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I do not know what I am missing but I've tried 3 different ways to achieve basically the same thing. Looking at the code below, why does only 1 out of the 4 ways work. I want to see if a value (located in a list) exists inside another list. I checked this SO question but still not understanding why the code is failing to print True1 , True2, and True4.
l1 = ["bravo", "alhpa", "charlie"]
l2 = ["alpha"]
if l1[1] in l2:
print "True1" # does not work
if l1[1] == l2[0]:
print "True2" # does not work
if "alpha" in l2:
print "True3" # works
for outer in l1:
for inner in l2:
if outer == inner:
print "True4" # does not work
You have a typo: "alhpa" vs. "alpha"
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list1 = [''ABC'',''XYZ'',''PQR'',''MNS'']
to
list1 = ['ABC','XYZ','PQR','MNS']
#I am using this code but it is not working
for i in range(0,len(list1)):
list1[i] = list1[i].replace("''","")
I find list comprehension to be the cleanest solution:
list2 = [s.replace("'", "") for s in list1]
In the snippet above, I iterate through the list binding s to each of the characters (as we traverse the list). In each iteration, I do the replacement.
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What is the correct syntax for using Sum() function in python for lists?
Say we have a list called list_1. When I tried these two syntax I get the same result:
total_1 = Sum(list_1)
total_2 = list_1.Sum()
What is the best syntax for that?
To sum a list of integers or floats, the correct method is:
list_1 = [1, 2, 3]
total = sum(list_1)
print(total)
which results in the output:
6
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I am trying to write a one-line list comprehension that takes a list of tuples and adds them to a new list if the second element of the tuple is not equal to 0
my_list = [x in my_list if x[1] != 0]
this is the code I wrote, says I have invalid syntax
The correct way
my_list = [x for x in my_list if x[1] != 0]
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Issue occurred right after I added the and x= "J1234": I don't know what's going on.
original = ""
if len(original) > 0 and x = "J123":
raw_input("Enter a word:")
original = raw_input('word')
print "original"
else:
print "empty"
x.isalpha()
So, you're getting a SyntaxError. To fix this, change:
x = "J123":
to...
x == "J123":
In Python the former is for setting values and the latter is for checking them. Therefore when you use this the wrong way round the syntax is incorrect.
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I am trying to write a quicksort program in python, however I'm getting an invalid syntax error at else statement in the second last line below:
import random
n=int(raw_input("Enter the size of the list: ")) # size of the list
intlist = [0]*n
for num in range(n):
intlist[num]=random.randint(0,10*n)
pivot=random.choice(intlist)
list_1=[] # list of elements smaller than pivot
list_2=[] # list of elements greater than pivot
for num in range(n):
if num<=pivot:
list_1.append(num)
else
list_2.append(num)
This is not a complete program as I am still writing.
add a colon after the else so that it looks like else:. and pick up a good tutorial ;)
Looks like you need a ':' after "else".