The page that I worked on has invisible hidden option button.
* download sample video in the page(button is hidden by html)
[button1] (<- LINK_TEXT i s 'button1')
[button2]
[button3]
so, I used 'EC.element_to_be_clickable'.
This code is working, but this way can not used if I don't know button's LINK_TEXT. The name of LINK_TEXT is different for each page.
I want to get only video's first link url(ex- button1).
_sDriver = webdriver.Firefox()
_sDriver.get('www.example.com/video')
wait = WebDriverWait(_sDriver, 10)
download_menu = _sDriver.find_element_by_id("download-button")
action = ActionChains(_sDriver)
action.move_to_element(download_menu).perform()
documents_url = wait.until(EC.element_to_be_clickable((By.LINK_TEXT, "button1"))).get_attribute('href')
my code's result is gotten by url of 'button1', but if I don't know 'button1' text, how to get first hidden button's url using python?
thanks for your help.
First of all, by "button" I assume you mean a element in this case.
And, since the button is hidden, element_to_be_clickable would not work, use presence_of_element_located. To get the very first a element, use the "by tag name" locator:
documents_url = wait.until(EC.presence_of_element_located((By.TAG_NAME, "a"))).get_attribute('href')
There could be a better way to locate the element, without seeing the actual HTML of the mentioned "button" elements, it is difficult to tell.
Related
HTML Image
I'm using selenium to get some information from a site, but the links that I need to click on require double clicking. Here's the code (I've included an attachment of the image of the HTML)
PATH = "C:\Program Files (x86)\msedgedriver.exe"
driver = webdriver.Edge(PATH)
action = ActionChains(driver)
from selenium import webdriver
from selenium.webdriver import ActionChains
frame = search_by_XPATH('//[#id="frmMain"]/table/tbody/tr/td[2]/div[2]').get_attribute('id').replace("_Div","_Frame")
WebDriverWait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.ID, frame)))
WebDriverWait(driver, 20).until(EC.frame_to_be_available_and_switch_to_it((By.ID,"fraTree_Frame")))
rows = driver.find_elements(By.XPATH,'//*[#id="ctl00_treChart_RadTreeView"]/ul/li/div/span[2]')
for row in rows:
# row.click()
action.double_click(row).perform()
sleep(1)
I'm accessing different pages to get the links, and although each page has the same content the "id" of the frame changes with each new page I access. So that's why I use the 'get_attribute' function to get the id of the frame of the page.
I'm using action chains right now to perform the double click, but every time I do I get the stale element reference: element is not attached to the page document error. I know it's not an issue with the XPATH I'm using to access the element because I can perform a element.click() function on it just fine and the element receives the click. Nothing changes after the first click except the element gets highlighted. The element's xpath doesn't change and its still on the page. I also tried doing the action.click().perform() on the element but that produces the same error.
I've tried clicking on other parts of the element that could receive the click (the div, the span2,etc) but I always get the error. The 'span2' is the part that holds the text of the link (although its not an 'a' tag so its not really a link in that sense.)
I don't understand why the element would be able to receive the click for the .click() function but then be unable to receive the double click. I'm using the double_click() function on another element previously in my code and that works as expected.
I am using webdriver to screenshot an entire page, but when scrolling down the page, I can't removed the navigation toolbar and so it will also be captured and have a problem when I am combining the images.
I am using chromedriver.
element = driver.find_element_by_css_selector('css.id.class')
driver.execute_script("arguments[0].style='position: none;'", element)
I just want to remove the header while scrolling down the page, but if there are still better capturing the whole page of a website, it will be much appreciated. Thanks.
First, you have syntax error
driver.execute_script("arguments[0].style.position = 'none';", element)
Second, position property has no option "none". Try
style.display = 'none';"
instead
I'm using Selenium with python to make a spider.
A part of the web page is like this:
text - <span class="sr-keyword">name</span> text
I need to find the href and click.
I've tried as below:
target = driver.find_element_by_class_name('_j_search_link')
target.click()
target is not None but it doesn't seem that it could be clicked because after target.click(), nothing happened.
Also, I've read this question: Click on hyperlink using Selenium Webdriver
But it can't help me because in my case, there is a <span class>, not just a simple text Google.
You can look for an element with class _j_search_link that contains text Wat Chedi Luang
driver.find_element_by_xpath('//a[#class="_j_search_link" and contains(., "Wat Chedi Luang")]')
driver.find_elements_by_partial_link_text("Wat Chedi Luang").click()
I think you didn't find right element. Use CSS or Xpath to target this element then click it, like:
//a[#class='_j_search_link']
or
//a[#class='_j_search_link']/span[#class='sr-keyword']
I've never studied HTML seriously, so probably what I'm going to say is not right.
While I was writing my selenium code, I noticed that some buttons on some webpages does not redirect to other pages, but they change the structure of the the first one. From what I've understood, this happens because there's some JavaScript code that modifies it.
So, when I wanna get some data which is not present on the first page loading, I just have to click the right sequence of button to obtain it, rigth?
The page I wanted to load is https://watch.nba.com/, and what I want to get is the match list of a given day. The fastest path to get it is to open the calendary:
calendary = driver.find_element_by_class_name("calendar-btn")
calendary.click()
and click the selected day:
page = calendary.find_element_by_xpath("//*[contains(text(), '" + time.strftime("%d") + "')]")
page.click()
running this code, I get this error:
selenium.common.exceptions.ElementNotVisibleException
I read somewhere that the problem is that the page is not correctly loaded, or the element is not visible/clickable, so I tried with this:
wait = WebDriverWait(driver, 10)
page = wait.until(EC.visibility_of_element_located((By.XPATH, "//*[contains(text(), '" + time.stfrtime("%d") + "')]")))
page.click()
But this time I get this error:
selenium.common.exceptions.TimeoutException
Can you help me to solve at least one of these two problems?
The reason you are getting such behavior is because this page is loaded with iFrames (I can see 15 on the main page) once you click the calendar button, you will need to switch your context to either be on the defaultContext or a specific iframe where the calendar resides. There is tons of code outthere that shows you how to switch into and out of iframe. Hope this helps.
I am trying to click a small button, which has no "ID" or "Name", on a website. The only unique identifier is onclick, which is as follows:
onclick="submitForm('DefaultFormName',1,{'param1':'HXCTIMECARDACTIVITIESPAGEXgm7J5oT','serverValidate':'1uCdqvhJe','param2':'',event:'details|1'});return false;"
However, another button on the page has the following onclick:
onclick="submitForm('DefaultFormName',1,{'param1':'HXCTIMECARDACTIVITIESPAGEXgm7J5oT','serverValidate':'1uCdqvhJe','param2':'',event:'details|2'});return false;"
The only difference is a 1 vs. a 2 in the middle of the code. I tried to use a "find_element_by_css_selector" with the following code but it didn't work:
driver.find_element_by_css_selector(".x1p[onclick*='details|1']").click()
Another option would be selecting the preceding element, with the following code:
precedingbutton = driver.find_element_by_name('B22_1_6')
And then sending tab and then enter. However, after I send Tab, I don't know of a way to send Enter without assigning the Send_Keys command back to the preceding box, which deselects the button I want.
Let me know if you can help!
If you can locate the parent, you can locate the child, either with xpath or the nth-child css selector, relative to it.
Edit in response to comments:
Assuming by "2 elements away" you mean it is a sibling preceding the target, try something like td[name="B22_1_6"] + td + td. This is the sibling selector.
You can do it easily by
driver.find_element(By.XPATH, 'your xpath').click()
For finding the xpath , just inspect the button with firebug, and in html tab right click on selected element and click on Copy XPath.
Hope it will help you.