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Python: filling a List of objects from a .txt file

For starters I've programmed in C++ for the past year and a half, and this is the first time I'm using Python.
The objects have two int attributes, say i_ and j_.
The text file is as follows:
1,0
2,0
3,1
4,0
...
What I want to do is have the list filled with objects with correct attributes. For example,
print(myList[2].i_, myList[2].j_, end = ' ')
would return
3 1
Here's my attempt after reading a little online.
class myClass:
def __init__(self, i, j):
self.i_ = i
self.j_ = j
with open("myFile.txt") as f:
myList = [list(map(int, line.strip().split(','))) for line in f]
for line in f:
i = 0
while (i < 28):
myList.append(myClass(line.split(","), line.split(",")))
i +=1
But it doesn't work obviously.
Thanks in advance!

Since you're working with a CSV file you might want to use the csv module. First you would pass the file object to the csv.reader function and it will return an iterable of rows from the file. From there you can cast it to a list and slice it to the 29 rows you are required to have. Finally, you can iterate over the rows (e.g. [1,0]) and simply unpack them in the class constructor.
class MyClass:
def __init__(self, i, j):
self.i = int(i)
self.j = int(j)
def __repr__(self):
return f"MyClass(i={self.i}, j={self.j})"
with open('test.txt') as f:
rows = [r.strip().split(',') for r in f.readlines()[:29]]
my_list = [MyClass(*row) for row in rows]
for obj in my_list:
print(obj.i, obj.j)
print(len(my_list))

I not sure you really what to stick with this format
print(myList[2].i_, myList[2].j_, end = ' ')
My solution is quite manual coded and i am using dictionary to store i and j
result = {'i':[],
'j':[]}
and below is my code
result = {'i':[],
'j':[]}
with open('a.txt', 'r') as myfile:
data=myfile.read().replace('\n', ',')
print(data)
a = data.split(",")
print (a)
b = [x for x in a if x]
print(b)
for i in range( 0, len(b)):
if i % 2 == 0:
result['i'].append(b[i])
else:
result['j'].append(b[i])
print(result['i'])
print(result['j'])
print(str(result['i'][2])+","+ str(result['j'][2]))
The result: 3,1

I'm not sure what you're trying to do with myList = [list(map(int, line.strip().split(','))) for line in f]. This will give you a list of lists with those pairs converted to ints. But you really want objects from those numbers. So let's do that directly as we iterate through the lines in the file and do away with the next while loop:
my_list = []
with open("myFile.txt") as f:
for line in f:
nums = [int(i) for i in line.strip().split(',') if i]
if len(nums) >= 2:
my_list.append(myClass(nums[0], nums[1]))

replace with value from array Python

I create txt file with my name in 3 lines of strings :
adam1
adam2
adam3
and array
array = ['Tom','Monica','Jean']
I wanna to replace "adam1" with "Tom" from array and "adam2" with "Monica" etc .
import string
s = open("test.txt",'r')
array = ["Tom''Monica','Jean']
I start code but i dont know how create for loop to do this with replace() method. Can anybody help?

with open('test.txt') as fin:
lst = list(map(lambda s: s.strip(), fin))
with open('test.txt', 'w') as fout:
lst[:len(array)] = array
for elem in lst:
fout.write(str(elem) + '\n')

with open('test_input.txt') as fin, open('test_output.txt','w') as fout:
for num, line in enumerate(fin,0):
fout.write(replace_array[num]+'\n')

How to read and delete first n lines from file in Python - Elegant Solution[2]

Originally posted here: How to read and delete first n lines from file in Python - Elegant Solution
I have a pretty big file ~ 1MB in size and I would like to be able to read first N lines, save them into a list (newlist) for later use, and then delete them.
My original code was:
import os
n = 3 #the number of line to be read and deleted
with open("bigFile.txt") as f:
mylist = f.read().splitlines()
newlist = mylist[:n]
os.remove("bigFile.txt")
thefile = open('bigFile.txt', 'w')
del mylist[:n]
for item in mylist:
thefile.write("%s\n" % item)
Based on Jean-François Fabre code that was posted and later deleted here I am able to run the following code:
import shutil
n = 3
with open("bigFile.txt") as f, open("bigFile2.txt", "w") as f2:
for _ in range(n):
next(f)
f2.writelines(f)
This works great for deleting the first n lines and "updating" the bigFile.txt but when I try to store the first n values into a list so I can later use them like this:
with open("bigFile.txt") as f, open("bigFile2.txt", "w") as f2:
mylist = f.read().splitlines()
newlist = mylist[:n]
for _ in range(n):
next(f)
f2.writelines(f)
I get an "StopIteration" error

In your sample code you are reading the entire file to find the first n lines:
# this consumes the entire file
mylist = f.read().splitlines()
This leaves nothing left to read for the subsequent code. Instead simply do:
with open("bigFile.txt") as f, open("bigFile2.txt", "w") as f2:
# read the first n lines into newlist
newlist = [f.readline() for _ in range(n)]
f2.writelines(f)

I would proceed as follows:
n = 3
yourlist = []
with open("bigFile.txt") as f, open("bigFile2.txt", "w") as f2:
i=0
for line in f:
i += 1
if i<n:
yourlist.append(line)
else:
f2.write(f)

Read data into 2 dimensional array?

I am trying to read a data file into a 2 dimensional array.
For example:
file.dat:
1 2 3 a
4 5 6 b
7 8 9 c
I tried something like:
file=open("file.dat","r")
var = [[]]
var.append([j for j in i.split()] for i in file)
but that didn't work.
I need the data in form of two dimensional array as I need to do operations with each element afterwards, e.g.
for k in range(3):
newval(k) = var[k,1]
Any idea how to do that?

file = open("file.dat", "r") # open file for reading
var = [] # initialize empty array
for line in file:
var.append(line.strip().split(' ')) # split each line on the <space>, and turn it into an array
# thus creating an array of arrays.
file.close() # close file.

This worked for me:
with open("/path/to/file", 'r') as f:
lines = [[float(n) for n in line.strip().split(' ')] for line in f]
It's really weird people said in the comments there is no one line solution for this. It took me so little testing to make this work.

v = []
with open("data.txt", 'r') as file:
for line in file:
if line.split():
line = [float(x) for x in line.split()]
v.append(line)
print(v)

How to delete line from the file in python

I have a file F, content huge numbers e.g F = [1,2,3,4,5,6,7,8,9,...]. So i want to loop over the file F and delete all lines contain any numbers in file say f = [1,2,4,7,...].
F = open(file)
f = [1,2,4,7,...]
for line in F:
if line.contains(any number in f):
delete the line in F

You can not immediately delete lines in a file, so have to create a new file where you write the remaining lines to. That is what chonws example does.

It's not clear to me what the form of the file you are trying to modify is. I'm going to assume it looks like this:
1,2,3
4,5,7,19
6,2,57
7,8,9
128
Something like this might work for you:
filter = set([2, 9])
lines = open("data.txt").readlines()
outlines = []
for line in lines:
line_numbers = set(int(num) for num in line.split(","))
if not filter & line_numbers:
outlines.append(line)
if len(outlines) < len(lines):
open("data.txt", "w").writelines(outlines)
I've never been clear on what the implications of doing an open() as a one-off are, but I use it pretty regularly, and it doesn't seem to cause any problems.

exclude = set((2, 4, 8)) # is faster to find items in a set
out = open('filtered.txt', 'w')
with open('numbers.txt') as i: # iterates over the lines of a file
for l in i:
if not any((int(x) in exclude for x in l.split(','))):
out.write(l)
out.close()
I'm assuming the file contains only integer numbers separated by ,

Something like this?:
nums = [1, 2]
f = open("file", "r")
source = f.read()
f.close()
out = open("file", "w")
for line in source.splitlines():
found = False
for n in nums:
if line.find(str(n)) > -1:
found = True
break
if found:
continue
out.write(line+"\n")
out.close()