I have been able to figure out how to get the name of the attached file in an email. i am just stuck after that. I don't know what to do after that, I have tried using os.path.join which just gives the path i want to download the folder to and joins it with the filename. Please suggest something. Thanks.
m = imaplib.IMAP4_SSL('outlook.office365.com',993)
m.login("UN", "PW")
m.select("Inbox")
typ, msgs = mail.search(None, '(SUBJECT "qwerty")')
msgs = msgs[0].split()
for emailid in msgs:
resp, data = mail.fetch(emailid, "(RFC822)")
email_body = data[0][1]
m = email.message_from_bytes(email_body)
if m.get_content_maintype() != 'multipart':
continue
for part in m.walk():
if part.get_content_maintype() == 'multipart':
continue
if part.get('Content-Disposition') is None:
continue
filename = part.get_filename()
print(filename)
Following the sample from this link you can set the path when using the open function. (raw string by prefixing the string with r)
fp = open(r'c:\tmp\folder\' + filename, 'wb')
fp.write(part.get_payload(decode=True))
fp.close()
print '%s saved!' % filename
Related
I am using python 3.7 and the email, imap library to read email and extract the content of email and attachments , all the attachment ( like excel, csv, pdf) is downloading as attachment but when i received any .eml file in email , it shows me error, please find the below code to read email content and attachment with error showing in case of eml file is received as attachment.
it is showing error at the time of writing eml file.
at the time of write part.get_payload(decode=True) is coming blank in eml file case.
filename = part.get_filename()
if filename is not None:
dot_position = filename.find('.')
file_prefix = filename[0:dot_position]
file_suffix = filename[dot_position:len(filename)]
# print(dot_position)
# print(file_prefix)
# print(file_suffix)
now = datetime.datetime.now()
timestamp = str(now.strftime("%Y%m%d%H%M%S%f"))
newFileName = file_prefix + "_" + timestamp + file_suffix
sv_path = os.path.join(svdir, newFileName)
# allfiles = allfiles.append([{"oldfilename": filename, "newfilename": newFileName}])
mydict = filename + '$$' + newFileName
mydict1 = mydict1 + ',' + mydict
print(mydict1)
if not os.path.isfile(sv_path):
print("oldpath:---->" + sv_path)
# filename = os.rename(filename, filename + '_Rahul')
# sv_path = os.path.join(svdir, filename)
# print("Newpath:---->" + sv_path)
fp = open(sv_path, 'wb')
# print("Rahul")
print(part.get_payload(decode=True))
# try:
# newFileByteArray = bytearray(fp)
# if part.get_payload(decode=True) is not None:
fp.write(part.get_payload(decode=True))
# except (TypeError, IOError):
# pass
fp.close()
Error is
<class 'TypeError'> ReadEmailUsingIMAP.py 129
a bytes-like object is required, not 'NoneType'
Just to explain why this is happening (it hit me too), quoting the v. 3.5 library doc. (v2 says the same):
If the message is a multipart and the decode flag is True, then None is returned.
If your attachment is an .EML, it's almost always going to be multi-part, thus the None.
Jin Thakur's workaround is appropriate if you're only expecting .EML multipart attachments (not sure if there is any other use cases); it should have been accepted as an answer.
Use eml_parser
https://pypi.org/project/eml-parser/
import datetime
import json
import eml_parser
def json_serial(obj):
if isinstance(obj, datetime.datetime):
serial = obj.isoformat()
return serial
with open('sample.eml', 'rb') as fhdl:
raw_email = fhdl.read()
parsed_eml = eml_parser.eml_parser.decode_email_b(raw_email)
print(json.dumps(parsed_eml, default=json_serial))
I am trying to save excel file attachments from my inbox to a directory. My code is executing just fine because I am seeing the print outs but the attachments wont save in the file directory. Is there something I am missing in my code that is preventing the action of saving?
import email, getpass, imaplib, os, sys
detach_dir = r'\directory link'
user = "test"
pwd = "test"
sender_email = "example#example.com"
m = imaplib.IMAP4_SSL("outlook.office365.com")
m.login(user,pwd)
m.select('"INBOX/somestuff"')
print("ok")
resp, items = m.search(None, 'FROM', '"%s"' % sender_email)
items = items[0].split()
print("ok")
for emailid in items:
resp, data = m.fetch(emailid, "(RFC822)")
email_body = data[0][1].decode('utf-8')
mail = email.message_from_string(email_body)
print("ok")
if mail.get_content_maintype() != 'multipart':
continue
subject = ""
if mail["subject"] is not None:
subject = mail["subject"]
print ("["+mail["From"]+"] :" + subject)
for part in mail.walk():
if part.get_content_maintype() == 'multipart':
continue
if part.get('Content-Disposition') is None:
continue
filename = part.get_filename()
counter = 1
if not filename:
filename = 'part-%03d%s' % (counter, 'bin')
counter += 1
att_path = os.path.join(detach_dir, filename)
if not os.path.isfile(att_path) :
fp = open(att_path, 'wb')
fp.write(part.get_payload(decode=True))
fp.close()
This code saves just one of the attachments in the subfolder but I am looking to get all attachments save to the directory:
detach_dir = r'directory link'
m = imaplib.IMAP4_SSL("outlook.office365.com")
m.login('user','pass')
m.select('"INBOX/subfolder"')
resp, items = m.search(None, 'All')
items = items[0].split()
for emailid in items:
resp, data = m.fetch(emailid, "(RFC822)")
filename = part.get_filename()
print(filename)
att_path = os.path.join(detach_dir, filename)
fp = open(att_path, 'wb')
fp.write(part.get_payload(decode=True))
fp.close()
print('check folder')
Question: This code saves just one of the attachments ... but I am looking to get all attachments
Implement iter-attachments()
resp, items = imap.search(None, "(UNSEEN)")
for n, num in enumerate(items[0].split(), 1):
resp, data = imap.fetch(num, '(RFC822)')
data01 = data[0][1]
msg_obj = email.message_from_string(data01)
for part in msg_obj.iter_attachments():
filename = part.get_filename()
print(filename)
iter_attachments()
Return an iterator over all of the immediate sub-parts of the message that are not candidate “body” parts. That is, skip the first occurrence of each of text/plain, text/html, multipart/related, or multipart/alternative (unless they are explicitly marked as attachments via Content-Disposition: attachment), and return all remaining parts.
Used modules and classes:
class imaplib.IMAP4
class email.message.EmailMessage
Here’s an example of how to unpack a MIME message, using email.message.walk(), into a directory of files:
I'm trying to use python imaplib.IMAP4_SSL to download attachments from gmail. But the problem is if the attachment is larger than 25M, it will be automatically converted to a file in google drive. By using the code below, I cannot find the attachment. Does anyone know how to access and download the file in google drive attached in gmail?
conn = imaplib.IMAP4_SSL("imap.gmail.com")
conn.login(config.username, config.password)
conn.select("Inbox")
resp, items = conn.search(None, '(FROM "xx#xx.com")')
items = items[0].split()
flag = False
emailid = items[-1]
resp, data = conn.fetch(emailid, "(RFC822)")
email_body = data[0][1]
mail = email.message_from_string(email_body)
msg = email.message_from_string(data[0][1])
for part in mail.walk():
if (part.get_content_maintype() == 'multipart'):
continue
if (part.get('Content-Disposition') is None):
continue
attachment_name = part.get_filename()
filename = "attachment_trial.xlsx"
fp = open(filename, 'wb')
fp.write(part.get_payload(decode = True))
fp.close()
flag = True
return flag
I have a script that fetches emails from my account, downloads the attachments, creates some html for an email blast program, and then zips them into a nice little archive. This works well when only one email is present in the inbox, however, the script hangs when multiple emails exist. I feel like this is because the section of the script that zips the files is not looping correctly. What I am trying to accomplish is one zip file for each email. 3 emails in the inbox = 3 seperate zip files. I've done my best to reduce my code for maximum readability while still maintaining the core structure. Could anyone point me in the right direction here? Thanks!
Code:
for emailid in items:
resp, data = m.fetch(emailid, "(RFC822)")
email_body = data[0][1]
mail = email.message_from_string(email_body)
for part in mail.walk():
if part.get_content_type() == 'text/plain':
content = part.get_payload()
#do something/define variables from email contents
if mail.get_content_maintype() != 'multipart':
continue
for part in mail.walk():
if part.get_content_maintype() == 'multipart':
continue
if part.get('Content-Disposition') is None:
continue
filename = part.get_filename()
counter = 1
if not filename:
filename = 'part-%03d%s' % (counter, 'bin')
counter += 1
att_path = os.path.join(detach_dir, filename)
if not os.path.isfile(att_path) :
fp = open(att_path, 'wb')
fp.write(part.get_payload(decode=True))
fp.close()
path = 'C:\directory'
os.chdir(path)
for file in os.listdir('.'):
#download attachments
htmlFile = str(token)+'.html'
htmlCode = ('<html>HTML goes here</html>')
htmlData = open(os.path.join('C:\directory', htmlFile), 'w+')
htmlData.write(htmlCode)
print htmlFile+' Complete'
htmlData.close()
allFiles = [f for f in os.listdir('.')]
for file in allFiles:
archive = zipfile.ZipFile(token+'.zip', mode='a')
archive.write(file)
archive.close()
os.unlink(file)
UPDATE
Here is alink to the complete code. http://ideone.com/WEXv9P
There seems to be a mistake here:
counter = 1
if not filename:
filename = 'part-%03d%s' % (counter, 'bin')
counter += 1
Counter will always be 1 in this loop, you probably want to define it before the second
for part in mail.walk():
EDIT:
Okay, so I think the problem is at the last part of the code
allFiles = [f for f in os.listdir('.')]
for file in allFiles:
archive = zipfile.ZipFile(token+'.zip', mode='a')
archive.write(file)
archive.close()
os.unlink(file)
this will create a zip file for each part of the email
I think what you want to do is indent this out a level and change it to something more like this:
allFiles = [f for f in os.listdir(detach_dir) if not f.endswith(".zip")]
for file in allFiles:
archive = zipfile.ZipFile(token+'.zip', mode='a')
archive.write(file)
archive.close()
os.unlink(file)
That way it won't recursively zip other zip files or remove them
I have a file that contain a tiff image and a document xml in a multipart mime document.
I would extract the image from this file.
How I can get it?
I have this code, but it requires an infinite time to extract it, if I have a big file (for example 30Mb), so this is unuseful.
f=open("content_file.txt","rb")
msg = email.message_from_file(f)
j=0
image=False
for i in msg.walk():
if i.is_multipart():
#print "MULTIPART: "
continue
if i.get_content_maintype() == 'text':
j=j+1
continue
if i.get_content_maintype() == 'image':
image=True
j=j+1
pl = i.get_payload(decode=True)
localFile = open("map.out.tiff", 'wb')
localFile.write(pl)
continue
f.close()
if (image==False):
sys.exit(0);
Thank you so much.
Solved:
def extract_mime_part_matching(stream, mimetype):
"""Return the first element in a multipart MIME message on stream
matching mimetype."""
msg = mimetools.Message(stream)
msgtype = msg.gettype()
params = msg.getplist()
data = StringIO.StringIO()
if msgtype[:10] == "multipart/":
file = multifile.MultiFile(stream)
file.push(msg.getparam("boundary"))
while file.next():
submsg = mimetools.Message(file)
try:
data = StringIO.StringIO()
mimetools.decode(file, data, submsg.getencoding())
except ValueError:
continue
if submsg.gettype() == mimetype:
break
file.pop()
return data.getvalue()
From:
http://docs.python.org/release/2.6.6/library/multifile.html
Thank you for the support.
It is not quite clear to me, why your code hangs. The indentation looks a bit wrong and opened files are not properly closed. You may also be low on memory.
This version works fine for me:
import email
import mimetypes
with open('email.txt') as fp:
message = email.message_from_file(fp)
for i, part in enumerate(message.walk()):
if part.get_content_maintype() == 'image':
filename = part.get_filename()
if not filename:
ext = mimetypes.guess_extension(part.get_content_type())
filename = 'image-%02d%s' % (i, ext or '.tiff')
with open(filename, 'wb') as fp:
fp.write(part.get_payload(decode=True))
(Partly taken from http://docs.python.org/library/email-examples.html#email-examples)