don't know how that works.
from thread import *
import socket
def init_conn():
thread_count =0
# Create a TCP/IP socket
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
# Bind the socket to the port
server_address = ('localhost', 8887)
print >>sys.stderr, 'starting up on %s port %s' % server_address
sock.bind(server_address)
# Listen for incoming connections
sock.listen(10)
#now keep talking with the client
while 1:
#wait to accept a connection - blocking call
conn, addr = sock.accept()
print 'Thread: '+ str(thread_count) + ' Connected with ' + addr[0] + ':' + str(addr[1])
#start new thread takes 1st argument as a function name to be run, second is the tuple of arguments to the function.
start_new_thread(clientthread ,(conn,))
thread_count +=1
sock.close()
def clientthread(conn):
# receive data from client and send back
def console():
print 'this is console'
option = raw_input('-v view clients')
if option == 'v':
print 'you press v'
def main():
start_new_thread( init_conn(),() )
start_new_thread( console(),() )
if __name__ == "__main__":
main()

Your problem is probably that you start the program, sometimes it prints "this is console" and then it ends.
The first bug is that you call the methods instead of passing the handle to start_new_thread. It must be:
start_new_thread( init_conn, () )
i.e. no () after the function name.
The program doesn't do much because start_new_thread() apparent starts a thread and then waits for it to stop. The documentation is pretty unclear. It's better to use the new threading module; See http://pymotw.com/2/threading/
def main():
t = threading.Thread( target=init_conn )
t.daemon = True
t.start()
console()
so the code will run until console() ends.
I suggest to split the server and the command line tool. Create a client which accepts commands from the command line and sends them to the server. That way, you can start the console from anywhere and you can keep the code for the two separate.

Seeing that you're new to python, have you tried taking a look at the threading module that comes with the standard library?
import threading
... #rest of your code
while conditions==True:
i = threading.Thread(target=init_conn)
c = threading.Thread(target=console)
i.start()
c.start()
Can't say I've done too much with networking programming with python, so I don't really have much to say in that manner, but at least this should get you started with adding multithreading to your project.

Using SocketServer you may implement a client/server system. The documentation gives small examples which may be useful for you. Here is an extended example from there:
server.py :
import SocketServer
import os
import logging
FORMAT = '[%(asctime)-15s] %(message)s'
logging.basicConfig(format=FORMAT, level=logging.DEBUG)
class MyServer(SocketServer.ThreadingMixIn, SocketServer.TCPServer):
# By setting this we allow the server to re-bind to the address by
# setting SO_REUSEADDR, meaning you don't have to wait for
# timeouts when you kill the server and the sockets don't get
# closed down correctly.
allow_reuse_address = True
request_queue_size = 10
def __init__(self, port):
self.host = os.uname()[1]
self.port = port
SocketServer.TCPServer.__init__(self, (self.host,self.port), MyTCPHandler)
logging.info( "Server has been started on {h}:{p}".format(h=self.host,p=self.port) )
class MyTCPHandler(SocketServer.BaseRequestHandler):
"""
The RequestHandler class for our server.
It is instantiated once per connection to the server, and must
override the handle() method to implement communication to the
client.
"""
def handle(self):
# self.request is the TCP socket connected to the client
# max length is here 1024 chars
self.data = self.request.recv(1024).strip()
logging.info( "received: {d}".format(d=self.data) )
# here you may execute different functions according to the
# request string
# here: just send back the same data, but upper-cased
self.request.sendall(self.data.upper())
PORT = 8887
if __name__ == "__main__":
# Create the server, binding to localhost on port 8887
#server = SocketServer.TCPServer((HOST, PORT), MyTCPHandler)
server = MyServer( PORT )
# Activate the server; this will keep running until you
# interrupt the program with Ctrl-C
server.serve_forever()
client.py
import socket
import sys
import logging
FORMAT = '[%(asctime)-15s] %(message)s'
logging.basicConfig(format=FORMAT, level=logging.DEBUG)
HOST, PORT = "workstation04", 8887
logging.info( "connect to server {h}:{p}".format(h=HOST,p=PORT ) )
# read command line
data = " ".join(sys.argv[1:])
# Create a socket (SOCK_STREAM means a TCP socket)
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
try:
# Connect to server and send data
sock.connect((HOST, PORT))
sock.sendall(data + "\n")
# Receive data from the server and shut down
received = sock.recv(1024)
finally:
sock.close()
logging.info( "Sent: {}".format(data) )
logging.info( "Received: {}".format(received) )
The output looks something like:
server side:
> python server.py
[2015-05-28 11:17:49,263] Server has been started on disasterarea:8887
[2015-05-28 11:17:50,972] received: my message
client side:
[2015-05-28 11:17:50,971] connect to server disasterarea:8887
[2015-05-28 11:17:50,972] Sent: my message
[2015-05-28 11:17:50,972] Received: MY MESSAGE
You can run several clients (from different consoles) in parallel. You may implement a request processor on the server side which processes the incoming requests and executes certain functions.
Alternatively, you may use the python module ParallelPython which executes python code locally on a multicore system or on a cluster and clusters. Check the http examples.
I had to force pip to install this module:
pip install --allow-external pp --allow-unverified pp pp

Why does my python script not keep listening

Hello stackoverflow users, so I have this problem where i am trying to code a web server but the script ends before I can even test if it works. So my question is how can I make the script so that it will keep running forever?
#import threading
#import socket
#import signal # Signal support (server shutdown on signal receive)
import multiprocessing
#import queue
def MasterProcessA():
import socket
import multiprocessing
import threading
HOST = '97.107.139.231' # Symbolic name, meaning all available interfaces
PORT = 8080 # Arbitrary non-privileged port
#print(PORT)
socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
#print 'Socket created'
#Bind socket to local host and port
#try:
socket.bind((HOST, PORT))
#except socket.error as msg:
##print 'Bind failed. Error Code : ' + str(msg[0]) + ' Message ' + msg[1]
#print 'Socket bind complete'
#Start listening on socket
socket.listen(100)
print "starting server"
def ConnProcessA():
print "thread step one"
Conn, Address = socket.accept()
t = threading.Thread(target=ConnectionProcessorA)
print "thread step two"
#t.daemon = True
t.start()
#print("A Got connection from:", Address)
DataRecived = Conn.recv(1024) #receive data from client
DataRecived = bytes.decode(DataRecived) #decode it to string
print DataRecived
Conn.send("HELLO World")
Conn.clouse()
ConnProcessA = threading.Thread(target=ConnProcessA)
#t.daemon = True
ConnProcessA.start()
MasterProcessA = multiprocessing.Process(target=MasterProcessA)
MasterProcessA.start()

There are several issues with your codes.
The thread doesn't run. You need to modify:
ConnProcessA.start()
ConnProcessA.join()
ConnectionProcessorA is not included in the codes you pasted. So I have to comment out these 2 lines:
t = threading.Thread(target=ConnectionProcessorA)
t.start()
Name shadowing. Refer to these lines:
socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
ConnProcessA = threading.Thread(target=ConnProcessA)
MasterProcessA = multiprocessing.Process(target=MasterProcessA)
You named instances with existing module/function names. Name shadowing is very dangerous. Just try to execute any of the 3 lines twice, you will see the error.
On the other side, it's ok to reuse a variable to hold different things, if straightforward enough. E.g., following two lines are close enough to avoid confusion:
DataRecived = Conn.recv(1024) #receive data from client
DataRecived = bytes.decode(DataRecived) #decode it to string
Seems your socket server is to continuously listen to a same port, then you probably need to add s.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1). As said at the most bottom of the doc.
A less severe point, in Python coding convention, CapWords is usually used for class names ref. You used it for both function names and variable names. Better to keep your codes consistent.