Saving to a file issue - python

i am trying to save the list that is generated to a file, i see the print out of the list fine but it will not write to the compoundlist.csv file. i am not sure what i am doing wrong, i have tried to write after the list is generated and also during the loop. I have gotten the same result.
import urllib
import urllib.request
from bs4 import BeautifulSoup
import os
import csv
def make_soup(url):
thepage = urllib.request.urlopen(url)
soupdata = BeautifulSoup(thepage, "html.parser")
return soupdata
compoundlist = []
soup = make_soup("http://www.genome.jp/dbget-bin/www_bget?ko00020")
i = 1
file = open("Compoundlist.csv", "wb")
for record in soup.findAll("nobr"):
compound = ''
if (record.text[0] == "C" and record.text[1] == '0') or (record.text[0] == "C" and record.text[1] == '1'):
compoundlist = "http://www.genome.jp/dbget-bin/www_bget?cpd:" + record.text
file.write(compoundlist)
print(compoundlist)

Try adding the following to the end of your code
file.close()
To flush the open file buffer into the file

Related

Handling HTML in python

I had a problem when I took out html files and imported them into excel.
This is the site i need to get information: https://www.kylc.com/stats/global/yearly_per_country/g_gdp/vnm.html
As you can see, in the GDP table I have a row named : 年份 separated from 2 lines
That's why after i exported the excel file it gave unexpected results
The result I want is that the first line in excel will only have : 年份 , GDP(美元), 占世界%
Sorry for my confusing explanation, I really don't know how to explain it in detail.
Here is my python code
import requests
from bs4 import BeautifulSoup
import lxml
import csv
def get_html(url):
try:
r = requests.get(url)
r.raise_for_status()
r.encoding = r.apparent_encoding
return r.text
except:
r = "fail"
return r
def getGDP(ulist,html):
soup = BeautifulSoup(html,"html.parser")
trs = soup.find_all('tr')
for tr in trs:
list = []
for th in tr:
ts = th.string
if ts == '\n':
continue
list.append(ts)
ulist.append(list)
def saveGDP(ulist):
file_name = '21095010 胡碧玉 GDP.csv'
with open(file_name,'w',errors='ignore',newline='') as f:
f_csv = csv.writer(f)
f_csv.writerows(ulist)
def main():
unifo=[]
url='https://www.kylc.com/stats/global/yearly_per_country/g_gdp/vnm.html'
html=get_html(url)
getGDP(unifo,html)
saveGDP(unifo)
if __name__=="__main__":
main()
Thank you so much!
Using pandas scraping tables and cleaning of results in most cases is mutch easier - under the hood beautifulsoup is working for you.
In this case read_html() the table, drop the unwanted header level and filter out the rows containings ads:
import pandas as pd
df = pd.read_html('https://www.kylc.com/stats/global/yearly_per_country/g_gdp/vnm.html')[0].droplevel(0, axis=1)
df[~df.iloc[:,0].str.contains('ads')].to_csv('21095010 胡碧玉 GDP.csv', index=False)
Answering your question
You have to select your elements more specific e.g. with css selectors.
So first get the thead information from all th witout colspan, than collect the data from all tr in tbody that do not contains ads:
def getGDP(html):
soup = BeautifulSoup(html,"html.parser")
data = []
data.append([th.text for th in soup.select('thead th:not([colspan])')])
for row in soup.select('tbody tr:not(:-soup-contains("ads"))'):
data.append(list(row.stripped_strings))
return data
Example
import requests
from bs4 import BeautifulSoup
import lxml
import csv
def get_html(url):
try:
r = requests.get(url)
r.raise_for_status()
r.encoding = r.apparent_encoding
return r.text
except:
r = "fail"
return r
def getGDP(html):
soup = BeautifulSoup(html,"html.parser")
data = []
data.append([th.text for th in soup.select('thead th:not([colspan])')])
for x in soup.select('tbody tr:not(:-soup-contains("ads"))'):
data.append(list(x.stripped_strings))
return data
def saveGDP(ulist):
file_name = '21095010 胡碧玉 GDP.csv'
print(ulist)
with open(file_name,'w',errors='ignore', encoding='utf-8') as f:
f_csv = csv.writer(f)
f_csv.writerows(ulist)
def main():
url='https://www.kylc.com/stats/global/yearly_per_country/g_gdp/vnm.html'
html=get_html(url)
saveGDP(getGDP(html))
if __name__=="__main__":
main()

Saving a "for loop" iteration

When I run the code below, the for loop saves the first text correctly into a separate file, but the second iteration saves the first AND the second into another separate file, and the third iteration saves the first, second and third into a separate file and so on.... I'd like to save each iteration into a separate file but not adding the previous iterations. I don't have a clue to what I'm missing here. Can anyone help, please?
import requests
from bs4 import BeautifulSoup
import pandas as pd
base_url = 'http://www.chakoteya.net/StarTrek/'
end_url = ['1.htm', '6.htm', '8.htm', '2.htm', '7.htm',
'5.htm', '4.htm', '10.htm', '12.htm', '11.htm', '3.htm', '16.htm']
episodes = []
count = 0
for end_url in end_url:
url = base_url + end_url
r = requests.get(url)
soup = BeautifulSoup(r.content, 'html.parser')
episodes.append(soup.text)
file_text = open(f"./{count}.txt", "w")
file_text.writelines()
file_text.close()
count = count + 1
print(f"saved file for url:{url}")
Please consider the following points!
there's no reason at all to use bs4! since response.text is actually holding the same.
You've to use Same Session explained on my previous answer
You can use iteration with fstring/format which will let your code more cleaner and easier to read.
with context manager is less headache as you don't need to remember to close your file after!
import requests
block = [9, 13, 14, 15]
def main(url):
with requests.Session() as req:
for page in range(1, 17):
if page not in block:
print(f'Extracing Page# {page}')
r = req.get(url.format(page))
with open(f'{page}.htm', 'w') as f:
f.write(r.text)
main('http://www.chakoteya.net/StarTrek/{}.htm')
You needed to empty your episodes for each iteration. Try the following:
import requests
from bs4 import BeautifulSoup
import pandas as pd
base_url = 'http://www.chakoteya.net/StarTrek/'
end_url = ['1.htm', '6.htm', '8.htm', '2.htm', '7.htm',
'5.htm', '4.htm', '10.htm', '12.htm', '11.htm', '3.htm', '16.htm']
count = 0
for end_url in end_url:
episodes = []
url = base_url + end_url
r = requests.get(url)
soup = BeautifulSoup(r.content, 'html.parser')
episodes.append(soup.text)
file_text = open(f"./{count}.txt", "w")
file_text.writelines(episodes)
file_text.close()
count = count + 1
print(f"saved file for url:{url}")
It doesn't appear that your code would save anything to the files at all as you are calling writelines with no arguments
if __name__ == '__main__':
import requests
from bs4 import BeautifulSoup
base_url = 'http://www.chakoteya.net/StarTrek/'
paths = ['1.htm', '6.htm', '8.htm', '2.htm', '7.htm',
'5.htm', '4.htm', '10.htm', '12.htm', '11.htm', '3.htm', '16.htm']
for path in paths:
url = f'{base_url}{path}'
filename = path.split('.')[0]
r = requests.get(url)
soup = BeautifulSoup(r.content, 'html.parser')
with open(f"./{filename}.txt", "w") as f:
f.write(soup.text)
print(f"saved file for url:{url}")
This is reworked a little. It wasn't clear why the data was appending to episodes so that was left off.
Maybe you were writing the list to the file which would account for dupes. You were adding the content to each file to a list and writing that growing list each iteration.

scraper filters out word's instead of line

So I was trying to make a filter that filter's out the crap from this scrape, but I have an issue where it filters out the words. I would like to filter out the whole line instead of the words.
from bs4 import BeautifulSoup
import requests
import os
def Scrape():
page = input("Page: ")
url = "https://openuserjs.org/?p=" + page
source = requests.get(url)
soup = BeautifulSoup(source.text,'lxml')
os.system('cls')
Filter(soup)
def Filter(soup):
crap = ""
f = open("Data/Crap.txt", "r")
for craptext in f:
crap = craptext
for Titles in soup.select("a.tr-link-a>b"):
print(Titles.text.replace(crap, "").strip())
while True:
Scrape()
Instead of:
print(Titles.text.replace(crap, "").strip())
Try using:
if crap not in Titles.text:
print(Titles.text.strip())

How can I save the results of my web scraping to a text file in beautiful soup?

I tried to write this code for some web scraping. The code works fine, but I still have trouble figuring out how I can save the results of my web scraping into a .txt file? I want to write the result of "print(div.text)" output into a .txt file.
import bs4 as bs
import urllib.request
for pg in range(1, 100 + 1):
source = urllib.request.urlopen('https://dsalsrv04.uchicago.edu/cgi-bin/app/hayyim_query.py?page='+ str(pg)).read()
soup = bs.BeautifulSoup(source,'lxml')
for div in soup.find_all('div', class_='hw_result'):
print(div.text)
Maybe, with f.open, f.write and f.close:
import bs4 as bs
import urllib.request
import re
output = ''
for pg in range(1, 100 + 1):
source = urllib.request.urlopen('https://dsalsrv04.uchicago.edu/cgi-bin/app/hayyim_query.py?page='+ str(pg)).read()
soup = bs.BeautifulSoup(source,'lxml')
for div in soup.find_all('div', class_='hw_result'):
output += div.text
output = re.sub(r"[\r\n]+", "", output)
f = open('/any/directory_you_like/any_name_that_you_like_with_any_extension.txt', 'w')
try:
f.write(output)
finally:
f.close()
Open a file before the loop
file = open(“testfile.txt”, “w”)
First argument is the file name and the second means that you want to write in this file
And then instead of print(div.text) you should use file.write(div.text)
Close the file after the loop with file.close()
After all your code should be like this:
import bs4 as bs
import urllib.request
file = open(“testfile.txt”, “w”)
for pg in range(1, 100 + 1):
source = urllib.request.urlopen('https://dsalsrv04.uchicago.edu/cgi-bin/app/hayyim_query.py?page='+ str(pg)).read()
soup = bs.BeautifulSoup(source,'lxml')
for div in soup.find_all('div', class_='hw_result'):
file.write(div.text)
file.close()

How to get all application link from the log text file?

I have a log file which contains:
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/
http://www.downloadray.com/windows/Photos_and_Images/Graphic_Capture/
http://www.downloadray.com/windows/Photos_and_Images/Digital_Photo_Tools/
I have this code:
from bs4 import BeautifulSoup
import urllib
import urlparse
f = open("downloadray2.txt")
g = open("downloadray3.txt", "w")
for line in f.readlines():
i = 1
while 1:
url = line+"?page=%d" % i
pageHtml = urllib.urlopen(url)
soup = BeautifulSoup(pageHtml)
has_more = 1
for a in soup.select("div.n_head2 a[href]"):
try:
print (a["href"])
g.write(a["href"]+"\n")
except:
print "no link"
if has_more:
i += 1
else:
break
This code do not give error but it do not working.
I tried modified it but can't solved it.
But when I try this code,it works well:
from bs4 import BeautifulSoup
import urllib
import urlparse
g = open("downloadray3.txt", "w")
url = "http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/"
pageUrl = urllib.urlopen(url)
soup = BeautifulSoup(pageUrl)
i = 1
while 1:
url1 = url+"?page=%d" % i
pageHtml = urllib.urlopen(url1)
soup = BeautifulSoup(pageHtml)
has_more = 2
for a in soup.select("div.n_head2 a[href]"):
try:
print (a["href"])
g.write(a["href"]+"\n")
except:
print "no link"
if has_more:
i += 1
else:
break
So how can I make it can read from the log text file. It is hard to take link one by one to be read.
Have you stripped the newline from the end of the line?
for line in f.readlines():
line = line.strip()
readlines() will produce a list of lines taken from the file including the newline \n character.
Proof Evidence by printing url variable (after the line url = line+"?page=%d" % i):
Your original code:
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/
?page=1
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/
?page=2
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/
?page=3
With my suggested fix:
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/?page=1
http://www.downloadray.com/TIFF-to-JPG_download/
http://www.downloadray.com/Moo0-Image-Thumbnailer_download/
http://www.downloadray.com/Moo0-Image-Sizer_download/
http://www.downloadray.com/Advanced-Image-Viewer-and-Converter_download/
http://www.downloadray.com/GandMIC_download/
http://www.downloadray.com/SendTo-Convert_download/
http://www.downloadray.com/PNG-To-JPG-Converter-Software_download/
http://www.downloadray.com/Graphics-Converter-Pro_download/
http://www.downloadray.com/PICtoC_download/
http://www.downloadray.com/Free-Images-Converter_download/
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/?page=2
http://www.downloadray.com/VarieDrop_download/
http://www.downloadray.com/Tinuous_download/
http://www.downloadray.com/Acme-CAD-Converter_download/
http://www.downloadray.com/AAOImageConverterandFTP_download/
http://www.downloadray.com/ImageCool-Converter_download/
http://www.downloadray.com/GeoJpeg_download/
http://www.downloadray.com/Android-Resizer-Tool_download/
http://www.downloadray.com/Scarab-Darkroom_download/
http://www.downloadray.com/Jpeg-Resizer_download/
http://www.downloadray.com/TIFF2PDF_download/
http://www.downloadray.com/windows/Photos_and_Images/Image_Convertors/?page=3
http://www.downloadray.com/JGraphite_download/
http://www.downloadray.com/Easy-PNG-to-Icon-Converter_download/
http://www.downloadray.com/JBatch-It!_download/
http://www.downloadray.com/Batch-It!-Pro_download/
http://www.downloadray.com/Batch-It!-Ultra_download/
http://www.downloadray.com/Image-to-Ico-Converter_download/
http://www.downloadray.com/PSD-To-PNG-Converter-Software_download/
http://www.downloadray.com/VectorNow_download/
http://www.downloadray.com/KeitiklImages_download/
http://www.downloadray.com/STOIK-Smart-Resizer_download/
Update:
Then again, this code won't run as expected, because the while loop will never continue since the has_more variable is never changed.
You know that you don't have more links when the list returned by `soup.select(...)` is empty. You can check for emptiness using `len(...)`. So that part might go like this:
list_of_links = soup.select("div.n_head2 a[href]")
if len(list_of_links)==0:
break
else:
for a in soup.select("div.n_head2 a[href]"):
print (a["href"])
g.write(a["href"]+"\n")
i += 1
Apparently the page still display the latest page available if it's queried beyond the maximum page. So if the maximum page number available is 82 and you query page 83, it will give page 82. To detect this case, you can save the list of previous page urls, and compare it with current list of urls.
Here is the full code (tested):
from bs4 import BeautifulSoup
import urllib
import urlparse
f = open("downloadray2.txt")
g = open("downloadray3.txt", "w")
for line in f.readlines():
line = line.strip()
i = 1
prev_urls = []
while 1:
url = line+"?page=%d" % i
print 'Examining %s' % url
pageHtml = urllib.urlopen(url)
soup = BeautifulSoup(pageHtml)
list_of_urls = soup.select("div.n_head2 a[href]")
if set(prev_urls)==set(list_of_urls):
break
else:
for a in soup.select("div.n_head2 a[href]"):
print (a["href"])
g.write(a["href"]+"\n")
i += 1
prev_urls = list_of_urls

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