I found this tutorial on how to do a watermark but I cannot figure out how to put it behind my plotted data.
https://www.tutorialspoint.com/how-to-plot-a-watermark-image-in-matplotlib
Changing zorder has no impact because I think it is being drawn on the entire figure. I would like to have a subdued logo behind my data which is always centered in the figure so I don't really want to plot an image as a data point because then it would move as it is panned/zoomed.
Setting the zorder to a negative value works for me. However, you also need to make the facecolor of the axes transparent:
import numpy as np
import matplotlib.cbook as cbook
import matplotlib.image as image
import matplotlib.pyplot as plt
with cbook.get_sample_data('logo2.png') as file:
im = image.imread(file)
fig, ax = plt.subplots()
fig.figimage(im, 10, 10, zorder=-1, alpha=.5)
ax.plot(np.sin(10 * np.linspace(0, 1)), '-o', ms=20,
alpha=0.7, mfc='orange')
ax.set_facecolor('none')
plt.show()
I am trying to plot a circle with a grid being shown. I wrote the following script which gives the below picture. However, the labels on the axes are interfering together. How to make the label appear (..,-10,-5,0,5,10,...) KEEPING the grid as it appears in the below figure?. I want to keep the dimension of the grid cell as 1*1 dimension.
I tried to use plt.locator_params(), but the dimension of the grid cell changed and became bigger.
import numpy as np
import matplotlib.pyplot as plt
import math
from matplotlib.pyplot import figure
R1=28
n=64
t=np.linspace(0, 2*np.pi, n)
x1=R1*np.cos(t)
y1=R1*np.sin(t)
plt.axis("square")
plt.grid(True, which='both', axis='both')
plt.xticks(np.arange(min(x1)-2,max(x1)+2, step=1))
plt.yticks(np.arange(min(y1)-2,max(y1)+2, step=1))
#plt.locator_params(axis='x', nbins=5)
#plt.locator_params(axis='y', nbins=5)
plt.plot(x1,y1)
plt.legend()
plt.show()
Not a matplotlib expert, so there may be a better way to do this, but perhaps like the following:
from matplotlib.ticker import MultipleLocator
...
fig, ax = plt.subplots(figsize=(6, 6))
ax.plot(x1,y1)
ax.xaxis.set_minor_locator(MultipleLocator())
ax.xaxis.set_major_locator(MultipleLocator(5))
ax.yaxis.set_minor_locator(MultipleLocator())
ax.yaxis.set_major_locator(MultipleLocator(5))
ax.grid(True, which='both', axis='both')
plt.show()
When saving a Matplotlib figure from a Jupyter notebook, how do I override the default transparent border so it will be opaque?
Looking at the savefig documentation, there are several parameters that seem like they would affect this but actually do not seem to do anything. Here is an example.
%matplotlib notebook
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = np.linspace(-6, 6, 100)
ax.plot(x, np.sinc(x))
plt.savefig(
'test.png',
transparent=False, # no change
frameon=True, # no change
edgecolor='blue', # no change (want 'white' but 'blue' should be noticeable)
facecolor='red', # no change (want 'white' but 'red' should be noticeable)
alpha=1, # no change
)
Here is the result. StackOverflow does not illustrate the transparency, but note that the edge is not 'blue' and the face is not 'red'.
This post mentions setting fig.patch.set_alpha(1) which turns out to work, regardless of the savefig parameters. Adding this command to the example code resolves the problem.
%matplotlib notebook
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
fig.patch.set_alpha(1) # solution
x = np.linspace(-6, 6, 100)
ax.plot(x, np.sinc(x))
fig.savefig('solved.png')
It turns out this is specific to Jupyter notebooks, and is probably a bug (I only have version 4.4.0). When I run the following code above from the command line, I instead get the desired behavior (change 'red' to 'white' to get the opaque white border).
import numpy as np
import matplotlib.pyplot as plt
fig, ax = plt.subplots()
x = np.linspace(-6, 6, 100)
ax.plot(x, np.sinc(x))
plt.savefig(
'test.png',
# transparent=False, # no change
# frameon=True, # no change
# edgecolor='blue', # no change
facecolor='red', # no change
# alpha=1, # no change
)
I have multiple plots that have the same x-axis. I would like to stack them in a report and have everything line up. However, matplotlib seems to resize them slightly based on the y tick label length.
Is it possible to force the plot area and location to remain the same across plots, relative to the pdf canvas to which I save it?
import numpy as np
import matplotlib.pyplot as plt
xs=np.arange(0.,2.,0.00001)
ys1=np.sin(xs*10.) #makes the long yticklabels
ys2=10.*np.sin(xs*10.)+10. #makes the short yticklabels
fig=plt.figure() #this plot ends up shifted right on the canvas
plt.plot(xs,ys1,linewidth=2.0)
plt.xlabel('x')
plt.ylabel('y')
fig=plt.figure() #this plot ends up further left on the canvas
plt.plot(xs,ys2,linewidth=2.0)
plt.xlabel('x')
plt.ylabel('y')
Your problem is a little unclear, however plotting them as subplots in the same figure should gaurantee that the axes and figure size of the two subplots will be alligned with each other
import numpy as np
import matplotlib.pyplot as plt
xs=np.arange(0.,2.,0.00001)
ys1=np.sin(xs*10.) #makes the long yticklabels
ys2=10.*np.sin(xs*10.)+10. #makes the short yticklabels
fig, (ax1, ax2) = plt.subplots(2, 1)
ax1.plot(xs,ys1,linewidth=2.0)
ax1.set_xlabel('x')
ax1.set_ylabel('y')
ax2.plot(xs,ys2,linewidth=2.0)
ax2.set_xlabel('x')
ax2.set_ylabel('y')
plt.subplots_adjust(hspace=0.3) # adjust spacing between plots
plt.show()
This produces the following figure:
I had the same problem. The following works for me.
Force the same figure width for all your plots around all your python scripts, for example:
fig1 = plt.figure(figsize=(12,6))
...
fig2 = plt.figure(figsize=(12,4))
And do not use (very important!):
fig.tight_layout()
Save the figure
plt.savefig('figure.png')
Plot areas should now be the same.
using subplots with the same x-axis should do the trick.
use sharex=True when you create the subplots. The benefit of sharex is that zooming or panning on 1 subplot will also auto-update on all subplots with shared axes.
import numpy as np
import matplotlib.pyplot as plt
xs = np.arange(0., 2., 0.00001)
ys1 = np.sin(xs * 10.) # makes the long yticklabels
ys2 = 10. * np.sin(xs * 10.) + 10. # makes the short yticklabels
fig, (ax1, ax2) = plt.subplots(2, sharex=True)
ax1.plot(xs, ys1, linewidth=2.0)
ax1.xlabel('x')
ax1.ylabel('y')
ax2.plot(xs, ys2, linewidth=2.0)
ax2.xlabel('x')
ax2.ylabel('y')
plt.show()
I'm working with matplotlib to plot a variable in latitude longitude coordinates. The problem is that this image cannot include axes or borders. I have been able to remove axis, but the white padding around my image has to be completely removed (see example images from code below here: http://imgur.com/a/W0vy9) .
I have tried several methods from Google searches, including these StackOverflow methodologies:
Remove padding from matplotlib plotting
How to remove padding/border in a matplotlib subplot (SOLVED)
Matplotlib plots: removing axis, legends and white spaces
but nothing has worked in removing the white space. If you have any advice (even if it is to ditch matplotlib and to try another plotting library instead) I would appreciate it!
Here is a basic form of the code I'm using that shows this behavior:
import numpy as np
import matplotlib
from mpl_toolkits.basemap import Basemap
from scipy import stats
lat = np.random.randint(-60.5, high=60.5, size=257087)
lon = np.random.randint(-179.95, high=180, size=257087)
maxnsz = np.random.randint(12, 60, size=257087)
percRange = np.arange(100,40,-1)
percStr=percRange.astype(str)
val_percentile=np.percentile(maxnsz, percRange, interpolation='nearest')
#Rank all values
all_percentiles=stats.rankdata(maxnsz)/len(maxnsz)
#Figure setup
fig = matplotlib.pyplot.figure(frameon=False, dpi=600)
#Basemap code can go here
x=lon
y=lat
cmap = matplotlib.cm.get_cmap('cool')
h=np.where(all_percentiles >= 0.999)
hl=np.where((all_percentiles < 0.999) & (all_percentiles > 0.90))
mh=np.where((all_percentiles > 0.75) & (all_percentiles < 0.90))
ml=np.where((all_percentiles >= 0.4) & (all_percentiles < 0.75))
l=np.where(all_percentiles < 0.4)
all_percentiles[h]=0
all_percentiles[hl]=0.25
all_percentiles[mh]=0.5
all_percentiles[ml]=0.75
all_percentiles[l]=1
rgba_low=cmap(1)
rgba_ml=cmap(0.75)
rgba_mh=cmap(0.51)
rgba_hl=cmap(0.25)
rgba_high=cmap(0)
matplotlib.pyplot.axis('off')
matplotlib.pyplot.scatter(x[ml],y[ml], c=rgba_ml, s=3, marker=',',edgecolor='none', alpha=0.4)
matplotlib.pyplot.scatter(x[mh],y[mh], c=rgba_mh, s=3, marker='o', edgecolor='none', alpha=0.5)
matplotlib.pyplot.scatter(x[hl],y[hl], c=rgba_hl, s=4, marker='*',edgecolor='none', alpha=0.6)
matplotlib.pyplot.scatter(x[h],y[h], c=rgba_high, s=5, marker='^', edgecolor='none',alpha=0.75)
fig.savefig('/home/usr/code/python/testfig.jpg', bbox_inches=0, nbins=0, transparent="True", pad_inches=0.0)
fig.canvas.draw()
The problem is that all the solutions given at Matplotlib plots: removing axis, legends and white spaces are actually meant to work with imshow.
So, the following clearly works
import matplotlib.pyplot as plt
fig = plt.figure()
ax=fig.add_axes([0,0,1,1])
ax.set_axis_off()
im = ax.imshow([[2,3,4,1], [2,4,4,2]], origin="lower", extent=[1,4,2,8])
ax.plot([1,2,3,4], [2,3,4,8], lw=5)
ax.set_aspect('auto')
plt.show()
and produces
But here, you are using scatter. Adding a scatter plot
import matplotlib.pyplot as plt
fig = plt.figure()
ax=fig.add_axes([0,0,1,1])
ax.set_axis_off()
im = ax.imshow([[2,3,4,1], [2,4,4,2]], origin="lower", extent=[1,4,2,8])
ax.plot([1,2,3,4], [2,3,4,8], lw=5)
ax.scatter([2,3,4,1], [2,3,4,8], c="r", s=2500)
ax.set_aspect('auto')
plt.show()
produces
Scatter has the particularity that matplotlib tries to make all points visible by default, which means that the axes limits are set such that all scatter points are visible as a whole.
To overcome this, we need to specifically set the axes limits:
import matplotlib.pyplot as plt
fig = plt.figure()
ax=fig.add_axes([0,0,1,1])
ax.set_axis_off()
im = ax.imshow([[2,3,4,1], [2,4,4,2]], origin="lower", extent=[1,4,2,8])
ax.plot([1,2,3,4], [2,3,4,8], lw=5)
ax.scatter([2,3,4,1], [2,3,4,8], c="r", s=2500)
ax.set_xlim([1,4])
ax.set_ylim([2,8])
ax.set_aspect('auto')
plt.show()
such that we will get the desired behaviour.