Develop Reference

How to delete all files in folder except CSV?

I wrote a dataframe to a csv in Pyspark. And I got the output files in the directory as:
._SUCCESS.crc
.part-00000-6cbfdcfd-afff-4ded-802c-6ccd67f3804a-c000.csv.crc
part-00000-6cbfdcfd-afff-4ded-802c-6ccd67f3804a-c000.csv
How do I keep only the CSV file in the directory and delete rest of the files, using Python?

import os
directory = "/path/to/directory/with/files"
files_in_directory = os.listdir(directory)
filtered_files = [file for file in files_in_directory if not file.endswith(".csv")]
for file in filtered_files:
path_to_file = os.path.join(directory, file)
os.remove(path_to_file)
first, you list all files in directory. Then, you only keep in list those, which don't end with .csv. And then, you remove all files that are left.

Try iterating over the files in the directory, and then os.remove only those files that do not end with .csv.
import os
dir_path = "path/to/the/directory/containing/files"
dir_list = os.listdir(dir_path)
for item in dir_list:
if not item.endswith(".csv"):
os.remove(os.path.join(dir_path, item))

You can also have fun with list comprehension for doing this:
import os
dir_path = 'output/'
[os.remove(os.path.join(dir_path, item)) for item in os.listdir(dir_path) if not item.endswith('.csv')]

I would recommended to use pathlib (Python >= 3.4) and the in-build type set() to substract all csv filenames from the list of all files. I would argument this is easy to read, fast to process and a good pythonic solution.
>>> from pathlib import Path
>>> p = Path('/path/to/directory/with/files')
>>> # Get all file names
>>> # https://stackoverflow.com/a/65025567/4865723
>>> set_all_files = set(filter(Path.is_file, p.glob('**/*')))
>>> # Get all csv filenames (BUT ONLY with lower case suffix!)
>>> set_csv_files = set(filter(Path.is_file, p.glob('**/*.csv')))
>>> # Create a file list without csv files
>>> set_files_to_delete = set_all_files - set_csv_files
>>> # Iteratore on that list and delete the file
>>> for file_name in set_files_to_delete:
... Path(file_name).unlink()

for (root,dirs,files) in os.walk('Test', topdown=true):
for name in files:
fp = os.path.join(root, name)
if name.endswith(".csv"):
pass
else:
os.remove(fp)
What the advandtage of os.walk?, it reads all the subdirectory in particular directory mentioned.

How to get a list of list of subfolder files with full path?

I would like to get the same list structure that i am getting in this approach but i get a full list instead which i would have to break down manually and it kills the "automate the task".
For example, I have a folder called test with 4 subfolders called A,B,C,D and inside each folder we can find files file1, file2, file3.
import os
import openpyxl
#Create a regex that matches files with the american date format
path = r'C:\Users\Dell_G7_15\Desktop\test'
pathWalk = os.walk(path)
fileIndex = os.listdir(path)
wb = openpyxl.Workbook()
i=0
filenames = []
filesPathLink=[]
for foldernames in pathWalk:
filenames.append(foldernames[-1]) #creating list of filenames
i= i+1
filenames.pop(0) #delete first value of the list that causes error
print(filenames)
When i print filenames i get:
[['file1', 'file2', 'file3'],['file1', 'file2', 'file3'],['file1', 'file2', 'file3']]
I am looking for the same list structure but to get the full path of each one and it would look like this:
[['../A/file1', '../A/file2', '../A/file3'],[....],[....]]

Is this what you are looking for?
For the following folder and sub folders -
# root/
# -img0.jpg
# sub1/
# -img1.jpg
# -img1 copy.jpg
# sub2/
# -img2.jpg
# subsub1/
# -img3.jpg
path = '/Users/name/Desktop/root'
[[r+'/'+fname for fname in f] for r,d,f in os.walk(path)]
[['/Users/name/Desktop/root/img0.jpg'],
['/Users/name/Desktop/root/sub1/img1 copy.jpg',
'/Users/name/Desktop/root/sub1/img1.jpg'],
['/Users/name/Desktop/root/sub2/img2.jpg'],
['/Users/name/Desktop/root/sub2/subsub1/img3.jpg']]
For completion sake, if anyone is looking for a flat list of all files with paths inside a multi-level folder structure then try this -
[r+'/'+fname for r,d,f in os.walk(path) for fname in f]
['/Users/name/Desktop/root/img0.jpg',
'/Users/name/Desktop/root/sub1/img1 copy.jpg',
'/Users/name/Desktop/root/sub1/img1.jpg',
'/Users/name/Desktop/root/sub2/img2.jpg',
'/Users/name/Desktop/root/sub2/subsub1/img3.jpg']
EDIT: Simple loop without a list comprehension
filepaths = []
for r,d,f in os.walk(path):
l = []
for fname in f:
l.append(r+'/'+fname)
filepaths.append(l)
print(filepaths)
[['/Users/name/Desktop/root/img0.jpg'],
['/Users/name/Desktop/root/sub1/img1 copy.jpg',
'/Users/name/Desktop/root/sub1/img1.jpg'],
['/Users/name/Desktop/root/sub2/img2.jpg'],
['/Users/name/Desktop/root/sub2/subsub1/img3.jpg']]

Counting the number of lines of text in all files within a folder and subfolders using Python

I have a huge folder with subfolders and multiple .sql files within those subfolders. I want to get the number of lines of code within every .sql file. This is what I've tried:
import os
import glob
os.chdir("path of folder")
names=[]
for fn in glob.glob("*.sql"):
with open(fn) as f:
names[fn]=sum(1 for line in f if line.strip() and not line.startswith('#'))
print(names)
But the output I get is [ ]. Could you guys help me with where I'm going wrong?
I know how to count the number of lines of code within a single file using "num_lines". I can't do that manually for each file and need to quicken the process.

The following version of you code works for files in the target directory, but not sub-folders:
import os
import glob
os.chdir("foo")
names = {}
for fn in glob.glob("*.sql"):
with open(fn) as f:
names[fn] = sum(1 for line in f if line.strip() and not line.startswith('#'))
print(names)
A version with the newer pathlib works recursively too:
#!/usr/bin/env python3
from pathlib import Path
target = Path("foo")
names = {}
for file in target.glob("**/*.sql"):
with file.open("rt") as f:
names[f.name] = sum(
1 for line in f
if line.strip() and not line.startswith('#')
)
print(names)

try this:
sql_folder_path = "full/path/to/sql/folder"
sql_files = [join(sql_folder_path, f) for f in listdir(sql_folder_path) if isfile(join(sql_folder_path, f)) and f.endswith(".sql")]
files_stats = {}
for file in sql_files:
with open(file) as f:
files_stats[file]=sum(1 for line in f if line.strip() and not line.startswith('#'))
print(files_stats)

Iterate over 2 files in each folder and compare them

I compare two text files and print out the results to a 3rd file. I am trying to make it so the script i'm running would iterate over all of the folders that have two text files in them, in the CWD of the script.
What i have so far:
import os
import glob
path = './'
for infile in glob.glob( os.path.join(path, '*.*') ):
print('current file is: ' + infile)
with open (f1+'.txt', 'r') as fin1, open(f2+'.txt', 'r') as fin2:
Would this be a good way to start the iteration process?
It's not the most clear code but it gets the job done. However, i'm pretty sure i need to take the logic out of the read / write methods but i'm not sure where to start.
What i'm basically trying to do is have a script iterate over all of the folders in its CWD, open each folder, compare the two text files inside, write a 3rd text file to the same folder, then move on to the next.
Another method i have tried is as follows:
import os
rootDir = 'C:\\Python27\\test'
for dirName, subdirList, fileList in os.walk(rootDir):
print('Found directory: %s' % dirName)
for fname in fileList:
print('\t%s' % fname)
And this outputs the following (to give you a better example of the file structure:
Found directory: C:\Python27\test
test.py
Found directory: C:\Python27\test\asdd
asd1.txt
asd2.txt
Found directory: C:\Python27\test\chro
ch1.txt
ch2.txt
Found directory: C:\Python27\test\hway
hw1.txt
hw2.txt
Would it be wise to put the compare logic under the for fname in fileList? How do i make sure it compares the two text files inside the specific folder and not with other fnames in the fileList?
This is the full code that i am trying to add this functionality into. I appologize for the Frankenstein nature of it but i am still working on a refined version but it does not work yet.
from collections import defaultdict
from operator import itemgetter
from itertools import groupby
from collections import deque
import os
class avs_auto:
def load_and_compare(self, input_file1, input_file2, output_file1, output_file2, result_file):
self.load(input_file1, input_file2, output_file1, output_file2)
self.compare(output_file1, output_file2)
self.final(result_file)
def load(self, fileIn1, fileIn2, fileOut1, fileOut2):
with open(fileIn1+'.txt') as fin1, open(fileIn2+'.txt') as fin2:
frame_rects = defaultdict(list)
for row in (map(str, line.split()) for line in fin1):
id, frame, rect = row[0], row[2], [row[3],row[4],row[5],row[6]]
frame_rects[frame].append(id)
frame_rects[frame].append(rect)
frame_rects2 = defaultdict(list)
for row in (map(str, line.split()) for line in fin2):
id, frame, rect = row[0], row[2], [row[3],row[4],row[5],row[6]]
frame_rects2[frame].append(id)
frame_rects2[frame].append(rect)
with open(fileOut1+'.txt', 'w') as fout1, open(fileOut2+'.txt', 'w') as fout2:
for frame, rects in sorted(frame_rects.iteritems()):
fout1.write('{{{}:{}}}\n'.format(frame, rects))
for frame, rects in sorted(frame_rects2.iteritems()):
fout2.write('{{{}:{}}}\n'.format(frame, rects))
def compare(self, fileOut1, fileOut2):
with open(fileOut1+'.txt', 'r') as fin1:
with open(fileOut2+'.txt', 'r') as fin2:
lines1 = fin1.readlines()
lines2 = fin2.readlines()
diff_lines = [l.strip() for l in lines1 if l not in lines2]
diffs = defaultdict(list)
with open(fileOut1+'x'+fileOut2+'.txt', 'w') as result_file:
for line in diff_lines:
d = eval(line)
for k in d:
list_ids = d[k]
for i in range(0, len(d[k]), 2):
diffs[d[k][i]].append(k)
for id_ in diffs:
diffs[id_].sort()
for k, g in groupby(enumerate(diffs[id_]), lambda (i, x): i - x):
group = map(itemgetter(1), g)
result_file.write('{0} {1} {2}\n'.format(id_, group[0], group[-1]))
def final(self, result_file):
with open(result_file+'.txt', 'r') as fin:
lines = (line.split() for line in fin)
for k, g in groupby(lines, itemgetter(0)):
fst = next(g)
lst = next(iter(deque(g, 1)), fst)
with open('final/{}.avs'.format(k), 'w') as fout:
fout.write('video0=ImageSource("old\%06d.jpeg", {}-3, {}+3, 15)\n'.format(fst[1], lst[2]))
fout.write('video1=ImageSource("new\%06d.jpeg", {}-3, {}+3, 15)\n'.format(fst[1], lst[2]))
fout.write('video0=BilinearResize(video0,640,480)\n')
fout.write('video1=BilinearResize(video1,640,480)\n')
fout.write('StackHorizontal(video0,video1)\n')
fout.write('Subtitle("ID: {}", font="arial", size=30, align=8)'.format(k))
using the load_and_compare() function, i define two input text files, two output text files, a file for the comparison results and a final phase that writes many files for all of the differences.
What i am trying to do is have this whole class run on the current working directory and go through every sub folder, compare the two text files, and write everything into the same folder, specifically the final() results.

You can indeed use os.walk(), since that already separates the directories from the files. You only need the directories it returns, because that's where you're looking for your 2 specific files.
You could also use os.listdir() but that returns directories as well files in the same list, so you would have to check for directories yourself.
Either way, once you have the directories, you iterate over them (for subdir in dirnames) and join the various path components you have: The dirpath, the subdir name that you got from iterating over the list and your filename.
Assuming there are also some directories that don't have the specific 2 files, it's a good idea to wrap the open() calls in a try..except block and thus ignore the directories where one of the files (or both of them) doesn't exist.
Finally, if you used os.walk(), you can easily choose if you only want to go into directories one level deep or walk the whole depth of the tree. In the former case, you just clear the dirnames list by dirnames[:] = []. Note that dirnames = [] wouldn't work, since that would just create a new empty list and put that reference into the variable instead of clearing the old list.
Replace the print("do something ...") with your program logic.
#!/usr/bin/env python
import errno
import os
f1 = "test1"
f2 = "test2"
path = "."
for dirpath, dirnames, _ in os.walk(path):
for subdir in dirnames:
filepath1, filepath2 = [os.path.join(dirpath, subdir, f + ".txt") for f in f1, f2]
try:
with open(filepath1, 'r') as fin1, open(filepath2, 'r') as fin2:
print("do something with " + str(fin1) + " and " + str(fin2))
except IOError as e:
# ignore directiories that don't contain the 2 files
if e.errno != errno.ENOENT:
# reraise exception if different from "file or directory doesn't exist"
raise
# comment the next line out if you want to traverse all subsubdirectories
dirnames[:] = []
Edit:
Based on your comments, I hope I understand your question better now.
Try the following code snippet instead. The overall structure stays the same, only now I'm using the returned filenames of os.walk(). Unfortunately, that would also make it harder to do something like "go only into the subdirectories 1 level deep", so I hope walking the tree recursively is fine with you. If not, I'll have to add a little code to later.
#!/usr/bin/env python
import fnmatch
import os
filter_pattern = "*.txt"
path = "."
for dirpath, dirnames, filenames in os.walk(path):
# comment this out if you don't want to filter
filenames = [fn for fn in filenames if fnmatch.fnmatch(fn, filter_pattern)]
if len(filenames) == 2:
# comment this out if you don't want the 2 filenames to be sorted
filenames.sort(key=str.lower)
filepath1, filepath2 = [os.path.join(dirpath, fn) for fn in filenames]
with open(filepath1, 'r') as fin1, open(filepath2, 'r') as fin2:
print("do something with " + str(fin1) + " and " + str(fin2))
I'm still not really sure what your program logic does, so you will have to interface the two yourself.
However, I noticed that you're adding the ".txt" extension to the file name explicitly all over your code, so depending on how you are going to use the snippet, you might or might not need to remove the ".txt" extension first before handing the filenames over. That would be achieved by inserting the following line after or before the sort:
filenames = [os.path.splitext(fn)[0] for fn in filenames]
Also, I still don't understand why you're using eval(). Do the text files contain python code? In any case, eval() should be avoided and be replaced by code that's more specific to the task at hand.
If it's a list of comma separated strings, use line.split(",") instead.
If there might be whitespace before or after the comma, use [word.strip() for word in line.split(",")] instead.
If it's a list of comma separated integers, use [int(num) for num in line.split(",")] instead - for floats it works analogously.
etc.

Iterate within directory to zip files with python

I need to iterate through a folder and find every instance where the filenames are identical (except for extension) and then zip (preferably using tarfile) each of these into one file.
So I have 5 files named: "example1" each with different file extensions. I need to zip them up together and output them as "example1.tar" or something similar.
This would be easy enough with a simple for loop such as:
tar = tarfile.open('example1.tar',"w")
for output in glob ('example1*'):
tar.add(output)
tar.close()
however, there are 300 "example" files and I need to iterate through each one and their associated 5 files in order to make this work. This is way over my head. Any advice greatly appreciated.

The pattern you're describing generalizes to MapReduce. I found a simple implementation of MapReduce online, from which an even-simpler version is:
def map_reduce(data, mapper, reducer):
d = {}
for elem in data:
key, value = mapper(elem)
d.setdefault(key, []).append(value)
for key, grp in d.items():
d[key] = reducer(key, grp)
return d
You want to group all files by their name without the extension, which you can get from os.path.splitext(fname)[0]. Then, you want to make a tarball out of each group by using the tarfile module. In code, that is:
import os
import tarfile
def make_tar(basename, files):
tar = tarfile.open(basename + '.tar', 'w')
for f in files:
tar.add(f)
tar.close()
map_reduce(os.listdir('.'),
lambda x: (os.path.splitext(x)[0], x),
make_tar)
Edit: If you want to group files in different ways, you just need to modify the second argument to map_reduce. The code above groups files that have the same value for the expression os.path.splitext(x)[0]. So to group by the base file name with all the extensions stripped off, you could replace that expression with strip_all_ext(x) and add:
def strip_all_ext(path):
head, tail = os.path.split(path)
basename = tail.split(os.extsep)[0]
return os.path.join(head, basename)

You could do this:
list all files in the directory
create a dictionary where the basename is the key and all the extensions are values
then tar all the files by dictionary key
Something like this:
import os
import tarfile
from collections import defaultdict
myfiles = os.listdir(".") # List of all files
totar = defaultdict(list)
# now fill the defaultdict with entries; basename as keys, extensions as values
for name in myfiles:
base, ext = os.path.splitext(name)
totar[base].append(ext)
# iterate through all the basenames
for base in totar:
files = [base+ext for ext in totar[base]]
# now tar all the files in the list "files"
tar = tarfile.open(base+".tar", "w")
for item in files:
tar.add(item)
tar.close()

You have to problems. Solve the separately.
Finding matching names. Use a collections.defaultict
Creating tar files after you find the matching names. You've got that pretty well covered.
So. Solve problem 1 first.
Use glob to get all the names. Use os.path.basename to split the path and basename. Use os.path.splitext to split the name and extension.
A dictionary of lists can be used to save all files that have the same name.
Is that what you're doing in part 1?
Part 2 is putting the files into tar archives. For that, you've got most of the code you need.

Try using the glob module: http://docs.python.org/library/glob.html

#! /usr/bin/env python
import os
import tarfile
tarfiles = {}
for f in os.listdir ('files'):
prefix = f [:f.rfind ('.') ]
if prefix in tarfiles: tarfiles [prefix] += [f]
else: tarfiles [prefix] = [f]
for k, v in tarfiles.items ():
tf = tarfile.open ('%s.tar.gz' % k, 'w:gz')
for f in v: tf.addfile (tarfile.TarInfo (f), file ('files/%s' % f) )
tf.close ()

import os
import tarfile
allfiles = {}
for filename in os.listdir("."):
basename = '.'.join (filename.split(".")[:-1] )
if not basename in all_files:
allfiles[basename] = [filename]
else:
allfiles[basename].append(filename)
for basename, filenames in allfiles.items():
if len(filenames) < 2:
continue
tardata = tarfile.open(basename+".tar", "w")
for filename in filenames:
tardata.add(filename)
tardata.close()