Is there any argument or options to setup a timeout for Python's subprocess.Popen method?
Something like this:
subprocess.Popen(['..'], ..., timeout=20) ?
I would advise taking a look at the Timer class in the threading module. I used it to implement a timeout for a Popen.
First, create a callback:
def timeout( p ):
if p.poll() is None:
print 'Error: process taking too long to complete--terminating'
p.kill()
Then open the process:
proc = Popen( ... )
Then create a timer that will call the callback, passing the process to it.
t = threading.Timer( 10.0, timeout, [proc] )
t.start()
t.join()
Somewhere later in the program, you may want to add the line:
t.cancel()
Otherwise, the python program will keep running until the timer has finished running.
EDIT: I was advised that there is a race condition that the subprocess p may terminate between the p.poll() and p.kill() calls. I believe the following code can fix that:
import errno
def timeout( p ):
if p.poll() is None:
try:
p.kill()
print 'Error: process taking too long to complete--terminating'
except OSError as e:
if e.errno != errno.ESRCH:
raise
Though you may want to clean the exception handling to specifically handle just the particular exception that occurs when the subprocess has already terminated normally.
subprocess.Popen doesn't block so you can do something like this:
import time
p = subprocess.Popen(['...'])
time.sleep(20)
if p.poll() is None:
p.kill()
print 'timed out'
else:
print p.communicate()
It has a drawback in that you must always wait at least 20 seconds for it to finish.
import subprocess, threading
class Command(object):
def __init__(self, cmd):
self.cmd = cmd
self.process = None
def run(self, timeout):
def target():
print 'Thread started'
self.process = subprocess.Popen(self.cmd, shell=True)
self.process.communicate()
print 'Thread finished'
thread = threading.Thread(target=target)
thread.start()
thread.join(timeout)
if thread.is_alive():
print 'Terminating process'
self.process.terminate()
thread.join()
print self.process.returncode
command = Command("echo 'Process started'; sleep 2; echo 'Process finished'")
command.run(timeout=3)
command.run(timeout=1)
The output of this should be:
Thread started
Process started
Process finished
Thread finished
0
Thread started
Process started
Terminating process
Thread finished
-15
where it can be seen that, in the first execution, the process finished correctly (return code 0), while the in the second one the process was terminated (return code -15).
I haven't tested in windows; but, aside from updating the example command, I think it should work since I haven't found in the documentation anything that says that thread.join or process.terminate is not supported.
You could do
from twisted.internet import reactor, protocol, error, defer
class DyingProcessProtocol(protocol.ProcessProtocol):
def __init__(self, timeout):
self.timeout = timeout
def connectionMade(self):
#defer.inlineCallbacks
def killIfAlive():
try:
yield self.transport.signalProcess('KILL')
except error.ProcessExitedAlready:
pass
d = reactor.callLater(self.timeout, killIfAlive)
reactor.spawnProcess(DyingProcessProtocol(20), ...)
using Twisted's asynchronous process API.
A python subprocess auto-timeout is not built in, so you're going to have to build your own.
This works for me on Ubuntu 12.10 running python 2.7.3
Put this in a file called test.py
#!/usr/bin/python
import subprocess
import threading
class RunMyCmd(threading.Thread):
def __init__(self, cmd, timeout):
threading.Thread.__init__(self)
self.cmd = cmd
self.timeout = timeout
def run(self):
self.p = subprocess.Popen(self.cmd)
self.p.wait()
def run_the_process(self):
self.start()
self.join(self.timeout)
if self.is_alive():
self.p.terminate() #if your process needs a kill -9 to make
#it go away, use self.p.kill() here instead.
self.join()
RunMyCmd(["sleep", "20"], 3).run_the_process()
Save it, and run it:
python test.py
The sleep 20 command takes 20 seconds to complete. If it doesn't terminate in 3 seconds (it won't) then the process is terminated.
el#apollo:~$ python test.py
el#apollo:~$
There is three seconds between when the process is run, and it is terminated.
As of Python 3.3, there is also a timeout argument to the blocking helper functions in the subprocess module.
https://docs.python.org/3/library/subprocess.html
Unfortunately, there isn't such a solution. I managed to do this using a threaded timer that would launch along with the process that would kill it after the timeout but I did run into some stale file descriptor issues because of zombie processes or some such.
No there is no time out. I guess, what you are looking for is to kill the sub process after some time. Since you are able to signal the subprocess, you should be able to kill it too.
generic approach to sending a signal to subprocess:
proc = subprocess.Popen([command])
time.sleep(1)
print 'signaling child'
sys.stdout.flush()
os.kill(proc.pid, signal.SIGUSR1)
You could use this mechanism to terminate after a time out period.
Yes, https://pypi.python.org/pypi/python-subprocess2 will extend the Popen module with two additional functions,
Popen.waitUpTo(timeout=seconds)
This will wait up to acertain number of seconds for the process to complete, otherwise return None
also,
Popen.waitOrTerminate
This will wait up to a point, and then call .terminate(), then .kill(), one orthe other or some combination of both, see docs for full details:
http://htmlpreview.github.io/?https://github.com/kata198/python-subprocess2/blob/master/doc/subprocess2.html
For Linux, you can use a signal. This is platform dependent so another solution is required for Windows. It may work with Mac though.
def launch_cmd(cmd, timeout=0):
'''Launch an external command
It launchs the program redirecting the program's STDIO
to a communication pipe, and appends those responses to
a list. Waits for the program to exit, then returns the
ouput lines.
Args:
cmd: command Line of the external program to launch
time: time to wait for the command to complete, 0 for indefinitely
Returns:
A list of the response lines from the program
'''
import subprocess
import signal
class Alarm(Exception):
pass
def alarm_handler(signum, frame):
raise Alarm
lines = []
if not launch_cmd.init:
launch_cmd.init = True
signal.signal(signal.SIGALRM, alarm_handler)
p = subprocess.Popen(cmd, stdout=subprocess.PIPE)
signal.alarm(timeout) # timeout sec
try:
for line in p.stdout:
lines.append(line.rstrip())
p.wait()
signal.alarm(0) # disable alarm
except:
print "launch_cmd taking too long!"
p.kill()
return lines
launch_cmd.init = False
Here's the Python code to run an arbitrary command returning its stdout data, or raise an exception on non-zero exit codes:
proc = subprocess.Popen(
cmd,
stderr=subprocess.STDOUT, # Merge stdout and stderr
stdout=subprocess.PIPE,
shell=True)
communicate is used to wait for the process to exit:
stdoutdata, stderrdata = proc.communicate()
The subprocess module does not support timeout--ability to kill a process running for more than X number of seconds--therefore, communicate may take forever to run.
What is the simplest way to implement timeouts in a Python program meant to run on Windows and Linux?
In Python 3.3+:
from subprocess import STDOUT, check_output
output = check_output(cmd, stderr=STDOUT, timeout=seconds)
output is a byte string that contains command's merged stdout, stderr data.
check_output raises CalledProcessError on non-zero exit status as specified in the question's text unlike proc.communicate() method.
I've removed shell=True because it is often used unnecessarily. You can always add it back if cmd indeed requires it. If you add shell=True i.e., if the child process spawns its own descendants; check_output() can return much later than the timeout indicates, see Subprocess timeout failure.
The timeout feature is available on Python 2.x via the subprocess32 backport of the 3.2+ subprocess module.
I don't know much about the low level details; but, given that in
python 2.6 the API offers the ability to wait for threads and
terminate processes, what about running the process in a separate
thread?
import subprocess, threading
class Command(object):
def __init__(self, cmd):
self.cmd = cmd
self.process = None
def run(self, timeout):
def target():
print 'Thread started'
self.process = subprocess.Popen(self.cmd, shell=True)
self.process.communicate()
print 'Thread finished'
thread = threading.Thread(target=target)
thread.start()
thread.join(timeout)
if thread.is_alive():
print 'Terminating process'
self.process.terminate()
thread.join()
print self.process.returncode
command = Command("echo 'Process started'; sleep 2; echo 'Process finished'")
command.run(timeout=3)
command.run(timeout=1)
The output of this snippet in my machine is:
Thread started
Process started
Process finished
Thread finished
0
Thread started
Process started
Terminating process
Thread finished
-15
where it can be seen that, in the first execution, the process
finished correctly (return code 0), while the in the second one the
process was terminated (return code -15).
I haven't tested in windows; but, aside from updating the example
command, I think it should work since I haven't found in the
documentation anything that says that thread.join or process.terminate
is not supported.
jcollado's answer can be simplified using the threading.Timer class:
import shlex
from subprocess import Popen, PIPE
from threading import Timer
def run(cmd, timeout_sec):
proc = Popen(shlex.split(cmd), stdout=PIPE, stderr=PIPE)
timer = Timer(timeout_sec, proc.kill)
try:
timer.start()
stdout, stderr = proc.communicate()
finally:
timer.cancel()
# Examples: both take 1 second
run("sleep 1", 5) # process ends normally at 1 second
run("sleep 5", 1) # timeout happens at 1 second
If you're on Unix,
import signal
...
class Alarm(Exception):
pass
def alarm_handler(signum, frame):
raise Alarm
signal.signal(signal.SIGALRM, alarm_handler)
signal.alarm(5*60) # 5 minutes
try:
stdoutdata, stderrdata = proc.communicate()
signal.alarm(0) # reset the alarm
except Alarm:
print "Oops, taking too long!"
# whatever else
Here is Alex Martelli's solution as a module with proper process killing. The other approaches do not work because they do not use proc.communicate(). So if you have a process that produces lots of output, it will fill its output buffer and then block until you read something from it.
from os import kill
from signal import alarm, signal, SIGALRM, SIGKILL
from subprocess import PIPE, Popen
def run(args, cwd = None, shell = False, kill_tree = True, timeout = -1, env = None):
'''
Run a command with a timeout after which it will be forcibly
killed.
'''
class Alarm(Exception):
pass
def alarm_handler(signum, frame):
raise Alarm
p = Popen(args, shell = shell, cwd = cwd, stdout = PIPE, stderr = PIPE, env = env)
if timeout != -1:
signal(SIGALRM, alarm_handler)
alarm(timeout)
try:
stdout, stderr = p.communicate()
if timeout != -1:
alarm(0)
except Alarm:
pids = [p.pid]
if kill_tree:
pids.extend(get_process_children(p.pid))
for pid in pids:
# process might have died before getting to this line
# so wrap to avoid OSError: no such process
try:
kill(pid, SIGKILL)
except OSError:
pass
return -9, '', ''
return p.returncode, stdout, stderr
def get_process_children(pid):
p = Popen('ps --no-headers -o pid --ppid %d' % pid, shell = True,
stdout = PIPE, stderr = PIPE)
stdout, stderr = p.communicate()
return [int(p) for p in stdout.split()]
if __name__ == '__main__':
print run('find /', shell = True, timeout = 3)
print run('find', shell = True)
Since Python 3.5, there's a new subprocess.run universal command (that is meant to replace check_call, check_output ...) and which has the timeout= parameter as well.
subprocess.run(args, *, stdin=None, input=None, stdout=None, stderr=None, shell=False, cwd=None, timeout=None, check=False, encoding=None, errors=None)
Run the command described by args. Wait for command to complete, then return a CompletedProcess instance.
It raises a subprocess.TimeoutExpired exception when the timeout expires.
timeout is now supported by call() and communicate() in the subprocess module (as of Python3.3):
import subprocess
subprocess.call("command", timeout=20, shell=True)
This will call the command and raise the exception
subprocess.TimeoutExpired
if the command doesn't finish after 20 seconds.
You can then handle the exception to continue your code, something like:
try:
subprocess.call("command", timeout=20, shell=True)
except subprocess.TimeoutExpired:
# insert code here
Hope this helps.
surprised nobody mentioned using timeout
timeout 5 ping -c 3 somehost
This won't for work for every use case obviously, but if your dealing with a simple script, this is hard to beat.
Also available as gtimeout in coreutils via homebrew for mac users.
I've modified sussudio answer. Now function returns: (returncode, stdout, stderr, timeout) - stdout and stderr is decoded to utf-8 string
def kill_proc(proc, timeout):
timeout["value"] = True
proc.kill()
def run(cmd, timeout_sec):
proc = subprocess.Popen(shlex.split(cmd), stdout=subprocess.PIPE, stderr=subprocess.PIPE)
timeout = {"value": False}
timer = Timer(timeout_sec, kill_proc, [proc, timeout])
timer.start()
stdout, stderr = proc.communicate()
timer.cancel()
return proc.returncode, stdout.decode("utf-8"), stderr.decode("utf-8"), timeout["value"]
Another option is to write to a temporary file to prevent the stdout blocking instead of needing to poll with communicate(). This worked for me where the other answers did not; for example on windows.
outFile = tempfile.SpooledTemporaryFile()
errFile = tempfile.SpooledTemporaryFile()
proc = subprocess.Popen(args, stderr=errFile, stdout=outFile, universal_newlines=False)
wait_remaining_sec = timeout
while proc.poll() is None and wait_remaining_sec > 0:
time.sleep(1)
wait_remaining_sec -= 1
if wait_remaining_sec <= 0:
killProc(proc.pid)
raise ProcessIncompleteError(proc, timeout)
# read temp streams from start
outFile.seek(0);
errFile.seek(0);
out = outFile.read()
err = errFile.read()
outFile.close()
errFile.close()
Prepending the Linux command timeout isn't a bad workaround and it worked for me.
cmd = "timeout 20 "+ cmd
subprocess.Popen(cmd.split(), stdout=subprocess.PIPE, stderr=subprocess.PIPE)
(output, err) = p.communicate()
I added the solution with threading from jcollado to my Python module easyprocess.
Install:
pip install easyprocess
Example:
from easyprocess import Proc
# shell is not supported!
stdout=Proc('ping localhost').call(timeout=1.5).stdout
print stdout
Here is my solution, I was using Thread and Event:
import subprocess
from threading import Thread, Event
def kill_on_timeout(done, timeout, proc):
if not done.wait(timeout):
proc.kill()
def exec_command(command, timeout):
done = Event()
proc = subprocess.Popen(command, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
watcher = Thread(target=kill_on_timeout, args=(done, timeout, proc))
watcher.daemon = True
watcher.start()
data, stderr = proc.communicate()
done.set()
return data, stderr, proc.returncode
In action:
In [2]: exec_command(['sleep', '10'], 5)
Out[2]: ('', '', -9)
In [3]: exec_command(['sleep', '10'], 11)
Out[3]: ('', '', 0)
The solution I use is to prefix the shell command with timelimit. If the comand takes too long, timelimit will stop it and Popen will have a returncode set by timelimit. If it is > 128, it means timelimit killed the process.
See also python subprocess with timeout and large output (>64K)
if you are using python 2, give it a try
import subprocess32
try:
output = subprocess32.check_output(command, shell=True, timeout=3)
except subprocess32.TimeoutExpired as e:
print e
I've implemented what I could gather from a few of these. This works in Windows, and since this is a community wiki, I figure I would share my code as well:
class Command(threading.Thread):
def __init__(self, cmd, outFile, errFile, timeout):
threading.Thread.__init__(self)
self.cmd = cmd
self.process = None
self.outFile = outFile
self.errFile = errFile
self.timed_out = False
self.timeout = timeout
def run(self):
self.process = subprocess.Popen(self.cmd, stdout = self.outFile, \
stderr = self.errFile)
while (self.process.poll() is None and self.timeout > 0):
time.sleep(1)
self.timeout -= 1
if not self.timeout > 0:
self.process.terminate()
self.timed_out = True
else:
self.timed_out = False
Then from another class or file:
outFile = tempfile.SpooledTemporaryFile()
errFile = tempfile.SpooledTemporaryFile()
executor = command.Command(c, outFile, errFile, timeout)
executor.daemon = True
executor.start()
executor.join()
if executor.timed_out:
out = 'timed out'
else:
outFile.seek(0)
errFile.seek(0)
out = outFile.read()
err = errFile.read()
outFile.close()
errFile.close()
Once you understand full process running machinery in *unix, you will easily find simplier solution:
Consider this simple example how to make timeoutable communicate() meth using select.select() (available alsmost everythere on *nix nowadays). This also can be written with epoll/poll/kqueue, but select.select() variant could be a good example for you. And major limitations of select.select() (speed and 1024 max fds) are not applicapable for your task.
This works under *nix, does not create threads, does not uses signals, can be lauched from any thread (not only main), and fast enought to read 250mb/s of data from stdout on my machine (i5 2.3ghz).
There is a problem in join'ing stdout/stderr at the end of communicate. If you have huge program output this could lead to big memory usage. But you can call communicate() several times with smaller timeouts.
class Popen(subprocess.Popen):
def communicate(self, input=None, timeout=None):
if timeout is None:
return subprocess.Popen.communicate(self, input)
if self.stdin:
# Flush stdio buffer, this might block if user
# has been writing to .stdin in an uncontrolled
# fashion.
self.stdin.flush()
if not input:
self.stdin.close()
read_set, write_set = [], []
stdout = stderr = None
if self.stdin and input:
write_set.append(self.stdin)
if self.stdout:
read_set.append(self.stdout)
stdout = []
if self.stderr:
read_set.append(self.stderr)
stderr = []
input_offset = 0
deadline = time.time() + timeout
while read_set or write_set:
try:
rlist, wlist, xlist = select.select(read_set, write_set, [], max(0, deadline - time.time()))
except select.error as ex:
if ex.args[0] == errno.EINTR:
continue
raise
if not (rlist or wlist):
# Just break if timeout
# Since we do not close stdout/stderr/stdin, we can call
# communicate() several times reading data by smaller pieces.
break
if self.stdin in wlist:
chunk = input[input_offset:input_offset + subprocess._PIPE_BUF]
try:
bytes_written = os.write(self.stdin.fileno(), chunk)
except OSError as ex:
if ex.errno == errno.EPIPE:
self.stdin.close()
write_set.remove(self.stdin)
else:
raise
else:
input_offset += bytes_written
if input_offset >= len(input):
self.stdin.close()
write_set.remove(self.stdin)
# Read stdout / stderr by 1024 bytes
for fn, tgt in (
(self.stdout, stdout),
(self.stderr, stderr),
):
if fn in rlist:
data = os.read(fn.fileno(), 1024)
if data == '':
fn.close()
read_set.remove(fn)
tgt.append(data)
if stdout is not None:
stdout = ''.join(stdout)
if stderr is not None:
stderr = ''.join(stderr)
return (stdout, stderr)
You can do this using select
import subprocess
from datetime import datetime
from select import select
def call_with_timeout(cmd, timeout):
started = datetime.now()
sp = subprocess.Popen(cmd, stdout=subprocess.PIPE)
while True:
p = select([sp.stdout], [], [], timeout)
if p[0]:
p[0][0].read()
ret = sp.poll()
if ret is not None:
return ret
if (datetime.now()-started).total_seconds() > timeout:
sp.kill()
return None
python 2.7
import time
import subprocess
def run_command(cmd, timeout=0):
start_time = time.time()
df = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
while timeout and df.poll() == None:
if time.time()-start_time >= timeout:
df.kill()
return -1, ""
output = '\n'.join(df.communicate()).strip()
return df.returncode, output
Example of captured output after timeout tested in Python 3.7.8:
try:
return subprocess.run(command, shell=True, capture_output=True, timeout=20, cwd=cwd, universal_newlines=True)
except subprocess.TimeoutExpired as e:
print(e.output.decode(encoding="utf-8", errors="ignore"))
assert False;
The exception subprocess.TimeoutExpired has the output and other members:
cmd - Command that was used to spawn the child process.
timeout - Timeout in seconds.
output - Output of the child process if it was captured by run() or
check_output(). Otherwise, None.
stdout - Alias for output, for symmetry with stderr.
stderr - Stderr output of the child process if it was captured by
run(). Otherwise, None.
More info: https://docs.python.org/3/library/subprocess.html#subprocess.TimeoutExpired
I've used killableprocess successfully on Windows, Linux and Mac. If you are using Cygwin Python, you'll need OSAF's version of killableprocess because otherwise native Windows processes won't get killed.
Although I haven't looked at it extensively, this decorator I found at ActiveState seems to be quite useful for this sort of thing. Along with subprocess.Popen(..., close_fds=True), at least I'm ready for shell-scripting in Python.
This solution kills the process tree in case of shell=True, passes parameters to the process (or not), has a timeout and gets the stdout, stderr and process output of the call back (it uses psutil for the kill_proc_tree). This was based on several solutions posted in SO including jcollado's. Posting in response to comments by Anson and jradice in jcollado's answer. Tested in Windows Srvr 2012 and Ubuntu 14.04. Please note that for Ubuntu you need to change the parent.children(...) call to parent.get_children(...).
def kill_proc_tree(pid, including_parent=True):
parent = psutil.Process(pid)
children = parent.children(recursive=True)
for child in children:
child.kill()
psutil.wait_procs(children, timeout=5)
if including_parent:
parent.kill()
parent.wait(5)
def run_with_timeout(cmd, current_dir, cmd_parms, timeout):
def target():
process = subprocess.Popen(cmd, cwd=current_dir, shell=True, stdout=subprocess.PIPE, stdin=subprocess.PIPE, stderr=subprocess.PIPE)
# wait for the process to terminate
if (cmd_parms == ""):
out, err = process.communicate()
else:
out, err = process.communicate(cmd_parms)
errcode = process.returncode
thread = Thread(target=target)
thread.start()
thread.join(timeout)
if thread.is_alive():
me = os.getpid()
kill_proc_tree(me, including_parent=False)
thread.join()
There's an idea to subclass the Popen class and extend it with some simple method decorators. Let's call it ExpirablePopen.
from logging import error
from subprocess import Popen
from threading import Event
from threading import Thread
class ExpirablePopen(Popen):
def __init__(self, *args, **kwargs):
self.timeout = kwargs.pop('timeout', 0)
self.timer = None
self.done = Event()
Popen.__init__(self, *args, **kwargs)
def __tkill(self):
timeout = self.timeout
if not self.done.wait(timeout):
error('Terminating process {} by timeout of {} secs.'.format(self.pid, timeout))
self.kill()
def expirable(func):
def wrapper(self, *args, **kwargs):
# zero timeout means call of parent method
if self.timeout == 0:
return func(self, *args, **kwargs)
# if timer is None, need to start it
if self.timer is None:
self.timer = thr = Thread(target=self.__tkill)
thr.daemon = True
thr.start()
result = func(self, *args, **kwargs)
self.done.set()
return result
return wrapper
wait = expirable(Popen.wait)
communicate = expirable(Popen.communicate)
if __name__ == '__main__':
from subprocess import PIPE
print ExpirablePopen('ssh -T git#bitbucket.org', stdout=PIPE, timeout=1).communicate()
I had the problem that I wanted to terminate a multithreading subprocess if it took longer than a given timeout length. I wanted to set a timeout in Popen(), but it did not work. Then, I realized that Popen().wait() is equal to call() and so I had the idea to set a timeout within the .wait(timeout=xxx) method, which finally worked. Thus, I solved it this way:
import os
import sys
import signal
import subprocess
from multiprocessing import Pool
cores_for_parallelization = 4
timeout_time = 15 # seconds
def main():
jobs = [...YOUR_JOB_LIST...]
with Pool(cores_for_parallelization) as p:
p.map(run_parallel_jobs, jobs)
def run_parallel_jobs(args):
# Define the arguments including the paths
initial_terminal_command = 'C:\\Python34\\python.exe' # Python executable
function_to_start = 'C:\\temp\\xyz.py' # The multithreading script
final_list = [initial_terminal_command, function_to_start]
final_list.extend(args)
# Start the subprocess and determine the process PID
subp = subprocess.Popen(final_list) # starts the process
pid = subp.pid
# Wait until the return code returns from the function by considering the timeout.
# If not, terminate the process.
try:
returncode = subp.wait(timeout=timeout_time) # should be zero if accomplished
except subprocess.TimeoutExpired:
# Distinguish between Linux and Windows and terminate the process if
# the timeout has been expired
if sys.platform == 'linux2':
os.kill(pid, signal.SIGTERM)
elif sys.platform == 'win32':
subp.terminate()
if __name__ == '__main__':
main()
Late answer for Linux only, but in case someone wants to use subprocess.getstatusoutput(), where the timeout argument isn't available, you can use the built-in Linux timeout on the beginning of the command, i.e.:
import subprocess
timeout = 25 # seconds
cmd = f"timeout --preserve-status --foreground {timeout} ping duckgo.com"
exit_c, out = subprocess.getstatusoutput(cmd)
if (exit_c == 0):
print("success")
else:
print("Error: ", out)
timeout Arguments:
--preserve-status : Preserving the Exit Status
--foreground : Running in Foreground
25 : timeout value in seconds
Unfortunately, I'm bound by very strict policies on the disclosure of source code by my employer, so I can't provide actual code. But for my taste the best solution is to create a subclass overriding Popen.wait() to poll instead of wait indefinitely, and Popen.__init__ to accept a timeout parameter. Once you do that, all the other Popen methods (which call wait) will work as expected, including communicate.
https://pypi.python.org/pypi/python-subprocess2 provides extensions to the subprocess module which allow you to wait up to a certain period of time, otherwise terminate.
So, to wait up to 10 seconds for the process to terminate, otherwise kill:
pipe = subprocess.Popen('...')
timeout = 10
results = pipe.waitOrTerminate(timeout)
This is compatible with both windows and unix. "results" is a dictionary, it contains "returnCode" which is the return of the app (or None if it had to be killed), as well as "actionTaken". which will be "SUBPROCESS2_PROCESS_COMPLETED" if the process completed normally, or a mask of "SUBPROCESS2_PROCESS_TERMINATED" and SUBPROCESS2_PROCESS_KILLED depending on action taken (see documentation for full details)
for python 2.6+, use gevent
from gevent.subprocess import Popen, PIPE, STDOUT
def call_sys(cmd, timeout):
p= Popen(cmd, shell=True, stdout=PIPE)
output, _ = p.communicate(timeout=timeout)
assert p.returncode == 0, p. returncode
return output
call_sys('./t.sh', 2)
# t.sh example
sleep 5
echo done
exit 1
Sometimes you need to process (ffmpeg) without using communicate() and in this case you need asynchronous timeout, a practical way to do this using ttldict
pip install ttldict
from ttldict import TTLOrderedDict
sp_timeout = TTLOrderedDict(default_ttl=10)
def kill_on_timeout(done, proc):
while True:
now = time.time()
if sp_timeout.get('exp_time') == None:
proc.kill()
break
process = subprocess.Popen(cmd, stdout=subprocess.PIPE, text=True, stderr=subprocess.STDOUT)
sp_timeout['exp_time'] = time.time()
done = Event()
watcher = Thread(target=kill_on_timeout, args=(done, process))
watcher.daemon = True
watcher.start()
done.set()
for line in process.stdout:
.......