I am trying to download a SWF file using Python,
but for some reason everytime I use urllib.urlretrieve(url,filepathwithname) or wget.download(url), it says:
File "C:\Users\User-PC\Desktop\check.py", line 3, in <module>
response =
urllib.urlretrieve('www.domain.com\\folder\\folder\\52sd1399sc2emaple-story-
vthree-f.swf','file.swf')
File "C:\Python27\lib\urllib.py", line 98, in urlretrieve
return opener.retrieve(url, filename, reporthook, data)
File "C:\Python27\lib\urllib.py", line 245, in retrieve
fp = self.open(url, data)
File "C:\Python27\lib\urllib.py", line 213, in open
return getattr(self, name)(url)
File "C:\Python27\lib\urllib.py", line 469, in open_file
return self.open_local_file(url)
File "C:\Python27\lib\urllib.py", line 483, in open_local_file
raise IOError(e.errno, e.strerror, e.filename)
IOError: [Errno 2] The system cannot find the path specified:
'www.domain.com\\folder\\folder\\52sd1399sc2emaple-story-vthree-f.swf'
while the wget line still gives the same error when running the line in a seperate file than my code(which runs perfectly without that download line), it does work sometimes, but wget never works with the swf links I've placed.
*Note. The string I enter is "www.domain.com\folder\folder\52sd1399sc2emaple-story-vthree-f.swf" and the error contains "www.domain.com\folder\folder\52sd1399sc2emaple-story-vthree-f.swf".
Please help.
#Blckknght You are amazing. that was the whole problem. Thanks to everyone who tried to help!
The whole problem was a missing http:// in the urlretrieve link... I have spent almost 10 hours trying to solve that problem using wget and other methods, and #Blckknght just solved it for me. =)
I wish you all the best, have a great day
-CodingCode.
Related
I am trying to run this tensorflow example: https://github.com/tensorflow/tensorflow/blob/master/tensorflow/examples/skflow/text_classification_character_cnn.py
However it keeps failing at the stage to open the tar file. This is the error message I am getting:
Successfully downloaded dbpedia_csv.tar.gz 1613 bytes.
Traceback (most recent call last):
File "text_classification_character_cnn.py", line 110, in <module>
tf.app.run()
File "/Users/alechewitt/Envs/solar_detection/lib/python2.7/site-packages/tensorflow/python/platform/app.py", line 30, in run
sys.exit(main(sys.argv))
File "text_classification_character_cnn.py", line 87, in main
'dbpedia', test_with_fake_data=FLAGS.test_with_fake_data, size='large')
File "/Users/alechewitt/Envs/solar_detection/lib/python2.7/site-packages/tensorflow/contrib/learn/python/learn/datasets/__init__.py", line 64, in load_dataset
return DATASETS[name](size, test_with_fake_data)
File "/Users/alechewitt/Envs/solar_detection/lib/python2.7/site-packages/tensorflow/contrib/learn/python/learn/datasets/text_datasets.py", line 48, in load_dbpedia
maybe_download_dbpedia(data_dir)
File "/Users/alechewitt/Envs/solar_detection/lib/python2.7/site-packages/tensorflow/contrib/learn/python/learn/datasets/text_datasets.py", line 40, in maybe_download_dbpedia
tfile = tarfile.open(archive_path, 'r:*')
File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/tarfile.py", line 1672, in open
raise ReadError("file could not be opened successfully")
tarfile.ReadError: file could not be opened successfully
Any help would be much appreciated
When you get that error, you can look at the downloaded dbpedia_dsv.tar.gz in a text editor, and you might find that it is actually a 404 webpage. The file you want seems to be available here as well (I found this link here):
https://drive.google.com/drive/folders/0Bz8a_Dbh9Qhbfll6bVpmNUtUcFdjYmF2SEpmZUZUcVNiMUw1TWN6RDV3a0JHT3kxLVhVR2M
Download that file (at your own risk) and replace it manually. Then you can run your script again.
Open the tar file using the full path. BTW the link you gave is 404 not found.
I'm trying to unzip a zip file inside my script using Python's zipfile module. The problem is that when I try to unzip this file, it raises Bad magic number for file header error:
This is the error:
..
zip_ref.extractall(destination_to_unzip_file)
File "C:\Python27\lib\zipfile.py", line 1040, in extractall
self.extract(zipinfo, path, pwd)
File "C:\Python27\lib\zipfile.py", line 1028, in extract
return self._extract_member(member, path, pwd)
File "C:\Python27\lib\zipfile.py", line 1082, in _extract_member
with self.open(member, pwd=pwd) as source, \
File "C:\Python27\lib\zipfile.py", line 971, in open
raise BadZipfile("Bad magic number for file header")
zipfile.BadZipfile: Bad magic number for file header
The file I want to unzip is downloaded this way:
_url = """http://edane.drsr.sk/report/ds_dphs_csv.zip"""
def download_platici_dph(self):
if os.path.isfile(_destination_for_downloads+'platici_dph.zip'):
os.remove(_destination_for_downloads+'platici_dph.zip')
with open(_destination_for_downloads+'platici_dph.zip','w') as f:
response = requests.get(_url,stream=True)
if not response.ok:
print 'Something went wrong'
return False
else:
for block in response.iter_content(1024):
f.write(block)
Do anybody knows where is the problem?
Quoth the documentation for open(): "when opening a binary file, you should append 'b' to the mode value to open the file in binary mode"
Open your output file using b for binary:
with open(_destination_for_downloads+'platici_dph.zip','wb') as f:
I tried downloading your archive without using your download-code and then extracting it with:
import zipfile
with zipfile.ZipFile("ds_dphs_csv.zip") as a:
a.extractall()
It worked fine. The exception zipfile.BadZipfile is raised when there is a problem in a header thus I think your file is corrupted after download. There must be a problem with your downloading method.
You can find more details on the exception in this post: Python - Extracting files from a large (6GB+) zip file
I'm just getting started with python so please bear with me ;)
While following a basic tutorial I ran into a problem while opening a file, here's the traceback:
File "/home/nick/Dropbox/workspace/pytest/schlange.py", line 55, in <module>
f=open("file.csv","r")
File "/usr/lib/python2.6/aifc.py", line 922, in open
return Aifc_read(f)
File "/usr/lib/python2.6/aifc.py", line 335, in __init__
self.initfp(f)
File "/usr/lib/python2.6/aifc.py", line 288, in initfp
raise Error, 'file does not start with FORM id'
aifc.Error: file does not start with FORM id
Does that mean that 'aifc.py' in my python installation is broken or did I miss something important here?
You've decided to import * from aifc, and its open() has shadowed the built-in open(). This is why we don't import *. Import the module itself instead and use the reference to get to its names when required, e.g. aifc.open().
[2012-06-01 15:33:10,638][molisamples] ERROR:web-services:Uncaught exception
Traceback (most recent call last):
File "osv\osv.pyo", line 122, in wrapper
File "osv\osv.pyo", line 176, in execute
File "osv\osv.pyo", line 167, in execute_cr
File "C:\Program Files (x86)\OpenERP 6.0\Server\addons\base_report_designer\base_report_designer.py", line 42, in sxwtorml
File "C:\Program Files (x86)\OpenERP 6.0\Server\addons\base_report_designer\openerp_sxw2rml\openerp_sxw2rml.py", line 309, in sxw2rml
File "C:\Program Files (x86)\OpenERP 6.0\Server\addons\base_report_designer\openerp_sxw2rml\openerp_sxw2rml.py", line 294, in unpackNormalize
File "C:\Program Files (x86)\OpenERP 6.0\Server\addons\base_report_designer\openerp_sxw2rml\openerp_sxw2rml.py", line 269, in oo_read
File "zipfile.pyo", line 346, in init
File "zipfile.pyo", line 366, in _GetContents
File "zipfile.pyo", line 378, in _RealGetContents
BadZipfile: File is not a zip file
I get the above error when I try to convert a report I just designed to .rml (using Open Office Writer). Please what could be the issue. I am seriously confused here
You can convert your .sxw to .rml using base_report_designer module.
Try following steps:
Open terminal -> go to openerp_sxw2rml folder like this:
cd addons/base_report_designer/openerp_sxw2rml
Then run this command: python openerp_sxw2rml.py absolute path of sxw > absolute path of rml
Like this:
python openerp_sxw2rml.py /home/arya/my_module/report/my_report.sxw > /home/arya/my_module/report/my_report.rml
This will convert sxw file into rml and you can find your file at given path of rml.
Thank you.
The error says that the file is not a zip file, so it's probably expecting the compressed format of sxw file. Any chance you saved the file in OpenOffice's uncompressed format?
Make sure when you save in Openoffice Writer, you select the old format, the one with SXW extension.
Don't just type .sxw, make sure the program puts it there by itself by selecting the correct entry in the fileformat selectionbox (i forget the full title and cannot check atm)
I figured it out. I had some errors in the python parser file for the report. That's what was causing the issue. It's been fixed now. Thanks y'all for the help
I recently started writing a simple client using the Blogger API to do some basic posting I implemented the client in Python and used the example code verbatim from the Blogger Developer's Guide to login, get the blog id, and make a new post. I ran the script and everything went fine until I got to this line:
return blogger_service.Post(entry, '/feeds/%s/posts/default' % blog_id)
I got the error message:
Traceback (most recent call last):
File "cs1121post.py", line 38, in <module>
cs1121post()
File "cs1121post.py", line 33, in cs1121post
return blogger_service.Post(entry, '/feeds/%s/posts/default' % blog_id)
File "/usr/local/lib/python2.7/dist-packages/gdata/service.py", line 1236, in Post
media_source=media_source, converter=converter)
File "/usr/local/lib/python2.7/dist-packages/gdata/service.py", line 1322, in PostOrPut
headers=extra_headers, url_params=url_params)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 93, in optional_warn_function
return f(*args, **kwargs)
File "/usr/local/lib/python2.7/dist-packages/atom/service.py", line 176, in request
content_length = CalculateDataLength(data)
File "/usr/local/lib/python2.7/dist-packages/atom/service.py", line 736, in CalculateDataLength
return len(str(data))
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 377, in __str__
return self.ToString()
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 374, in ToString
return ElementTree.tostring(self._ToElementTree(), encoding=string_encoding)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 369, in _ToElementTree
self._AddMembersToElementTree(new_tree)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 331, in _AddMembersToElementTree
member._BecomeChildElement(tree)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 357, in _BecomeChildElement
self._AddMembersToElementTree(new_child)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 342, in _AddMembersToElementTree
ExtensionContainer._AddMembersToElementTree(self, tree)
File "/usr/local/lib/python2.7/dist-packages/atom/__init__.py", line 224, in _AddMembersToElementTree
tree.text = self.text.decode(MEMBER_STRING_ENCODING)
AttributeError: 'list' object has no attribute 'decode'
By which I'm taking it that ElementTree is at fault here. I installed ElementTree via
sudo python setup.py install
in case it matters. Is there some known incompatibility between ElementTree and Python v2.7.1? Has this happened to anybody else and how did you get it working? If you need any additional information, please reply to the thread. All the source code that is relevant is basically just the example code from the Developers Guide mentioned above. I haven't modified that at all (not even the variable names). Any input is greatly appreciated.
The stacktrace is actually pretty clear about this: You're calling decode() on a list instead of a tree element. Try getting the first element from the list and calling decode() on that:
firsttext = self.text[0].decode(MEMBER_STRING_ENCODING)