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I have a very simple program.
count = 0
total = 0
def iseven(number):
if number % 2 == 0:
True
else:
False
while count < 10 :
if iseven(count):
total = total * 2
else:
total = total * 4
print total
count = count + 1
print "final total is ", total
But this just prints zero on every iteration, and the final total is then zero.
So looks like the total value is not being updated.
Any ideas?
count = 0
total = 1
def iseven(number):
if number % 2 == 0:
return True
else:
return False
while count < 10 :
if iseven(count):
total = total * 2
else:
total = total * 4
print (total)
count = count + 1
print ("final total is ", total)
You are multiplying 0, which always results in 0
Output:
2
8
16
64
128
512
1024
4096
8192
32768
final total is 32768
Your is_even function is missing a return statement.
Also, total should be initialised to 1, instead of 0 (1 is the idempotent value for the multiplication, not 0).
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I just need to divide some number by only 10. For instance, if the number is 127, the result should only be 12 and remained to be 7. Is there a way I can get Python to give me these BOTH results? Because I need to divide that remainder by some number as well for instance 2.
So overall it should be like this:
127 = 12 (10) and 3 (2) and 1(remainder).
Hope that makes sense
You can try using double division and modulus division -
quotient = 127 // 10
remainder = 127 % 10
print(quotient) # 12
print(remainder) # 7
Or use divmod -
num = 127
d = 10 # Divisor
quotient,remainder = divmod(num, d) # It returns tuple
print(quotient) # 12
print(remainder) # 7
def divide_and_get_remainder(num, divisor):
quotient = num // divisor
remainder = num % divisor
return quotient, remainder
if __name__ == '__main__':
num = 127
divisor = 10
q, r = divide_and_get_remainder(num,divisor)
print(f'{num} / {divisor} = {q} with remainder = {r}')
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I am writing a python script right now to check if a number a Wilson Prime, but it says I have a syntax error on line 9.
I've tried both the mod function with x%y == 0 and x/y == int, but both of them have given me a syntax error.
n = int(input("Type a natural number here"))
fact = 1
for i in range(1,n):
fact = fact * i
finalfact = fact + 1
if finalfact % n == 0
print(n, "is a prime number!")
if (finalfact/n) % n == 0
print(n, "is also a Wilson Prime!")
I'm trying to make it check if (n-1)!+1 is divisible by n (which is a way to find prime numbers) and to check if (n-1)!+1 is divisible by n^2 (Wilson Primes), but it gives me a syntax error on line 9 and nothing happens.
You are missing : at the end of if statements.
Change:
if finalfact % n == 0
To:
if finalfact % n == 0:
And:
if (finalfact/n) % n == 0
To:
if (finalfact/n) % n == 0:
Need to indent the code properly:
Change:
for i in range(1,n):
fact = fact * i
To:
for i in range(1,n):
fact = fact * i
Also:
finalfact / n # 5 / 2 = 2.5
Should be:
finalfact // n # 5 // 2 = 2
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Am new to programming and I just started studying and practicing. I started with python and am at for loops now. I kinda coded something that’s getting confusing for me because I can’t seem to understand how the code arrived at that output. Can someone please explain it to me. Would be very grateful.
Here’s the code I did:
a = range(1,20)
total = 0
for i in a :
if i%3==0 or i%5==0 :
total new = total + i
print (total new)
And the output was 18.
a = range(1,20)
Your program is creating a range of numbers between 1 and 19 (ranges go to one less than the max number you specify) like [1, 2, 3, 4, ..., 19]
total = 0
Your program is initializing the variable total to equal 0
for i in a:
You start looping through the range you made earlier, the first iteration i=1, the next i=2 and so on until i=19
if i % 3 == 0 or i % 5 == 0:
You are selecting only the data where the modulo of 5 or 3 is 0. For example:
3 % 3 == 0 (0 remainder)
4 % 3 == 1 (1 remainder)
Now altering your variable to a reasonable name (without spaces) that will actually utilize the variable we initialized above
total = total + i # alternatively written "total += i"
This says that every time the value i is evenly divisible by 3 or 5 we will add it to our total
print(total)
We show the final result after adding values. You incorrectly scripted your program to do this though so it only showed the largest value that was evenly divisible by 5 or 3 which is 18.
When scripted correctly:
a = range(1, 20)
total = 0
for i in a:
if i % 3 == 0 or i % 5 == 0:
total += i
print(total)
Outputs
78
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The following python coding is written to generate the triangle numbers between 1 to 55. But the coding is not working why ?
num = 1
sum = 0
while (num <= 10)
sum = sum + num
num = num + 1
print (sum, end=' ')
Missing colon :
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print (sum, end=' ')
or
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print (sum, end=' ')
Output
1 3 6 10 15 21 28 36 45 55
For 2.7
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print sum,
Your error is an error that is not followed by a while statement, followed by a () wrap and end of print that are not supported by default in Python 2.x.
The Corrected Code is:
num = 1
sum = 0
while (num <= 10):
sum = sum + num
num = num + 1
print sum
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I've tried looking up some questions that were already on StackOverflow for project Euler problem 1 but not much has helped me. This is my code, it runs, but it's not correct. not sure whats wrong?
def sumOfMultiples(number):
sum = 0
for i in range(1,number):
if i % 3 == 0 or i % 5 == 0:
sum += 1
return sum
print (sumOfMultiples(15))
You are not using i at all. When the number meets the condition (divisible by 3 or 5), you want to add it, not 1.
sum += 1
should be
sum += i
The question asks for "the sum of all the multiples of 3 or 5 below 1000". You're adding 1 to the sum instead of adding the multiple of 3 or 5 to the sum.
So sum += 1 should be sum += i.
import time
#Recording start time of the program
start=time.time()
#A variable to store the sum
result=0
#calculating the sum for all the numbers below 1000
for i in range(1,1000):
#Checking the the condition
if i%3==0 or i%5==0:
result=result+i
print("Sum of all numbers that are multiples of 3 or 5 below 1000 is",result)
print("Execution time of program is",time.time()-start)
def sumOfMultiples(number):
sum = 0
for i in range(1,number):
if i % 3 == 0 or i % 5 == 0:
sum += i
return sum
print (sumOfMultiples(15))
In place of sum+=1 write sum+=i.
Here is a single-liner for you to ponder:
print sum([x for x in xrange(1,1000) if x%3==0 or x%5==0])
or you could also do it like this:
print sum([[0,x][x%3==0 or x%5==0] for x in xrange(1,10**3)])
try using this:
def sumOfMultiples(number):
sum = 0
for i in range(1,number):
if i % 3 == 0 or i % 5 == 0:
sum += i ## You needed to add i, not 1. Probably just a type-o as they are similar looking characters.
print(sum)
(sumOfMultiples(1000)) ## Also Euler1 requires this input to be 1000 for correct answer.