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Python Pathlib escaping string stored in variable

I'm on windows and have an api response that includes a key value pair like
object = {'path':'/my_directory/my_subdirectory/file.txt'}
I'm trying to use pathlib to open and create that structure relative to the current working directory as well as a user supplied directory name in the current working directory like this:
output = "output_location"
path = pathlib.Path.cwd().joinpath(output,object['path'])
print(path)
What this gives me is this
c:\directory\my_subdirectory\file.txt
Whereas I'm looking for it to output something like:
'c:\current_working_directory\output_location\directory\my_subdirectory\file.txt'
The issue is because the object['path'] is a variable I'm not sure how to escape it as a raw string. And so I think the escapes are breaking it. I can't guarantee there will always be a leading slash in the object['path'] value so I don't want to simply trim the first character.
I was hoping there was an elegant way to do this using pathlib that didn't involve ugly string manipulation.

Try lstrip('/')
You want to remove your leading slash whenever it’s there, because pathlib will ignore whatever comes before it.

import pathlib
object = {'path': '/my_directory/my_subdirectory/file.txt'}
output = "output_location"
# object['path'][1:] removes the initial '/'
path = pathlib.PureWindowsPath(pathlib.Path.cwd()).joinpath(output,object[
'path'][1:])
# path = pathlib.Path.cwd().joinpath(output,object['path'])
print(path)

How to make subfolders inside a parameterized folder?

I made a folder and inside there are 100 subfolders which are made by parameters. Now I want to create one subfolder inside each of this 100 subfolders. But whatever I am doing it is not working.
I added a simple example.
number=[1,2,3]
for i in range (len(number)):
Name = 'GD_%d'%(number[i])
os.mkdir('C:/Temp/t2_t1_18/'+Name) #till this works fine
subfolder_name='S1_%d'%(number[i])
#This does not work and idea somehow not correct
os.mkdir(os.path.join('C:/Temp/t2_t1_18/Name'+subfolder_name))

Some Notes
It is better not to use string concatenation when concatenating paths.
Since you just need the numbers it is better to iterate over them, instead of using range
You can take a look at python's new way of formatting https://realpython.com/python-f-strings/
Assuming I got your question right and you want to create a subdirectory in the newly created directory, I would do something like that
import os
numbers = [1,2,3]
main_dir = os.path.normpath('C:/Temp/t2_t1_18/')
for number in numbers:
dir_name = f'GD_{number}'
# dir_name = 'GD_{}'.format(number) # python < 3.6
dir_path = os.path.join(main_dir, dir_name)
os.mkdir(dir_path)
subdir_name = f'S1_{number}'
subdir_path = os.path.join(dir_path, subdir_name)
os.mkdir(subdir_path)

There is a better answer to your question already.
In your example this should be an easy solution (if your Python version is sufficient):
from pathlib import Path
numbers = (1, 2, 3, 4)
for n in numbers:
Path(f"C:/Temp/t2_t1_18/GD_{n}/S1_{n}").mkdir(parents=True, exist_ok=True)

I'm not certain I understand what you're trying to do, but here is a version of your code that is cleaned up a bit. It assumes the C:\Temp directory exists, and will create 3 folders in C:\Temp, and 1 subfolder in each of those 3 folders.
import os
numbers = [1,2,3]
base_path = os.path.join('C:/', 'Temp')
for number in numbers:
# create the directory C:\Temp\{name}
os.mkdir(os.path.join(base_path, f'GD_{number}'))
# create the directory C:\Temp\{name}\{subfolder_name}
os.mkdir(os.path.join(base_path, f'GD_{number}', f'S1_{number}'))
Some Notes and Tips:
Indentation is part of the syntax in python, so make sure you indent every line that is in a code block (such as your for loop)
There are many ways to format strings, I like f-strings (a.k.a. string interpolation) which were introduced in python 3.6. If you're using an earlier version of python, either update, or use a different string formatting method. Whatever you choose, be consistent.
It is a good idea to use os.path.join() when working with paths, as you were trying to do. I expanded the use of this method in the code above.
As another answer pointed out, you can simply iterate over your numbers collection instead of using range() and indexing.

How to modify a path which's in a variable (python)?

After finding the path of the Python file which I am actually working on with os.getcwd() and __file__ I want to modify it, so if I put it in a variable named r and then delete one part of the path that will be very good. For example, the path is 'C:\\Users\\Shadow\\Desktop\\213.py' if I want to delete \\213.py from the path (r) how can I do that?

you can manipulate your string:
r = 'C:\\Users\\Shadow\\Desktop\\213.py'
r.rsplit('\\', 1)[0]
output:
'C:\\Users\\Shadow\\Desktop'
you may also want to have a look over pathlib.Path

You extract the directory name in your example. This is easily achieved with os.path.dirname.
import os
os.path.dirname(__file__)
This solution is cross-platform (mostly), and avoids most pitfalls that arise from treating paths as strings.
If you need the value stored in a variable:
import os
r = on.path.dirname(__file__)

How to deal with multiple dots in a file name with Python pathlib?

I am having an issue with pathlib when I try to construct a file path that has a "." in its name, the pathlib module ignores it.
Here are example lines (I tried multiple versions, all resulted the same issue)
The issue is that the original file name will be coming from another application, so it is not like I can edit the name myself. I also do not want to do string replacement work arounds, if possible.
path=r"c:\temp"
1
p=Path(path).joinpath("myfile.001").with_suffix(".bat")
2
p=Path(path, "myfile.001").with_suffix(".bat")
3
p=Path(path).with_name("myfile.001").with_suffix(".bat")
All these lines will yield to
WindowsPath('C:/temp/myfile.bat')
So how do I make pathlib.Path to construct this full path properly. The final path has to be
WindowsPath('C:/temp/myfile.001.bat')
Not
WindowsPath('C:/temp/myfile.bat')
Naturally I am looking for a way to do it through pathlib itself, otherwise I can just use os.
thanks

You are telling pathlib to replace the suffix .001 with the suffix .bat. pathlib complies.
Tell pathlib to add .bat to the existing suffix.
p = Path(path, 'myfile.001')
p = p.with_suffix(p.suffix+'.001')

Python os.path.join() mangling absolute path in Windows

I'm new to Python and I'm trying to access a file with a full path represented by the following:
'X:/01 File Folder/MorePath/Data/Test/myfile.txt'
Every time I try to build the full string using os.path.join, it ends up slicing out everything between the drive letter and the second path string, like so:
import os
basePath = 'X:/01 File Folder/MorePath'
restofPath = '/Data/Test/myfile.txt'
fullPath = os.path.join(basePath,restofPath)
gives me:
'X:/Data/Test/myfile.txt'
as the fullPath name.
Can anyone tell me what I'm doing wrong? Does it have something to do with the digits near the beginning of the base path name?

The / at the beginning of your restofPath means "start at the root directory." So os.path.join() helpfully does that for you.
If you don't want it to do that, write your restofPath as a relative directory, i.e., Data/Test/myfile.txt, rather than an absolute one.
If you are getting your restofPath from somewhere outside your program (user input, config file, etc.), and you always want to treat it as relative even if the user is so gauche as to start the path with a slash, you can use restofPath.lstrip(r"\/").