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python check_output FileNotFoundError: [WinError 2] The system cannot find the file specified

I'm running the next piece of code to check the type of my file:
import subprocess as sub
output = sub.check_output(["file", "test.py"]).decode('ascii')
#output=sub.check_output(["file","C:/Users/Roger.That/PycharmProjects/test/test.py"]).decode('ascii')
and I keep getting the following error:
Traceback (most recent call last):
File "C:/Users/Roger That/PycharmProjects/test/test.py", line 2, in <module>
output = sub.check_output(["file", "test.py"]).decode('ascii')
File "C:\Users\Roger That\AppData\Local\Programs\Python\Python37-32\lib\subprocess.py", line 395, in check_output
**kwargs).stdout
File "C:\Users\Roger That\AppData\Local\Programs\Python\Python37-32\lib\subprocess.py", line 472, in run
with Popen(*popenargs, **kwargs) as process:
File "C:\Users\Roger That\AppData\Local\Programs\Python\Python37-32\lib\subprocess.py", line 775, in __init__
restore_signals, start_new_session)
File "C:\Users\Roger That\AppData\Local\Programs\Python\Python37-32\lib\subprocess.py", line 1178, in _execute_child
startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified
The full path of my test.py : "C:/Users/Roger.That/PycharmProjects/test/test.py"
output from gitbash :
$ file /c/Users/Roger\ That/PycharmProjects/test/test.py
/c/Users/Roger That/PycharmProjects/test/test.py: ASCII text, with CRLF line terminators
Any chance that it is related to the fact that I have a dot between "Roger" and "That"? Although it doesn't work also when I use the relative path (only the file name)
Update
I changed my user's dir name from Roger that to Roger.that, but it still didn't help:
python /c/Users/Roger.That/PycharmProjects/test/test.py
same error..
checked also :
import subprocess as sub
output = sub.check_output(["ls" "-l"])
got same error

I created from scratch the virtual environment and it solved my problem.

Execute Robot Framework file from python script

from subprocess import call
import os
call(['robot '+os.getcwd()+'\\aaa.robot'])
file_dir: D:/aaa/test/aaa.robot
script for now in same dir
Output:
Traceback (most recent call last):
File "__init.py", line 7, in <module>
call(['robot '+os.getcwd()+'\\aaa.robot'])
File "C:\Python27\lib\subprocess.py", line 522, in call
return Popen(*popenargs, **kwargs).wait()
File "C:\Python27\lib\subprocess.py", line 710, in __init_
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 958, in _execut
startupinfo)
WindowsError: [Error 2] Nie mo┐na odnalečŠ okreťlonego pliku
I just cant handle it. I dont get why in python tunning anything is so complicated :(
I want same result as this line (written directly to cmd):
/>robot aaa.robot

Here is another way
import robot
logFile = open('mylog.txt', 'w')
robot.run("tmp.robot",stdout=logFile)

subprocess expects a list but you're inputting a string ('robot '+os.getcwd()+'\\aaa.robot').
Try:
call(['C:/Python27/python.exe', '-m', 'robot', 'D:/aaa/test/aaa.robot'])
or
call(['C:/Python27/Scripts/robot.bat', 'D:/aaa/test/aaa.robot'])

run a .exe file with additional parameters

I am using windows and struggeling to get this work...
I can execute this in cmd.exe:
"C:\Program Files (x86)\Test 123\Test.exe" "H:\Test Test\file.txt" -f "doStuff"
but when I try to do it in python:
subprocess.call([r'"C:\Program Files (x86)\Test 123\Test.exe" "H:\Test Test\file.txt" -f "doStuff"'])
I get this error:
Traceback (most recent call last):
File "testing12.py", line 20, in <module>
subprocess.call([r'"C:\Program Files (x86)\Test 123\Test\Test.exe" "H:\Test Test\Folder\file.txt" -f "doStuff"'])
File "c:\Python27\lib\subprocess.py", line 522, in call
return Popen(*popenargs, **kwargs).wait()
File "c:\Python27\lib\subprocess.py", line 709, in __init__
errread, errwrite)
File "c:\Python27\lib\subprocess.py", line 957, in _execute_child
startupinfo)
WindowsError: [Error 5] Access is denied
How can I execute it properly? Thanks.

If you're going to pass in an array, make it an actual array -- one argument per parameter, separated by commas. Otherwise you'll need to use shell=True, which has all the (generally undesirable) side effects of invoking a shell (and should just pass in your command string as a string, no array called for in that use case).
subprocess.call([
"C:\Program Files (x86)\Test 123\Test.exe",
"H:\Test Test\file.txt",
"-f", "doStuff"])
If you don't use commas between your strings, they're consolidated together.

subprocess.call() for shell program which write a file

I need to execute a shell script using python. Output of shell program is a text file. No inputs to the script. Help me to resolve this.
def invokescript( shfile ):
s=subprocess.Popen(["./Script1.sh"],stderr=subprocess.PIPE,stdin=subprocess.PIPE);
return;
invokescript("Script1.sh");
On using above code., I receive the following error.
Traceback (most recent call last):
File "./test4.py", line 12, in <module>
invokescript("Script1.sh");
File "./test4.py", line 8, in invokescript
s=subprocess.Popen(["./Script1.sh"],stderr=subprocess.PIPE,stdin=subprocess.PIPE);
File "/usr/lib/python2.7/subprocess.py", line 679, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1249, in _execute_child
raise child_exception
OSError: [Errno 8] Exec format error
Thanks in advance...

Try this:
import shlex
def invokescript(shfile):
return subprocess.Popen(
shlex.split(shfile),
stderr=subprocess.PIPE,
stdin=subprocess.PIPE
)
invokescript("Script1.sh");
And add #!/usr/bin/env bash to your bash file of course.

I used os.system() to call shell script. This do what i expected. Make sure that you have imported os module in your python code.
invokescript( "Script1.sh" ) // Calling Function
function invokescript( shfile ): // Function Defenition
os.system("/root/Saranya/Script1.sh")
return;
following is also executable:
invokescript( "Script1.sh" ) // Calling Function
function invokescript( shfile ): // Function Defenition
os.system(shfile)
return;
Thanks for your immediate response guys.

NamedTemporaryFile cannot be acessed from command line

I have the following (simplified) code:
with NamedTemporaryFile() as f:
f.write(zip_data)
f.flush()
subprocess.call("/usr/bin/7z x %s" % f.name)
It dies with the following error:
Traceback (most recent call last):
File "decrypt_resource.py", line 70, in <module>
unpack(sys.argv[2])
File "decrypt_resource.py", line 28, in unpack
print(subprocess.check_output(cmd))
File "/usr/lib/python2.7/subprocess.py", line 568, in check_output
process = Popen(stdout=PIPE, *popenargs, **kwargs)
File "/usr/lib/python2.7/subprocess.py", line 711, in __init__
errread, errwrite)
File "/usr/lib/python2.7/subprocess.py", line 1308, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory
However, if I use NamedTemporaryFile(delete=False) and then print & execute the command, it works. What's wrong here?
My System is an ArchLinux with a 3.9.5-1-ARCH kernel.

You are using subprocess.call() incorrectly.
Pass in a list of arguments:
subprocess.call(["/usr/bin/7z", "x", f.name])
The argument is not handled by a shell and is not parsed out like a shell would do. This is a good thing as it prevents a security problem with untrusted command line arguments.
Your other options include using shlex.split() to do the whitespace splitting for you, or, as a last resort, telling subprocess to use a shell for your command with the shell=True flag. See the big warning on the subprocess documentation about enabling the shell.