Develop Reference

Read a file line by line, subtract each number from one, replace hyphens with colons, and print the output on one single line

I have a text file (s1.txt) containing the following information. There are some lines that contain only one number and others that contain two numbers separated by a hyphen.
1
3-5
10
11-13
111
113-150
1111
1123-1356
My objective is to write a program that reads the file line by line, subtracts each number from one, replaces hyphens with colons, and prints the output on one single line. The following is my expected outcome.
{0 2:4 9 10:12 110 112:149 1110 1122:1355}
Using the following code, I am receiving an output that is quite different from what I expected. Please, let me know how I can correct it.
s1_file = input("Enter the name of the S1 file: ")
s1_text = open(s1_file, "r")
# Read contents of the S1 file to string
s1_data = s1_text.read()
for atoms in s1_data.split('\n'):
if atoms.isnumeric():
qm_atom = int(atoms) - 1
#print(qm_atom)
else:
qm_atom = atoms.split('-')
print(qm_atom)

If your goal is to output directly to the screen as a single line you should add end=' ' to the print function.
Or you can store the values in a variable and print everything at the end.
Regardless of that, you were missing at the end to subtract 1 from the values and then join them with the join function. The join function is used on a string where it creates a new string with the values of an array (all values must be strings) separated by the string on which the join method is called.
For example ', '.join(['car', 'bike', 'truck']) would get 'car, bike, truck'.
s1_file = input("Enter the name of the S1 file: ")
s1_text = open(s1_file, "r")
# Read contents of the S1 file to string
s1_data = s1_text.read()
output = []
for atoms in s1_data.split('\n'):
if atoms.isnumeric():
qm_atom = int(atoms) - 1
output.append(str(qm_atom))
else:
qm_atom = atoms.split('-')
# loop the array to subtract 1 from each number
qm_atom_substrated = [str(int(q) - 1) for q in qm_atom]
# join function to combine int with :
output.append(':'.join(qm_atom_substrated))
print(output)

An alternative way of doing it could be:
s1_file = input("Enter the name of the S1 file: ")
with open (s1_file) as f:
output_string = ""
for line in f:
elements = line.strip().split('-')
elements = [int(element) - 1 for element in elements]
elements = [str(element) for element in elements]
elements = ":".join(elements)
output_string += elements + " "
print(output_string)

why are you needlessly complicating a simple task by checking if a element is numerical then handle it else handle it differently.
Also your code gave you a bad output because your else clause is incorrect , it just split elements into sub lists and there is no joining of this sub list with ':'
anyways here is my complete code
f=open(s1_file,'r')
t=f.readlines()#reading all lines
for i in range(0,len(t)):
t[i]=t[i][0:-1]#removing /n
t[i]=t[i].replace('-',':') #replacing - with :
try:t[i]=int(t[i])-1 #convert str into int & process
except:
t[i]=f"{int(t[i].split(':')[0])-1}:{int(t[i].split(':')[1])-1}" #if str case then handle
print(t)

python 3 parsing a semicolon separated very long string to remove each second element

I'm pretty new to python and are looking for a way to get the following result from a long string
reading in lines of a textfile where each line looks like this
; 2:55:12;PuffDG;66,81; Puff4OG;66,75; Puff3OG;35,38;
after dataprocessing the data shall be stored in another textfile with this data
short example
2:55:12;66,81;66,75;35,38;
the real string is much longer but always with the same pattern
; 2:55:12;PuffDG;66,81; Puff4OG;66,75; Puff3OG;35,38; Puff2OG;30,25; Puff1OG;29,25; PuffFB;23,50; ....
So this means remove leading semicolon
keep second element
remove third element
keep fourth element
remove fith element
keep sixth element
and so on
the number of elements can vary so I guess as a first step I have to parse the string to get the number of elements and then do some looping through the string and assign each part that shall be kept to a variable
I have tried some variations of the command .split() but with no success.
Would it be easier to store all elements in a list and then for-loop through the list keeping and dropping elements?
If Yes how would this look like so at the end I have stored a file with
lines like this
2:55:12 ; 66,81 ; 66,75 ; 35,38 ;
2:56:12 ; 67,15 ; 74;16 ; 39,15 ;
etc. ....
best regards Stefan

This solution works independently of the content between the semicolons
One line, though it's a bit messier:
result = ' ; '.join(string.split(';')[1::2])
Getting rid of lead semicolon:
Just slice it off!
string = string[2:]
Splitting by semicolon & every second element:
Given a string, we can split by semicolon:
arr = string.split(';')[1::2]
The [::2] means to slice out every second element, starting with index 1. This keeps all "even" elements (second, fourth, etcetera).
Resulting string
To produce the string result you want, simply .join:
result = ' ; '.join(arr)

A regex based solution, which operates on the original input:
inp = "; 2:55:12;PuffDG;66,81; Puff4OG;66,75; Puff3OG;35,38;"
output = re.sub(r'\s*[A-Z][^;]*?;', '', inp)[2:]
print(output)
This prints:
2:55:12;66,81;66,75;35,38;

This shows how to do it for one line of input if the same pattern repeats itself every time
input_str = "; 2:55:12;PuffDG;66,81; Puff4OG;66,75; Puff3OG;35,38;"
f = open('output.txt', 'w') # open text to write to
output_list = input_str.split(';')[1::2] # create list with numbers of interest
# write to file
for out in output_list:
f.write(f"{out.strip()} ; ")
# end line
f.write("\n")

thank you very much for the quick response. You are awesome.
Your solutions are very comact.
In the meantime I found another solution but this solution needs more lines of code
best regards Stefan
I'm not familiar with how to insert code as a code-section properly
So I add it as plain text
fobj = open(r"C:\Users\Stefan\AppData\Local\Programs\Python\Python38-32\Heizung_2min.log")
wobj = open(r"C:\Users\Stefan\AppData\Local\Programs\Python\Python38-32\Heizung_number_2min.log","w")
for line in fobj:
TextLine = fobj.readline()
print(TextLine)
myList = TextLine.split(';')
TextLine = ""
for index, item in enumerate(myList):
if index % 2 == 1:
TextLine += item
TextLine += ";"
TextLine += '\n'
print(TextLine)
wobj.write(TextLine)
fobj.close()
wobj.close()`

How can I print list of items from multiple lines into a single line in Python?

I am trying to convert items list from multiple lines to a single line string and vice-versa. I am able to convert items from a single line string to multiple line vertical item list with following code:
Items = ["Apple","Ball","Cat"]
A = ("\n".join(Items))
print (A)
Which prints item list as follows:
Apple
Ball
Cat
I am all set with above code
My Question is regarding second code (which I can't figure out) down below:
However, I am unable to convert vertical list from multiple lines to a single line string.
I have following items in multiple lines;
Apple
Ball
Cat
and I want to print them in a single line as:
Apple Ball Cat
I appreciate any kind of advice.

Replace your code with this:
A = (" ".join(Items))

You are joining the items with a new line character '\n'. Try joining them with just a space ' '.
So instead of
Items = ["Apple","Ball","Cat"]
A = ("\n".join(Items))
print (A)
You do
Items = ["Apple","Ball","Cat"]
A = (" ".join(Items))
print (A)

No join() required
things = ["Apple","Ball","Cat"]
s1 = ''
for item in things:
s1 += item + ' '
print(s1.rstrip())
# output
''' Apple Ball Cat '''

print(A,end="") replace the last line with this

Removing white space and colon

I have a file with a bunch of numbers that have white spaces and colons and I am trying to remove them. As I have seen on this forum the function line.strip.split() works well to achieve this. Is there a way of removing the white space and colon all in one go? Using the method posted by Lorenzo I have this:
train = []
with open('C:/Users/Morgan Weiss/Desktop/STA5635/DataSets/dexter/dexter_train.data') as train_data:
train.append(train_data.read().replace(' ','').replace(':',''))
size_of_train = np.shape(train)
for i in range(size_of_train[0]):
for j in range(size_of_train[1]):
train[i][j] = int(train[i][j])
print(train)
Although I get this error:
File "C:/Users/Morgan Weiss/Desktop/STA5635/Homework/Homework_1/HW1_Dexter.py", line 11, in <module>
for j in range(size_of_train[1]):
IndexError: tuple index out of range

I think the above syntax is not correct, but anyways as per your question, you can use replace function present in python.
When reading each line as a string from that file you can do something like,
train = []
with open('/Users/sushant.moon/Downloads/dexter_train.data') as f:
list = f.read().split()
for x in list:
data = x.split(':')
train.append([int(data[0]),int(data[1])])
# this part becomes redundant as i have already converted str to int before i append data to train
size_of_train = np.shape(train)
for i in range(size_of_train[0]):
for j in range(size_of_train[1]):
train[i][j] = int(train[i][j])
Here I am using replace function to replace space with blank string, and similar with colon.

You did not provide an example of what your input file looks like so we can only speculate what solution you need. I'm going to suppose that you need to extract integers from your input text file and print their values.
Here's how I would do it:
Instead of trying to eliminate whitespace characters and colons, I will be searching for digits using a regular expression
Consecutive digits would constitute a number
I would convert this number to an integer form.
And here's how it would look like:
import re
input_filename = "/home/evens/Temporaire/Stack Exchange/StackOverflow/Input_file-39359816.txt"
matcher = re.compile(r"\d+")
with open(input_filename) as input_file:
for line in input_file:
for digits_found in matcher.finditer(line):
number_in_string_form = digits_found.group()
number = int(number_in_string_form)
print(number)
But before you run away with this code, you should continue to learn Python because you don't seem to grasp its basic elements yet.

python - matching string and replacing

I have a file i am trying to replace parts of a line with another word.
it looks like bobkeiser:bob123#bobscarshop.com:0.0.0.0.0:23rh32o3hro2rh2:234212
i need to delete everything but bob123#bobscarshop.com, but i need to match 23rh32o3hro2rh2 with 23rh32o3hro2rh2:poniacvibe , from a different text file and place poniacvibe infront of bob123#bobscarshop.com
so it would look like this bob123#bobscarshop.com:poniacvibe
I've had a hard time trying to go about doing this, but i think i would have to split the bobkeiser:bob123#bobscarshop.com:0.0.0.0.0:23rh32o3hro2rh2:234212 with data.split(":") , but some of the lines have a (:) in a spot that i don't want the line to be split at, if that makes any sense...
if anyone could help i would really appreciate it.

ok, it looks to me like you are using a colon : to separate your strings.
in this case you can use .split(":") to break your strings into their component substrings
eg:
firststring = "bobkeiser:bob123#bobscarshop.com:0.0.0.0.0:23rh32o3hro2rh2:234212"
print(firststring.split(":"))
would give:
['bobkeiser', 'bob123#bobscarshop.com', '0.0.0.0.0', '23rh32o3hro2rh2', '234212']
and assuming your substrings will always be in the same order, and the same number of substrings in the main string you could then do:
firststring = "bobkeiser:bob123#bobscarshop.com:0.0.0.0.0:23rh32o3hro2rh2:234212"
firstdata = firststring.split(":")
secondstring = "23rh32o3hro2rh2:poniacvibe"
seconddata = secondstring.split(":")
if firstdata[3] == seconddata[0]:
outputdata = firstdata
outputdata.insert(1,seconddata[1])
outputstring = ""
for item in outputdata:
if outputstring == "":
outputstring = item
else
outputstring = outputstring + ":" + item
what this does is:
extract the bits of the strings into lists
see if the "23rh32o3hro2rh2" string can be found in the second list
find the corresponding part of the second list
create a list to contain the output data and put the first list into it
insert the "poniacvibe" string before "bob123#bobscarshop.com"
stitch the outputdata list back into a string using the colon as the separator
the reason your strings need to be the same length is because the index is being used to find the relevant strings rather than trying to use some form of string type matching (which gets much more complex)
if you can keep your data in this form it gets much simpler.
to protect against malformed data (lists too short) you can explicitly test for them before you start using len(list) to see how many elements are in it.
or you could let it run and catch the exception, however in this case you could end up with unintended results, as it may try to match the wrong elements from the list.
hope this helps
James
EDIT:
ok so if you are trying to match up a long list of strings from files you would probably want something along the lines of:
firstfile = open("firstfile.txt", mode = "r")
secondfile= open("secondfile.txt",mode = "r")
first_raw_data = firstfile.readlines()
firstfile.close()
second_raw_data = secondfile.readlines()
secondfile.close()
first_data = []
for item in first_raw_data:
first_data.append(item.replace("\n","").split(":"))
second_data = []
for item in second_raw_data:
second_data.append(item.replace("\n","").split(":"))
output_strings = []
for item in first_data:
searchstring = item[3]
for entry in second_data:
if searchstring == entry[0]:
output_data = item
output_string = ""
output_data.insert(1,entry[1])
for data in output_data:
if output_string == "":
output_string = data
else:
output_string = output_string + ":" + data
output_strings.append(output_string)
break
for entry in output_strings:
print(entry)
this should achieve what you're after and as prove of concept will print the resulting list of stings for you.
if you have any questions feel free to ask.
James
Second edit:
to make this output the results into a file change the last two lines to:
outputfile = open("outputfile.txt", mode = "w")
for entry in output_strings:
outputfile.write(entry+"\n")
outputfile.close()