how to unittest and mock for open funtion - python

I have read many article over the last 6 hours and i still don't understand mocking and unit-testing. I want to unit test a open function, how can i do this correctly?
i am also concerned as the bulk of my code is using external files for data import and manipulation. I understand that i need to mock them for testing, but I am struggling to understand how to move forward.
Some advice please. Thank you in advance
prototype5.py
import os
import sys
import io
import pandas
pandas.set_option('display.width', None)
def openSetupConfig (a):
"""
SUMMARY
Read setup file
setup file will ONLY hold the file path of the working directory
:param a: str
:return: contents of the file stored as str
"""
try:
setupConfig = open(a, "r")
return setupConfig.read()
except Exception as ve:
ve = (str(ve) + "\n\nPlease ensure setup file " + str(a) + " is available")
sys.exit(ve)
dirPath = openSetupConfig("Setup.dat")
test_prototype5.py
import prototype5
import unittest
class TEST_openSetupConfig (unittest.TestCase):
"""
Test the openSetupConfig function from the prototype 5 library
"""
def test_open_correct_file(self):
result = prototype5.openSetupConfig("Setup.dat")
self.assertTrue(result)
if __name__ == '__main__':
unittest.main()

So the rule of thumb is to mock, stub or fake all external dependencies to the method/function under test. The point is to test the logic in isolation. So in your case you want to test that it can open a file or log an error message if it can't be opened.
import unittest
from mock import patch
from prototype5 import openSetupConfig # you don't want to run the whole file
import __builtin__ # needed to mock open
def test_openSetupConfig_with_valid_file(self):
"""
It should return file contents when passed a valid file.
"""
expect = 'fake_contents'
with patch('__builtin__.open', return_value=expect) as mock_open:
actual = openSetupConfig("Setup.dat")
self.assertEqual(expect, actual)
mock_open.assert_called()
#patch('prototype5.sys.exit')
def test_openSetupConfig_with_invalid_file(self, mock_exit):
"""
It should log an error and exit when passed an invalid file.
"""
with patch('__builtin__.open', side_effect=FileNotFoundError) as mock_open:
openSetupConfig('foo')
mock_exit.assert_called()

Related

How to check what was written to a mock_open() fake file?

I have a productive function that read a file and in some situations also write (more than once) to another file (with kind of detailed error output).
I am able to mock the file reading and give specific file content in the unittests. But I do not know how to test for what was written to the the second file which is also mocked via mock_open().
One important point is that I am not interested in writing a real file to the filesystem when unittesting.
That is the productive code:
import pathlib
def my_prod_code(fp):
with fp.open('r') as if:
result = if.read()
with fp.with_suffix('.error.out').open('w') as of:
of.write(f'Read {result}.')
of.write('FIN.')
return result
That is the unittest
import unittest
from unittest import mock
import pathlib
class MyTest(unittest.TestCase):
def test_foobar(self, mock_unlink):
opener = mock.mock_open(read_data='foobar')
with mock.patch('pathlib.Path.open', opener):
result = my_prod_code(pathlib.Path('file.in'))
self.assertEqual(result, 'foobar')
# Want to check for the written content also
There is no built-in way to do this, so you either have to add your own handling in the mock, or use some package that fakes the file system.
Adding your own handling would mean to implement your own write, e.g. something like this:
class MockWriter:
"""Collect all written data."""
def __init__(self):
self.contents = ''
def write(self, data):
self.contents += data
class MyTest(unittest.TestCase):
def test_foobar(self):
opener = mock.mock_open(read_data='foobar')
writer = MockWriter()
# replace the write method in the mock with your own
opener.return_value.write = writer.write
with mock.patch('pathlib.Path.open', opener) as f:
result = my_prod_code(pathlib.Path('file.in'))
self.assertEqual(result, 'foobar')
self.assertEqual(writer.contents, 'Read foobar.FIN.')
The other possibility is to use a fake file system like pyfakefs:
from pyfakefs.fake_filesystem_unittest import TestCase
class MyTest(TestCase):
def setUp(self):
self.setUpPyfakefs()
def test_foobar(self):
self.fs.create_file('file.in', contents='foobar')
result = my_prod_code(pathlib.Path('file.in'))
self.assertEqual(result, 'foobar')
path = pathlib.Path('file.error.out')
self.assertEqual(path.read_text(), 'Read foobar.FIN.')
This way, you don't have to do the mocking yourself and can use the standard file system functions, with the downside that you need an extra package that generates some test overhead.
Disclaimer:
I'm a contributor to pyfakefs.

pytest How to mock s3fs.S3FileSystem open file

I am trying to mockup the call to open a file in a S3 bucket. The code that I have is:
# mymodule.py
import s3fs
#...
def __init__(self):
self.s3_filesystem = s3fs.S3FileSystem(anon=False, key=s3_key,
secret=s3_secret)
#...
def mymethod(self):
with self.s3_filesystem.open(filename, 'r') as csv_file:
file_dataframe = pd.read_csv(csv_file)
The mock that I have in pytest is:
import pytest
def test(mocker)
mocker.patch('mypackage.mymodule.s3fs.S3FileSystem.open',
return_value=open)
But at run the test I get the error:
> with self.s3_filesystem.open(filename, 'r') as csv_file:
E AttributeError: __enter__
Any idea why?
Disclaimer: All credits to my answer are due to the OP Juan Fernando Jaramillo Botero and his comment to his own question, above. I am posting an answer here, because it appears that the OP does not have at least 15 reputation points at the moment - and thus, can't answer his own question, as indicated in this help page. Please, if this is not the case, I encourage the OP to add his answer - and accept it - because it helped me a lot!
I was having the same problem, where I had to mock two methods from s3fs.S3FileSystem: open (as OP), and also ls, in a pytest suite of tests.
By using the decorator patch, and its argument side_effect, all calls for s3fs.S3FileSystem.open and s3fs.S3FileSystem.ls during tests are properly replaced by open and os.listdir, respectively, which in my case was the desired effect.
Simplified situation:
my_module.py
import s3fs
class Operation():
def compile_files(self, fs, input_bucket):
files = fs.ls(input_bucket)
return files
def copy_files(self, fs, files, input_bucket, output_bucket):
for file in files:
with fs.open(f'{input_bucket}/{file}', 'rb') as source:
with fs.open(f'{output_bucket}/{file}', 'wb') as destination:
destination.write(source.read())
def transform(self, input_bucket, output_bucket):
fs = s3fs.S3FileSystem()
files = self.compile_files(fs, input_bucket)
self.copy_files(fs, files, input_bucket, output_bucket)
my_module_test.py
import os
from unittest.mock import patch
from my_module import Operation
#patch('s3fs.S3FileSystem.open', side_effect=open)
#patch('s3fs.S3FileSystem.ls', side_effect=os.listdir)
def test_my_module(mock_s3fs_ls, mock_s3fs_open):
input_bucket = 'test/fixtures/files'
output_bucket = 'test/fixtures/tmp_output'
os.mkdir(output_bucket)
Operation().transform(input_bucket, output_bucket)
# Proceed to assert everything went as expected...
Note that the test file does not import pytest, but it is fully compatible and can be run within a pytest test suite.

HTMLTestRunner error:raise TypeError("{} is not callable".format(repr(test)))

When I use HTMLTestRunner for Python 3.5,it shows an error.
I have changed the HTMLTestRunner for support python 3.5.
The code :
import pymysql
import pymysql
import unittest
import time
import unittest.suite
import HTMLTestRunner
import sys
def hell(a):
print(a)
return a
testunit = unittest.TestSuite()
testunit.addTest(hell('ad'))
filename = '/Users/vivi/Downloads/aa.html'
fp = open(filename, 'wb')
runner = HTMLTestRunner.HTMLTestRunner(stream=fp, title=u'print', description=u'简单')
runner.run(testunit)
When I run it, I got this error:
Traceback (most recent call last):
File "/Applications/Python 3.5/……/B.py", line 30, in <module>
testunit.addTest(hell('ad'))
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/unittest/suite.py", line 47, in addTest
raise TypeError("{} is not callable".format(repr(test)))
TypeError: 'ad' is not callable
What should I do to make the script works?
You're adding the result of the call to hell('ad') to your tests, not the hell function itself. Since the hell function returns its argument, it returns the string ad, which is not a callable (function or the like).
Use
testunit.addTest(hell)
instead.
What about that argument then, how do you pass that?
Well, there are ways to do that, but generally, try not to let your unit test functions take an argument. Thus, hell() should siply not take an argument.
If you code your unit test correctly, you'll find that you rarely need to pass it an argument.
The line testunit.addTest(hell('ad')) doesn't do what you intend it to do. It doesn't tell the test suite to run hell('ad') later on. Rather, it calls that function immediately and passed the return value (which happens to be the string 'ad' you gave it as an argument) to addTest. That causes the exception later on, since a string is not a valid test case.
I'm not exactly sure how you should fix this. Your hell function doesn't appear to actually test anything, so there's not an obvious way to transform it into a proper test. There is a unittest.FunctionTestCase class that wraps a function up as a TestCase, but it doesn't appear to have any way of passing arguments to the function. Probably you should write a TestCase subclass class, and add various test_-prefixed methods that actually test things.
I had a right answer for my question, give the code:
# -*- coding: utf-8 -*-
import unittest
import HTMLTestRunner
def hell(a):
print(a)
return a
class HellTest(unittest.TestCase):
def setUp(self):
self.hell = hell
def tearDown(self):
pass
def testHell(self):
self.assertEqual(self.hell('aaa'), 'aaa')
if __name__ == '__main__':
testunit = unittest.TestSuite()
testunit.addTest(HellTest('testHell'))
filename = '/Users/vivi/Downloads/aa.html'
fp = open(filename, 'wb')
runner = HTMLTestRunner.HTMLTestRunner(stream=fp, title=u'不要生成error啦!', description=u'简单1112')
runner.run(testunit)
fp.close()
But, I do not know why add the class code 'class HellTest()'.The answer comes from a Chinese people whoes name is '幽谷奇峰'。Source code reference:https://segmentfault.com/q/1010000007427143?_ea=1345414

How to mock open differently depending on the parameters passed to open()

My question is how to mock open in python, such that it reacts differently depending on the argument open() is called with. These are some different scenario's that should be possible:
open a mocked file; read preset contents, the basic scenario.
open two mocked files and have them give back different values for the read() method. The order in which the files are opened/read from should not influence the results.
Furthermore, if I call open('actual_file.txt') to open an actual file, I want the actual file to be opened, and not a magic mock with mocked behavior. Or if I just don't want the access to a certain file mocked, but I do want other files to be mocked, this should be possible.
I know about this question: Python mock builtin 'open' in a class using two different files.
But that answer only partially answers up to the second requirement. The part about order independent results is not included and it does not specify how to mock only some calls, and allow other calls to go through to the actual files (default behavior).
A bit late, but I just recently happened upon the same need, so I'd like to share my solution, based upon this answer from the referred-to question:
import pytest
from unittest.mock import mock_open
from functools import partial
from pathlib import Path
mock_file_data = {
"file1.txt": "some text 1",
"file2.txt": "some text 2",
# ... and so on ...
}
do_not_mock: {
# If you need exact match (see note in mocked_file(),
# you should replace these with the correct Path() invocations
"notmocked1.txt",
"notmocked2.txt",
# ... and so on ...
}
# Ref: https://stackoverflow.com/a/38618056/149900
def mocked_file(m, fn, *args, **kwargs):
m.opened_file = Path(fn)
fn = Path(fn).name # If you need exact path match, remove this line
if fn in do_not_mock:
return open(fn, *args, **kwargs)
if fn not in mock_file_data:
raise FileNotFoundError
data = mock_file_data[fn]
file_obj = mock_open(read_data=data).return_value
file_obj.__iter__.return_value = data.splitlines(True)
return file_obj
def assert_opened(m, fn):
fn = Path(fn)
assert m.opened_file == fn
#pytest.fixture()
def mocked_open(mocker):
m = mocker.patch("builtins.open")
m.side_effect = partial(mocked_file, m)
m.assert_opened = partial(assert_opened, m)
return m
def test_something(mocked_open):
...
# Something that should NOT invoke open()
mocked_open.assert_not_called()
...
# Something that SHOULD invoke open()
mocked_open.assert_called_once()
mocked_open.assert_opened("file1.txt")
# Depends on how the tested unit handle "naked" filenames,
# you might have to change the arg to:
# Path.cwd() / "file1.txt"
# ... and so on ...
Do note that (1) I am using Python 3, and (2) I am using pytest.
This can be done by following the approach in the other question's accepted answer (Python mock builtin 'open' in a class using two different files) with a few alterations.
First off. Instead of just specifying a side_effect that can be popped. We need to make sure the side_effect can return the correct mocked_file depending on the parameters used with the open call.
Then if the file we wish to open is not among the files we wish to mock, we instead return the original open() of the file instead of any mocked behavior.
The code below demonstrates how this can be achieved in a clean, repeatable way. I for instance have this code inside of a file that provides some utility functions to make testing easier.
from mock import MagicMock
import __builtin__
from mock import patch
import sys
# Reference to the original open function.
g__test_utils__original_open = open
g__test_utils__file_spec = None
def create_file_mock(read_data):
# Create file_spec such as in mock.mock_open
global g__test_utils__file_spec
if g__test_utils__file_spec is None:
# set on first use
if sys.version_info[0] == 3:
import _io
g__test_utils__file_spec = list(set(dir(_io.TextIOWrapper)).union(set(dir(_io.BytesIO))))
else:
g__test_utils__file_spec = file
file_handle = MagicMock(spec=g__test_utils__file_spec)
file_handle.write.return_value = None
file_handle.__enter__.return_value = file_handle
file_handle.read.return_value = read_data
return file_handle
def flexible_mock_open(file_map):
def flexible_side_effect(file_name):
if file_name in file_map:
return file_map[file_name]
else:
global g__test_utils__original_open
return g__test_utils__original_open(file_name)
global g__test_utils__original_open
return_value = MagicMock(name='open', spec=g__test_utils__original_open)
return_value.side_effect = flexible_side_effect
return return_value
if __name__ == "__main__":
a_mock = create_file_mock(read_data="a mock - content")
b_mock = create_file_mock(read_data="b mock - different content")
mocked_files = {
'a' : a_mock,
'b' : b_mock,
}
with patch.object(__builtin__, 'open', flexible_mock_open(mocked_files)):
with open('a') as file_handle:
print file_handle.read() # prints a mock - content
with open('b') as file_handle:
print file_handle.read() # prints b mock - different content
with open('actual_file.txt') as file_handle:
print file_handle.read() # prints actual file contents
This borrows some code straight from the mock.py (python 2.7) for the creating of the file_spec.
side note: if there's any body that can help me in how to hide these globals if possible, that'd be very helpful.

Mocking ftplib.FTP for unit testing Python code

I don't know why I'm just not getting this, but I want to use mock in Python to test that my functions are calling functions in ftplib.FTP correctly. I've simplified everything down and still am not wrapping my head around how it works. Here is a simple example:
import unittest
import ftplib
from unittest.mock import patch
def download_file(hostname, file_path, file_name):
ftp = ftplib.FTP(hostname)
ftp.login()
ftp.cwd(file_path)
class TestDownloader(unittest.TestCase):
#patch('ftplib.FTP')
def test_download_file(self, mock_ftp):
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
mock_ftp.cwd.assert_called_with('pub/files')
When I run this, I get:
AssertionError: Expected call: cwd('pub/files')
Not called
I know it must be using the mock object since that is a fake server name, and when run without patching, it throws a "socket.gaierror" exception.
How do I get the actual object the fuction is running? The long term goal is not having the "download_file" function in the same file, but calling it from a separate module file.
When you do patch(ftplib.FTP) you are patching FTP constructor. dowload_file() use it to build ftp object so your ftp object on which you call login() and cmd() will be mock_ftp.return_value instead of mock_ftp.
Your test code should be follow:
class TestDownloader(unittest.TestCase):
#patch('ftplib.FTP', autospec=True)
def test_download_file(self, mock_ftp_constructor):
mock_ftp = mock_ftp_constructor.return_value
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
mock_ftp_constructor.assert_called_with('ftp.server.local')
self.assertTrue(mock_ftp.login.called)
mock_ftp.cwd.assert_called_with('pub/files')
I added all checks and autospec=True just because is a good practice
Like Ibrohim's answer, I prefer pytest with mocker.
I have went a bit further and have actually wrote a library which helps me to mock easily. Here is how to use it for your case.
You start by having your code and a basic pytest function, with the addition of my helper library to generate mocks to modules and the matching asserts generation:
import ftplib
from mock_autogen.pytest_mocker import PytestMocker
def download_file(hostname, file_path, file_name):
ftp = ftplib.FTP(hostname)
ftp.login()
ftp.cwd(file_path)
def test_download_file(mocker):
import sys
print(PytestMocker(mocked=sys.modules[__name__],
name=__name__).mock_modules().prepare_asserts_calls().generate())
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
When you run the test for the first time, it would fail due to unknown DNS, but the print statement which wraps my library would give us this valuable input:
...
mock_ftplib = mocker.MagicMock(name='ftplib')
mocker.patch('test_29817963.ftplib', new=mock_ftplib)
...
import mock_autogen
...
print(mock_autogen.generator.generate_asserts(mock_ftplib, name='mock_ftplib'))
I'm placing this in the test and would run it again:
def test_download_file(mocker):
mock_ftplib = mocker.MagicMock(name='ftplib')
mocker.patch('test_29817963.ftplib', new=mock_ftplib)
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
import mock_autogen
print(mock_autogen.generator.generate_asserts(mock_ftplib, name='mock_ftplib'))
This time the test succeeds and I only need to collect the result of the second print to get the proper asserts:
def test_download_file(mocker):
mock_ftplib = mocker.MagicMock(name='ftplib')
mocker.patch(__name__ + '.ftplib', new=mock_ftplib)
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
mock_ftplib.FTP.assert_called_once_with('ftp.server.local')
mock_ftplib.FTP.return_value.login.assert_called_once_with()
mock_ftplib.FTP.return_value.cwd.assert_called_once_with('pub/files')
If you would like to keep using unittest while using my library, I'm accepting pull requests.
I suggest using pytest and pytest-mock.
from pytest_mock import mocker
def test_download_file(mocker):
ftp_constructor_mock = mocker.patch('ftplib.FTP')
ftp_mock = ftp_constructor_mock.return_value
download_file('ftp.server.local', 'pub/files', 'wanted_file.txt')
ftp_constructor_mock.assert_called_with('ftp.server.local')
assert ftp_mock.login.called
ftp_mock.cwd.assert_called_with('pub/files')

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