So I have this piece of code, very basic stuff that I'm working on. I stumbled upon this "slow type" thing, that I like but if I use it instead of all print functions, most of my output is written on one row.
import sys, time
def print_slow(str):
for letter in str:
sys.stdout.write(letter)
sys.stdout.flush()
time.sleep(0.02)
print_slow('What\'s your name?')
name = raw_input()
print_slow('My name is ' + name)
if name == 'alex' or name == 'Alex':
print_slow('That\'s a good name')
if name == 'Alexandru' or name == 'alexandru':
print_slow('That\'s a very good name')
You can print a newline character (\n) at the end of each line where you so desire, or add it to the print_slow function.
Related
I need to check whether the input is empty or not and cannot use if statements.
print("What is your name?")
name = input()
print("Hi, {}".format(name))
Use a while loop that only terminates if the length of name is 0:
name = ""
while len(name) == 0:
print("What is your name?")
name = input()
print("Hi, {}".format(name))
You could try something like this:
print("What is your name?")
name = input()
name = "Hi, {}".format(name)
while name == "Hi, ":
name = "You didn't key in any name"
print(name)
This is ugly, but it will produce the exact output you want.
The idea is to use a loop that will run only once, and will only run if the name variable is empty after input() is called.
I would recommend assert. It will stop your programming to continue running when the requirement is not met.
print("What is your name?")
name = input()
assert name != "", "You didn't key in any name"
print("Hi, {}".format(name))
What is your name?
AssertionError: You didn't key in any name
As my previous answer with the while loop received some criticism, I decided to demonstrate a less "naive" but perhaps more complicated solution, that actually does not use any kind of direct conditional operator:
print("What is your name?")
name = input()
answer = {}
answer[len(name)] = "Hi, {}".format(name)
answer[0] = "You didn't key in any name"
print(answer[len(name)])
Here we rely on a dictionary with the length of the input as an integer key.
We don't even need to compare the length to 0, we just overwrite the 0 key with the error message.
If input length is greater than 0, the name will be under its own key, and will be printed, if not, the empty "Hi" string will be replaced.
Would this ever be useful in the real world?
Probably not, unless there are many more than 2 options.
Does it comply with the task requirements?
Yes. It gives the desired output.
I am attempting to make a game that I made via Rpg Maker MV in python but I've hit a road block in the if statement or rather the gender input. The code is meant to have the user input either "Boy" or "Girl" and depending on that the variable "gender" will be set for pronouns. How ever the console is saying This
This is the code
import time
print ("Elvoria")
print ("Start")
input = input()
if input == ("Start"):
print ("Always Great To See New People")
time.sleep(1)
print ("Now Are You A Boy Or Girl")
genderin = input()
if input == ("Boy"):
gender = 1
elif input == ("Girl"):
gender = 2
else:
print ("Error")
You need to check the input using the variable name genderin that you defined, instead of input == ("Boy").
EDIT: Also, you are mirroring the built-in method input() with the variable name input and you should not do that. Rename your variable to e.g. start_input.
import time
print ("Elvoria")
print ("Start")
start_input = input()
if start_input == "Start":
print ("Always Great To See New People")
time.sleep(1)
print ("Now Are You A Boy Or Girl")
genderin = input()
if genderin == "Boy":
gender = 1
elif genderin == "Girl":
gender = 2
else:
print ("Error")
You're defining the variable "input" on line 4 to be a string, given from the "input" function. This overrides the keyword. Then, on line 9, you're calling "input" again. Since you've replaced the built-in function with a string, an error is thrown (the error "not callable" means that you're trying to treat a non-function like a function).
Here's your code sample, without overriding built-in methods:
import time
print ("Elvoria")
print ("Start")
user_input = input()
if user_input == ("Start"):
print ("Always Great To See New People")
time.sleep(1)
print ("Now Are You A Boy Or Girl")
genderin = input()
if genderin == ("Boy"):
gender = 1
elif genderin == ("Girl"):
gender = 2
else:
print ("Error")
You should avoid using input as a varible name, since a built-in function with that name already exists, input(). So just change it's name to something else. Secondly, you're storing the gender input (boy/girl) in genderin, but then checking input, when you should be checking genderin. So the code after fixing these would look something like this:
import time
print ("Elvoria")
print ("Start")
choice = input()
if choice == "Start":
print("Always Great To See New People")
time.sleep(1)
print("Now Are You A Boy Or Girl?")
genderin = input()
if genderin == "Boy":
gender = 1
elif genderin == "Girl":
gender = 2
else:
print("Error")
I have used choice for demonstration purposes, you can use a different name if you want, just remember to make sure that a python built-in with that name doesn't exist. Also, no need to put ("Start") in the if statement, use "Start" instead (same goes for other if/elif statements)
You have also used print ("example") (space between print and brackets), i've rarely ever seen someone using this, most people use print("example") instead.
Finally a tip -> You can make the string lowercase, genderin = genderin.lower() to manage case sensitivity, i.e, both boy and Boy will be valid inputs, etc.
In my code, it asks what is your name and if your name is in the file then say welcome back then their name if their name is not in it then ask if they want for Cora to remember it if yes then write their name into the file.
def AI():
names = open("\\\\ph-fss1\\Students\\S39055\\Desktop\\names.txt","w")
name = raw_input("Hello and welcome to the Creative, Orginal, Reactive, A.I, Cora. What is your name? ")
file.read(names)
if name in names:
print "Welcome back " + name
if name not in names:
print "You are a new user would you like to me to remember your name?"
name_yes = raw_input("Yes/No: ").lower()
if name_yes == "yes":
file.wright(name)
file.close()
Lets take a look at a few improvements. Since you use raw_input() i'll assume Python 2.x:
def AI():
# you can use r'' to specify a raw string and avoid using '\\' to escape '\'
fpath = r'\\ph-fss1\Students\S39055\Desktop\names.txt'
# this is called a 'context manager'
# when you are done with your operations, the file will close automatically
# the 'r+' mode opens for reading and writing
with open(fpath, 'r+') as f:
# this is list comprehension and I assume each name is on a new line
# a set is a container for unique values
# assuming that you will not have multiple of the same names
# if so, how do you plan to account for them?
names = set([line for line in f])
print "Hello and welcome to the Creative, Orginal, Reactive, A.I, Cora."
name = raw_input("What is your name? ")
if name in names:
print "Welcome back " + name
else:
print "You are a new user, would you like to me to remember your name?"
# this is fine, but what happens I just put in 'y' or 'n'?
# look for methods to handle invalid input
choice = raw_input("Yes/No: ").lower()
if choice == "yes":
# because we opened the file in 'r+', we seek(0) which puts us at the top
# then when we writelines(list(names)) we overwrite the entire file
# and store the original data with the new name as well
file.seek(0)
names.add(name)
# writelines() just writes an iterable versus a string
file.writelines(list(names))
There are some design choices you have to make here. But if you have any questions, ask away.
The issue was that you never actual read the contents of the file in order to check if the name existed. Try this:
name = raw_input("Hello and welcome to the Creative, Orginal, Reactive, A.I, Cora. What is your name? ")
if name in open("\\\\ph-fss1\\Students\\S39055\\Desktop\\names.txt").read():
print "Welcome back " + name
else:
print "You are a new user would you like to me to remember your name?"
name_yes = raw_input("Yes/No: ").lower()
if name_yes == "yes":
with open("\\\\ph-fss1\\Students\\S39055\\Desktop\\names.txt", "a") as myfile:
myfile.write(name)
I'm trying to create a very simple program but I ran into a problem with my if/then statement. A very simplified version of the code I was using is as follows:
print "What's your name?"
name = raw_input()
if name == 'Bob':
print "Hi Bob."
if name == 'Mary':
print "Hi Mary."
else:
print "I don't know your name."
If I enter 'Bob' it prints "Hi Bob." followed by the else statement (which is the problem), but if I enter 'Mary' it doesn't print the else statement. I tried adding the else statement after each if statement, but that didn't work either. What am I doing wrong? How can I use more than one if statement if there is only one else statement?
Use elif like this:
from __future__ import print_function
print("What's your name?")
name = raw_input()
if name == 'Bob':
print("Hi Bob.")
elif name == 'Mary':
print("Hi Mary.")
else:
print("I don't know your name.")
Python Tutorial on control flow:
https://docs.python.org/3/tutorial/controlflow.html
EDIT: Use print() in portable Python 2/3 way.
I've just undertaken my first proper project with Python, a code snippet storing program.
To do this I need to first write, then read, multiple lines to a .txt file. I've done quite a bit of googling and found a few things about writing to the file (which didn't really work). What I have currently got working is a function that reads each line of a multiline input and writes it into a list before writing it into a file. I had thought that I would just be able to read that from the text file and add each line into a list then print each line separately using a while loop, which unfortunately didn't work.
After going and doing more research I decided to ask here. This is the code I have currently:
'''
Project created to store useful code snippets, prehaps one day it will evolve
into something goregous, but, for now it's just a simple archiver/library
'''
#!/usr/local/bin/python
import sys, os, curses
os.system("clear")
Menu ="""
#----------- Main Menu ---------#
# 1. Create or edit a snippet #
# 2. Read a snippet #
# 0. Quit #
#-------------------------------#
\n
"""
CreateMenu ="""
#-------------- Creation and deletion --------------#
# 1. Create a snippet #
# 2. Edit a snippet #
# 3. Delete a snippet (Will ask for validation) #
# 0. Go back #
#---------------------------------------------------#
\n
"""
ReadMenu="""
#------ Read a snippet ------#
# 1. Enter Snippet name #
# 2. List alphabetically #
# 3. Extra #
# 0. Go Back #
#----------------------------#
"""
def readFileLoop(usrChoice, directory):
count = 0
if usrChoice == 'y' or 'n':
if usrChoice == 'y':
f = open(directory, 'r')
text = f.read()
f.close()
length = len(text)
print text
print length
raw_input('Enter to continue')
readMenu()
f.close()
elif choice == 'n':
readMenu()
def raw_lines(prompt=''):
result = []
getmore = True
while getmore:
line = raw_input(prompt)
if len(line) > 0:
result.append(line)
else:
getmore = False
result = str(result)
result.replace('[','').replace(']','')
return result
def mainMenu():
os.system("clear")
print Menu
choice = ''
choice = raw_input('--: ')
createLoop = True
if choice == '1':
return creationMenu()
elif choice == '2':
readMenu()
elif choice == '0':
os.system("clear")
sys.exit(0)
def create():
os.system("clear")
name = raw_input("Enter the file name: ")
dire = ('shelf/'+name+'.txt')
if os.path.exists(dire):
while os.path.exists(dire):
os.system("clear")
print("This snippet already exists")
name = raw_input("Enter a different name: ")
dire = ('shelf/'+name+'.txt')
print("File created\n")
f = open(dire, "w")
print("---------Paste code below---------\n")
text = raw_lines()
raw_input('\nEnter to write to file')
f.writelines(text)
f.close()
raw_input('\nSnippet successfully filled, enter to continue')
else:
print("File created")
f = open(dire, "w")
print("---------Paste code below---------\n")
text = raw_lines()
print text
raw_input('\nEnter to write to file')
f.writelines(text)
f.close()
raw_input('\nSnippet successfully filled, enter to continue')
def readMenu():
os.system("clear")
name = ''
dire = ''
print ReadMenu
choice = raw_input('--:')
if choice == '1':
os.system("clear")
name = raw_input ('Enter Snippet name: ')
dire = ('shelf/'+name+'.txt')
if os.path.exists(dire):
choice = ''
choice = raw_input('The Snippet exists! Open? (y/n)')
'''if not choice == 'y' or 'n':
while (choice != 'y') or (choice != 'n'):
choice = raw_input('Enter \'y\' or \'n\' to continue: ')
if choice == 'y' or 'n':
break'''
readFileLoop(choice, dire)
else:
raw_input('No snippet with that name exists. Enter to continue: ') #add options to retry, create snippet or go back
readMenu()
elif choice == '0':
os.system("clear")
print Menu
def creationMenu(): ###### Menu to create, edit and delete a snippet ######
os.system("clear")
print CreateMenu
choice = raw_input('--: ')
if choice == '1': ### Create a snippet
os.system("clear")
print create()
print creationMenu()
elif choice == '2':
os.system("clear") ### Edit a snippet
print ("teh editon staton")
raw_input()
print creationMenu()
elif choice == '3':
os.system("clear") ### Delete a snippet
print ("Deletion staton")
raw_input()
print creationMenu()
elif choice == '0': ### Go Back
os.system("clear")
######## Main loop #######
running = True
print ('Welcome to the code library, please don\'t disturb other readers!\n\n')
while running:
mainMenu()
######## Main loop #######
Tl;Dr: Need to write and read multiline text files
The problem that I'm having is the way the multilines are being stored to the file, it's stored in list format e.g ['line1', 'line2', 'line3'] which is making it difficult to read as multilines because I can't get it to be read as a list, when I tried it added the whole stored string into one list item. I don't know if I'm writing to the file correctly.
OK, so the problem is with writing the file. You're reading it in correctly, it just doesn't have the data you want. And the problem is in your raw_lines function. First it assembles a list of lines in the result variable, which is good. Then it does this:
result = str(result)
result.replace('[','').replace(']','')
There are two small problems and one big one here.
First, replace:
Return[s] a copy of the string with all occurrences of substring old replaced by new.
Python strings are immutable. None of their methods change them in-place; all of them return a new string instead. You're not doing anything with that new string, so that line has no effect.
Second, if you want to join a sequence of strings into a string, you don't do that by calling str on the sequence and then trying to parse it. That's what the join method is for. For example, if your lines already end with newlines, you want ''.join(result). If not, you want something like '\n'.join(result) + '\n'. What you're doing has all kinds of problems—you forgot to remove the extra commas, you will remove any brackets (or commas, once you fix that) within the strings themselves, etc.
Finally, you shouldn't be doing this in the first place. You want to return something that can be passed to writelines, which:
Write[s] a sequence of strings to the file. The sequence can be any iterable object producing strings, typically a list of strings.
You have a list of strings, which is exactly what writelines wants. Don't try to join them up into one string. If you do, it will run, but it won't do the right thing (because a string is, itself, a sequence of 1-character strings).
So, if you just remove those two lines entirely, your code will almost work.
But there's one last problem: raw_input:
… reads a line from input, converts it to a string (stripping a trailing newline), and returns that.
But writelines:
… does not add line separators.
So, you'll end up with all of your lines concatenated together. You need the newlines, but raw_input throws them away. So, you have to add them back on. You can fix this with a simple one-line change:
result.append(line + '\n')
To read multiple lines from a file, it's easiest to use readlines(), which will return a list of all lines in the file. To read the file use:
with open(directory, 'r') as f:
lines = f.readlines()
And to write out your changes, use:
with open(directory, 'w') as f:
f.writelines(lines)
fileList = [line for line in open("file.txt")]
While the previously mention idiom will work for reading files, I like mine. Its short and to the point.