Started learning python after lots of ruby experience. With that context in mind:
I have a csv file that looks something like this:
city_names.csv
"abidjan","addis_ababa","adelaide","ahmedabad"
With the following python script I'd like to read this into a list:
city_names_reader.py
import csv
city_name_file = r"./city_names.csv"
with open(city_name_file, 'rb') as file:
reader = csv.reader(file)
city_name_list = list(reader)
print city_name_list
The result surprised me:
[['abidjan', 'addis_ababa', 'adelaide', 'ahmedabad']]
Any idea why I'm getting a nested list rather than a 4-element list? I must be overlooking something self-evident.
A CSV file represents a table of data. A table contains both columns and rows, like a spreadsheet. Each line in a CSV file is one row in the table. One row contains multiple columns, separated by ,
When you read a CSV file you get a list of rows. Each row is a list of columns.
If your file have only one row you can easily just read that row from the list:
city_name_list = city_name_list[0]
Usually each column represent some kind of data (think "column of email addresses"). Each row then represent a different object (think "one object per row, each row can have one email address"). You add more objects to the table by adding more rows.
It is not common with wide tables. Wide tables are those that grow by adding more columns instead of rows. In your case you have only one kind of data: city names. So you should have one column ("name"), with one row per city. To get city names from your file you could then read the first element from each row:
city_name_list = [row[0] for row in city_name_list]
In both cases you can flatten the list by using itertools.chain:
city_name_list = itertools.chain(city_name_list)
As others suggest, your file is not an idiomatic CSV file. You can simply do:
with open(city_name_file, "rb") as fp:
city_names_list = fp.read().split(",")
Based on comments, here is a possible solution:
import csv
city_name_file = r"./city_names.csv"
city_name_list = []
with open(city_name_file, 'rb') as file:
reader = csv.reader(file)
for item in reader:
city_name_list += item
print city_name_list
Related
I want to create a program in which reads a CSV file and writes in another file. My problem is, the file I'm ready is kinda big and I don't want to go through every column by doing this:
columns = defaultdict(list)
reader = csv.DictReader(csvfile)
for row in reader:
for (k,v) in row.items():
columns[k].append(v)
print(columns['name'])
print(columns['id'])
...
I wanted to, instead, do columns[0] to find 'name', and so on. Is there any way I can do this?
You are now reading the CSV with a DictReader this creates the columns based on names, in your case you could just use the reader:
columns = defaultdict(list)
reader = csv.reader(csvfile)
next(reader) # to skip the header row
for row in reader:
for i, v in enumerate(row):
columns[i].append(v)
print(columns[0])
print(columns[1])
I'm not sure that I understand your question. If you are asking, "can I read only the first column?", then the short answer is no. CSV is specifically designed to read a fixed number of columns from variable length records. More specifically, the data is organized as a list of rows, not a list of columns. You can't just seek past what you don't want to read. It sounds like what you are trying to do is reorganized your data into columns.
If you want to minimize the processing of what you do read, it sounds like all you need to do is use csv.reader and skip the first row containing the header. Each row from the reader will return a list of strings and the construction of this list should be less expensive than a map.
If you collect the list of rows you can then put it in a numpy array. A numpy array will allow you to access columns (e.g., x[:, 0]) or rows (e.g., x[0, :]).
Given that I am not entirely sure what you are asking, my answers may not not be what you are looking for; however, whatever your problem is, I am certain you cannot avoid reading the entire file.
I'm doing some manipulation on a CSV file using Python and the csv module. I take a CSV file, do some operations, and output an XML file. Very simplified, but the input data looks similar to this:
name,group
joe,staff
jane,student
bill,staff
barry,support
jack,student
I have a list as follows:
outputList = ['staff', 'support']
Essentially, what I want to do is remove the line of data if the group field isn't contained in the outputList. So what I would end up with is:
name,group
joe,staff
bill,staff
barry,support
The main reason I need to remove the rows is because I then need to sort by outputList (which is a lot longer than in this example, and in a specific non-alphabetical order).
Doing the sorting is relatively easy:
csvData = sorted(csvData, key=lambda k: (outputList.index(k['group'])))
However, obviously without removing the rows that aren't needed I get an error that the group value isn't in the outputList.
Is there an easy way of removing the data, or do I just need to iterate over each row and check whether the value is present? I've seen methods of doing it when you just have two lists. E.G.
data = ['staff', 'support', 'student']
csvData = [data for data in csvData if data not in outputList]
There's no other way to filter the data without scanning all the data of course, you can simply do something like this:
import csv
def parser(fp, groups):
with open(fp) as fin:
reader = csv.reader(fp)
for row in reader:
if row[1] in groups:
yield row
csvData = parser('~/some_loc/file.csv', outputList)
Load your csv into a pandas dataframe df.
The you can use:
df = df[df.group.isin(outputList)]
Isin creates a boolean series(mask) which you can use to select only the relevant rows.
I'm "pseudo" creating a .bib file by reading a csv file and then following this structure writing down every thing including newline characters. It's a tedious process but it's a raw form on converting csv to .bib in python.
I'm using Pandas to read csv and write row by row, (and since it has special characters I'm using latin1 encoder) but I'm getting a huge problem: it only reads the first row. From the official documentation I'm using their method on reading row by row, which only gives me the first row (example 1):
row = next(df.iterrows())[1]
But if I remove the next() and [1] it gives me the content of every column concentrated in one field (example 2).
Why is this happenning? Why using the method in the docs does not iterate through all rows nicely? How would be the solution for example 1 but for all rows?
My code:
import csv
import pandas
import bibtexparser
import codecs
colnames = ['AUTORES', 'TITULO', 'OUTROS', 'DATA','NOMEREVISTA','LOCAL','VOL','NUM','PAG','PAG2','ISBN','ISSN','ISSN2','ERC','IF','DOI','CODEN','WOS','SCOPUS','URL','CODIGO BIBLIOGRAFICO','INDEXAÇÕES',
'EXTRAINFO','TESTE']
data = pandas.read_csv('test1.csv', names=colnames, delimiter =r";", encoding='latin1')#, nrows=1
df = pandas.DataFrame(data=data)
with codecs.open('test1.txt', 'w', encoding='latin1') as fh:
fh.write('#Book{Arp, ')
fh.write('\n')
rl = data.iterrows()
for i in rl:
ix = str(i)
fh.write(' Title = {')
fh.write(ix)
fh.write('}')
fh.write('\n')
PS: I'm new to python and programming, I know this code has flaws and it's not the most effective way to convert csv to bib.
The example row = next(df.iterrows())[1] intentionally only returns the first row.
df.iterrows() returns a generator over tuples describing the rows. The tuple's first entry contains the row index and the second entry is a pandas series with your data of the row.
Hence, next(df.iterrows()) returns the next entry of the generator. If next has not been called before, this is the very first tuple.
Accordingly, next(df.iterrows())[1] returns the first row (i.e. the second tuple entry) as a pandas series.
What you are looking for is probably something like this:
for row_index, row in df.iterrows():
convert_to_bib(row)
Secondly, all your writing to your file handle fh must happen within the block with codecs.open('test1.txt', 'w', encoding='latin1') as fh:
because at the end of the block the file handle will be closed.
For example:
with codecs.open('test1.txt', 'w', encoding='latin1') as fh:
# iterate through all rows
for row_index, row in df.iterrows():
# iterate through all elements in the row
for colname in df.columns:
row_element = row[colname]
fh.write('%s = {%s},\n' % (colname, str(row_element)))
Still I am not sure if the names of the columns exactly match the bibtex fields you have in mind. Probably you have to convert these first. But I hope you get the principle behind the iterations :-)
Python 2.6(necessary for the job)
import csv
list = ['apple,whiskey,turtle', 'orange,gin,wolf', 'banana,vodka,sparrow']
fieldNames = ['Fruit', 'Spirit', 'Animal']
reader = csv.DictReader(list,fieldnames= fieldNames)
for row in reader:
print row['Fruit']
for row in reader:
print row['Fruit']
I have some code that generates a uniform list of items per row, making a list object. For ease of use I used the csv module's DictReader to step through the rows and do any calculations I need to but when I try to iterate a second time, I get no output. I suspect the end of the list is being treated like an EOF but I am unable to 'seek' to the beginning of the list to do the iteration again.
Any suggestions on what I can do? Perhaps there is a better way than using the CSV, it just seemed really convenient.
New Code
import csv
list = ['apple,"whiskey,rum",turtle', 'orange,gin,wolf', 'banana,vodka,sparrow']
processed = []
fieldNames = ['Fruit', 'Spirit', 'Animal']
reader = csv.DictReader(list,fieldnames= fieldNames, quoatechar = '"')
for row in reader:
processed.append(row)
print row
for row in processed:
print row['Fruit']
for row in processed:
print row['Spirit']
#jonrsharpe suggested placing the rows of reader into a list. It works perfectly for what I had in mind. Thank you everyone.
You're indeed correct that iterating over the rows once is what the DictReader provides. So your options are:
Create a new DictReader and iterate again (seems wasteful)
Iterate over the rows once and perform all computations that you want to perform
Iterate over the rows once, store the data in another data structure and iterate over that data structure as many times as you wish.
Also, if you have only the list and the field names you don't need a DictReader to do the same thing. If you know the data is relatively straightforward (no comma's inside the data for example and all the same number of items) then you can simply do:
merged = [zip(fieldnames, row.split(",")) for row in my_list]
print merged
I'm trying to create a list in python from a csv file. The CSV file contains only one column, with about 300 rows of data. The list should (ideally) contain a string of the data in each row.
When I execute the below code, I end up with a list of lists (each element is a list, not a string). Is the CSV file I'm using formatted incorrectly, or is there something else I'm missing?
filelist = []
with open(r'D:\blah\blahblah.csv', 'r') as expenses:
reader = csv.reader(expenses)
for row in reader:
filelist.append(row)
row is a row with one field. You need to get the first item in that row:
filelist.append(row[0])
Or more concisely:
filelist = [row[0] for row in csv.reader(expenses)]
It seems your "csv" doesn't contain any seperator like ";" or ",".
Because you said it only contains 1 column. So it ain't a real csv and there shouldn't be a seperator.
so you could simply read the file line-wise:
filelist = []
for line in open(r'D:\blah\blahblah.csv', 'r').readlines():
filelist.append(line.strip())
Each row is read as list of cells.
So what you want to do is
output = [ row[0] for row in reader ]
since you only have the first cell filled out in each row.