I got a model where I would like to create a folder when a model is created:
The model:
class Drive(models.Model):
user = models.ManyToManyField(User)
id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
path = models.CharField(max_length=150, editable=False,
default='C:/Users/User/Desktop/Python/RavNet/media/storage/drives/{}'.format(str(id)))
def save(self):
super().save()
I am trying to use signals, but I must admit this is my first ever attempt at making a signal not following a tutorial on point, and even after reading the documentation I am having a tough time.
from django.db.models.signals import post_save
from django.dispatch import receiver
from .models import Drive
import os
#receiver(post_save, sender=Drive)
def create_drive(sender, instance, created, **kwargs):
if created:
os.mkdir(Drive.path)
Nothing happens when I create a new drive model via the django admin. I have tested out my code in the shell and using a placeholder path (C:/Users/User/Desktop/Python/RavNet/media/storage/drives/test) that I know works in the signal in a try to debug, and have gotten as far as realising I am having two issues.
The first: When calling the Drive.path in the shell, I am getting the path:
'C:/Users/User/Desktop/Python/RavNet/media/storage/drives/<django.db.models.fields.UUIDField>'
Instead of a path with the actual id as I hoped for. How do I solve this?
Secondly, my signal isn't working. It's like it isn't getting called. What am I doing wrong?
You must import your signals in app.py. Please check your app.py. It must be like this:
from django.apps import AppConfig
class YourAppConfig(AppConfig):
name = '...'
def ready(self):
import your_project.your_app.signals
Also your app/__init__.py must include this code:
default_app_config = 'your_project.your_app.apps.YourAppConfig'
In case you have many signals and don't want the app.py defined in your app.
you could do so:
signals are in folder app/signals/__init__.py signal1.py signal2.py
import all files in __init__.py
from .signal1 import *
from .signal2 import *
from app.signals import * inside of app/views/__init__.py
I've updated from Django 1.8 to 1.9.
apps/comment/__init__.py (in 1.8)
from .models import Mixin
In Django 1.9 this no longer works but I still want to import Mixin in the same way.
So I tried this:
apps/comment/__init__.py
default_app_config = 'comment.apps.CommentConfig'
apps/comment/apps.py
# Django imports.
from django.apps import AppConfig
class CommentConfig(AppConfig):
name = 'comments'
def ready(self):
"""
Perform initialization tasks.
"""
from .models import CommentMixin
This however, does not appear to work, i.e. I cannot do from comment import Mixin, why?
Adding from .models import CommentMixin imports CommentMixin so that you can use it inside the ready() method. It does not magically add it to the comment module so that you can access it as comments.CommentMixin
You could assign it to the comments module in the ready() method.
# Django imports.
from django.apps import AppConfig
import comments
class CommentConfig(AppConfig):
name = 'comments'
def ready(self):
"""
Perform initialization tasks.
"""
from .models import CommentMixin
comments.CommentMixin = CommentsMixin
However I would discourage you from doing this, you might end up with hard-to-debug import errors later on. I would just change your imports to from comment.models import CommentMixin.
I'm trying to define a constant with the value of model's class in the settings.py to provide a dynamically-defined FK for one of my models:
from catalog.models import Product
PRODUCT_MODEL = Product
No surprise it's leading to an AppRegistryNotReady exception:
django.core.exceptions.AppRegistryNotReady: Apps aren't loaded yet.
since there was no call to django.setup() method.
If I add
import django
django.setup()
in front of the model's import, instead of AppRegistryNotReady exception, I'm getting
AttributeError: 'Settings' object has no attribute 'PRODUCT_MODEL'
when I'm using
from django.conf import settings
...
product = models.ForeignKey(
settings.PRODUCT_MODEL,
related_name='order_items')
Is there any way to implement this without errors?
I'm using Python 3.5 and Django 1.9.5.
You shouldn't import models or call django.setup() in your settings file.
Instead, use a string to refer to your model.
PRODUCT_MODEL = 'catalog.Product'
Then, in your models, you can use the setting.
product = models.ForeignKey(
settings.PRODUCT_MODEL,
related_name='order_items',
)
Note that the AUTH_USER_MODEL setting uses a string like this, you do not import the user model in the settings file.
Store the model name as a string.
In settings.py:
PRODUCT_MODEL = 'YourModel'
In your models.py:
from django.apps import AppConfig
....
field = models.ForeignKey(AppConfig.get_model(PRODUCT_MODEL))
(This works from Django 1.9.)
Use catalog.Product in settings and lazy import
In the name of maintainability, I moved some of my larger models to their own files. So before i had this:
app/
models.py
and now I have this:
app/
models/
__init__.py
model_a.py
model_b.py
This works fine, but when I use manage.py to do sync db, it doesn't create a table for these models anymore.
Am I forgetting something?
Thanks,
Models must be found in module named app.models where app is an app name. So you should write in app/models/__init__.py file
from model_a import *
from model_b import *
In Django < 1.7
Note fron django 1.7 onwards this is not neccessary.
Moreover --- (that's what I had problem with) you will have to manually update app_label attribute for your models, so write:
__all__ = ["ModelA", "ModelA1"]
class ModelA(models.Model):
class Meta:
app_label = 'your_app'
without it app will be set incorrectly by django.
If you are afreid that from model_a import * are evil you allways can set up __all__ attributes in all modules.
You need to set Meta.app_label for each of the models to the app name where it belongs and make sure they are imported from models/__init__.py.
You can have a look here for more details: https://code.djangoproject.com/wiki/CookBookSplitModelsToFiles
I have a Django app that requires a settings attribute in the form of:
RELATED_MODELS = ('appname1.modelname1.attribute1',
'appname1.modelname2.attribute2',
'appname2.modelname3.attribute3', ...)
Then hooks their post_save signal to update some other fixed model depending on the attributeN defined.
I would like to test this behaviour and tests should work even if this app is the only one in the project (except for its own dependencies, no other wrapper app need to be installed). How can I create and attach/register/activate mock models just for the test database? (or is it possible at all?)
Solutions that allow me to use test fixtures would be great.
You can put your tests in a tests/ subdirectory of the app (rather than a tests.py file), and include a tests/models.py with the test-only models.
Then provide a test-running script (example) that includes your tests/ "app" in INSTALLED_APPS. (This doesn't work when running app tests from a real project, which won't have the tests app in INSTALLED_APPS, but I rarely find it useful to run reusable app tests from a project, and Django 1.6+ doesn't by default.)
(NOTE: The alternative dynamic method described below only works in Django 1.1+ if your test case subclasses TransactionTestCase - which slows down your tests significantly - and no longer works at all in Django 1.7+. It's left here only for historical interest; don't use it.)
At the beginning of your tests (i.e. in a setUp method, or at the beginning of a set of doctests), you can dynamically add "myapp.tests" to the INSTALLED_APPS setting, and then do this:
from django.core.management import call_command
from django.db.models import loading
loading.cache.loaded = False
call_command('syncdb', verbosity=0)
Then at the end of your tests, you should clean up by restoring the old version of INSTALLED_APPS and clearing the app cache again.
This class encapsulates the pattern so it doesn't clutter up your test code quite as much.
#paluh's answer requires adding unwanted code to a non-test file and in my experience, #carl's solution does not work with django.test.TestCase which is needed to use fixtures. If you want to use django.test.TestCase, you need to make sure you call syncdb before the fixtures get loaded. This requires overriding the _pre_setup method (putting the code in the setUp method is not sufficient). I use my own version of TestCase that lets me add apps with test models. It is defined as follows:
from django.conf import settings
from django.core.management import call_command
from django.db.models import loading
from django import test
class TestCase(test.TestCase):
apps = ()
def _pre_setup(self):
# Add the models to the db.
self._original_installed_apps = list(settings.INSTALLED_APPS)
for app in self.apps:
settings.INSTALLED_APPS.append(app)
loading.cache.loaded = False
call_command('syncdb', interactive=False, verbosity=0)
# Call the original method that does the fixtures etc.
super(TestCase, self)._pre_setup()
def _post_teardown(self):
# Call the original method.
super(TestCase, self)._post_teardown()
# Restore the settings.
settings.INSTALLED_APPS = self._original_installed_apps
loading.cache.loaded = False
I shared my solution that I use in my projects. Maybe it helps someone.
pip install django-fake-model
Two simple steps to create fake model:
1) Define model in any file (I usualy define model in test file near a test case)
from django_fake_model import models as f
class MyFakeModel(f.FakeModel):
name = models.CharField(max_length=100)
2) Add decorator #MyFakeModel.fake_me to your TestCase or to test function.
class MyTest(TestCase):
#MyFakeModel.fake_me
def test_create_model(self):
MyFakeModel.objects.create(name='123')
model = MyFakeModel.objects.get(name='123')
self.assertEqual(model.name, '123')
This decorator creates table in your database before each test and remove the table after test.
Also you may create/delete table manually: MyFakeModel.create_table() / MyFakeModel.delete_table()
I've figured out a way for test-only models for django 1.7+.
The basic idea is, make your tests an app, and add your tests to INSTALLED_APPS.
Here's an example:
$ ls common
__init__.py admin.py apps.py fixtures models.py pagination.py tests validators.py views.py
$ ls common/tests
__init__.py apps.py models.py serializers.py test_filter.py test_pagination.py test_validators.py views.py
And I have different settings for different purposes(ref: splitting up the settings file), namely:
settings/default.py: base settings file
settings/production.py: for production
settings/development.py: for development
settings/testing.py: for testing.
And in settings/testing.py, you can modify INSTALLED_APPS:
settings/testing.py:
from default import *
DEBUG = True
INSTALLED_APPS += ['common', 'common.tests']
And make sure that you have set a proper label for your tests app, namely,
common/tests/apps.py
from django.apps import AppConfig
class CommonTestsConfig(AppConfig):
name = 'common.tests'
label = 'common_tests'
common/tests/__init__.py, set up proper AppConfig(ref: Django Applications).
default_app_config = 'common.tests.apps.CommonTestsConfig'
Then, generate db migration by
python manage.py makemigrations --settings=<your_project_name>.settings.testing tests
Finally, you can run your test with param --settings=<your_project_name>.settings.testing.
If you use py.test, you can even drop a pytest.ini file along with django's manage.py.
py.test
[pytest]
DJANGO_SETTINGS_MODULE=kungfu.settings.testing
Quoting from a related answer:
If you want models defined for testing only then you should check out
Django ticket #7835 in particular comment #24 part of which
is given below:
Apparently you can simply define models directly in your tests.py.
Syncdb never imports tests.py, so those models won't get synced to the
normal db, but they will get synced to the test database, and can be
used in tests.
This solution works only for earlier versions of django (before 1.7). You can check your version easily:
import django
django.VERSION < (1, 7)
Original response:
It's quite strange but form me works very simple pattern:
add tests.py to app which you are going to test,
in this file just define testing models,
below put your testing code (doctest or TestCase definition),
Below I've put some code which defines Article model which is needed only for tests (it exists in someapp/tests.py and I can test it just with: ./manage.py test someapp ):
class Article(models.Model):
title = models.CharField(max_length=128)
description = models.TextField()
document = DocumentTextField(template=lambda i: i.description)
def __unicode__(self):
return self.title
__test__ = {"doctest": """
#smuggling model for tests
>>> from .tests import Article
#testing data
>>> by_two = Article.objects.create(title="divisible by two", description="two four six eight")
>>> by_three = Article.objects.create(title="divisible by three", description="three six nine")
>>> by_four = Article.objects.create(title="divisible by four", description="four four eight")
>>> Article.objects.all().search(document='four')
[<Article: divisible by two>, <Article: divisible by four>]
>>> Article.objects.all().search(document='three')
[<Article: divisible by three>]
"""}
Unit tests also working with such model definition.
I chose a slightly different, albeit more coupled, approach to dynamically creating models just for testing.
I keep all my tests in a tests subdirectory that lives in my files app. The models.py file in the tests subdirectory contains my test-only models. The coupled part comes in here, where I need to add the following to my settings.py file:
# check if we are testing right now
TESTING = 'test' in sys.argv
if TESTING:
# add test packages that have models
INSTALLED_APPS += ['files.tests',]
I also set db_table in my test model, because otherwise Django would have created the table with the name tests_<model_name>, which may have caused a conflict with other test models in another app. Here's my my test model:
class Recipe(models.Model):
'''Test-only model to test out thumbnail registration.'''
dish_image = models.ImageField(upload_to='recipes/')
class Meta:
db_table = 'files_tests_recipe'
Here's the pattern that I'm using to do this.
I've written this method that I use on a subclassed version of TestCase. It goes as follows:
#classmethod
def create_models_from_app(cls, app_name):
"""
Manually create Models (used only for testing) from the specified string app name.
Models are loaded from the module "<app_name>.models"
"""
from django.db import connection, DatabaseError
from django.db.models.loading import load_app
app = load_app(app_name)
from django.core.management import sql
from django.core.management.color import no_style
sql = sql.sql_create(app, no_style(), connection)
cursor = connection.cursor()
for statement in sql:
try:
cursor.execute(statement)
except DatabaseError, excn:
logger.debug(excn.message)
pass
Then, I create a special test-specific models.py file in something like myapp/tests/models.py that's not included in INSTALLED_APPS.
In my setUp method, I call create_models_from_app('myapp.tests') and it creates the proper tables.
The only "gotcha" with this approach is that you don't really want to create the models ever time setUp runs, which is why I catch DatabaseError. I guess the call to this method could go at the top of the test file and that would work a little better.
Combining your answers, specially #slacy's, I did this:
class TestCase(test.TestCase):
initiated = False
#classmethod
def setUpClass(cls, *args, **kwargs):
if not TestCase.initiated:
TestCase.create_models_from_app('myapp.tests')
TestCase.initiated = True
super(TestCase, cls).setUpClass(*args, **kwargs)
#classmethod
def create_models_from_app(cls, app_name):
"""
Manually create Models (used only for testing) from the specified string app name.
Models are loaded from the module "<app_name>.models"
"""
from django.db import connection, DatabaseError
from django.db.models.loading import load_app
app = load_app(app_name)
from django.core.management import sql
from django.core.management.color import no_style
sql = sql.sql_create(app, no_style(), connection)
cursor = connection.cursor()
for statement in sql:
try:
cursor.execute(statement)
except DatabaseError, excn:
logger.debug(excn.message)
With this, you don't try to create db tables more than once, and you don't need to change your INSTALLED_APPS.
If you are writing a reusable django-app, create a minimal test-dedicated app for it!
$ django-admin.py startproject test_myapp_project
$ django-admin.py startapp test_myapp
add both myapp and test_myapp to the INSTALLED_APPS, create your models there and it's good to go!
I have gone through all these answers as well as django ticket 7835, and I finally went for a totally different approach.
I wanted my app (somehow extending queryset.values() ) to be able to be tested in isolation; also, my package does include some models and I wanted a clean distinction between test models and package ones.
That's when I realized it was easier to add a very small django project in the package!
This also allows a much cleaner separation of code IMHO:
In there you can cleanly and without any hack define your models, and you know they will be created when you run your tests from in there!
If you are not writing an independent, reusable app you can still go this way: create a test_myapp app, and add it to your INSTALLED_APPS only in a separate settings_test_myapp.py!
Someone already mentioned Django ticket #7835, but there appears to be a more recent reply that looks much more promising for more recent versions of Django. Specifically #42, which proposes a different TestRunner:
from importlib.util import find_spec
import unittest
from django.apps import apps
from django.conf import settings
from django.test.runner import DiscoverRunner
class TestLoader(unittest.TestLoader):
""" Loader that reports all successful loads to a runner """
def __init__(self, *args, runner, **kwargs):
self.runner = runner
super().__init__(*args, **kwargs)
def loadTestsFromModule(self, module, pattern=None):
suite = super().loadTestsFromModule(module, pattern)
if suite.countTestCases():
self.runner.register_test_module(module)
return suite
class RunnerWithTestModels(DiscoverRunner):
""" Test Runner that will add any test packages with a 'models' module to INSTALLED_APPS.
Allows test only models to be defined within any package that contains tests.
All test models should be set with app_label = 'tests'
"""
def __init__(self, *args, **kwargs):
self.test_packages = set()
self.test_loader = TestLoader(runner=self)
super().__init__(*args, **kwargs)
def register_test_module(self, module):
self.test_packages.add(module.__package__)
def setup_databases(self, **kwargs):
# Look for test models
test_apps = set()
for package in self.test_packages:
if find_spec('.models', package):
test_apps.add(package)
# Add test apps with models to INSTALLED_APPS that aren't already there
new_installed = settings.INSTALLED_APPS + tuple(ta for ta in test_apps if ta not in settings.INSTALLED_APPS)
apps.set_installed_apps(new_installed)
return super().setup_databases(**kwargs)