Python pool code not running - python

I'm writing a Windows service with multiproccesing and I'm running into problems with the method that's called in the pool.
Right now I'm able to install the service and run it, it outputs The service started running... to the log file but nothing else.
Looking at the process explorer (see screenshot below), I see that the processes are being created and finishing constantly, but the code within the TestMethod isn't being run, and the service isn't exiting the pool because nothing else is being written to the file.
I'm not able to stop the service since it's stuck in the pool and doesn't reach the check for the stop event.
Why is the code within the TestMethod not running at all?
Service code:
import servicemanager
import win32event
import win32service
import win32serviceutil
import multiprocessing
class TestService(win32serviceutil.ServiceFramework):
_svc_name_ = "TestService"
_svc_display_name_ = "Test Service"
def testMethod(self, testVar):
with open('C:\\Test.log', 'a') as f:
f.write('The method is running: ' + testVar)
f.close()
def __init__(self, args):
win32serviceutil.ServiceFramework.__init__(self, args)
self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
socket.setdefaulttimeout(60)
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
win32event.SetEvent(self.hWaitStop)
def SvcDoRun(self):
with open('C:\\Test.log', 'a') as f:
f.write('The service started running...\n')
f.close()
rc = None
p = multiprocessing.Pool(5)
p.map(TestService.testMethod, range(1,6))
with open('C:\\Test.log', 'a') as f:
f.write('Finished method...\n')
f.close()
while rc != win32event.WAIT_OBJECT_0:
with open('C:\\Test.log', 'a') as f:
f.write('The service is running...\n')
f.close()
rc = win32event.WaitForSingleObject(self.hWaitStop, 5000)
with open('C:\\Test.log', 'a') as f:
f.write('StreamCapture service stopped.\n')
f.close()
if __name__ == '__main__':
if len(sys.argv) == 1:
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(TestService)
servicemanager.StartServiceCtrlDispatcher()
else:
win32serviceutil.HandleCommandLine(TestService)

There are two problems in your code:
you point map to TestService.testMethod, which is an "unbound function" that lives in the Class namespace, but testMethod is defined like a class method. You either need to call it with self.testMethod or you remove the self from the function definition
you try to add an int to a string, use f.write('The method is running: {}'.format(testVar)) instead
Your stripped down program, corrected would look like this:
import multiprocessing
class TestService:
def testMethod(self, testVar):
with open('C:\\Test.log', 'a') as f:
f.write('The method is running: {}'.format(testVar))
f.close()
def SvcDoRun(self):
p = multiprocessing.Pool(5)
p.map(self.testMethod, range(1,6))
if __name__ == "__main__":
d = TestService()
d.SvcDoRun()
P.S. try to post a minimal code example the next time: Strip down the code to the bare minimum which generates the error. The code fragment I posted would have been enough to explain the problem. This way it is easier to understand for readers and you get an answer faster.

The problem was caused by a known issue with pyinstaller and onefile executables on Windows.
Adding the following try block after my imports fixed it for me:
try:
# Python 3.4+
if sys.platform.startswith('win'):
import multiprocessing.popen_spawn_win32 as forking
else:
import multiprocessing.popen_fork as forking
except ImportError:
import multiprocessing.forking as forking
See https://github.com/pyinstaller/pyinstaller/wiki/Recipe-Multiprocessing for more details

Related

How to make my code stopable? (Not killing/interrupting)

I'm asking this question in a more broad spectrum because I'm not facing this specific issue right now, but I'm wondering how to do it in the future.
If I have a long running python script, that is supposed to do something all the time (could be a infine loop, if that helps). The code is started by running python main.py command on a terminal.
The code doesn't have an ending, so there will be no sys.exit().
I don't want to use KeyboardInterrupt and I don't want to kill the task. Because those options are abrupt, and you can't predict precisely at what point you are stoping the code.
Is there a way to 'softly' terminate the code when I eventually decide to fo it? For example using another command, preparing a class or running another script?
What would be the best practice for this?
PS.: Please, bear in mind that I'm a novice coder.
EDIT:
I'm adding some generic code, in order to make my question clearer.
import time,csv
import GenericAPI
class GenericDataCollector:
def __init__(self):
self.generic_api = GenericAPI()
def collect_data(self):
while True: #Maybe this could be a var that is changed from outside of the class?
data = self.generic_api.fetch_data() #Returns a JSON with some data
self.write_on_csv(data)
time.sleep(1)
def write_on_csv(self, data):
with open('file.csv','wt') as f:
writer = csv.writer(f)
writer.writerow(data)
def run():
obj = GenericDataCollector()
obj.collect_data()
if __name__ == "__main__":
run()
In this particular case, the class is collecting data from some generic API (that comes in JSON) and writing it in a csv file, in a infinite loop. How could I code a way (method?) to stop it (when called uppon, so unexpected), without abruptly interrupting (Ctrl+C or killing task).
I would recommend use the signal module. This allows you to handle signal interrupts (SIGINT) and clean up the program before your exit. Take the following code for example:
import signal
running = True
def handle(a, b):
global running
running = False
# catch the SIGINT signal and call handle() when the process
# receives it
signal.signal(signal.SIGINT, handle)
# your code here
while running:
pass
You can still exit with a Ctrl+C, but what you put in the while loop will not be cut off half way.
Based on #Calder White, how about this (not tested):
import signal
import time,csv
import GenericAPI
class GenericDataCollector:
def __init__(self):
self.generic_api = GenericAPI()
self.cont = True
def collect_data(self):
while self.cont:
signal.signal(signal.SIGINT, self.handle)
data = self.generic_api.fetch_data() #Returns a JSON with some data
self.write_on_csv(data)
time.sleep(1)
def handle(self):
self.cont = False
def write_on_csv(self, data):
with open('file.csv','wt') as f:
writer = csv.writer(f)
writer.writerow(data)
def run():
obj = GenericDataCollector()
obj.collect_data()
if __name__ == "__main__":
run()

Python program as Windows Service

below is my code that I am trying to turn into a windows service. You'll see test.py as the call it makes and all this is a short script that writes into a log file (as a test).
The code is there to make it a windows service and it does that fine, but when I run it nothing writes into the log file. Help greatly appreciated. Below is the code:
import win32service
import win32serviceutil
import win32api
import win32con
import win32event
import win32evtlogutil
import os, sys, string, time
class aservice(win32serviceutil.ServiceFramework):
_svc_name_ = "MyServiceShortName"
_svc_display_name_ = "A python test"
_svc_description_ = "Writing to a log"
def __init__(self, args):
win32serviceutil.ServiceFramework.__init__(self, args)
self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
win32event.SetEvent(self.hWaitStop)
def SvcDoRun(self):
import servicemanager
servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,servicemanager.PYS_SERVICE_STARTED,(self._svc_name_, ''))
self.timeout = 1000 #1 seconds
# This is how long the service will wait to run / refresh itself (see script below)
while 1:
# Wait for service stop signal, if I timeout, loop again
rc = win32event.WaitForSingleObject(self.hWaitStop, self.timeout)
# Check to see if self.hWaitStop happened
if rc == win32event.WAIT_OBJECT_0:
# Stop signal encountered
servicemanager.LogInfoMsg("SomeShortNameVersion - STOPPED!") #For Event Log
break
else:
#what to run
try:
file_path = "test.py"
execfile(file_path)
except:
pass
#end of what to run
def ctrlHandler(ctrlType):
return True
if __name__ == '__main__':
win32api.SetConsoleCtrlHandler(ctrlHandler, True)
win32serviceutil.HandleCommandLine(aservice)
Edit: Thought for the sake of it I'd include my test.py file's code, it has unnecessary imports but will get the job done if you run it alone.
import win32service
import win32serviceutil
import win32api
import win32con
import win32event
import win32evtlogutil
import os
logfile = open("log.txt", "a") #open file to log restart timestamp
logfile.write("\nthat's good!!!!")
logfile.close()
Okay so I figured it out and would like to come back and post in case anyone else is dealing with this, all though this was a tad unique.
You have to specify your file path if you are within a windows service, duh... but it wasn't done and I pulled my hair out for no reason.
file_path = "test.py"
should have been
file_path = r"c:\users\...\test.py"
Be careful when using '\' for windows file paths. They must be escaped like '\\' or the string must be declared as raw string ('r'). Using the unix like slash '/' separators works also but may look odd for windows users.

Propagate system call interruptions in threads

I'm running two python threads (import threading). Both of them are blocked on a open() call; in fact they try to open named pipes in order to write in them, so it's a normal behaviour to block until somebody try to read from the named pipe.
In short, it looks like:
import threading
def f():
open('pipe2', 'r')
if __name__ == '__main__':
t = threading.Thread(target=f)
t.start()
open('pipe1', 'r')
When I type a ^C, the open() in the main thread is interrupted (raises IOError with errno == 4).
My problem is: the t threads still waits, and I'd like to propagate the interruption behaviour, in order to make it raise IOError too.
I found this in python docs:
"
... only the main thread can set a new signal handler, and the main thread will be the only one to receive signals (this is enforced by the Python signal module, even if the underlying thread implementation supports sending signals to individual threads). This means that signals can’t be used as a means of inter-thread communication. Use locks instead.
"
Maybe you should also check these docs:
exceptions.KeyboardInterrupt
library/signal.html
One other idea is to use select to read the pipe asynchronously in the threads. This works in Linux, not sure about Windows (it's not the cleanest, nor the best implementation):
#!/usr/bin/python
import threading
import os
import select
def f():
f = os.fdopen(os.open('pipe2', os.O_RDONLY|os.O_NONBLOCK))
finput = [ f ]
foutput = []
# here the pipe is scanned and whatever gets in will be printed out
# ...as long as 'getout' is False
while finput and not getout:
fread, fwrite, fexcep = select.select(finput, foutput, finput)
for q in fread:
if q in finput:
s = q.read()
if len(s) > 0:
print s
if __name__ == '__main__':
getout = False
t = threading.Thread(target=f)
t.start()
try:
open('pipe1', 'r')
except:
getout = True

Sending ^C to Python subprocess objects on Windows

I have a test harness (written in Python) that needs to shut down the program under test (written in C) by sending it ^C. On Unix,
proc.send_signal(signal.SIGINT)
works perfectly. On Windows, that throws an error ("signal 2 is not supported" or something like that). I am using Python 2.7 for Windows, so I have the impression that I should be able to do instead
proc.send_signal(signal.CTRL_C_EVENT)
but this doesn't do anything at all. What do I have to do? This is the code that creates the subprocess:
# Windows needs an extra argument passed to subprocess.Popen,
# but the constant isn't defined on Unix.
try: kwargs['creationflags'] = subprocess.CREATE_NEW_PROCESS_GROUP
except AttributeError: pass
proc = subprocess.Popen(argv,
stdin=open(os.path.devnull, "r"),
stdout=subprocess.PIPE,
stderr=subprocess.PIPE,
**kwargs)
There is a solution by using a wrapper (as described in the link Vinay provided) which is started in a new console window with the Windows start command.
Code of the wrapper:
#wrapper.py
import subprocess, time, signal, sys, os
def signal_handler(signal, frame):
time.sleep(1)
print 'Ctrl+C received in wrapper.py'
signal.signal(signal.SIGINT, signal_handler)
print "wrapper.py started"
subprocess.Popen("python demo.py")
time.sleep(3) #Replace with your IPC code here, which waits on a fire CTRL-C request
os.kill(signal.CTRL_C_EVENT, 0)
Code of the program catching CTRL-C:
#demo.py
import signal, sys, time
def signal_handler(signal, frame):
print 'Ctrl+C received in demo.py'
time.sleep(1)
sys.exit(0)
signal.signal(signal.SIGINT, signal_handler)
print 'demo.py started'
#signal.pause() # does not work under Windows
while(True):
time.sleep(1)
Launch the wrapper like e.g.:
PythonPrompt> import subprocess
PythonPrompt> subprocess.Popen("start python wrapper.py", shell=True)
You need to add some IPC code which allows you to control the wrapper firing the os.kill(signal.CTRL_C_EVENT, 0) command. I used sockets for this purpose in my application.
Explanation:
Preinformation
send_signal(CTRL_C_EVENT) does not work because CTRL_C_EVENT is only for os.kill. [REF1]
os.kill(CTRL_C_EVENT) sends the signal to all processes running in the current cmd window [REF2]
Popen(..., creationflags=CREATE_NEW_PROCESS_GROUP) does not work because CTRL_C_EVENT is ignored for process groups. [REF2]
This is a bug in the python documentation [REF3]
Implemented solution
Let your program run in a different cmd window with the Windows shell command start.
Add a CTRL-C request wrapper between your control application and the application which should get the CTRL-C signal. The wrapper will run in the same cmd window as the application which should get the CTRL-C signal.
The wrapper will shutdown itself and the program which should get the CTRL-C signal by sending all processes in the cmd window the CTRL_C_EVENT.
The control program should be able to request the wrapper to send the CTRL-C signal. This might be implemnted trough IPC means, e.g. sockets.
Helpful posts were:
I had to remove the http in front of the links because I'm a new user and are not allowed to post more than two links.
http://social.msdn.microsoft.com/Forums/en-US/windowsgeneraldevelopmentissues/thread/dc9586ab-1ee8-41aa-a775-cf4828ac1239/#6589714f-12a7-447e-b214-27372f31ca11
Can I send a ctrl-C (SIGINT) to an application on Windows?
Sending SIGINT to a subprocess of python
http://bugs.python.org/issue9524
http://ss64.com/nt/start.html
http://objectmix.com/python/387639-sending-cntrl-c.html#post1443948
Update: IPC based CTRL-C Wrapper
Here you can find a selfwritten python module providing a CTRL-C wrapping including a socket based IPC.
The syntax is quite similiar to the subprocess module.
Usage:
>>> import winctrlc
>>> p1 = winctrlc.Popen("python demo.py")
>>> p2 = winctrlc.Popen("python demo.py")
>>> p3 = winctrlc.Popen("python demo.py")
>>> p2.send_ctrl_c()
>>> p1.send_ctrl_c()
>>> p3.send_ctrl_c()
Code
import socket
import subprocess
import time
import random
import signal, os, sys
class Popen:
_port = random.randint(10000, 50000)
_connection = ''
def _start_ctrl_c_wrapper(self, cmd):
cmd_str = "start \"\" python winctrlc.py "+"\""+cmd+"\""+" "+str(self._port)
subprocess.Popen(cmd_str, shell=True)
def _create_connection(self):
self._connection = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
self._connection.connect(('localhost', self._port))
def send_ctrl_c(self):
self._connection.send(Wrapper.TERMINATION_REQ)
self._connection.close()
def __init__(self, cmd):
self._start_ctrl_c_wrapper(cmd)
self._create_connection()
class Wrapper:
TERMINATION_REQ = "Terminate with CTRL-C"
def _create_connection(self, port):
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind(('localhost', port))
s.listen(1)
conn, addr = s.accept()
return conn
def _wait_on_ctrl_c_request(self, conn):
while True:
data = conn.recv(1024)
if data == self.TERMINATION_REQ:
ctrl_c_received = True
break
else:
ctrl_c_received = False
return ctrl_c_received
def _cleanup_and_fire_ctrl_c(self, conn):
conn.close()
os.kill(signal.CTRL_C_EVENT, 0)
def _signal_handler(self, signal, frame):
time.sleep(1)
sys.exit(0)
def __init__(self, cmd, port):
signal.signal(signal.SIGINT, self._signal_handler)
subprocess.Popen(cmd)
conn = self._create_connection(port)
ctrl_c_req_received = self._wait_on_ctrl_c_request(conn)
if ctrl_c_req_received:
self._cleanup_and_fire_ctrl_c(conn)
else:
sys.exit(0)
if __name__ == "__main__":
command_string = sys.argv[1]
port_no = int(sys.argv[2])
Wrapper(command_string, port_no)
New answer:
When you create the process, use the flag CREATE_NEW_PROCESS_GROUP. And then you can send CTRL_BREAK to the child process. The default behavior is the same as CTRL_C, except that it won't affect the calling process.
Old answer:
My solution also involves a wrapper script, but it does not need IPC, so it is far simpler to use.
The wrapper script first detaches itself from any existing console, then attach to the target console, then files the Ctrl-C event.
import ctypes
import sys
kernel = ctypes.windll.kernel32
pid = int(sys.argv[1])
kernel.FreeConsole()
kernel.AttachConsole(pid)
kernel.SetConsoleCtrlHandler(None, 1)
kernel.GenerateConsoleCtrlEvent(0, 0)
sys.exit(0)
The initial process must be launched in a separate console so that the Ctrl-C event will not leak. Example
p = subprocess.Popen(['some_command'], creationflags=subprocess.CREATE_NEW_CONSOLE)
# Do something else
subprocess.check_call([sys.executable, 'ctrl_c.py', str(p.pid)]) # Send Ctrl-C
where I named the wrapper script as ctrl_c.py.
Try calling the GenerateConsoleCtrlEvent function using ctypes. As you are creating a new process group, the process group ID should be the same as the pid. So, something like
import ctypes
ctypes.windll.kernel32.GenerateConsoleCtrlEvent(0, proc.pid) # 0 => Ctrl-C
should work.
Update: You're right, I missed that part of the detail. Here's a post which suggests a possible solution, though it's a bit kludgy. More details are in this answer.
Here is a fully working example which doesn't need any modification in the target script.
This overrides the sitecustomize module so it might no be suitable for every scenario. However, in this case you could use a *.pth file in site-packages to execute code at the subprocess startup (see https://nedbatchelder.com/blog/201001/running_code_at_python_startup.html).
Edit This works only out of the box for subprocesses in Python. Other processes have to manually call SetConsoleCtrlHandler(NULL, FALSE).
main.py
import os
import signal
import subprocess
import sys
import time
def main():
env = os.environ.copy()
env['PYTHONPATH'] = '%s%s%s' % ('custom-site', os.pathsep,
env.get('PYTHONPATH', ''))
proc = subprocess.Popen(
[sys.executable, 'sub.py'],
env=env,
creationflags=subprocess.CREATE_NEW_PROCESS_GROUP,
)
time.sleep(1)
proc.send_signal(signal.CTRL_C_EVENT)
proc.wait()
if __name__ == '__main__':
main()
custom-site\sitecustomize.py
import ctypes
import sys
kernel32 = ctypes.WinDLL('kernel32', use_last_error=True)
if not kernel32.SetConsoleCtrlHandler(None, False):
print('SetConsoleCtrlHandler Error: ', ctypes.get_last_error(),
file=sys.stderr)
sub.py
import atexit
import time
def cleanup():
print ('cleanup')
atexit.register(cleanup)
while True:
time.sleep(1)
I have a single file solution with the following advantages:
- No external libraries. (Other than ctypes)
- Doesn't require the process to be opened in a specific way.
The solution is adapted from this stack overflow post, but I think it's much more elegant in python.
import os
import signal
import subprocess
import sys
import time
# Terminates a Windows console app sending Ctrl-C
def terminateConsole(processId: int, timeout: int = None) -> bool:
currentFilePath = os.path.abspath(__file__)
# Call the below code in a separate process. This is necessary due to the FreeConsole call.
try:
code = subprocess.call('{} {} {}'.format(sys.executable, currentFilePath, processId), timeout=timeout)
if code == 0: return True
except subprocess.TimeoutExpired:
pass
# Backup plan
subprocess.call('taskkill /F /PID {}'.format(processId))
if __name__ == '__main__':
pid = int(sys.argv[1])
import ctypes
kernel = ctypes.windll.kernel32
r = kernel.FreeConsole()
if r == 0: exit(-1)
r = kernel.AttachConsole(pid)
if r == 0: exit(-1)
r = kernel.SetConsoleCtrlHandler(None, True)
if r == 0: exit(-1)
r = kernel.GenerateConsoleCtrlEvent(0, 0)
if r == 0: exit(-1)
r = kernel.FreeConsole()
if r == 0: exit(-1)
# use tasklist to wait while the process is still alive.
while True:
time.sleep(1)
# We pass in stdin as PIPE because there currently is no Console, and stdin is currently invalid.
searchOutput: bytes = subprocess.check_output('tasklist /FI "PID eq {}"'.format(pid), stdin=subprocess.PIPE)
if str(pid) not in searchOutput.decode(): break;
# The following two commands are not needed since we're about to close this script.
# You can leave them here if you want to do more console operations.
r = kernel.SetConsoleCtrlHandler(None, False)
if r == 0: exit(-1)
r = kernel.AllocConsole()
if r == 0: exit(-1)
exit(0)
For those interested in a "quick fix", I've made a console-ctrl package based on Siyuan Ren's answer to make it even easier to use.
Simply run pip install console-ctrl, and in your code:
import console_ctrl
import subprocess
# Start some command IN A SEPARATE CONSOLE
p = subprocess.Popen(['some_command'], creationflags=subprocess.CREATE_NEW_CONSOLE)
# ...
# Stop the target process
console_ctrl.send_ctrl_c(p.pid)
I have been trying this but for some reason ctrl+break works, and ctrl+c does not. So using os.kill(signal.CTRL_C_EVENT, 0) fails, but doing os.kill(signal.CTRL_C_EVENT, 1) works. I am told this has something to do with the create process owner being the only one that can pass a ctrl c? Does that make sense?
To clarify, while running fio manually in a command window it appears to be running as expected. Using the CTRL + BREAK breaks without storing the log as expected and CTRL + C finishes writing to the file also as expected. The problem appears to be in the signal for the CTRL_C_EVENT.
It almost appears to be a bug in Python but may rather be a bug in Windows. Also one other thing, I had a cygwin version running and sending the ctrl+c in python there worked as well, but then again we aren't really running native windows there.
example:
import subprocess, time, signal, sys, os
command = '"C:\\Program Files\\fio\\fio.exe" --rw=randrw --bs=1M --numjobs=8 --iodepth=64 --direct=1 ' \
'--sync=0 --ioengine=windowsaio --name=test --loops=10000 ' \
'--size=99901800 --rwmixwrite=100 --do_verify=0 --filename=I\\:\\test ' \
'--thread --output=C:\\output.txt'
def signal_handler(signal, frame):
time.sleep(1)
print 'Ctrl+C received in wrapper.py'
signal.signal(signal.SIGINT, signal_handler)
print 'command Starting'
subprocess.Popen(command)
print 'command started'
time.sleep(15)
print 'Timeout Completed'
os.kill(signal.CTRL_C_EVENT, 0)
(This was supposed to be a comment under Siyuan Ren's answer but I don't have enough rep so here's a slightly longer version.)
If you don't want to create any helper scripts you can use:
p = subprocess.Popen(['some_command'], creationflags=subprocess.CREATE_NEW_CONSOLE)
# Do something else
subprocess.run([
sys.executable,
"-c",
"import ctypes, sys;"
"kernel = ctypes.windll.kernel32;"
"pid = int(sys.argv[1]);"
"kernel.FreeConsole();"
"kernel.AttachConsole(pid);"
"kernel.SetConsoleCtrlHandler(None, 1);"
"kernel.GenerateConsoleCtrlEvent(0, 0);"
"sys.exit(0)",
str(p.pid)
]) # Send Ctrl-C
But it won't work if you use PyInstaller - sys.executable points to your executable, not the Python interpreter. To solve that issue I've created a tiny utility for Windows: https://github.com/anadius/ctrlc
Now you can send the Ctrl+C event with:
subprocess.run(["ctrlc", str(p.pid)])

How to attach debugger to a python subproccess?

I need to debug a child process spawned by multiprocessing.Process(). The pdb degugger seems to be unaware of forking and unable to attach to already running processes.
Are there any smarter python debuggers which can be attached to a subprocess?
I've been searching for a simple to solution for this problem and came up with this:
import sys
import pdb
class ForkedPdb(pdb.Pdb):
"""A Pdb subclass that may be used
from a forked multiprocessing child
"""
def interaction(self, *args, **kwargs):
_stdin = sys.stdin
try:
sys.stdin = open('/dev/stdin')
pdb.Pdb.interaction(self, *args, **kwargs)
finally:
sys.stdin = _stdin
Use it the same way you might use the classic Pdb:
ForkedPdb().set_trace()
Winpdb is pretty much the definition of a smarter Python debugger. It explicitly supports going down a fork, not sure it works nicely with multiprocessing.Process() but it's worth a try.
For a list of candidates to check for support of your use case, see the list of Python Debuggers in the wiki.
This is an elaboration of Romuald's answer which restores the original stdin using its file descriptor. This keeps readline working inside the debugger. Besides, pdb special management of KeyboardInterrupt is disabled, in order it not to interfere with multiprocessing sigint handler.
class ForkablePdb(pdb.Pdb):
_original_stdin_fd = sys.stdin.fileno()
_original_stdin = None
def __init__(self):
pdb.Pdb.__init__(self, nosigint=True)
def _cmdloop(self):
current_stdin = sys.stdin
try:
if not self._original_stdin:
self._original_stdin = os.fdopen(self._original_stdin_fd)
sys.stdin = self._original_stdin
self.cmdloop()
finally:
sys.stdin = current_stdin
Building upon #memplex idea, I had to modify it to get it to work with joblib by setting the sys.stdin in the constructor as well as passing it directly along via joblib.
import os
import pdb
import signal
import sys
import joblib
_original_stdin_fd = None
class ForkablePdb(pdb.Pdb):
_original_stdin = None
_original_pid = os.getpid()
def __init__(self):
pdb.Pdb.__init__(self)
if self._original_pid != os.getpid():
if _original_stdin_fd is None:
raise Exception("Must set ForkablePdb._original_stdin_fd to stdin fileno")
self.current_stdin = sys.stdin
if not self._original_stdin:
self._original_stdin = os.fdopen(_original_stdin_fd)
sys.stdin = self._original_stdin
def _cmdloop(self):
try:
self.cmdloop()
finally:
sys.stdin = self.current_stdin
def handle_pdb(sig, frame):
ForkablePdb().set_trace(frame)
def test(i, fileno):
global _original_stdin_fd
_original_stdin_fd = fileno
while True:
pass
if __name__ == '__main__':
print "PID: %d" % os.getpid()
signal.signal(signal.SIGUSR2, handle_pdb)
ForkablePdb().set_trace()
fileno = sys.stdin.fileno()
joblib.Parallel(n_jobs=2)(joblib.delayed(test)(i, fileno) for i in range(10))
remote-pdb can be used to debug sub-processes. After installation, put the following lines in the code you need to debug:
import remote_pdb
remote_pdb.set_trace()
remote-pdb will print a port number which will accept a telnet connection for debugging that specific process. There are some caveats around worker launch order, where stdout goes when using various frontends, etc. To ensure a specific port is used (must be free and accessible to the current user), use the following instead:
from remote_pdb import RemotePdb
RemotePdb('127.0.0.1', 4444).set_trace()
remote-pdb may also be launched via the breakpoint() command in Python 3.7.
Just use PuDB that gives you an awesome TUI (GUI on terminal) and supports multiprocessing as follow:
from pudb import forked; forked.set_trace()
An idea I had was to create "dummy" classes to fake the implementation of the methods you are using from multiprocessing:
from multiprocessing import Pool
class DummyPool():
#staticmethod
def apply_async(func, args, kwds):
return DummyApplyResult(func(*args, **kwds))
def close(self): pass
def join(self): pass
class DummyApplyResult():
def __init__(self, result):
self.result = result
def get(self):
return self.result
def foo(a, b, switch):
# set trace when DummyPool is used
# import ipdb; ipdb.set_trace()
if switch:
return b - a
else:
return a - b
if __name__ == '__main__':
xml = etree.parse('C:/Users/anmendoza/Downloads/jim - 8.1/running-config.xml')
pool = DummyPool() # switch between Pool() and DummyPool() here
results = []
results.append(pool.apply_async(foo, args=(1, 100), kwds={'switch': True}))
pool.close()
pool.join()
results[0].get()
Here is the version of the ForkedPdb(Romuald's Solution) which will work for Windows and *nix based systems.
import sys
import pdb
import win32console
class MyHandle():
def __init__(self):
self.screenBuffer = win32console.GetStdHandle(win32console.STD_INPUT_HANDLE)
def readline(self):
return self.screenBuffer.ReadConsole(1000)
class ForkedPdb(pdb.Pdb):
def interaction(self, *args, **kwargs):
_stdin = sys.stdin
try:
if sys.platform == "win32":
sys.stdin = MyHandle()
else:
sys.stdin = open('/dev/stdin')
pdb.Pdb.interaction(self, *args, **kwargs)
finally:
sys.stdin = _stdin
The problem here is that Python always connects sys.stdin in the child process to os.devnull to avoid contention for the stream. But this means that when the debugger (or a simple input()) tries to connect to stdin to get input from the user, it immediately reaches end-of-file and reports an error.
One solution, at least if you don't expect multiple debuggers to run at the same time, is to reopen stdin in the child process. That can be done by setting sys.stdin to open(0), which always opens the active terminal. This in fact is what the ForkedPdb solution does, but it can be done more simply and in an os-independent manner like this:
import multiprocessing, sys
def main():
process = multiprocessing.Process(target=worker)
process.start()
process.join()
def worker():
# Python automatically closes sys.stdin for the subprocess, so we reopen
# stdin. This enables pdb to connect to the terminal and accept commands.
# See https://stackoverflow.com/a/30149635/3830997.
sys.stdin = open(0) # or os.fdopen(0)
print("Hello from the subprocess.")
breakpoint() # or import pdb; pdb.set_trace()
print("Exited from breakpoint in the subprocess.")
if __name__ == '__main__':
main()
If you are on a supported platform, try DTrace. Most of the BSD / Solaris / OS X family support DTrace.
Here is an intro by the author. You can use Dtrace to debug just about anything.
Here is a SO post on learning DTrace.

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