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How can i zip() two lists together without the output having "\n" at the beginning of every second element? [closed]

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I currently have two lists
songlist = []
artistlist = []
I return
list(zip(songlist, artistlist))
and it gives me what I want(a 3d list of a 2d list containing each song title and respective artist) but before each second item in each list is "\n"
for example a list in the 3d list would look like: ["Amarillo By Morning","\nGeorge Strait"]
I'm gonna be using the artist in a later function so I'd rather there not be the \n there.
instead of my above code i tried returning a variable containing:
[i + j for i, j in zip(songlist, artistlist)]
but that just returned: ["Amarillo By Morning\nGeorge Strait", ... cont.

To avoid making another iterator, you can just modify each artist as they come along, if you can't modify it at the source.
Also, return a list instead of using string concatenation if you want a list.
[[song, artist.strip()] for song, artist in zip(songlist, artistlist)]

Use the strip() method to remove the whitespace characters from the start and the end of the string (including the new line characters) :
zipped_list = list(zip([song.strip() for song in songlist], [artist.strip() for artist in artistlist]))

I CANNOT get rid of brackets when trying to print these lists for some reason [closed]

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I have tried most methods but for some reason it just does not want to print without the brackets. Why is that??

It means that list1 and/or list2 are lists of lists. Try:
for x in list1:
print(x[0])
for y in list2:
print(y[0])

Hey reffering to the first answer which i really liked, it makes you use indexing which i dont really like in my code writing in python.
The complete solution without using any external library or indexing is to use a nested for loop, if it is really a list of lists use the function like so:
def printMe(self):
for list in list1:
for x in list:
print(x)
and the same for the second list,
I was able to repredouce your work and it worked, i wouldve used also more parsing in the strings but it is your own choice,
Hope it helped :)

It is probably caused by an extra axis.
Try this:
for x in list1[0]:
print(x)

If you want to just print the list without square brackets use the command:
print(*x,sep=" ")

When would using the filter function be used instead of a list comprehension? [closed]

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Recently, I have learned a bit about the filter method, an alternative to using list comprehensions.
Say I have a list as such:
names = ["Bob", "Billy", "Samuel", "Adam", "Rob"]
Now, I would like to get a list containing the names that start with the letter, "B". I could go about this in a couple of ways. This is one:
b_starting_names = list(filter(lambda name: name.startswith("B"), names))
This is another:
b_starting_names = [name for name in names if name.startswith("B")]
Could someone please explain what the difference is between a list comprehension and the filter function, and why someone may want to use one over the other?

There's no harm in using either. A similar comment can be made about map.
I tend to use whatever one feels easier to read. In your case I would avoid using the lambda as it is a bit verbose, and instead use the comprehension.
I would use filter or map methods if I already had a function existing I could just pass to the method, which would be more terse than the comprehension.
For example, say I write a program for finding the length of the largest name:
# Using map
longest = max(map(len, names))
# Using generator expression
longest = max(len(name) for name in names))
In the above example I would choose map over the generator expression, but it's entirely personal preference.

Search and Replace a word within a word in Python. Replace() method not working [closed]

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How do I search and replace using built-in Python methods?
For instance, with a string of appleorangegrapes (yes all of them joined),
Replace "apple" with "mango".
The .replace method only works if the words are evenly spaced out but not if they are combined as one. Is there a way around this?
I searched the web but again the .replace method only gives me an example if they are spaced out.
Thank you for looking at the problem!

This works exactly as expected and advertised. Have a look:
s = 'appleorangegrapes'
print(s) # -> appleorangegrapes
s = s.replace('apple', 'mango')
print(s) # -> mangoorangegrapes
The only thing that you have to be careful of is that replace is not an in-place operator and as such it does not update s automatically; it only creates a new string that you have to assign to something.
s = 'appleorangegrapes'
s.replace('apple', 'mango') # the change is made but not saved
print(s) # -> appleorangegrapes

replace can work for any string, why you think that it doesn't, here is the test:
>>> s='appleorangegrapes'
>>> s.replace('apple','mango')
'mangoorangegrapes'
>>>
Don't you see that you received your expected result?

Can't edit a tuple from inside a function [closed]

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I am programming an application in python. Here is the function:
def aircraftListBoxRefresh():
sqlConnect=sqlite3.connect("fglconfdb")
sqlCursor=sqlConnect.cursor()
sqlCursor.execute("SELECT fgAircraftDir FROM fglconfig")
adl=sqlCursor.fetchall()
global aircraftDirectories
for x in adl:
aircraftDirectories=aircraftDirectories+(x,)
I put print(aircraftDirectories) to test whether the value changes. It changes in side the function. But outside the function it is null.
I am trying to access the value with this:
aircraftDirectories=()
aircraftDir=StringVar(value=aircraftDirectories)
aircraftListBox=Listbox(mainframe,height=7,width=100,listvariable=aircraftDir)
aircraftListBox.place(x=170,y=170)
But I can't.
Any help greatly appreciated.
Regards.

You can't modify tuples anywhere, inside a function or outside, they're immutable. Maybe you want lists:
def aircraftListBoxRefresh():
sqlConnect=sqlite3.connect("fglconfdb")
sqlCursor=sqlConnect.cursor()
sqlCursor.execute("SELECT fgAircraftDir FROM fglconfig")
adl=sqlCursor.fetchall()
for x in adl:
aircraftDirectories.append(x)
aircraftDirectories=[]
aircraftDir=StringVar(value=aircraftDirectories)
aircraftListBox=Listbox(mainframe,height=7,width=100,listvariable=aircraftDir)
aircraftListBox.place(x=170,y=170)
With this approach, since you're modifying the list and not re-assigning to the variable, you don't need global.

You can't modify a tuple, but you can replace it. In this example M[] is a list of tuples, each tuple contains two numbers. I want to replace the first number of a tuple to 0, but keep the second number.
M[j] = (0, M[j][1])