I'm using this code to check for new mails with a 10 seconds delay.
import poplib
from email import parser
import time
def seeit():
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('xxx')
pop_conn.pass_('xx')
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:a
messages = ["\n".join(mssg[1]) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print message['subject']
pop_conn.quit()
starttime=time.time()
while True:
k=10.0
print "tick"
seeit()
time.sleep(k - ((time.time() - starttime) % k))
How can i retrieve the email body without headers?
Look at the method get_payload() method from the email package.
Try this after you get the messages from server:
import email
...
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
...
for i in messages:
mssg = email.message_from_string(i)
print(mssg.get_payload())
Related
I'm trying to parse emails from Outlook.
I would like the following printed:
subject
body (excluding sender's signature)
Ignore all previous emails from conversion (reply & forward)
Is there any way I can print out the body text before multi-space between lines (usually this is how signature being separated from the main text)?
Any help would be appreciated!
import win32com.client
#other libraries to be used in this script
import os
from datetime import datetime, timedelta
outlook = win32com.client.Dispatch('outlook.application')
mapi = outlook.GetNamespace("MAPI")
for account in mapi.Accounts:
print(account.DeliveryStore.DisplayName)
inbox = mapi.GetDefaultFolder(6)
messages = inbox.Items
messages.Sort('[ReceivedTime]', True)
received_dt = datetime.now() - timedelta(days=1)
received_dt = received_dt.strftime('%m/%d/%Y %H:%M %p')
messages = messages.Restrict("[ReceivedTime] >= '" + received_dt + "'")
messages = messages.Restrict("[SenderEmailAddress] = 'firstname.lastname#gmail.com'")
message = messages.GetFirst()
print ("Current date/time: "+ received_dt)
while message:
print(message.Subject)
print(message.body)
message = messages.GetNext ()
You can use a regex to ignore everything after three newlines (there are normally one or two newlines between paragraphs):
import re
r = re.compile(r"(.*)\n\n\n", re.MULTILINE + re.DOTALL)
# ...
while message:
# ...
match = r.match(message.body)
if match:
body_without_signature = r.match(message.body).groups(0)
else:
# No signature found
body_without_signature = message.body
print(body_without_signature)
The script is first doing it job
find the message with specific subject
send a message to the sender
copy the message to folder 'answered'
delete the message
sleep for 1min and repeat
mail.select()
status, messages = mail.select("INBOX")
n = int(str(messages[0], 'utf-8'))
messages = int(messages[0])
for i in range(messages, messages-n,-1):
res, msg = mail.fetch(str(i), "(RFC822)")
for response in msg:
if isinstance(response, tuple):
# parse a bytes email into a message object
msg = email.message_from_bytes(response[1])
Sub, encoding = decode_header(msg.get("Subject"))[0] # Error is about this line
Sub=Sub.decode((encoding))
if Sub == pat:
fro, encoding = decode_header(msg.get("From"))[0]
if isinstance(fro, bytes):
fro = fro.decode(encoding)
# if s == 0:
# time.sleep(60)
# mai_load(1)
print("From:", fro)
send_mail(fro)
mail.copy(str(i), 'praca')
mail.store(str(i), '+FLAGS', '\\Deleted')
print("=" * 100)
time.sleep(60)
mai_load(0)
And here is the problem, messages are mark as read and when the scripts connects again I'm receiving an error:
line 99, in mai_load
Sub, encoding = decode_header(msg.get("Subject"))[0]
File "/usr/lib/python3.8/email/header.py", line 80, in decode_header
if not ecre.search(header):
TypeError: expected string or bytes-like object
Try my lib: https://github.com/ikvk/imap_tools
from imap_tools import MailBox, AND, MailMessageFlags
with MailBox('imap.mail.com').login('test#mail.com', 'pwd', 'INBOX') as mailbox:
# get list of email senders from INBOX folder
senders = [msg.from_ for msg in mailbox.fetch()]
# FLAG unseen messages in current folder (INBOX) as Flagged
mailbox.flag(mailbox.fetch(AND(seen=False)), [MailMessageFlags.FLAGGED], True)
I have this code that sends out emails individually through gmail from a list of emails in an excel file. I just want to know how to make the bot pause for 60 seconds after it's sent 50 emails and then continue with the list after the 60 seconds is up. I'm just trying to be safe with gmails daily limits.
import smtplib
import openpyxl as xl
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
username = str(input('Your Username:' ))
password = str(input('Your Password:' ))
From = username
Subject = 'Free Beats and Samples For You :)'
wb = xl.load_workbook(r'C:\Users\19548\Documents\EMAILS.xlsx')
sheet1 = wb.get_sheet_by_name('EMAIL TEST - Sheet1')
names = []
emails = []
for cell in sheet1['A']:
emails.append(cell.value)
for cell in sheet1['B']:
names.append(cell.value)
server = smtplib.SMTP('smtp.gmail.com', 587)
server.starttls()
server.login(username, password)
for i in range(len(emails)):
msg = MIMEMultipart()
msg['From'] = username
msg['To'] = emails[i]
msg['Subject'] = Subject
text = '''
{}
'''.format(names[i])
msg.attach(MIMEText(text, 'plain'))
message = msg.as_string()
server.sendmail(username, emails[i], message)
print('Mail sent to', emails[i])
server.quit()
print('All emails sent successfully!')
You can use time.sleep() to wait a given number of seconds, and you can keep track of the number of emails sent using a variable that gets incremented with each iteration of the loop. Since you're already working with both the emails themselves and their indices, you can simplify this counting by using Python's enumerate function, which gives you both the next value and its corresponding index:
for index, email in enumerate(emails, start=1):
msg = <...>
message = msg.as_string()
server.sendmail(username, email, message)
if index % 50 == 0:
time.sleep(60)
if(your_value%50==0):
time.sleep(60)
I'm unable to find ANY code that will function to retrieve Gmail.
import poplib
from email import parser
SERVER = "pop.gmail.com"
USER = "user#gmail.com"
PASSWORD = "password"
pop_conn = poplib.POP3_SSL(SERVER)
pop_conn.user(USER)
pop_conn.pass_(PASSWORD)
#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
# Concat message pieces:
messages = ["\n".join(mssg[1]) for mssg in messages]
#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message['subject'])
print(message['body'])
This produces only:
TypeError Traceback (most recent call last)
<ipython-input-8-e557fa99ae8d> in ()
12 messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
13 # Concat message pieces:
---> 14 messages = ["\n".join(mssg[1]) for mssg in messages]
15 #Parse message intom an email object:
16 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
<ipython-input-8-e557fa99ae8d> in (.0)
12 messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
13 # Concat message pieces:
---> 14 messages = ["\n".join(mssg[1]) for mssg in messages]
15 #Parse message intom an email object:
16 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
TypeError: sequence item 0: expected str instance, bytes found
I'VE SPENT DAYS trying to do a "simple" e-mail retrieve, and EVERY scrap of code I've found is totally non-functional.
Can anyone actually get Gmail, with subjects, etc?
This code is incomplete but may help you.
source: https://www.code-learner.com/python-use-pop3-to-read-email-example/
import poplib
import smtplib, ssl
# input email address, password and pop3 server domain or ip address
email = 'yourgmail#gmail.com'
password = 'password'
# connect to pop3 server:
server = poplib.POP3_SSL('pop.gmail.com')
# open debug switch to print debug information between client and pop3 server.
server.set_debuglevel(1)
# get pop3 server welcome message.
pop3_server_welcome_msg = server.getwelcome().decode('utf-8')
# print out the pop3 server welcome message.
print(server.getwelcome().decode('utf-8'))
# user account authentication
server.user(email)
server.pass_(password)
# stat() function return email count and occupied disk size
print('Messages: %s. Size: %s' % server.stat())
# list() function return all email list
resp, mails, octets = server.list()
print(mails)
# retrieve the newest email index number
index = len(mails)
# server.retr function can get the contents of the email with index variable value index number.
resp, lines, octets = server.retr(index)
# lines stores each line of the original text of the message
# so that you can get the original text of the entire message use the join function and lines variable.
msg_content = b'\r\n'.join(lines).decode('utf-8')
# now parse out the email object.
from email.parser import Parser
from email.header import decode_header
from email.utils import parseaddr
import poplib
# parse the email content to a message object.
msg = Parser().parsestr(msg_content)
# get email from, to, subject attribute value.
email_from = msg.get('From')
email_to = msg.get('To')
email_subject = msg.get('Subject')
print('From ' + email_from)
print('To ' + email_to)
print('Subject ' + email_subject)
# delete the email from pop3 server directly by email index.
# server.dele(index)
# close pop3 server connection.
server.quit()
This is the code
import poplib
from email import parser
pop_conn = poplib.POP3_SSL('pop.gmail.com')
pop_conn.user('user#gmail.com')
pop_conn.pass_('password')
messages = [pop_conn.retr(i) for i in range(1, len(pop_conn.list()[1]) + 1)]
messages = ["\n".join(mssg[1]) for mssg in messages]
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message)
When it gets to the 8th line (messages = ["\n".join(mssg[1]) for mssg in messages])
It says this:
TypeError: sequence item 0: expected str instance, bytes found
Does anyone know what i'm doing wrong?
Convert the bytes objects into string using bytes.decode:
messages = ["\n".join(m.decode() for m in mssg[1]) for mssg in messages]