Subplot of Windrose in matplotlib - python

I am trying to make a figure with 4 subplots of windrose, But I realised that the windrose only have axis like this:ax = WindroseAxes.from_ax() So, how can I draw a subplots with windrose?

There are two solutions:
(a) creating axes from rectangles
First of all there is a similar question already here: How to add specific axes to matplotlib subplot?
There, the solution is to create a rectangle rect with coordinates of the new subplot axes within the figure and then call ax = WindroseAxes(fig, rect)
An easier to understand example would be
from windrose import WindroseAxes
from matplotlib import pyplot as plt
import numpy as np
ws = np.random.random(500) * 6
wd = np.random.random(500) * 360
fig=plt.figure()
rect=[0.5,0.5,0.4,0.4]
wa=WindroseAxes(fig, rect)
fig.add_axes(wa)
wa.bar(wd, ws, normed=True, opening=0.8, edgecolor='white')
plt.show()
(b) adding a projection
Now it may be rather annoying to create this rectangle and it would be much better to be able to use the matplotlib subplot functionality.
One suggestion that has been made here is to register the WindroseAxes as a projection into matplotlib. To this end, you need to edit the file windrose.py in the site-packages/windrose as follows:
Include an import from matplotlib.projections import register_projection at the beginning of the file.
Then add a name variable :
class WindroseAxes(PolarAxes):
name = 'windrose'
...
Finally, at the end of windrose.py, you add:
register_projection(WindroseAxes)
Once that is done, you can easily create your windrose axes using the projection argument to the matplotlib axes:
from matplotlib import pyplot as plt
import windrose
import matplotlib.cm as cm
import numpy as np
ws = np.random.random(500) * 6
wd = np.random.random(500) * 360
fig = plt.figure()
ax = fig.add_subplot(221, projection="windrose")
ax.contourf(wd, ws, bins=np.arange(0, 8, 1), cmap=cm.hot)
ax.legend(bbox_to_anchor=(1.02, 0))
plt.show()

To make the subplots on the same scale (e.g. for monthly data), simply add the rmax argument in the add_subplot function. For me worked:
ax = fig.add_subplot(nrows, ncols, month, projection="windrose", rmax = 50)

Inspired by the accepted answer (by ImportanceOfBeingErnest) I used the following to add a windrose to an existing subplots instance:
import matplotlib as plt
from windrose import WindroseAxes
fig, axes = plt.subplots(1,2)
rect=axes[0,1].get_position()
wax=WindroseAxes(fig, rect)
wax.bar(wd, ws)
axes[0,1].axis('off')

Related

How to control colorbar position when using subplots in Matplotlib [duplicate]

This question already has an answer here:
adjusting subplot with a colorbar
(1 answer)
Closed 3 years ago.
I am trying to use Matplotlib to plot a time series along with its spectrogram and its associated colorbar.
Below is a MCVE:
import numpy as np
import matplotlib.pyplot as plt
import scipy.signal as scignal
import random
array=np.random.random(10000)
t,f,Sxx=scignal.spectrogram(array,fs=100)
plt.subplot(211)
plt.plot(array)
plt.subplot(212)
plt.pcolormesh(Sxx)
plt.colorbar()
This code yields the following figure:
However, I would like both subplots to have the same size:
I thought of changing the orientation of the colorbar using plt.colorbar(orientation='horizontal') but I am not satisfied with the result as the subplots end up not having the same height.
Any help will be appreciated!
The reason this happens is that plt.colorbar creates a new Axes object, which "steals" space from the lower Axes (this is the reason making a horizontal colourbar also affects the two original plots).
There are a few ways to work around this; one is to create a Figure with four Axes, allocate most of the space to the left ones, and just make one invisible:
import numpy as np
import matplotlib.pyplot as plt
import scipy.signal as scignal
import random
array = np.random.random(10000)
t, f, Sxx = scignal.spectrogram(array,fs=100)
fig, axes = plt.subplots(nrows=2, ncols=2, figsize=(5, 6), gridspec_kw={'width_ratios': [19, 1]})
(ax1, blank), (ax2, ax_cb) = axes
blank.set_visible(False)
ax1.plot(array)
m = ax2.pcolormesh(Sxx)
fig.colorbar(m, cax=ax_cb)

How to create legend with proxy artist for contourf plot in Matplotlib

I am trying to create a graphic where I overlay multiple contour plots on a single image. So I want to have colorbars for each of the plots, as well as a legend indicating what each contour represents. However Matplotlib will not allow me to create a separate legend for my contour plots. Simple example:
import matplotlib as mpl
import matplotlib.pyplot as plt
import cartopy
import cartopy.crs as ccrs
import numpy as np
def create_contour(i,j):
colors = ["red","green","blue"]
hatches = ['-','+','x','//','*']
fig = plt.figure()
ax = plt.axes(projection=ccrs.PlateCarree())
ax.set_extent((-15.0,15.0,-15.0,15.0))
delta = 0.25
x = np.arange(-3.0,3.0,delta)
y = np.arange(-2.0,2.0,delta)
X, Y = np.meshgrid(x, y)
data = np.full(np.shape(X), 1.0)
plot = ax.contourf(X,Y,data, levels = [float(i),float(i+1)], hatch=[hatches[j]], colors = colors[i], label="label")
plt.legend(handles=[plot], labels=["label"])
plt.savefig("figure_"+str(i)+".png")
create_contour(1,3)
When I run this, I get the following message:
UserWarning: Legend does not support
(matplotlib.contour.QuadContourSet object at 0x7fa69df7cac8)
instances. A proxy artist may be used instead. See:
http://matplotlib.org/users/legend_guide.html#creating-artists-specifically-for-adding-to-the-legend-aka-proxy-artists
"aka-proxy-artists".format(orig_handle)
But as far as I can tell, I am following those directions as closely as possible, the only difference being that they do not use contourf in the example.
Any help would be greatly appreciated.
The comments to your question look like they have solved the question (by making custom patches and passing those through to the legend). There is also an example that I added many years ago to the matplotlib documentation to do something similar (about the same time I added contour hatching to matplotlib): https://matplotlib.org/examples/pylab_examples/contourf_hatching.html#pylab-examples-contourf-hatching
It is such a reasonable request that there is even a method on the contour set to give you legend proxies out of the box: ContourSet.legend_elements.
So your example might look something like:
%matplotlib inline
import matplotlib.pyplot as plt
import cartopy.crs as ccrs
import numpy as np
fig = plt.figure(figsize=(10, 10))
ax = plt.axes(projection=ccrs.PlateCarree())
ax.coastlines('10m')
y = np.linspace(40.0, 60.0, 30)
x = np.linspace(-10.0, 10.0, 40)
X, Y = np.meshgrid(x, y)
data = 2*np.cos(2*X**2/Y) - np.sin(Y**X)
cs = ax.contourf(X, Y, data, 3,
hatches=['//','+','x','o'],
alpha=0.5)
artists, labels = cs.legend_elements()
plt.legend(handles=artists, labels=labels)
plt.show()

Controlling legend across multiple subplots with windrose axes

I cannot figure out how to make the legends not overlap with my figures (see below figure) in subplots. The problem is my axes are complicated because they are from a windrose. To get the axes:
1) I have downloaded the windrose.py from https://github.com/akrherz/windrose/tree/darylchanges
2) I copied the windrose.py into the same path with my python script, example.py
3) I changed windrose.py so that it is able to do subplots, according to the steps from Subplot of Windrose in matplotlib . Those steps were to make WindroseAxes as a projection into matplotlib. I edited the file windrose.py:
3a) Include an
import from matplotlib.projections import register_projection
at the beginning of the file.
3b) Then add a name variable :
class WindroseAxes(PolarAxes):
name = 'windrose'
...
3c) Finally, at the end of windrose.py, you add:
register_projection(WindroseAxes)
Once that is done, you can easily create your windrose axes using the projection argument to the matplotlib axes.
4) Now I ran my script below (example of my real script)
from windrose import WindroseAxes
import numpy as np
import matplotlib.pyplot as plt
from windrose_subplot import WindroseAxes
wind_speeds1 = np.array([12,10,13,15])
wind_dirs1 = np.array([60,76,32,80]) # in degrees
wind_speeds2 = np.array([23,12,10,8])
wind_dirs2 = np.array([23,45,29,13])
fig = plt.figure()
ax1 = fig.add_subplot(231,projection='windrose')
ax1.bar(wind_dirs1,wind_speeds1,normed=True,opening=0.8,edgecolor='white')
ax2 = fig.add_subplot(232,projection='windrose')
ax2.bar(wind_dirs2,wind_speeds2,normed=True,opening=0.8,edgecolor='white')
ax1.legend()
ax2.legend()
plt.tight_layout()
plt.show()
Ideally, I would like to create one legend with the max/min of all the subplots because they are all the same units . This legend will have to be the corresponding colors for each subplot for the same values across subplots (eg, a single normal legend relevant to all subplots). There will be 6 subplots in the real script but 2 here for now shows the point.
This is simple to fix. In order to only plot one legend, comment out or delete where you plot the first legend. In order to move the legend off of the plot, use bbox_to_anchor=() with some logical location. See below for an example that works for this example.
import numpy as np
import matplotlib.pyplot as plt
from windrose_subplot import WindroseAxes
wind_speeds1 = np.array([12,10,13,15])
wind_dirs1 = np.array([60,76,32,80]) # in degrees
wind_speeds2 = np.array([23,12,10,8])
wind_dirs2 = np.array([23,45,29,13])
fig = plt.figure()
ax1 = fig.add_subplot(231,projection='windrose')
ax1.bar(wind_dirs1,wind_speeds1,normed=True,opening=0.8,edgecolor='white')
ax2 = fig.add_subplot(232,projection='windrose')
ax2.bar(wind_dirs2,wind_speeds2,normed=True,opening=0.8,edgecolor='white')
# ax1.legend()
ax2.legend(bbox_to_anchor=(1.2 , -0.1))
plt.tight_layout()
plt.show()
However, note the bbox_to_anchor is reliant on the axis that the legend comes from, so
ax1.legend(bbox_to_anchor=1.2, -0.1))
#ax2.legend()
would display the legend underneath the second axis:
Thank you Hazard11, I found your answer very useful :) There is an issue with the answer though is the legend does not represent the first subplot because the bins are generated when creating the second subplot.
I just solved this issue by calculating the bins using numpy.histogram first and then passing that to windrose.WindroseAxes.bar() when creating each wind rose. Doing it this way means you need to pick which one you want to use to generate the bins. Another way to do it would be to define the bins manually or to create a function which generates some efficient binning for both which could then be used.
wind_speeds1 = np.array([12,10,13,15])
wind_dirs1 = np.array([60,76,32,80]) # in degrees
wind_speeds2 = np.array([23,12,10,8])
wind_dirs2 = np.array([23,45,29,13])
wind_speeds_bins = np.histogram(wind_speeds2, 5)[1]
fig = plt.figure()
ax1 = fig.add_subplot(231, projection='windrose')
ax1.bar(wind_dirs1 ,wind_speeds1, normed=True, opening=0.8, edgecolor='white', bins=wind_speeds_bins)
ax2 = fig.add_subplot(232, projection='windrose')
ax2.bar(wind_dirs2, wind_speeds2, normed=True, opening=0.8, edgecolor='white', bins=wind_speeds_bins)
# ax1.legend()
ax2.legend(bbox_to_anchor=(1.2 , -0.1))
plt.tight_layout()
plt.show()

Zigzag or wavy lines in matplotlib

Is there an easy way to draw a zigzag or wavy line in matplotlib?
I'm aware of the different line styles (http://matplotlib.org/examples/lines_bars_and_markers/line_styles_reference.html), and I'm of course aware that instead of plotting
plt.figure(); plt.plot(n.linspace(0.7,1.42,100),[0.7]*100)
I could plot
plt.figure(); plt.plot(n.linspace(0.7,1.42,100),[0.69,0.71]*50)
for a zigzag-line, but I was wondering whether there was a more straightforward way?
Yes there is, but it comes with a little bit of fallout. The easiest way is to use the xkcd mode in matplotlib.
import numpy as np
import matplotlib.pyplot as plt
plt.xkcd()
plt.figure()
plt.plot(np.linspace(0.7,1.42,100),[0.7]*100)
plt.show()
Which gives you the following:
If you take a look at the code used to achieve this you will find that the xkcd function makes some changes to the rcParams dictionary. Most notably the entry rcParams['path.sketch'] = (scale, length, randomness) which is a path effect that is able to simulate a hand drawn look. The default parameters used by xkcd style are:
# explanation from the docstring of the xkcd function
scale = 1 # amplitude of the wiggle
length = 100 # length of the wiggle along the line
randomness = 2 # scale factor for shrinking and expanding the length
You can change the entries in the rcParams dictionary if you import it from the matplotlib package. In the following example I increased the randomness value from 2 to 100:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import rcParams
rcParams['path.sketch'] = (1, 100, 100)
plt.plot(np.linspace(0.7,1.42,100),[0.7]*100)
plt.show()
Which will result in the following plot:
As you can see, more jiggling and the font used for the ticks is still 'normal'. However, the style is also used to draw the axes and so far I have not found a way around that.
Two workarounds could be:
Work without drawn borders/ spines.
Plot spines and line independently (hard and annoying to automize).
Dig through the documentation of matplotlib and path styles and find out if there is a way to set path styles only for a subset of drawn lines.
Option 1 can be achieved like this:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import rcParams
rcParams['path.sketch'] = (10, 10, 100)
fig = plt.plot(np.linspace(0.7,1.42,100),[0.7]*100)
for pos, spine in fig[0].axes.spines.items():
spine.set_visible(False)
plt.show()
Which, in my opinion look quite ok. borders around plots are highly overrated anyways.
Edit: Less Chaos
To get an evenly waved line, set the randomness parameter to 1 and pick small values for amplitude and length:
import numpy as np
import matplotlib.pyplot as plt
from matplotlib import rcParams
rcParams['path.sketch'] = (3, 10, 1)
fig = plt.plot(np.linspace(0.7,1.42,100),[0.7]*100)
for pos, spine in fig[0].axes.spines.items():
spine.set_visible(False)
plt.show()
Bonus image: More Chaos
rcParams['path.sketch'] = (100, 1, 100)
You can apply the change in rcParams['path.sketch'] dictionary only to selected curves using with.
import matplotlib as mpl
import matplotlib.pyplot as plt
import numpy as np
# prepare some fancy data
x = np.linspace(0,5,200)
y_0 = 10*x**0.2-x**1.5
y_1 = 20*np.sin(x)
y_2 = x**2
# prepare figure and axis
fig, ax = plt.subplots(nrows=1, ncols = 1, figsize = (5,3), dpi = 128)
# plot with some normal style
ax.plot(x, y_0, color = 'gray', ls='-.', lw = 2, label = 'normal style')
# now plot the wavy-like style!!!!
with mpl.rc_context({'path.sketch': (5, 15, 1)}):
ax.plot(x, y_1, color = 'blue', label = 'wavy style!')
# again plot with some different normal style
ax.plot(x, y_2, color = 'orange', ls = '-', lw = 3, label = 'again normal style')
ax.legend(loc='best') # turn on legend with automatic best location
plt.show()

matplotlib interactive subplots with sharex and twiny

I am plotting a figure with matplotlib using the following code. I have two stacked subplots, as well as a added second x axis using twiny.
#!/usr/bin/python
import os
import numpy as np
import matplotlib.pylab as mp
# random data
data = np.random.random((10,3))
data[:,0] = np.linspace(0,1,10)
# init figure
fig, axs = mp.subplots(2, sharex=True)
axs = np.append(axs,axs[1].twiny())
# plot top
axs[0].plot(data[:,0],data[:,1],'bo-',linewidth=2.0)
axs[0].axis([data[0,0],data[-1,0],data[:,1].min(),data[:,1].max()])
# plot bottom
axs[1].plot(data[:,0],data[:,2],'rx-',linewidth=2.0)
# add second axis
axs[2].xaxis.set_ticks_position('bottom')
axs[2].xaxis.set_label_position('bottom')
axs[2].spines['bottom'].set_position(('outward', 40))
axs[2].set_xlim(-180,180)
# plot
mp.tight_layout(pad=0.6)
mp.show()
My problem is in the interactive plot window: if I pan the lower plot, all 3 x-axes move accordingly. If I pan the top plot, the added twiny axis does not move. Would this be possible in the current set up?

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