I have some hex strings (splited_colors) which I want to convert them into the colors. The splited_colors is a list with length of 221228 which its first row is like splited_colors[1] = [['ab0232'],['0013aa'],['ac0102']]. Also, I have another strings like '000000'. Some of rows are converted but the others not. I checked that, all the hex strings are the same and I don't have any unusual hex string. What is this error refers to ?
RGB_colors_1 = []
for j in range (len(splited_colors)):
RGB_1 = tuple(int(splited_colors[j][0][k:k+2], 16) for k in (0, 2, 4))
RGB_colors_1.append (RGB_1)
Check out this link to see if it helps you with your question: ValueError: invalid literal for int() with base 16: ''. This exception can be called if you have an empty string or any letter after f in the alphabet.
To find what string is causing the problem, I would add something like print(j, RGB_1) in your loop. This allows you to find the index of the hex that is causing the problem.
I'm attempting to create a bar chart using a csv file and I keep getting this message.
My data is almost all integers.
for item in text_list :
pieces_list = item.strip().split(',')
print(pieces_list)
Month_list.append(pieces_list[0])
Total_list.append(int(pieces_list[1]))
The string '"1"' is three separate characters: { ", 1, " }, and " is not valid in the context of evaluating an integer. This is no doubt caused by the CSV allowing quotes around a field:
"has quotes", does not have quotes, "1"
You need to strip off those double-quotes from the beginning and end of the string first (if they're there). For example:
>>> withq = '"42"'
>>> int(withq)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '"42"'
>>> int(withq.strip('"'))
42
Just keep in mind that this will strip all " characters from the start and end of a string, so """"""""42""" will still come through as 42. And replace() will replace quotes anywhere in the string. To be absolutely safe, a better option would probably be a function to do the grunt work for you:
# Get integer from a string CSV field.
# If first and last characters are both '"', convert the inner bit.
# Otherwise, convert the whole thing.
# May throw if bit being converted in not valid integer.
def csv_int(field):
if len(field) >= 2 and field[0] == '"' and field[-1] == '"':
return int(field[1:-1])
return int(field)
Looks like I get the same error when doing
print(int('"1"'))
Notice the " surrounding the digit 1.
ValueError: invalid literal for int() with base 10: '"1"'
So I suggest you use replace() on this string or something else to remove this occurrence.
print(int('"1"'.replace('"','')))
output
1
What is the best solution to convert a '"1"' or "'1'" (string) into 1 (int) using python?
int() method will return this value error message
ValueError: invalid literal for int() with base 10: "'1'"
if you try int('"1"') or int("'1'")
The solution that I used is as follow:
tmp = '"1"'
tmp = tmp.replace('"', "")
tmp
# output: 1
The flaw in this "solution" is that the inner quotation (single/double) matters.
I would use
tmp = tmp.strip("'\"")
This removes both ' and " from the start/end of tmp.
nextt[0:1] = "*2"
rds = int(nextt[0:1].replace("*",""))
And there is problem, it says:ValueError: invalid literal for int() with base 10: ''
I just need to delete "*" from string and convert it to int.
You are slicing just one character:
>>> '*2foo'[0:1]
'*'
Replacing the * gives you an empty string. Perhaps you wanted to slice two characters?
>>> '*2foo'[:2]
'*2'
If you are slicing anyway, just pick the digit character without the *:
int(nextt[1])
int('*2'.replace('*', ''))
'*2'.replace('*', '') this replaces * with empty string and results in '2'
Now you cast it to int.
I got this error from my code:
ValueError: invalid literal for int() with base 10: ''.
What does it mean? Why does it occur, and how can I fix it?
The error message means that the string provided to int could not be parsed as an integer. The part at the end, after the :, shows the string that was provided.
In the case described in the question, the input was an empty string, written as ''.
Here is another example - a string that represents a floating-point value cannot be converted directly with int:
>>> int('55063.000000')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '55063.000000'
Instead, convert to float first:
>>> int(float('55063.000000'))
55063
See：https://www.geeksforgeeks.org/python-int-function/
The following work fine in Python:
>>> int('5') # passing the string representation of an integer to `int`
5
>>> float('5.0') # passing the string representation of a float to `float`
5.0
>>> float('5') # passing the string representation of an integer to `float`
5.0
>>> int(5.0) # passing a float to `int`
5
>>> float(5) # passing an integer to `float`
5.0
However, passing the string representation of a float, or any other string that does not represent an integer (including, for example, an empty string like '') will cause a ValueError:
>>> int('')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: ''
>>> int('5.0')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '5.0'
To convert the string representation of a floating-point number to integer, it will work to convert to a float first, then to an integer (as explained in #katyhuff's comment on the question):
>>> int(float('5.0'))
5
int cannot convert an empty string to an integer. If the input string could be empty, consider either checking for this case:
if data:
as_int = int(data)
else:
# do something else
or using exception handling:
try:
as_int = int(data)
except ValueError:
# do something else
Python will convert the number to a float. Simply calling float first then converting that to an int will work:
output = int(float(input))
This error occurs when trying to convert an empty string to an integer:
>>> int(5)
5
>>> int('5')
5
>>> int('')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: ''
The reason is that you are getting an empty string or a string as an argument into int. Check if it is empty or it contains alpha characters. If it contains characters, then simply ignore that part.
Given floatInString = '5.0', that value can be converted to int like so:
floatInInt = int(float(floatInString))
You've got a problem with this line:
while file_to_read != " ":
This does not find an empty string. It finds a string consisting of one space. Presumably this is not what you are looking for.
Listen to everyone else's advice. This is not very idiomatic python code, and would be much clearer if you iterate over the file directly, but I think this problem is worth noting as well.
My simple workaround to this problem was wrap my code in an if statement, taking advantage of the fact that an empty string is not "truthy":
Given either of these two inputs:
input_string = "" # works with an empty string
input_string = "25" # or a number inside a string
You can safely handle a blank string using this check:
if input_string:
number = int(input_string)
else:
number = None # (or number = 0 if you prefer)
print(number)
I recently came across a case where none of these answers worked. I encountered CSV data where there were null bytes mixed in with the data, and those null bytes did not get stripped. So, my numeric string, after stripping, consisted of bytes like this:
\x00\x31\x00\x0d\x00
To counter this, I did:
countStr = fields[3].replace('\x00', '').strip()
count = int(countStr)
...where fields is a list of csv values resulting from splitting the line.
This could also happen when you have to map space separated integers to a list but you enter the integers line by line using the .input().
Like for example I was solving this problem on HackerRank Bon-Appetit, and the got the following error while compiling
So instead of giving input to the program line by line try to map the space separated integers into a list using the map() method.
your answer is throwing errors because of this line
readings = int(readings)
Here you are trying to convert a string into int type which is not base-10. you can convert a string into int only if it is base-10 otherwise it will throw ValueError, stating invalid literal for int() with base 10.
This seems like readings is sometimes an empty string and obviously an error crops up.
You can add an extra check to your while loop before the int(readings) command like:
while readings != 0 or readings != '':
readings = int(readings)
I am creating a program that reads a
file and if the first line of the file
is not blank, it reads the next four
lines. Calculations are performed on
those lines and then the next line is
read.
Something like this should work:
for line in infile:
next_lines = []
if line.strip():
for i in xrange(4):
try:
next_lines.append(infile.next())
except StopIteration:
break
# Do your calculation with "4 lines" here
Another answer in case all of the above solutions are not working for you.
My original error was similar to OP: ValueError: invalid literal for int() with base 10: '52,002'
I then tried the accepted answer and got this error: ValueError: could not convert string to float: '52,002' --this was when I tried the int(float(variable_name))
My solution is to convert the string to a float and leave it there. I just needed to check to see if the string was a numeric value so I can handle it correctly.
try:
float(variable_name)
except ValueError:
print("The value you entered was not a number, please enter a different number")