Trying to write a program in python to display inventory and number of each item in inventory, but having difficulty pulling values from dict...
Using Python 3.5 on Win10, through default Python editor
From chapter 5 sample problem of "Automate the Boring Things with Python"
i={'color':'red','gold':3}
def bP(n):
inv=''
for v in n:
print (str(n)+':'+str(n[v])) #Problem is first print not displaying value
bP(i)
You can iterate dictionary by key-value pair too. Check the manual. Here is an example of it.
for k, v in dict.items():
print(k, v)
i={'color':'red','gold':3}
def bP(n):
inv=''
for key,value in n.items():
print (str(key)+':'+str(value))
bP(i)
when you iterate dict then should use items() method
Consider the following example:
d={'color':'red','gold':3}
for key,value in d.items():
print(key,value)
output:
gold 3
color red
d.items() outputs a key,value pair.
Also,
for item in d.values():
print(item)
output:
3
red
But,
for key in d.keys():
print(key)
output:
gold
color
However just doing this gives the same result as above,
for key in d:
print(key)
output:
gold
color
So in your case,
for v in n:
print (str(n)+':'+str(n[v]))
should be,
for v in n:
print (str(v)+':'+str(n[v]) )
if variables made more sense would be something like,
for key in my_dict:
print (str(key)+':'+str(my_dict[key])) #my_dict[key] is value
You are trying to print str(n) which is your dict. Alternatively, you can loop through items of the dictionary as the following:
for k, v in n.items():
print('{}:{}'.format(k, v))
While in your case, you can fix it by changing str(n):
for v in n:
print('{}:{}'.format(v, n[v]))
Related
I have a list of dictionaries which i want to display using Tkinter.
So far i only managed to print the desired result.
Example code:
for x in list:
for key, value in x.items():
print("{}: {}".format(key, value))
>>>key: value
key: value
key: value
The way it's printed is the exact way i want to display it on the application. How do i store this output as text?
Looks like you need.
out = ""
for x in list:
for key, value in x.items():
out += "{}: {}\n".format(key, value))
print(out)
I have a dictionary where each key has several lists of data as its values like this
myDict = {'data1' : ['data_d','dataD']['data_e','dataE']['data_f','dataF']}
I want to be able to input one of the values in the list and then be given the key. This is so I can get the other value in the list now that I have the key.
I've tried
dataKey = (list(myDict.keys())[list(myDict.values()).index(dataD)])
but that didn't work
I've also tried
for k, v in myDict.items():
if 'dataD' in v:
print k
but that didn't work as well.
Side question, in the questions that I've looked through, I see people using the variable k and v a lot even without the OP mentioning them, so I am wondering if k and v are already set variable in dictionaries?
Your second attempt was almost right, but a nested for loop is needed to traverse the list-of-lists:
myDict = {'data1' : [['data_d','dataD'], ['data_e','dataE'], ['data_f','dataF']]}
for key, value in myDict.items():
for sublist in value:
if 'dataD' in sublist:
print(key) # -> data1
Using variables named k, and v with dictionaries is purely optional and aren't special properties—other than being very short abbreviations for "key" and "value".
Note that if only one match is ever expected to occur, the code could be made more efficient by stopping the search after one is found. Here's one way of doing that:
target = 'dataD'
try:
for key, value in myDict.items():
for sublist in value:
if target in sublist:
print(key) # -> data1
raise StopIteration # found, so quit searching
except StopIteration:
pass # found
else:
print('{} not found'.format(target))
if they are all going to be lists then you can do something like this (if i am understanding correctly)
myDict = {
'data1': [['data_d','dataD'], ['data_e','dataE'], ['data_f','dataF']],
}
def find(dic, item):
for k, v in dic.items():
for ls in v:
if item in ls:
return k
return False
print(find(myDict, "data_d"))
# OUT [data1]
I have a dict like this:
d = {'first':'', 'second':'', 'third':'value', 'fourth':''}
and I want to find first non-empty value (and it's name, in this example 'third'). There may be more than one non-empty value, but I only want the first one I find.
How can I do this?
Use an OrderedDict which preserves the order of elements. Then loop over them and find the first that isn't empty:
from collections import OrderedDict
d = OrderedDict()
# fill d
for key, value in d.items():
if value:
print(key, " is not empty!")
You could use next (dictionaries are unordered - this somewhat changed in Python 3.6 but that's only an implementation detail currently) to get one "not-empty" key-value pair:
>>> next((k, v) for k, v in d.items() if v)
('third', 'value')
Like this?
def none_empty_finder(dict):
for e in dict:
if dict[e] != '':
return [e,dict[e]]
d = {'first':'', 'second':'', 'third':'value', 'fourth':''}
for k, v in d.items():
if v!='':
return k, v
Edit 1
from the comment if the value is None or '' we better use if v: instead of if v!=''. if v!='' only check the '' and skip others
You can find empty elements and make a list of them:
non_empty_list = [(k,v) for k,v in a.items() if v]
By using list comprehension, you can list all the non-empty values and then fetch the 0th value:
[val for key, val in d.items() if val][0]
So, I've been searching endlessly for something similiar to Lua's "Generic For Loop" in Python.
I've been working on a simple text based game in Python, and I've been working with dictionaries a lot.
Here is something I'm looking for (in Lua):
Dictionary = {
"Red" = "There is some red paint on the walls.",
"Green" = "There is a little bit of green paint on the floor.",
}
for i, v in pairs(Dictionary) do
print(i, v)
end
What this will do is, go through the dictionary, then print out the INDEX and the VALUE. How would I do something like this in Python?
I know there is this:
for i in Dictionary:
print(i)
But that just prints the INDEX. I would like to access both the INDEX and the VALUE. Something like:
for i, v in Dictionary:
print(i, v)
Any help is appreciated.
You're looking for items. Iterating over a dict just gives you the keys, so you'd have to do:
for key in my_dict:
x = my_dict[key]
What you want is this:
for key, value in my_dict.items():
# do something
two ways:
for i, v in Dictionary.items():
print(i, v) #outputs pairs as key value
for tup in Dictionary.items(): #same thing
print(tup) # outputs pairs as (key,value)
or
for key in Dictionary:
print(key,Dictionary[key])
EDIT RESPONSE TO COMMENT:
>>> d = {1:1,2:2,3:3,4:4}
>>> for item in d.items(): print(item)
(1, 1)
(2, 2)
(3, 3)
(4, 4)
>>> for key,val in d.items(): print(key,val)
1 1
2 2
3 3
4 4
this is because in the first loop, item is a tuple and the __repr__ for a tuple has the brackets and commas as part of it where as the second loop splits the tuple into two seperate variables. print then automatically adds a space delimiter in between each parameter passed in the print function.
As explained by Two-Bit Alchemist:
In case it's not entirely clear still, in the tup formulation you'd access the key and value as tup[0] and tup[1], respectively. for key, val in my_dict.items(): ... and for tup in my_dict.items(): key, val = tup is the same setup. The point is you can use tuple unpacking just fine inline in a for loop.
The items method (or in Py2, viewitems or iteritems to avoid making a whole new list containing copies of the dict key/value pairs) is the way to go:
for k, v in Dictionary.items(): # For performance, use .viewitems() on Py2.7, .items() on Py3.x
print(k, v)
How to get a particular key from dictionary in python?
I have a dictionary as :
dict = {'redorange':'1', 'blackhawak':'2', 'garlicbread':'3'}
I want to get value of that key which contains garlic in its key name.
How I can achieve it?
Let's call your dictionary d:
print [v for k,v in d.iteritems() if 'garlic' in k]
prints a list of all corresponding values:
['3']
If you know you want a single value:
print next(v for k,v in d.iteritems() if 'garlic' in k)
prints
'3'
This raises StopIterationError if no such key/value is found. Add the default value:
print next((v for k,v in d.iteritems() if 'garlic' in k), None)
to get None if such a key is not found (or use another default value).