Hi there I want to add a file to python with a few diffrent list in it like
File.txt:
ListA=1,2,3,4 ListB=2,3,4
I want to save the list in my script with the same name like in the File.txt. For example: ListA=[1,2,3,4] ListB=[2,3,4] After that I want to copy one list to a new list called for example li that I can use it. Here is my Script which dont work that u can see what I mean.
So 1st of all: How can I read lists from a txt file and use their name? 2nd How do I copy a specific list to a new list? Hope someone can help me :) And I hope it have not allready been asked.
def hinzu():
#file=input('text.txt')
f=open('text.txt','r')
**=f.read().split(',')
print ('li',**)
#this give me the output **=['ListA=1','2','3','4'] but actualy I want ListA=['1','2'...]
def liste():
total=1
li=input('which list do you want to use?')
for x in li:
float(x)
total *= x
print('ende', total)
You need to split the text by = sign which will seprate the list name with list contents then split the content by ,
f=open('text.txt','r')
a,b=f.read().split('=')
print (a,list(b.split(','))
Split your input first by =, then by ,:
name, list = f.read().split('=')
list = list.split(',')
You may want to add another .split() for your ListB.
To set the name as a variable in the global name scope you can use:
globals().update({name:list})
Related
What my script is doing now is adding elements to a list. For example, if the user types "JO", I will add "John" to the list. What I want to do now is that, if the user types "2 JO", I add two elements to the list: "John" and "John".
This is how the database looks like now:
Sample database copy.png
This is the code now:
import pandas
data = pandas.read_excel("Sample database copy.xlsx")
name = dict(zip(data["Abbreviation"],data["Name"]))
list1 = []
incoming_msg = input(Please type what you want to add: )
list1.append(name[incoming_msg])
I need to do it all from the same input, I cannot ask separately for quantity and abbreviation. I wanted to know if there is any library that can do this somehow easily because I am a beginner coder. If there is no library but you have any idea how I could solve it, it would be awesome as well.
Thank you so much in advance!
you can use string.split() to split the string by space into a list then use the first element to multiply a list that contains the value from the dictionary and increment it to the result list. see the code
name = dict(zip(data["Abbreviation"],data["Name"]))
list1 = []
incoming_msg = input('Please type what you want to add: ')
incoming_msg = incoming_msg.split() # split the string by space
if len(incoming_msg) == 2: # if there are two elements in the list (number and name)
list1 += [name[incoming_msg[1]]] * int(incoming_msg[0])
else:
list1.append(name[incoming_msg[0]])
I have three lists:
id = [1,3,4]
text = ["hello","hola","salut"]
date = ["20-12-2020","21-04-2018","15-04-2016"]
#I then combined it all in one list:
new_list = zip(id, text, date)
#which looks like [(1,"hello","20-12-2020"),(3,"hola","21-04-2018"),(4,"salut","15-04-2016")
I want to delete the whole list if it is not in english, do to this i installed lang id and am using lang id.classify
I ran a loop on only the text and its working but am unsure how to delete the whole value such as: (3,"hola","21-04-2018") as hola is not in english.
I am trying to achieve a new list which only has those lists in it that is only english. I want to further write the output list in a xml file.
To do that I have made a sample xml file and am using the date as a parent key as the date can be same for multiple texts.
Try this simple for loop
new_list = [(1,"hello","20-12-2020"),(3,"hola","21-04-2018"),(4,"salut","15-04-2016")]
for x in new_list:
# condition to check if word or sentence is english
if not isEnglishWord(x[1]):
new_list.pop(x)
Not sure how lang id.classify works or what parameters it takes in but something like this should work:
for i in range(len(new_list)):
if id.classify(new_list[i][1]) != 'english':
new_list.pop[i]
In this case, I'm assuming id.classify takes in a str and outputs which language the word belongs (as a str).
I'm also using the range list method to iterate so we don't end up changing the list as we are iterating over it.
I'm having some trouble figuring out the best implementation
I have data in file in this format:
|serial #|machine_name|machine_owner|
If a machine_owner has multiple machines, I'd like the machines displayed in a comma separated list in the field. so that.
|1234|Fred Flinstone|mach1|
|5678|Barney Rubble|mach2|
|1313|Barney Rubble|mach3|
|3838|Barney Rubble|mach4|
|1212|Betty Rubble|mach5|
Looks like this:
|Fred Flinstone|mach1|
|Barney Rubble|mach2,mach3,mach4|
|Betty Rubble|mach5|
Any hints on how to approach this would be appreciated.
You can use dict as temporary container to group by name and then print it in desired format:
import re
s = """|1234|Fred Flinstone|mach1|
|5678|Barney Rubble|mach2|
|1313|Barney Rubble||mach3|
|3838|Barney Rubble||mach4|
|1212|Betty Rubble|mach5|"""
results = {}
for line in s.splitlines():
_, name, mach = re.split(r"\|+", line.strip("|"))
if name in results:
results[name].append(mach)
else:
results[name] = [mach]
for name, mach in results.items():
print(f"|{name}|{','.join(mach)}|")
You need to store all the machines names in a list. And every time you want to append a machine name, you run a function to make sure that the name is not already in the list, so that it will not put it again in the list.
After storing them in an array called data. Iterate over the names. And use this function:
data[i] .append( [ ] )
To add a list after each machine name stored in the i'th place.
Once your done, iterate over the names and find them in in the file, then append the owner.
All of this can be done in 2 steps.
I'm making a program that allows the user to log loot they receive from monsters in an MMO. I have the drop tables for each monster stored in text files. I've tried a few different formats but I still can't pin down exactly how to take that information into python and store it into a list of lists of lists.
The text file is formatted like this
item 1*4,5,8*ns
item 2*3*s
item 3*90,34*ns
The item # is the name of the item, the numbers are different quantities that can be dropped, and the s/ns is whether the item is stackable or not stackable in game.
I want the entire drop table of the monster to be stored in a list called currentDropTable so that I can reference the names and quantities of the items to pull photos and log the quantities dropped and stuff.
The list for the above example should look like this
[["item 1", ["4","5","8"], "ns"], ["item 2", ["2","3"], "s"], ["item 3", ["90","34"], "ns"]]
That way, I can reference currentDropTable[0][0] to get the name of an item, or if I want to log a drop of 4 of item 1, I can use currentDropTable[0][1][0].
I hope this makes sense, I've tried the following and it almost works, but I don't know what to add or change to get the result I want.
def convert_drop_table(list):
global currentDropTable
currentDropTable = []
for i in list:
item = i.split('*')
currentDropTable.append(item)
dropTableFile = open("droptable.txt", "r").read().split('\n')
convert_drop_table(dropTableFile)
print(currentDropTable)
This prints everything properly except the quantities are still an entity without being a list, so it would look like
[['item 1', '4,5,8', 'ns'], ['item 2', '2,3', 's']...etc]
I've tried nesting another for j in i, split(',') but then that breaks up everything, not just the list of quantities.
I hope I was clear, if I need to clarify anything let me know. This is the first time I've posted on here, usually I can just find another solution from the past but I haven't been able to find anyone who is trying to do or doing what I want to do.
Thank you.
You want to split only the second entity by ',' so you don't need another loop. Since you know that item = i.split('*') returns a list of 3 items, you can simply change your innermost for-loop as follows,
for i in list:
item = i.split('*')
item[1] = item[1].split(',')
currentDropTable.append(item)
Here you replace the second element of item with a list of the quantities.
You only need to split second element from that list.
def convert_drop_table(list):
global currentDropTable
currentDropTable = []
for i in list:
item = i.split('*')
item[1] = item[1].split(',')
currentDropTable.append(item)
The first thing I feel bound to say is that it's usually a good idea to avoid using global variables in any language. Errors involving them can be hard to track down. In fact you could simply omit that function convert_drop_table from your code and do what you need in-line. Then readers aren't obliged to look elsewhere to find out what it does.
And here's yet another way to parse those lines! :) Look for the asterisks then use their positions to select what you want.
currentDropTable = []
with open('droptable.txt') as droptable:
for line in droptable:
line = line.strip()
p = line.find('*')
q = line.rfind('*')
currentDropTable.append([line[0:p], line[1+p:q], line[1+q:]])
print (currentDropTable)
I am new to python and am trying to access a single specific element in a list of lists.
I have tried:
line_list[2][0]
this one isn't right as its a tuple and the list only accepts integers.
line_list[(2, 0)]
line_list[2, 0]
This is probably really obvious but I just can't see it.
def rpd_truncate(map_ref):
#Munipulate string in order to get the reference value
with open (map_ref, "r") as reference:
line_list = []
for line in reference:
word_list = []
word_list.append(line[:-1].split("\t\t"))
line_list.append(word_list)
print line_list[2][0]
I get the exact same as if I used line_list[2]:
['Page_0', '0x00000000', '0x002DF8CD']
actually split will return a list
more over you don't require word_list variable
for line in reference:
line_list.append(line[:-1].split("\t\t"))
print line_list[2][0]