Develop Reference

Get Excel chart details to Python

I have an excel file which has the charts on a separate sheets and they have multiple series plotted on them. What I need to do is to plot exactly the same ranges using python. By the range I mean the following:
Is there a way to access this information via python?

Try this code:
Option 1 for all sheets
import win32com.client as client
def series_output(chart):
print(f'\tChart name is {chart.Name}')
for sc in chart.SeriesCollection():
print(f'\t\t{sc.Name}: {sc.Formula}')
xl = client.Dispatch('Excel.Application')
wb = xl.Workbooks.Open(r'c:\test\Charts.xlsm')
for sh in wb.Sheets:
print(f'Processed sheet {sh.Name}')
if sh.Type == -4100: # it's chart sheet
series_output(sh)
elif sh.Type == -4167: # it's worksheet with (possible) charts
for ch in sh.ChartObjects():
series_output(ch.Chart)
wb.Close(False) # don't save & close workbook
xl.Quit()
Option 2 for a specific sheet
import win32com.client as client
def series_output(chart):
print(f'\tChart name is {chart.Name}')
for sc in chart.SeriesCollection():
print(f'\t\t{sc.Name}: {sc.Formula}')
xl = client.Dispatch('Excel.Application')
wb = xl.Workbooks.Open(r'c:\test\Charts.xlsm') # your own path\name
sh = wb.Sheets('Sheet1') # your own worksheet name
print(f'Processed sheet {sh.Name}')
for ch in sh.ChartObjects():
series_output(ch.Chart)
wb.Close(False) # don't save & close workbook
xl.Quit()

How to copy worksheet onto a different worksheet (not as additional worksheet)

I'm trying to copy a worksheet from one excel file, to a worksheet on different excel file. But the problem is it is adding it as a additional sheet and not pasting on the existing sheet and overwriting the sheet. I know that I am using Before=wb2.Worksheets(1) which adds the new sheet before the existing sheet, but what is the argument to paste onto the existing sheet instead?
import time, os.path, os
from win32com.client import Dispatch
path1 = 'C:\\example.xlsx'
path2 = 'C:\\Todolist2.xlsx'
path3 = 'C:\\example2.xlsx'
xl = Dispatch("Excel.Application")
xl.Visible = True
wb1= xl.Workbooks.Open(Filename=path1)
wb2= xl.Workbooks.Open(Filename=path2)
ws1 = wb1.Worksheets(1)
ws1.Copy(Before=wb2.Worksheets(1))

One way to do it is using openpyxl library. If the cell has style, we can copy it to new sheet also.
import openpyxl as xl
from copy import copy
path1 = 'C:\\example.xlsx'
path2 = 'C:\\Todolist2.xlsx'
wb1 = xl.load_workbook(filename=path1)
ws1 = wb1.worksheets[0]
wb2 = xl.load_workbook(filename=path2)
ws2 = wb2.worksheets[0]
for row in ws1:
for cell in row:
ws2[cell.coordinate].value = cell.value
if cell.has_style:
ws2[cell.coordinate].font = copy(cell.font)
ws2[cell.coordinate].border = copy(cell.border)
ws2[cell.coordinate].fill = copy(cell.fill)
ws2[cell.coordinate].number_format = copy(cell.number_format)
ws2[cell.coordinate].protection = copy(cell.protection)
ws2[cell.coordinate].alignment = copy(cell.alignment)
wb2.save(path2)
Then you will see your sheet2 is replaced by sheet1.

#tomcy
The code is below. What I am really trying to accomplish is to be able to keep rewriting data to Todolist2.xlsx. I would really want to have Todolist2.xlsx open in excel application in windows and have it update the sheet whenever there is new data. So far I have found two ways to do this. One is the code you are helping me with using openpyxl. Doing it this way I think I will have to write data to Todolist2 then open. Then with new data, it will have to close before writing data back in. Then reopen it again. Below is what I have so far. Using the 10 sleep to allow me the chance to update example.xlsx so as to simulate writing new data to Todolist2. It works the first go, but on the second, it gives me permission denied to Todolist2.
import openpyxl as xl
from copy import copy
import time
path1 = 'C:\\example.xlsx'
path2 = 'C:\\Todolist2.xlsx'
wb1 = xl.load_workbook(filename=path1)
ws1 = wb1.worksheets[0]
wb2 = xl.load_workbook(filename=path2)
ws2 = wb2.worksheets[0]
while True:
for row in ws1:
for cell in row:
ws2[cell.coordinate].value = cell.value
if cell.has_style:
ws2[cell.coordinate].font = copy(cell.font)
ws2[cell.coordinate].border = copy(cell.border)
ws2[cell.coordinate].fill = copy(cell.fill)
ws2[cell.coordinate].number_format =
copy(cell.number_format)
ws2[cell.coordinate].protection = copy(cell.protection)
ws2[cell.coordinate].alignment = copy(cell.alignment)
wb2.save(path2)
wb2.close()
time.sleep(10) #during this time I will modify example.xlsx and
#save, so on the next go around it rewrites the
#new data to Todolist1.xlsx
The second way I'm trying to solve this is with win32com. This allows me to keep Todolist2 open in excel in windows while it writes to it from example, example1, then example2. But the problem is, it does not write on the activesheet, it keeps adding additional sheets. So on this one, If I can find a way to keep rewriting over the active sheet in Todolist2 or after it adds the additional sheet, if I can only delete one sheet i'm golden.
import time, os.path, os
from win32com.client import Dispatch
path1 = 'C:\\example.xlsx'
path2 = 'C:\\Todolist2.xlsx'
path3 = 'C:\\example2.xlsx'
path4 = 'C:\\example3.xlsx'
xl = Dispatch("Excel.Application")
xl.Visible = True
wb1= xl.Workbooks.Open(Filename=path1)
wb2= xl.Workbooks.Open(Filename=path2)
ws1 = wb1.Worksheets(1)
ws1.Copy(Before=wb2.Worksheets(1))
time.sleep(5)
wb3= xl.Workbooks.Open(Filename=path3)
ws3 = wb3.Worksheets(1)
ws2 = wb2.Worksheets(3) #it seems by using (3) is the only way it
#allows me to delete one sheet before it
#adds another.
ws2.Delete()
ws3.Copy(Before=wb2.Worksheets(1))
time.sleep(5)
wb4= xl.Workbooks.Open(Filename=path4)
ws4 = wb4.Worksheets(1)
ws2.Delete() #I got into trouble here, and throws error even
#though it does the delete and copy
ws4.Copy(Before=wb2.Worksheets(1))

How to copy a worksheet from one excel file to another?
from openpyxl import load_workbook
from copy import copy
def copySheet(target, source):
for (row, col), source_cell in source._cells.items():
target_cell = target.cell(column=col, row=row)
target_cell._value = source_cell._value
target_cell.data_type = source_cell.data_type
if source_cell.has_style:
target_cell.font = copy(source_cell.font)
target_cell.border = copy(source_cell.border)
target_cell.fill = copy(source_cell.fill)
target_cell.number_format = copy(source_cell.number_format)
target_cell.protection = copy(source_cell.protection)
target_cell.alignment = copy(source_cell.alignment)
if source_cell.hyperlink:
target_cell._hyperlink = copy(source_cell.hyperlink)
if source_cell.comment:
target_cell.comment = copy(source_cell.comment)
for attr in ('row_dimensions', 'column_dimensions'):
src = getattr(source, attr)
trg = getattr(target, attr)
for key, dim in src.items():
trg[key] = copy(dim)
trg[key].worksheet = trg
target.sheet_format = copy(source.sheet_format)
target.sheet_properties = copy(source.sheet_properties)
target.merged_cells = copy(source.merged_cells)
target.page_margins = copy(source.page_margins)
target.page_setup = copy(source.page_setup)
target.print_options = copy(source.print_options)
"copy to"
wb1 = load_workbook(path_to)
target = wb1.create_sheet("lol")
"copy from"
wb2 = load_workbook(path_from)
source = wb2.active
copySheet(target=target, source=source)
wb1.save("fusion.xlsx")

Print Excel workbook using python

Suppose I have an excel file excel_file.xlsx and i want to send it to my printer using Python so I use:
import os
os.startfile('path/to/file','print')
My problem is that this only prints the first sheet of the excel workbook but i want all the sheets printed. Is there any way to print the entire workbook?
Also, I used Openpyxl to create the file, but it doesn't seem to have any option to select the number of sheets for printing.
Any help would be greatly appreciated.

from xlrd import open_workbook
from openpyxl.reader.excel import load_workbook
import os
import shutil
path_to_workbook = "/Users/username/path/sheet.xlsx"
worksheets_folder = "/Users/username/path/worksheets/"
workbook = open_workbook(path_to_workbook)
def main():
all_sheet_names = []
for s in workbook.sheets():
all_sheet_names.append(s.name)
for sheet in workbook.sheets():
if not os.path.exists("worksheets"):
os.makedirs("worksheets")
working_sheet = sheet.name
path_to_new_workbook = worksheets_folder + '{}.xlsx'.format(sheet.name)
shutil.copyfile(path_to_workbook, path_to_new_workbook)
nwb = load_workbook(path_to_new_workbook)
print "working_sheet = " + working_sheet
for name in all_sheet_names:
if name != working_sheet:
nwb.remove_sheet(nwb.get_sheet_by_name(name))
nwb.save(path_to_new_workbook)
ws_files = get_file_names(worksheets_folder, ".xlsx")
# Uncomment print command
for f in xrange(0, len(ws_files)):
path_to_file = worksheets_folder + ws_files[f]
# os.startfile(path_to_file, 'print')
print 'PRINT: ' + path_to_file
# remove worksheets folder
shutil.rmtree(worksheets_folder)
def get_file_names(folder, extension):
names = []
for file_name in os.listdir(folder):
if file_name.endswith(extension):
names.append(file_name)
return names
if __name__ == '__main__':
main()
probably not the best approach, but it should work.
As a workaround you can create separate .xlsx files where each has only one spreadsheet and then print them with os.startfile(path_to_file, 'print')

I have had this issue(on windows) and it was solved by using pywin32 module and this code block(in line 5 you can specify the sheets you want to print.)
import win32com.client
o = win32com.client.Dispatch('Excel.Application')
o.visible = True
wb = o.Workbooks.Open('/Users/1/Desktop/Sample.xlsx')
ws = wb.Worksheets([1 ,2 ,3])
ws.printout()

you could embed vBa on open() command to print the excel file to a default printer using xlsxwriter's utility mentioned in this article:
PBPYthon's Embed vBA in Excel

Turns out, the problem was with Microsoft Excel,
os.startfile just sends the file to the system's default app used to open those file types. I just had to change the default to another app (WPS Office in my case) and the problem was solved.

Seems like you should be able to just loop through and change which page is active. I tried this and it did print out every sheet, BUT for whatever reason on the first print it grouped together two sheets, so it gave me one duplicate page for each workbook.
wb = op.load_workbook(filepath)
for sheet in wb.sheetnames:
sel_sheet = wb[sheet]
# find the max row and max column in the sheet
max_row = sel_sheet.max_row
max_column = sel_sheet.max_column
# identify the sheets that have some data in them
if (max_row > 1) & (max_column > 1):
# Creating new file for each sheet
sheet_names = wb.sheetnames
wb.active = sheet_names.index(sheet)
wb.save(filepath)
os.startfile(filepath, "print")

Importing Multiple Excel Files using OpenPyXL

I am trying to read in multiple excel files and append the data from each file into one master file. Each file will have the same headers (So I can skip the import of the first row after the initial file).
I am pretty new to both Python and the OpenPyXL module. I am able to import the first workbook without problem. My problem comes in when I need to open the subsequent file and copy the data to paste into the original worksheet.
Here is my code so far:
# Creating blank workbook
from openpyxl import Workbook
wb = Workbook()
# grab active worksheet
ws = wb.active
# Read in excel data
from openpyxl import load_workbook
wb = load_workbook('first_file.xlsx') #explicitly loading workbook, will automate later
# grab active worksheet in current workbook
ws = wb.active
#get max columns and rows
sheet = wb.get_sheet_by_name('Sheet1')
print ("Rows: ", sheet.max_row) # for debugging purposes
print ("Columns: ", sheet.max_column) # for debugging purposes
last_data_point = ws.cell(row = sheet.max_row, column = sheet.max_column).coordinate
print ("Last data point in current worksheet:", last_data_point) #for debugging purposes
#import next file and add to master
append_point = ws.cell(row = sheet.max_row + 1, column = 1).coordinate
print ("Start new data at:", append_point)
wb = load_workbook('second_file.xlsx')
sheet2 = wb.get_sheet_by_name('Sheet1')
start = ws.cell(coordinate='A2').coordinate
print("New data start: ", start)
end = ws.cell(row = sheet2.max_row, column = sheet2.max_column).coordinate
print ("New data end: ", end)
# write a value to selected cell
#sheet[append_point] = 311
#print (ws.cell(append_point).value)
#save file
wb.save('master_file.xlsx')
Thanks!

I don't really understand your code. It looks too complicated. When copying between worksheets you probably want to use ws.rows.
wb1 = load_workbook('master.xlsx')
ws2 = wb1.active
for f in files:
wb2 = load_workbook(f)
ws2 = wb2['Sheet1']
for row in ws2.rows[1:]:
ws1.append((cell.value for cell in row))

Python win32com - Read text in a text box to a cell?

I would like to read the text from a text box in an Excel File and save that value to a variable. The problem I am having is with the reading of the TextBox. I have tried several methods, this one showed the most promise, as it does not generate an error, but it does not elicit the desired result either. Any suggestions are appreciated. See code below.
import win32com.client as win32
excel = win32.gencache.EnsureDispatch('Excel.Application')
wb = excel.Workbooks.Open("C:\\users\\khillstr\\Testing\\Scripts\\Book1.xlsx")
excel.Visible = False
ws = wb.Worksheets
canvas = excel.ActiveSheet.Shapes
for shp in canvas.CanvasItems:
if shp.TextFrame.Characters:
print shp.TextFrame.Characters
else:
print "no"

Canvas has to do with graphics in excel files. I think you want access to the cells. Below is code that prints out each row as a tuple.
import win32com.client as win32
excel = win32.gencache.EnsureDispatch('Excel.Application')
wb = excel.Workbooks.Open("C:\\users\\khillstr\\Testing\\Scripts\\Book1.xlsx")
excel.Visible = False
sheet = wb.Worksheets(1)
for row in sheet.UsedRange.Value:
print row

To get the text in a textbox object on a sheet you need to use shp.TextFrame.Characters.Caption as the Characters method returns a Characters object and not a string.

import win32com.client as win32
file_name = 'path_to_excel'
excel = win32.gencache.EnsureDispatch('Excel.Application')
wb = excel.Workbooks.Open(self.file_name)
excel.Visible = False
sheet = wb.Worksheets(1)
deep = lambda r,c: sheet.Cells(r,c)
print(deep(row_num,col_num))
excel.Application.Quit()
This code will open an excel located at 'path_to_excel' and read a cell located at (Row_Number = row_num, Column_Number = col_num)