Develop Reference

Python and CSV: find a row that is given by the user and give column value

It consists in creating a function that searches for the name that the user will give us and we need to print his email
here is a small part of the CSV file and it is structured as this:
Name
Email
mahmoud
mahmoud.123#gmail.com
sam
sam.123#gmail.com
import pandas as pd
data = pd.read_csv(r'C:\Users\samer\Downloads\cvs\mail list.csv')
print (data)
df= pd.DataFrame()
df['Name1'] = input("Enter Name:")
for row in data:
if row == "Name1":
print(row)
I have been stuck here, i dont know how to print the email after checking if the name the user gives us exist
here's an example of the output:
if the user gives a name that is sam
the output will be sam.123#gmail.com

You can assign the Name column to the index when loading the CSV to a DataFrame and then use .loc to locate the name explicitly:
import pandas as pd
df = pd.read_csv(r'./mail list.csv', index_col='Name')
name = input("Enter Name:")
email = df.loc[name, 'Email']
Which results in
sam.123#gmail.com

Admitting all your names in Name column are unique :
def get_email(df, name):
email_list = list(df.loc[df["Name"] == name]["Email"])
if email_list:
print(email_list[0])
else:
print("User does not exist")
get_email(df, "sam")
[Out] : sam.123#gmail.com
get_email(df, "Jean")
[Out] : User does not exist
Edit: I used this data to run the test:
Name Email
mahmoud mahmoud.123#gmail.com
sam sam.123#gmail.com

Extract data from text file using Python (or any language)

I have a text file that looks like:
First Name Bob
Last name Smith
Phone 555-555-5555
Email bob#bob.com
Date of Birth 11/02/1986
Preferred Method of Contact Text Message
Desired Appointment Date 04/29
Desired Appointment Time 10am
City Pittsburgh
Location State
IP Address x.x.x.x
User-Agent (Browser/OS) Apple Safari 14.0.3 / OS X
Referrer http://www.example.com
First Name john
Last name Smith
Phone 555-555-4444
Email john#gmail.com
Date of Birth 03/02/1955
Preferred Method of Contact Text Message
Desired Appointment Date 05/22
Desired Appointment Time 9am
City Pittsburgh
Location State
IP Address x.x.x.x
User-Agent (Browser/OS) Apple Safari 14.0.3 / OS X
Referrer http://www.example.com
.... and so on
I need to extract each entry to a csv file, so the data should look like: first name, last name, phone, email, etc. I don't even know where to start on something like this.

first of all you'll need to open the text file in read mode.
I'd suggest using a context manager like so:
with open('path/to/your/file.txt', 'r') as file:
for line in file.readlines():
# do something with the line (it is a string)
as for managing the info you could build some intermediate structure, for example a dictionary or a list of dictionaries, and then translate that into a CSV file with the csv module.
you could for example split the file whenever there is a blank line, maybe like this:
with open('Downloads/test.txt', 'r') as f:
my_list = list() # this will be the final list
entry = dict() # this contains each user info as a dict
for line in f.readlines():
if line.strip() == "": # if line is empty start a new dict
my_list.append(entry) # and append the old one to the list
entry = dict()
else: # otherwise split the line and create new dict
line_items = line.split(r' ')
print(line_items)
entry[line_items[0]] = line_items[1]
print(my_list)
this code won't work because your text is not formatted in a consistent way: you need to find a way to make the split between "title" and "content" (like "first name" and "bob") in a consistent way. I suggest maybe looking at regex and fixing the txt file by making spacing more consistent.

assuming the data resides in a:
a="""
First Name Bob
Last name Smith
Phone 555-555-5555
Email bob#bob.com
Date of Birth 11/02/1986
Preferred Method of Contact Text Message
Desired Appointment Date 04/29
Desired Appointment Time 10am
City Pittsburgh
Location State
IP Address x.x.x.x
User-Agent (Browser/OS) Apple Safari 14.0.3 / OS X
Referrer http://www.example.com
First Name john
Last name Smith
Phone 555-555-4444
Email john#gmail.com
Date of Birth 03/02/1955
Preferred Method of Contact Text Message
Desired Appointment Date 05/22
Desired Appointment Time 9am
City Pittsburgh
Location State
IP Address x.x.x.x
User-Agent (Browser/OS) Apple Safari 14.0.3 / OS X
Referrer http://www.example.com
"""
line_sep = "\n" # CHANGE ME ACCORDING TO DATA
fields = ["First Name", "Last name", "Phone",
"Email", "Date of Birth", "Preferred Method of Contact",
"Desired Appointment Date", "Desired Appointment Time",
"City", "Location", "IP Address", "User-Agent","Referrer"]
records = a.split(line_sep * 2)
all_records = []
for record in records:
splitted_record = record.split(line_sep)
one_record = {}
csv_record = []
for f in fields:
found = False
for one_field in splitted_record:
if one_field.startswith(f):
data = one_field[len(f):].strip()
one_record[f] = data
csv_record.append(data)
found = True
if not found:
csv_record.append("")
all_records.append(";".join(csv_record))
one_record will have the record as dictionary and csv_record will have it as a list of fields (ordered as fields variable)

Edited to add: ignore this answer, the code from Koko Jumbo looks infinitely more sensible and actually gives you a CVS file at the end of it! It was a fun exercise though :)
Just to expand on fcagnola's code a bit.
If it's a quick and dirty one-off, and you know that the data will be consistently presented, the following should work to create a list of dictionaries with the correct key/value pairing. Each line is processed by splitting the line and comparing the line number (reset to 0 with each new dict) against an array of values that represent where the boundary between key and value falls.
For example, "First Name Bob" becomes ["First","Name","Bob"]. The function has been told that linenumber= 0 so it checks entries[linenumber] to get the value "2", which it uses to join the key name (items 0 & 1) and then join the data (items 2 onwards). The end result is ["First Name", "Bob"] which is then added to the dictionary.
class Extract:
def extractEntry(self,linedata,lineindex):
# Hardcoded list! The quick and dirty part.
# This is specific to the example data provided. The entries
# represent the index to be used when splitting the string
# between the key and the data
entries = (2,2,1,1,3,4,3,3,1,1,2,2,1)
return self.createNewEntry(linedata,entries[lineindex])
def createNewEntry(self,linedata,dataindex):
list_data = linedata.split()
key = " ".join(list_data[:dataindex])
data = " ".join(list_data[dataindex:])
return [key,data]
with open('test.txt', 'r') as f:
my_list = list() # this will be the final list
entry = dict() # this contains each user info as a dict
extr = Extract() # class for splitting the entries into key/value
x = 0
for line in f.readlines():
if line.strip() == "": # if line is empty start a new dict
my_list.append(entry) # and append the old one to the list
entry = dict()
x = 0
else: # otherwise split the line and create new dict
extracted_data = extr.extractEntry(line,x)
entry[extracted_data[0]] = extracted_data[1]
x += 1
my_list.append(entry)
print(my_list)

How to assign a name to a dictionary based on input from a user

How do we assign a dictionary a name that is taken from input from the user and save that dictionary to a txt file so that we can search for it by its name and print output to the user?
I am currently here:
Any ideas how?
import sys
import pathlib
'''Arg-V's should be in following order <app.py> <action> <nick_name> <name> <phone> <email>'''
if str(sys.argv[1]).lower == 'add':
current = {'Name': sys.argv[3], 'Phone Number': sys.argv[4], 'Email': sys.argv[5]}
with open('contacts.txt', 'w') as f:
f.write(current)

As per Naming Lists Using User Input :
An indirect answer is that, as several other users have told you, you don't want to let the user choose your variable names, you want to be using a dictionary of lists, so that you have all the lists that users have created together in one place.
import json
name = input('name/s of dictionary/ies : ')
names = {}
name = name.split()
print(name)
for i in name:
names[i]={}
print(names)
for i in names:
print(i,'--------->', names[i])
for i in names:
names[i] = '1'*len(i)
for i in names:
with open(i+'.txt', 'w+') as file:
file.write('prova : '+json.dumps(names[i]))

How to search a student ID with user input and output with the student name and student ID in python?

I am trying to split a studentID and studentName in a file called Student.txt so I can have a user input to search for a specific student id in the file and display the student name and ID. But I don't know how to separate the studentID and student name in the file.
this is the content of my file
201707001 Michael_Tan
201707002 Richard_Lee_Wai_Yong
201707003 Jean_Yip
201707004 Mark_Lee
201707005 Linda_Wong
201707006 Karen_Tan
201707007 James_Bond
201707008 Sandra_Smith
201707009 Paul_Garcia
201707010 Donald_Lim
And this is my attempted code in Python
# user can search the studentID
searchStudent = input("Please enter a student ID: ")
# read the students file
with open('C:\\Users\\jaspe\\Desktop\\PADS Assignment\\Student.txt') as f:
studentFile = f.readlines()
for student in studentFile:
print(student)

You can use student.split(" ") to split each line into id and name
searchStudent = input("Please enter a student ID: ")
with open('C:\\Users\\jaspe\\Desktop\\PADS Assignment\\Student.txt') as f:
studentFile = f.readlines()
for student in studentFile:
id, name = student.strip().split(" ", 1)

You need to parse every line and check if the Ids match. In other words, you need to split every line in two elements, id and name.
Check split documentation page.

You need to split each line using the space as a separator:
for line in studentFile:
uid, student = line.strip().split(" ")
print(student)

Converting a text file into csv file using python

I have a requirement where in I need to convert my text files into csv and am using python for doing it. My text file looks like this ,
Employee Name : XXXXX
Employee Number : 12345
Age : 45
Hobbies: Tennis
Employee Name: xxx
Employee Number :123456
Hobbies : Football
I want my CSV file to have the column names as Employee Name, Employee Number , Age and Hobbies and when a particular value is not present it should have a value of NA in that particular place. Any simple solutions to do this? Thanks in advance

You can do something like this:
records = """Employee Name : XXXXX
Employee Number : 12345
Age : 45
Hobbies: Tennis
Employee Name: xxx
Employee Number :123456
Hobbies : Football"""
for record in records.split('Employee Name'):
fields = record.split('\n')
name = 'NA'
number = 'NA'
age = 'NA'
hobbies = 'NA'
for field in fields:
field_name, field_value = field.split(':')
if field_name == "": # This is employee name, since we split on it
name = field_value
if field_name == "Employee Number":
number = field_value
if field_name == "Age":
age = field_value
if field_name == "Hobbies":
hobbies = field_value
Of course, this method assumes that there is (at least) Employee Name field in every record.

Maybe this helps you get started? It's just the static output of the first employee data. You would now need to wrap this into some sort of iteration over the file. There is very very likely a more elegant solution, but this is how you would do it without a single import statement ;)
with open('test.txt', 'r') as f:
content = f.readlines()
output_line = "".join([line.split(':')[1].replace('\n',';').strip() for line in content[0:4]])
print(output_line)

I followed very simple steps for this and may not be optimal but solves the problem. Important case here I can see is there can be multiple keys ("Employee Name" etc) in single file.
Steps
Read txt file to list of lines.
convert list to dict(logic can be more improved or complex lambdas can be added here)
Simply use pandas to convert dict to csv
Below is the code,
import pandas
etxt_file = r"test.txt"
txt = open(txt_file, "r")
txt_string = txt.read()
txt_lines = txt_string.split("\n")
txt_dict = {}
for txt_line in txt_lines:
k,v = txt_line.split(":")
k = k.strip()
v = v.strip()
if txt_dict.has_key(k):
list = txt_dict.get(k)
else:
list = []
list.append(v)
txt_dict[k]=list
print pandas.DataFrame.from_dict(txt_dict, orient="index")
Output:
0 1
Employee Number 12345 123456
Age 45 None
Employee Name XXXXX xxx
Hobbies Tennis Football
I hope this helps.