I'm trying to form the command for sorting using elasticsearch-dsl. However I have trouble passing the variable in correct format in.
The format should be
s=Search()
s = s.sort({"time":{"order":"asc"}}, {"anoter_field":{"order":"desc"}})
s.execute()
The problem is I'm trying to put {"time":{"order":"asc"}}, {"anoter_field":{"order":"desc"}} as a variable, but I can't seem to get this in the right syntax. I tried using dict, list, and string, and none seems to work.
My input would be a dict that looks like
input = {"time":"asc", "another_field":"desc"}
data_input = {"time":"asc", "another_field":"desc"}
args = [{k:{'order':v}} for k,v in data_input.items()]
s.sort(*args)
I guess is what you are asking? Its hard to tell ...
Related
Im trying to retrieve data from a database named RethinkDB, they output JSON when called with r.db("Databasename").table("tablename").insert([{ "id or primary key": line}]).run(), when doing so it outputs [{'id': 'ValueInRowOfid\n'}] and I want to parse that to just the value eg. "ValueInRowOfid". Ive tried with JSON in Python, but I always end up with the typeerror: list indices must be integers or slices, not str, and Ive been told that it is because the Database outputs invalid JSON format. My question is how can a JSON format be invalid (I cant see what is invalid with the output) and also what would be the best way to parse it so that the value "ValueInRowOfid" is left in a Operator eg. Value = ("ValueInRowOfid").
This part imports the modules used and connects to RethinkDB:
import json
from rethinkdb import RethinkDB
r = RethinkDB()
r.connect( "localhost", 28015).repl()
This part is getting the output/value and my trial at parsing it:
getvalue = r.db("Databasename").table("tablename").sample(1).run() # gets a single row/value from the table
print(getvalue) # If I print that, it will show as [{'id': 'ValueInRowOfid\n'}]
dumper = json.dumps(getvalue) # I cant use `json.loads(dumper)` as JSON object must be str. Which the output of the database isnt (The output is a list)
parsevalue = json.loads(dumper) # After `json.dumps(getvalue)` I can now load it, but I cant use the loaded JSON.
print(parsevalue["id"]) # When doing this it now says that the list is a str and it needs to be an integers or slices. Quite frustrating for me as it is opposing it self eg. It first wants str and now it cant use str
print(parsevalue{'id'}) # I also tried to shuffle it around as seen here, but still the same result
I know this is janky and is very hard to comprehend this level of stupidity that I might be on. As I dont know if it is the most simple problem or something that just isnt possible (Which it should or else I cant use my data in the database.)
Thank you for reading this through and not jumping straight into the comments and say that I have to read the JSON documentation, because I have and I havent found a single piece that could help me.
I tried reading the documentation and watching tutorials about JSON and JSON parsing. I also looked for others whom have had the same problems as me and couldnt find.
It looks like it's returning a dictionary ({}) inside a list ([]) of one element.
Try:
getvalue = r.db("Databasename").table("tablename").sample(1).run()
print(getvalue[0]['id'])
in python I have:
dict = {}
dict['test'] = 'test'
when I print I get:
{'test':'test'}
How can I make it like this:
{"test":"test"}
Please Note, replace won't work as test may be test't...
I tried:
dict = {}
dict["test"] = "test"
You can use json.dumps()
For example, if you use print json.dumps(dict) you should get the desired output.
Additionally, as suggested in a different related question, you may construct your own version of a dict with special printing:
How to create a Python dictionary with double quotes as default quote format?
So I'm trying to learn Python here, and would appreciate any help you guys could give me. I've written a bit of code that asks one of my favorite websites for some information, and the api call returns an answer in a dictionary. In this dictionary is a list. In that list is a dictionary. This seems crazy to me, but hell, I'm a newbie.
I'm trying to assign the answers to variables, but always get various error messages depending on how I write my {},[], or (). Regardless, I can't get it to work. How do I read this return? Thanks in advance.
{
"answer":
[{"widgets":16,
"widgets_available":16,
"widgets_missing":7,
"widget_flatprice":"156",
"widget_averages":15,
"widget_cost":125,
"widget_profit":"31",
"widget":"90.59"}],
"result":true
}
Edited because I put in the wrong sample code.
You need to show your code, but the de-facto way of doing this is by using the requests module, like this:
import requests
url = 'http://www.example.com/api/v1/something'
r = requests.get(url)
data = r.json() # converts the returned json into a Python dictionary
for item in data['answer']:
print(item['widgets'])
Assuming that you are not using the requests library (see Burhan's answer), you would use the json module like so:
data = '{"answer":
[{"widgets":16,
"widgets_available":16,
"widgets_missing":7,
"widget_flatprice":"156",
"widget_averages":15,
"widget_cost":125,
"widget_profit":"31",
"widget":"90.59"}],
"result":true}'
import json
data = json.loads(data)
# Now you can use it as you wish
data['answer'] # and so on...
First I will mention that to access a dictionary value you need to use ["key"] and not {}. see here an Python dictionary syntax.
Here is a step by step walkthrough on how to build and access a similar data structure:
First create the main dictionary:
t1 = {"a":0, "b":1}
you can access each element by:
t1["a"] # it'll return a 0
Now lets add the internal list:
t1["a"] = ["x",7,3.14]
and access it using:
t1["a"][2] # it'll return 3.14
Now creating the internal dictionary:
t1["a"][2] = {'w1':7,'w2':8,'w3':9}
And access:
t1["a"][2]['w3'] # it'll return 9
Hope it helped you.
I would like to use a list of int to be used in a query as below:
db.define_table('customer',Field('name'),Field('cusnumber','integer'))
def custmr():
listOfNumbers=[22,12,76,98]
qry=db(db.customer.cusnumber==listOfNumbers).select(db.customer.name)
print qry
this arise an issue that the only accepted data type in the query is int or str.
Is there any way to avoid this issue (preferably by not using for loop)
Regards
It is really difficult to know what you're trying to ask, but from the syntax of db.define_table(...), I take a wild guess you're on web2py and trying to do a query which fetch any int in your listOfNumbers.
You may use contains attribute like this:
# if all=True, cusnumber will need to contains all listOfNumbers, False means any
qry=db(db.customer.cusnumber.contains(listOfNumbers, all=False)).select(db.customer.name)
You can read more in details in HERE
As OP replied that contains only works for string, I'm going to suggest using for/loop will be a better answer:
listOfNumbers=[22,12,76,98]
for each in listOfNumbers:
qry=db(db.customer.cusnumber==each).select(db.customer.name)
# ... do your stuff or whatever ...
Assuming you want the set of records for which the cusnumber is in listOfNumbers, you should use the .belongs method:
qry = db(db.customer.cusnumber.belongs(listOfNumbers)).select(db.customer.name)
I'm trying to get the some data from a MySQL table (ipb_members) using web.py's database.select. This is the code I'm using: members = db.select("ipb_members", where="name=\"asdfquerty\"")
it returns an instance of iterbetter. What I'm trying to figure out is how to convert that to a dictionary or a list. I saw this, which recommends using list(), but that just puts everything in the first index. I've also tried dict(), but that didn't work either. What am I doing wrong?
This should work:
members = db.select("ipb_members", where="name=\"asdfquerty\"")
for member in members #members is IterBetter
print member.posts #member is Storage
Note that you dont have to call .list() on the result of db.select if you need to iterate over it only once.
Have you tried dict(members)?
iterBetter is not very convenient as it can only iterate once, here is code convert iterBetter to list:
list_conv_from_db = []
for menber in menbers:
temp = dict()
for key in menber:
temp[key]=menber[key]
list_conv_from_db.append(temp)
then you get list_conv_from_db you can do everything you want!