Develop Reference

How do I use the Selenium Click function

I am trying to click a login button after filling out all the information for the website. So far I have been able to fill in spaces using driver.find_element("id","username").send_keys("username") when I use driver.find_element_id("username").send_keys("username") it wont work.
The login button elements are class=radius and type=sumbit also i class="fa fa-2x fa-sign-in"
(I would just link the site but I dont know if that would be against TOS)
So far I have used the following commands
element = driver.find_element_by_link_text("Login")
element.click()
driver.find_element_by_xpath(//*[#id="login"]/button.click() but xpath gives an "unresolved reference"
I am using IDE PyCharm Build #PC-222.4167.33 on Windows

Try this code:
driver.find_element(By.ID, "username").send_keys("<enter the username>")
driver.find_element(By.ID, "password").send_keys("<enter the password>")
time.sleep(1)
driver.find_element(By.CSS_SELECTOR, ".radius").click()
time.sleep(2)
driver.find_element(By.CSS_SELECTOR, ".button.secondary.radius").click()
time.sleep(2)
I have added 'time.sleep()' just to show you it is working correctly, avoid using it in your real-time projects.

Looks like the same problem I solve here Selenium, selecting from dropdown
You should localize the element with XPath or CSS selector, i recommend you try with CSS selector, if don't work try with xpath .

Why won't Selenium in Python click the pop-up privacy button?

I am having some issues with Selenium not clicking the pop-up privacy button on https://www.transfermarkt.com/
Here is my code so far:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get('https://www.transfermarkt.com/')
accept_button = driver.find_element_by_xpath('/html/body/div/div[2]/div[3]/div[2]/button')
accept_button.click()
It comes up saying:
NoSuchElementException: Message: no such element: Unable to locate element: {"method":"xpath","selector":"/html/body/div/div[2]/div[3]/div[2]/button"}
Anyone have any thoughts?

I believe the issue is that the element you are trying to click is inside an iframe. In order to click that element you'll have to first switch to that frame. I noticed the iframe has title="SP Consent Message" so I'll use a CSS Selector to identify it based on that. Your code with the added line:
from selenium import webdriver
driver = webdriver.Chrome()
driver.get('https://www.transfermarkt.com/')
driver.switch_to.frame(driver.find_element_by_css_selector('iframe[title="SP Consent Message"]'))
accept_button = driver.find_element_by_xpath('/html/body/div/div[2]/div[3]/div[2]/button')
accept_button.click()
Note that you may have to switch back to the default frame to continue your test, I'm not 100% sure as that iframe has gone away.
Also it seems like some folks don't get that popup when the hit the website, not sure why, may be something you want to look in to to determine how you want to test this.
Like #Prophet says you should improve the xpath for the button (again it seems to have a unique title so I would use CSS Selector 'button[title="ACCEPT ALL"]'), but this works for me to click it.

There are 2 issues here:
You need to add wait / delay before accept_button = driver.find_element_by_xpath('/html/body/div/div[2]/div[3]/div[2]/button') to let the page load
It's very, very bad practice to use absolute XPaths. You have to define an unique, short and clear related XPath expression.
Additionally, I see no pop-up privacy button when I open that page. So, maybe that element is indeed not there.

selenium and XPATH unable to locate a button

I am trying to save the same stuff with selenium in my Yandex account, the problem is that when I try to pass the code to click the button "save to Yandex disk", selenium pass me the message unable to locate the element.
Thats my code:
browser.find_element_by_xpath('/html/body/div[1]/div/div[2]/div[1]/div[1]/div/div[1]/div[3]/button[1]').click()
this is the page with the button "Save to yandex disk": https://yadi.sk/d/0ReZErv_cLl1-w
I read that u can also pass elements by name or by CSS selector, but when I try with firefox inspector to copy element, the browser gives me strange code.
Any suggestions?
..of course, the same error with or without logged into Yandex.
Thank you

You can use this XPath for detecting needed element:
//div[#class = 'folder-content content content_other content_dir']//button[contains(#class, "save")]

Use this xpath //*[contains(text(),'Save to Yandex.Disk')] to click "Save to Yandex.Disk" button

First thing is that we need to improve the xpath you are using to find the element we should use the xpath that is relative but in your case you are using the xpath that is absolute, I use the extension chropath in chrome to find the xpath of the element
Below mentioned is the chro path I would recommend you to use although the above two mentioned xpath can also be used
Let me know If you have any more queries, I can form a good xpath for you
//div[#class='folder-content__header']//span[contains(text(),'Save to Yandex.Disk')]
Below mentioned is one of the xpath I have used in my own project take a look maybe this can improve your horizon
//label[contains(text(),'Plant Code*')]//parent::div[#class='rb_Work_FieldContainer']//following-sibling::div[contains(#class,'rb_Work_FieldValueArea rb_Work_FieldValueArea_create ')]//textarea[#class='textarea']

How to locate the element as per the html provided through Selenium, Python and Xpath

I'm using selenium to fill a webform, but this particular textbox for some reason is giving me trouble. The html for it is:
<input type="text" class="black_ar" value="" size="25" id="type" name="type"
onmouseover="showTip(this.id)" onmouseout="hideTip(this.id)"
onblur="trimByAutoTag(this);onSubTypeChangeUnit('className',this,'unitSpan')"
autocomplete="off" title="">
I have used:
driver.find_element_by_name('type').click()
and
driver.find_element_by_xpath('xpath').click()
But they both say that the element cannot be found. I am not sure if it is in an iframe or not (if anyone knows a way to check) and am using chropath which is a chrome extension to find the xpath of the element.
Edit: chropath says under the relative xpath "It might be child of svg/pseudo/comment/iframe. XPath doesn't support for them." if that helps

As per the HTML you have shared to click within the textbox you can use either of the following solutions:
xpath:
driver.find_element_by_xpath("//input[#class='black_ar' and #id='type']").click()
css_selector:
driver.find_element_by_css_selector("input.black_ar#type").click()

Now ChroPath supports iframe. So if you inspect any element and that element is inside iframe, ChroPath will tell that element is inside iframe as well as it will generate the relative xpath.

Open your page in browser let say chrome. Press right click on textbox and select inspect menu. In oped dev tools look if your textbox has parent iframe element. One way to do it:
Click inside chrome dev tools and press ctrl+f
In opened search field copy iframe input.black_ar
If does you have first switch to this frame function for switching frames in python, selenium
To locate your input use driver.find_element_by_css_selector(‘input.black_ar’)

Have you tried, driver.find_element_by_xpath("//input[#id='type']").click(); ?
You could all check by press F12 while in your browser, or going to developer tool; press Ctrl+f afterwards and type in //iframe and try to see if it exists in the page.

Python/Selenium:Different ways to click this specific button

I am trying to understand Python in general as I just switched over from using VBA. I interested in the possible ways you could approach this single issue. I already went around it by just going to the link directly, but I need to understand and apply here.
from selenium import webdriver
chromedriver = r'C:\Users\dd\Desktop\chromedriver.exe'
browser = webdriver.Chrome(chromedriver)
url = 'https://www.fake.com/'
browser.get(url)
browser.find_element_by_id('txtLoginUserName').send_keys("Hello")
browser.find_element_by_id('txtLoginPassword').send_keys("There")
browser.find_element_by_id('btnLogin').click()
At this point, I am trying to navigate to a particular button/link.
Here is the info from the page/element
T-Mobile
Here are some of the things I tried:
for elem in browser.find_elements_by_xpath("//*[contains(text(), 'T-Mobile')]"):
elem.click
browser.execute_script("InitiateCallBack(187, True, T-Mobile, https://www.fake.com/, TMobile)")
I also attempted to look for tags and use css selector all of which I deleted out of frustration!
Specific questions
How do I utilize the innertext,"T-Mobile", to click the button?
How would I execute the onclick event?
I've tried to read the following links, but still have not succeeded incoming up with a different way. Part of it is probably because I don't understand the specific syntax yet. This is just some of the things I looked at. I spent about 3 hours trying various things before I came here!
selenium python onclick() gives StaleElementReferenceException
http://selenium-python.readthedocs.io/locating-elements.html
Python: Selenium to simulate onclick
https://stackoverflow.com/questions/43531654/simulate-a-onclick-with-selenium-https://stackoverflow.com/questions/45360707/python-selenium-using-onclick
Running javascript in Selenium using Python

How do I utilize the innertext,"T-Mobile", to click the button?
find_elements_by_link_text would be appropriate for this case.
elements = driver.find_elements_by_link_text('T-Mobile')
for elem in elements:
elem.click()
There's also a by_partial_link_text locator as well if you don't have the full exact text.
How would I execute the onclick event?
The simplest way would be to simply call .click() on the element as shown above and the event should, naturally, execute at that time.
Alternatively, you can retrieve the onclick attribute and use driver.execute_script to run the js.
for elem in elements:
script = elem.get_attribute('onlcick')
driver.execute_script(script)
Edit:
note that in your code you did element.click -- this does nothing. element.click() (note the parens) calls the click method.
is there a way to utilize browser.execute_script() for the onclick event
execute_script can fire the equivalent event, but there may be more listeners that you miss by doing this. Using the element click method is the most sound. There may very well be many implementation details of the site that may hinder your automation efforts, but those possibilities are endless. Without seeing the actual context, it's hard to say.
You can use JS methods to click an element or otherwise interact with the page, but you may miss certain event listeners that occur when using the site 'normally'; you want to emulate, more or less, the normal use as closely as possible.

As per the HTML you have shared it's pretty clear the website uses JavaScript. So to click() on the link with text as T-Mobile you have to induce WebDriverWait with expected_conditions clause as element_to_be_clickable and your can use the following code block :
WebDriverWait(driver, 20).until(expected_conditions.element_to_be_clickable((By.XPATH, "//a[contains(.,'T-Mobile')]"))).click()

you can use it
<div class="button c_button s_button" onclick="submitForm('rMTF')" style="margin-bottom: 30px;">
<input class="v_small" type="button"></input>
<span>
Reset
</span>