array with pairs - python

How to make a pair of an array with numbers?
array = []
subjects = raw_input("Subject: ")
array.append(subjects)
When I do this I will get an array like this:
["PSP","PMT","PMF"]
I wanted my output to be like this
[("PSP",1),("PMT",2),("PMF",3)]
How can I make it like that?

Try using p.write("\n".join(entires)).
Alternatively, if you do not wish to hold the entire string in memory, you may as well loop over it like so:
for line in entries:
p.write(line)

Related

How to turn this Matrix into a list of integers?

I am trying to extract a list of integers from a input that looks like this:
[[matrix([[0.57863575]])], [matrix([[0.57170157]])], [matrix([[0.44320711]])], [matrix([[0.37195535]])]]
I am trying to get an output like so:
[0.57863575,0.57170157,0.44320711,0.37195535]
What are my options?
You can use a loop comprehension:
from numpy import matrix
l = [[matrix([[0.57863575]])], [matrix([[0.57170157]])], [matrix([[0.44320711]])], [matrix([[0.37195535]])]]
[e[0].flat[0] for e in l]
output: [0.57863575, 0.57170157, 0.44320711, 0.37195535]
The real question is, how did you get this format in the first place? It might be better to fix it there.

Append does not update list values in Python

I would like to find the rolling mean of the last 10 elements in a list in Python, using something like:
...
mean_last_10 = stats.mean(data_list[i-10:i])
print("test mean", mean_last_10 )
array.append([id[i],a[i], mean_last_10])
The printed values look correct but the array shows that values for mean_last_10 is kept the same. Why is this the case? Should I use deepcopy?
Outside your for loop create a list
mean_last_10 = []
mean_last_10.append(stats.mean(data_list[i-10:i]))
array.append([id[i],a[i], mean_last_10[i]])

Extracting data out of Complex JSON

This is the JSON data I am using
In this dataset, I want to extract the value of "yaw" and store it into in camera_loc. My first attempt for the code was as follows:
with open(
"/home/siddhant/catkin_ws/src/view-adaptation/multi_sensors.json"
) as sensors:
multi_sensors = json.load(sensors)
camera_loc = [
multi_sensors["sensors"][0]["yaw"],
multi_sensors["sensors"][1]["yaw"],
multi_sensors["sensors"][2]["yaw"],
multi_sensors["sensors"][3]["yaw"],
multi_sensors["sensors"][4]["yaw"],
multi_sensors["sensors"][5]["yaw"],
]
This gives me the expected result.
But I want to generalize the same for any number of entries in the 'sensors' array.
I tried executing a 'for' loop and extracting the values for the same as follows:
for i in multi_sensors["sensors"]:
camera_loc = []
camera_loc.append(i["yaw"])
However, this method only gives a single value in the camera_loc list which is the last 'yaw' value from the JSON file. I am looking for a better approach or even any modifications to the way I execute the loop so that I can extract all the values of 'yaw' from the JSON file - in this example there are 6 entries but I want to generalize it for 'n' entries that may be created in other cases.
Thank you!
That's because you're defining your camera_loc array inside the loop, meaning every iteration resets it to []. This code should work if you remove the array definition from the loop:
camera_loc = []
for i in multi_sensors["sensors"]:
camera_loc.append(i["yaw"])
This is also a perfect use case for a List Comprehension:
camera_loc = [i["yaw"] for i in multi_sensors["sensors"]]
Both answers results in the same array though, so you may choose whichever you like most.

Best method to store in python [duplicate]

I'm trying to add items to an array in python.
I run
array = {}
Then, I try to add something to this array by doing:
array.append(valueToBeInserted)
There doesn't seem to be a .append method for this. How do I add items to an array?
{} represents an empty dictionary, not an array/list. For lists or arrays, you need [].
To initialize an empty list do this:
my_list = []
or
my_list = list()
To add elements to the list, use append
my_list.append(12)
To extend the list to include the elements from another list use extend
my_list.extend([1,2,3,4])
my_list
--> [12,1,2,3,4]
To remove an element from a list use remove
my_list.remove(2)
Dictionaries represent a collection of key/value pairs also known as an associative array or a map.
To initialize an empty dictionary use {} or dict()
Dictionaries have keys and values
my_dict = {'key':'value', 'another_key' : 0}
To extend a dictionary with the contents of another dictionary you may use the update method
my_dict.update({'third_key' : 1})
To remove a value from a dictionary
del my_dict['key']
If you do it this way:
array = {}
you are making a dictionary, not an array.
If you need an array (which is called a list in python ) you declare it like this:
array = []
Then you can add items like this:
array.append('a')
Arrays (called list in python) use the [] notation. {} is for dict (also called hash tables, associated arrays, etc in other languages) so you won't have 'append' for a dict.
If you actually want an array (list), use:
array = []
array.append(valueToBeInserted)
Just for sake of completion, you can also do this:
array = []
array += [valueToBeInserted]
If it's a list of strings, this will also work:
array += 'string'
In some languages like JAVA you define an array using curly braces as following but in python it has a different meaning:
Java:
int[] myIntArray = {1,2,3};
String[] myStringArray = {"a","b","c"};
However, in Python, curly braces are used to define dictionaries, which needs a key:value assignment as {'a':1, 'b':2}
To actually define an array (which is actually called list in python) you can do:
Python:
mylist = [1,2,3]
or other examples like:
mylist = list()
mylist.append(1)
mylist.append(2)
mylist.append(3)
print(mylist)
>>> [1,2,3]
You can also do:
array = numpy.append(array, value)
Note that the numpy.append() method returns a new object, so if you want to modify your initial array, you have to write: array = ...
Isn't it a good idea to learn how to create an array in the most performant way?
It's really simple to create and insert an values into an array:
my_array = ["B","C","D","E","F"]
But, now we have two ways to insert one more value into this array:
Slow mode:
my_array.insert(0,"A") - moves all values ​​to the right when entering an "A" in the zero position:
"A" --> "B","C","D","E","F"
Fast mode:
my_array.append("A")
Adds the value "A" to the last position of the array, without touching the other positions:
"B","C","D","E","F", "A"
If you need to display the sorted data, do so later when necessary. Use the way that is most useful to you, but it is interesting to understand the performance of each method.
I believe you are all wrong. you need to do:
array = array[] in order to define it, and then:
array.append ["hello"] to add to it.

Can I condense these values with a loop?

I have a set of values that get modified like so:
iskDropped = irrelevant1
iskDestroyed = irrelevant2
iskTotal = irrelevant3
iskDropped = condense_value(int(iskDropped[:-7].replace(',','')))
iskDestroyed = condense_value(int(iskDestroyed[:-7].replace(',','')))
iskTotal = condense_value(int(iskTotal[:-7].replace(',','')))
As you can see, all three lines go through the same changes. (condensed, shortened, and commas removed) before overwriting their original value.
I want to condense those three lines if possible because it feels inefficient.
I was trying something like this:
for value in [iskDropped,iskDestroyed,iskTotal]:
value = condense_value(int(value[:-7].replace(',','')))
which if you changed into a print statement successfully does print the correct values but it does not work in the regard of overwriting / updating the values (iskDropped,iskDestroyed, and iskTotal) that I need to call later in the program.
Is it possible to condense these lines in Python? If so can someone point me in the right direction?
You can do it like this:
iskDropped, iskDestroyed, iskTotal = [condense_value(int(value[:-7].replace(',',''))) for value in [iskDropped, iskDestroyed, iskTotal]]
This works by looping through the list of your 3 variables, performing the condense_value function on each and creates a list of the results, then finally unpacks the list back into the original values.

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