I'm currently trying to webscrape a website, and am doing so with python's urllib.request and bs4. However, this particular website has a truncated/dummy url, and so I can't put in the url and work with the html.
import urllib.request
import bs4 as bs
mylink = urllib.request.urlopen("http://www.vacationstogo.com/ticker.cfm").read()
soup = bs.BeautifulSoup(mylink, "html.parser")
NOTE:
http://www.vacationstogo.com/custom.cfm is the website where I fill in some inputs, and then when I click the search button, I get the url http://www.vacationstogo.com/ticker.cfm. Note however, that the previous URL will redirect me to some empty search page, and is not the url for the website with my search results.
Thanks.
Related
I am testing using the requests module to get the content of a webpage. But when I look at the content I see that it does not get the full content of the page.
Here is my code:
import requests
from bs4 import BeautifulSoup
url = "https://shop.nordstrom.com/c/womens-dresses-shop?origin=topnav&cm_sp=Top%20Navigation-_-Women-_-Dresses&offset=11&page=3&top=72"
page = requests.get(url)
soup = BeautifulSoup(page.content, 'html.parser')
print(soup.prettify())
Also on the chrome web-browser if I look at the page source I do not see the full content.
Is there a way to get the full content of the example page that I have provided?
The page is rendered with JavaScript making more requests to fetch additional data. You can fetch the complete page with selenium.
from bs4 import BeautifulSoup
from selenium import webdriver
driver = webdriver.Chrome()
url = "https://shop.nordstrom.com/c/womens-dresses-shop?origin=topnav&cm_sp=Top%20Navigation-_-Women-_-Dresses&offset=11&page=3&top=72"
driver.get(url)
soup = BeautifulSoup(driver.page_source, 'html.parser')
driver.quit()
print(soup.prettify())
For other solutions see my answer to Scraping Google Finance (BeautifulSoup)
Request is different from getting page source or visual elements of the web page, also viewing source from web page doesn't give you full access to everything that is on the web page including database requests and other back-end stuff. Either your question is not clear enough or you've misinterpreted how web browsing works.
I am having trouble figuring out how to use BeautifulSoup to scrape all 100 link titles on the page since it is under "a href = ....." . I have tried the below code but it returns a blank.
from bs4 import BeautifulSoup
from urllib.request import urlopen
import bs4
url = 'https://www150.statcan.gc.ca/n1/en/type/data?count=100'
page = urlopen(url)
soup = bs4.BeautifulSoup(page,'html.parser')
title = soup.find_all('a')
Additionally, is there a way to ensure I am scraping everything under the "Tables (8898)" tabs? Thanks in advance!
Link:
https://www150.statcan.gc.ca/n1/en/type/data?count=100
The link you provided is loading it's contents with async javascript requests. So when you exec page = urlopen(url) it is only fetching the empty HTML and javascript blocks.
You need to use a browser to execute js to load page contents. You can checkout this link to learn how to do it: https://towardsdatascience.com/web-scraping-using-selenium-python-8a60f4cf40ab
I am trying to extract urls for listings from a city page in AirBnb, using python 3 libraries. I am familiar with how to scrape simpler websites with Beautifulsoup and requests libraries.
url: 'https://www.airbnb.com/s/Denver--CO--United-States/homes'
element in the html
If I inspect the element of a link on the page (in Chrome), I get:
xpath: "//*[#id="listing-9770909"]/div[2]/a"
selector: "listing-9770909 > div._v72lrv > a"
My attempts:
import requests
from bs4 import BeautifulSoup
url = 'https://www.airbnb.com/s/Denver--CO--United-States/homes'
html = requests.get(url)
soup = BeautifulSoup(html.text, 'html.parser')
divs = soup.find_all('div', attrs={'id': 'listing'})
attempt 2:
import requests
from lxml import html
page = requests.get(url)
root = html.fromstring(page.content)
tree = root.getroottree()
result = root.xpath('//div[#id="listing-9770909"]/div[2]/a')
for r in result:
print(r)
Neither of these returns anything. What I need to be able to extract is the url for the page link. Any ideas?
To extract the links, first you have to make sure that the urls to the links exists in the page source. For this you can search with any of the listing ids in the page source(ctrl+u if you are using google chrome,mozilla firefox). If the urls exist in the page source you can directly scrape them using xpath in the response text of the listing page. Here the above listing page of Airbnb is not having the links in the page source, so the page might be sending requests to some other pages(usually json requests). You can find out those requests and send requests to those pages and get the required data.
Please comment if you have any doubt regarding this.
I am trying to scrape some data from a specific website using the requests and Beautiful Soup libraries. Unfortunately, I am not receiving the HTML for that page, but for the parent page https://salesweb.civilview.com. Thank you for your help!
import requests
from bs4 import BeautifulSoup
example="https://salesweb.civilview.com/Sales/SaleDetails?PropertyId=473016965"
exampleGet=requests.get(example)
exampleGetText=exampleGet.text
soup = BeautifulSoup(exampleGetText,"lxml")
soup
You need to feed a cookie to the request:
import requests
from bs4 import BeautifulSoup
cookie = {'ASP.NET_SessionId': 'rk2b0dxast1eyu5jvxezltgh'}
example="https://salesweb.civilview.com/Sales/SaleDetails?PropertyId=473016964"
exampleGet=requests.get(example, cookies=cookie)
exampleGetText=exampleGet.text
soup = BeautifulSoup(exampleGetText,"lxml")
soup.title
<title>Sales Listing Detail</title>
That particular cookie may not work for you, so you'll need manually navigate to that page one time, then go into the developer (web inspector) tools in your browser, and lookup the cookie under "Headers" in the network tab. My cookie looked like 'ASP.NET_SessionId=rk2b0dxast1eyu5jvxezltgh'.
The cookie should be valid for other property pages as well.
I want to get a fragment from a HTML website with python.
For example from the url http://steven-universe.wikia.com/wiki/Steven_Universe_Wiki I want to get the text in the box "next Episode", as a string. How can I get it?
First of all download BeautifulSoup latest version from here
and requests from here
from bs4 import BeautifulSoup
import requests
con = requests.get(url).content
soup = BeautifulSoup(con)
text = soup.find_all("a",href="/wiki/Gem_Harvest").text;
print(link)