I'm using the following code:
for x in range(8):
print(x,end=" ") #Loop run for 8 times(from 0 to 7)
print('\n')
for x in range(1,8):
print(x,end=" ")
When I run it, the output is:
0 1 2 3 4 5 6 7
1 2 3 4 5 6 7
I only need one new line in the answer; that is, I want the output as:
0 1 2 3 4 5 6 7
1 2 3 4 5 6 7
The print function has a default end of a linefeed. If you tell it to print a linefeed, it will do that, and then add the default ending linefeed, resulting in two linefeeds. If you only want one, call it with no arguments:
print()
for x in range(8):
print(x, end=" ")
print()
for x in range(1,8):
print(x, end=" ")
Add another print statement between the loops:
print()
This will print the new line.
Related
for make in range(1, content+1):
print(make)
Result:
1
2
3
4
5
But i want them like this :
1 2 3 4 5 6 7
You need to modify the print command to tell it the separator to use with the "end" argument:
for make in range(1, content+1):
print(make,end=' ')
I would like to print the following pattern in Python
input: 5
output:
5
456
34567
2345678
123456789
I have used the following code but it is not showing the above pattern. Anyone help me on this topic, please?
CODE:
rows = int(input("Enter number of rows: "))
k = 0
count=0
count1=0
for i in range(1, rows+1):
for space in range(1, (rows-i)+1):
print(" ", end="")
count+=1
while k!=((2*i)-1):
if count<=rows-1:
print(i+k, end=" ")
count+=1
else:
count1+=1
print(i+k-(2*count1), end=" ")
k += 1
count1 = count = k = 0
print()
OUTPUT:
1
2 3 2
3 4 5 4 3
4 5 6 7 6 5 4
5 6 7 8 9 8 7 6 5
If I understand your question correctly, you just want a pattern starting from n and going to 1 in decreasing order left side, and starting from n and going to 2n-1 in increasing order right side
def pattern(n):
for i in range(n,0,-1):
for j in range(1,i):
print(" ",end="")
for k in range(i,2*n-i+1):
print(k,end="")
print()
pattern(5)
5
456
34567
2345678
123456789
Code
fav_numbers = {
'bill': [4,6,7,1],
'uros': [9,0,1,2],
'pera': [1,6,3,5],
}
for name, numbers in fav_numbers.items():
print(name.title())
for num in numbers:
print(num, end=' ')
Result
Bill
4 6 7 1 Uros
9 0 1 2 Pera
1 6 3 5 [Finished in 0.1s]
Question
How do I write the for loop so that the last two names are formatted properly?
The problem is not the end=' ', but the print(name.title()) that's missing it. Add end= ' to that, too, to print the numbers into the same line, then finish with a print() for the final linebreak.
for name, numbers in fav_numbers.items():
print(name.title(), end=' ') # no newline here
for num in numbers:
print(num, end=' ')
print() # but newline here
Alternatively, you can use print without special parameters and pass the numbers as var-arg parameter using *.
for name, numbers in fav_numbers.items():
print(name.title(), *numbers)
This prints the name and the individual numbers, all separated with spaces. Both ways, the output is:
Pera 1 6 3 5
Bill 4 6 7 1
Uros 9 0 1 2
Just add another print at the end of the loop to start in a new line:
for name, numbers in fav_numbers.items():
print(name.title())
for num in numbers:
print(num, end=' ')
print()
Here have it live
fav_numbers = {
'bill': [4,6,7,1],
'uros': [9,0,1,2],
'pera': [1,6,3,5],
}
for k,v in fav_numbers.items():
print(k, *v)
Output
bill 4 6 7 1
uros 9 0 1 2
pera 1 6 3 5
format is great for printing in a specific format
for name,numbers in fav_numbers.items():
print('{}: {}'.format(name,' '.join((str(n) for n in numbers))))
bill: 4 6 7 1
uros: 9 0 1 2
pera: 1 6 3 5
fav_numbers = {
'bill': [4,6,7,1],
'uros': [9,0,1,2],
'pera': [1,6,3,5],
}
for name,numbers in fav_numbers.items():
print(", ".join( repr(e) for e in numbers ).replace(',',''),name)
Output
4 6 7 1 bill
9 0 1 2 uros
1 6 3 5 pera
I'm trying to print a half pyramid that stars on the left side in python.
So far, this is my code
for i in range(1,12):
for j in range(12 - i):
print(" ", end = " ")
for j in range(1, i):
print(j, end = " " )
print("\n")
and my output is
1
1 2
1 2 3
1 2 3 4
1 2 3 4 5
1 2 3 4 5 6
1 2 3 4 5 6 7
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8 9 10
However, my output is meant to be in the opposite order:
1
2 1
3 2 1
4 3 2 1
5 4 3 2 1
How can I make this change?
Just reverse the second loop -- the one that prints that actual numbers:
for j in range(i-1, 0, -1):
The last parameter controls the "step", or how much the variable changes on each loop iteration. Output:
1
2 1
3 2 1
4 3 2 1
5 4 3 2 1
...
Reverse the range by adding the third argument (-1). Also format your numbers to use 2 places, so 10 is not pushing the last line to the right. Finally, the last print should probably not have \n, since that is already the default ending character of print:
for i in range(1,12):
for j in range(12 - i):
print(" ", end = "")
for j in range(i-1, 0,-1):
print(str(j).rjust(2), end = "" )
print()
You could just reverse the range that you print out as numbers
for i in range(1,12):
for j in range(12 - i):
print(" ", end = " ")
for j in reversed(range(1, i)):
print(j, end = " " )
print("\n")
The problem is in your second for loop, as you are looping from 1 to i, meaning you start off with 1 being printed first, and every following number until (not including) i.
Fortunately, for loops are able to go in reverse. So, instead of:
for j in range(1, i)
You could write:
for j in range((i-1), 0, -1)
Where the first parameter is signifies where the loop starts, the second is where the loop finishes, and the third signifies how large our jumps are going to be, in this case negative. The reason we are starting at i-1 and finishing at 0 is because loops start at exactly the first given number, and loop until just before the second given number, so in your given code the loop stops just before i, and so this one starts just before i as well, although you could remove the -1 if you wish to include 12 in the pyramid.
In this question I had to create a program that prompts the user for a number and then prompt again for how many rows to create. Something like:
1 1 1 1 1 1 1
2 2 2 2 2 2 2
3 3 3 3 3 3 3
4 4 4 4 4 4 4
This is what I came up with and I have tried many different ways to get the same result but it didn't work.
num=int(input("Enter a number between 1 and 10: "))
rows=int(input("Enter how many rows to of numbers: "))
for i in range(num):
print(i,end=" ")
for x in range(rows):
print (x)
This is the output I came up with:
Enter a number between 1 and 10: 6
Enter how many rows to of numbers: 4
0 1 2 3 4 5 0
1
2
3
You may simply do it like:
num = 5
rows = 4
for i in range(1, num+1):
print('{} '.format(i) * rows)
Output:
1 1 1 1
2 2 2 2
3 3 3 3
4 4 4 4
5 5 5 5
Explanation: When you multiply a str with some number say n, new string is returned with original string repeated n times. Doing this you will eliminate your nested loop
Simple solution: Just use nested for loops:
num = int(input("Enter a number between 1 and 10: "))
rows = int(input("Enter how many rows to of numbers: "))
for i in range(num):
print ('\n')
for x in range(rows):
print (i + 1)
The code above will go through the range 0 to num, printing first a new line and then printing the current number rows times.
rows = 5
side = int(input("Please Enter any Side of a Square : "))
for i in range(side):
for j in range(side):
if(i == 0 or i == side - 1 or j == 0 or j == side - 1):
print(i, end = ' ')
else:
print(i, end = ' ')
print()