I'm working at my first project in Django and learning it by the way. Currently I'm stuck at the part of the project where I have to show additional data if checkbox is selected as true.
Long story short, there have to be checkbox at my page which name is "Cars", if user check the checkbox as True, select list of models of cars should be displayed immediately, below this checkbox, without affecting other input sources on current page.
Is there easy way how to accomplis this? Thanks for help.
/edit
HTML code
<p class="dhcp"> DHCP: {{ form.dhcp }} </p>
<p class="collapse1 collapse"> IPv4 adresy: {{form.ipv4_adress }} </p>
<p class="dhcpv6"> DHCPv6: {{ form.dhcpv6 }} </p>
<p class="collapse2 collapse"> IPv6 adresy: {{form.ipv6_adress }} </p>
JS code
$(document).ready(function() {
$(".dhcp").click(function(event) {
$(".collapse1").fadeToggle().delay(100);
});
$(".dhcpv6").click(function(event) {
$(".collapse2").fadeToggle().delay(100);
});
})
It's just part of it, its quite "big" by now and not telling anything because of being generated by django form. Main issue right now is that if I click on same row as is checkbox, it trigger action of displaying data.
take a look at this JS Fiddle . Its a simple JS solution with a fadeToggle for your problem. The Delay of 100 is optional but it makes the hole thing more elegant although this stays in conflict with your "should be displayed immediately" ;)
<input class="collapsed" type="checkbox">Cars
<div class="collapse2 collapse" style="display:none;">
<li>car hello</li>
<li>car lala</li>
<li>car 1</li>
</div>
$(".collapsed").click(function(event){
$(".collapse2").fadeToggle().delay(100);
})
If there are multiple checkboxes like this you maybe would have to use the this keyword in JS.
That should do the Trick if not leave a comment.
Related
I am new working with HTML and Python, and I am trying to develop some code for personal use.
The goal is to show the different leagues with a color code: red or green, and if I click on a league, it opens a different tab with more detailes information of that league, that is to say, it would be necessary to send the id of the league to the server to be able to use it for the next tab. I am trying to use a form, but it is not working.
The if-else condition is just to choose whether the color is red or green based on a league condition.
The problem I am having is that, creating the form with the for loop as I am doing, the league id that sends is always the same (1st league of the lopp), it is not dynamic, then I would like to know how to program it to be able to see the chosen league.
No matter on what league you click, you always access the same league information. I guess there is something wrong with the code because it is not dynamic, it does not display info based on my selection.
My idea was to have multiple forms created with the loop, one for each league, but it doesnt work.
I would really appreciate your help, thank you very much!
This is the HTML code:
competicionesAPIDict is a dict where the key is the country and the values the different leagues that exists in it.
competicionesAPI is the value obtained from the dict, that is iterated to get the info from each league.
<div style="width: 80%; height: 70%; background-color: azure; width: max-content">
{% for paisAPI, competicionesAPI in competicionesAPIDict.items() %}
<div class="div_pais">
<h4>{{paisAPI}} </h4>
<img src={{dict_banderas_pais[paisAPI]}} alt="No funciona" width="30px" height="30px"/>
{% for competicionAPI in competicionesAPI %}
{% if dict_hay_competicion[competicionAPI['id']] %}
<form name="siCompeticion"+{{competicionAPI['id']}} method="POST" action="/RAI/API/competicion">
<input type="hidden" name="id_competicion" value={{competicionAPI['id']}} />
<a href=/RAI/API/competicion style="font-size: 14px;margin-left: 17px;color: green;"
onclick="document.forms[0].submit();return false;">{{competicionAPI['name']}}</a>
</form>
{% else %}
<form name="noCompeticion"+{{competicionAPI['id']}} method="POST" action="/RAI/API/competicion">
<input type="hidden" name="id_competicion" value={{competicionAPI['id']}} />
<a href=/RAI/API/competicion style="font-size: 14px;margin-left: 17px;color: red;"
onclick="document.forms[0].submit();return false;">{{competicionAPI['name']}}</a>
</form>
{% endif %}
{% endfor %}
</div>
{% endfor %}
OK, I was wrong in a comment about hidden input field value being a problem.
I mean, it is still a problem, but it should work as is, except for JS code bug you made.
So first, what gave me wrong impression was that you would usually make one form per request, and then do as I said, set the forms values correctly to provide data of the request upon submit. You made a lot of forms, one per iteration, which is not wrong, but what you did is say in onclick event to activate always the first form on the site. I.e.
document.forms[0]
so, whatever you click, only first form will be submitted with the value of the first hidden input field in it.
As you have if-else clauses, I wouldn't rely on form indexes within the DOM, but use something to create unique IDs per each form, then use document.getElementById() to get that exact form and submit it. But you already gave your forms names, so you can use those with document.getElementsByName() or give the form an ID of same value.
Names does not need to be unique, IDs should.
Just a little sample:
<form id="siCompeticion"+{{competicionAPI['id']}} ...>
<input type="hidden" name="something" value={{competicionAPI['id']}}>
CLICK ME
</form>
In your place I would most probably write a little JS code to perform AJAX request, most likely using jquery. In any case, I would avoid making a lot of forms.
I'm extremely inexperienced with html and although I know python, I had never used django before this. I'm trying to set up a simple website where the user can view some code on the left side of the screen and enter some text about it on the right side of the screen. The code can be pretty long sometimes so the webpage scrolls, but I want the textbox to always be present even if you scroll up or down. As my code is now, the textbox is on the right side of the screen, but it always stays at the bottom. Here's a screenshot of what it looks like:
(can't seem to get screenshot to show up in the post, here's the link http://imgur.com/3JfgHH3)
Here's the .html file I'm using in my templates directory in django:
<div style="display: inline-block">
{% if error_message %}<p><strong>{{ error_message }}</strong></p>{% endif %}
<pre>{{ source_code }}<pre>
</div>
<div style ="display: inline-block" >
<form method="post" action="/labeling/{{ document_id }}/send/">
{% csrf_token %}
<input type="text" name="textfield">
<input type="submit" value="Finish" name="finish_btn" />
</form>
</div>
Sorry for my complete lack of html knowledge. How would I fix this either in django or in the html file directly so that the textbox and button move up and down with the scrolling, instead of being permanently attached to the bottom right of the screen? If necessary I can post the django code too, I just wasn't sure if this was possible directly in html.
<div style ="display: inline-block;position: fixed;" >
Implement position: fixed; into your styling of the first div. That should already do the trick. Like #furas said is - when it comes to styling - CSS the language you have to learn.
In the CSS file please add the following Code:
div.[class_name_of_div_element] {
position: fixed;
}
I need to get the user input in a textbox and process it using my python script when user presses Submit button. Unfortunately I am using an external server that does not support CGI. Is there any other way I can do this? This is my sample HTML.
<body>
<form name="form1" method="post" action="script1.py">
<div id="heading"><big><big><big>My analysis</big></big></big></div>
<textarea cols="50" rows="1" name="Query_text" id="Query_text"></textarea>
<div id="Button"><input name="Submit" value="Submit" type="submit"></div>
</form>
</body>
You can do the form processing with Javascript but hopefully you don't want to save this input beyond the next page the person accesses. Another old school option is emailing yourself the contents of Query_text. But honestly this is a lot more work than you want to do and not worth the effort (for most people). What you need is a new web host.
I am creating a html template for a django based app. I am using the twitter bootstrap API for buttons here, but one of them (the cancel button) doesn't seem to be working correctly. I link it to another page using an href, but when I click on the button, it redirects to the current page's post method. See below:
<h2>Add new Schedule:</h2>
<form class="form-horizontal" method='post'>
<table>
{% load bootstrap %}
{{ form|bootstrap }}
{% csrf_token %}
<tr>
<td></td>
<td>
<input class="btn btn-primary" type='submit' name='reset' value='Save' />
</td>
<td></td>
<td>Cancel</button></td>
</tr>
</table>
</form>
However, if I get rid of the button and use it as a simple href it seems to work:
<td><a href='{%url head.views.edit_instance_binding binding.id %}'>Cancel</a></td>
What's going on here?
You have a <button> inside an <a> element - get rid of the button, otherwise you'll be submitting your form.
If you want your anchor to be styled as a button, give it a btn class.
And Bootstrap is just a big set of CSS facilities with little js thrown in - no APIs at all :))
EDIT: nowadays HTML semantics and appearance are well separated [though someone may argue that Bootstrap has its hacks regarding this, see its <i>'s use for icons].
Keeping the eye on your case, you wanted to use a <button> to style a simple anchor like an embossed button. But a <button> tag is just a way to provide a richer <input type="submit">, in which you can insert images for example [see all the BS examples with icons beside buttons].
Well, <input type="submit"> and <button> inside a <form> trigger the latter's action, i.e. they post some data the user entered to such location.
If you just need to reach some URL without submitting anything, you need an anchor tag [<a>], which can be styled as you wish, e.g. with BS btn, btn-primary, btn-whateva classes.
Does anyone have any idea how to use the tag so the table of content comes onto the 1st page and all text is coming behind. This is what i've got so far, it generates the table of content behind my text...
pdf.html
<htmL>
<body>
<div>
<pdf:toc />
</div>
<pdf:nextpage>
<br/>
<h1> test </h1>
<h2> second </h2>
some text
<h1> test_two </h1>
<h2> second </h2>
some text
</body>
</html>
I can't seem to get everything in the right position, even with the it doesn't seem to work... any help or documentation somewhere? The PISA docs are rly crappy with details actually...
Btw 1 more extra thing, is it possible to make this table of content jump to the right page? If yes how does this works?
Regards,
I found I couldn't get that pagebreak to work for me, so I used inline CSS and, specifically, the page-break property to fix it.
In your case, this should do the trick:
<div style="page-break-after:always;>
<pdf:toc />
</div>
<h1> test </h1> ...etc...
As far as the links are concerned, there may be a way to automatically generate them, but I found it easier to manually create a table of contents using links and anchors:
<h1>Table of Contents</h1>
<ul>
<li><a href="section1">The name of section 1</li>
<li><a href="section2">The name of section 2</li>
</ul>
<h2>The name of section 1</h2>
<a name="section1"></a>
<h2>The name of section 2</h2>
<a name="section2"></a>
There's obviously some duplication, but I haven't found it difficult to maintain for my documents. It depends how long or complicated you expect yours to became.
The bigger downside is that this option won't include page numbers.
Steve's comment about the page-break property is correct. I personally used a separate CSS file with
h2 {
page-break-before:always;
}
so that all of my sections would start on a new page.