Curl request to python request - python

I have a curl request as below:
curl -X POST \
https://example.com \
-H 'Content-Type: multipart/form-data' \
--form-string 'message=<messageML>Hello world!</messageML>'
How do i pass --form-string data in python request?
Thanks!


Use the files parameter to post your data, example:
import requests
url = 'https://httpbin.org/anything'
data = {'message':'<messageML>Hello world!</messageML>'}
r = requests.post(url, files=data)
print(r.text)
You don't have to use headers because 'multipart/form-data' is the default 'Content-Type' header when posting files.

Related

Python requests application/x-www-form-urlencoded non json body

I am trying to hit an API endpoint using python requests. I have been unable to successfully send the body of the request except when using cURL. Here is the cURL command that succeeds:
curl --location --request POST '<api endpoint url>' \
--header 'Content-Type: application/x-www-form-urlencoded' \
--data-urlencode 'obj={"login":"<email>","pword":"<password>"}'
Using python requests like this returns an error from the API because of the body of the request:
payload = 'obj={"login":"<email>","pword":"<password>"}'
headers = {
'Content-Type': 'application/x-www-form-urlencoded'
}
response = requests.post(url, headers=headers, data=payload)
print(response.text)
I also tried requests.request("POST") but got the same results.

Your data is URL encoded as you can see in the curl Content-Type header, so you have to provide the data in an URL encoded format, not JSON.
Use the following instead. requests will set the Content-Type header to application/x-www-form-urlencoded automatically. It will also take care of the URL encoding.
data = {"login": "<email>", "pword": "<password>"}
response = requests.post(url, data=data)

Convert CURL API command to Python API using requests and json

I am connecting through an API to receive data. From the website API documentation, the instructions use either two CURL methods to connect the API; however, I need to connect using python.
1st Method
Curl Example
curl -d '' -X POST 'https://api.bcda.cms.gov/auth/token' \
-H "accept: application/json" \
-H "authorization: Basic <Client_Secret>"
My Python Conversion:
import requests
import json
url = 'https://api.bcda.cms.gov/auth/token'
headers = {"accept": "application/json", "authorization": 'Basic',
'<API_Key>': '<API_Secret>'}
r = requests.post(url = url, data ={}, headers = headers)
print(r)
2nd Method Curl
curl -d '' -X POST 'https://api.bcda.cms.gov/auth/token' \
--user <Client_Key>:<Client_Secret> \
-H "accept: application/json"
My 2nd Python conversion code:
import requests
import json
url = 'https://api.bcda.cms.gov/auth/token'
user = {"<Client_Key>":"<Client_Secret>", "accept": "application/json"}
r = requests.post(url = url, headers = user)
print(r)
I am receiving a 403 connection error, meaning "response status code indicates that the server understands the request but refuses to authorize it."

You should use auth parameter and not headers to convert --user option
headers = {'accept': 'application/json'}
r = requests.post(url=url, headers=headers, auth=(client_key, client_secret))

How should this PUT curl be converted to python requests?

How can I convert this CURL PUT request to python requests:
The curl is
curl -X PUT "https://example.com" -H "accept: application/json" -H "Content-Type: application/json-patch+json" -d "{ \"userName\": \"exampleuser\", \"password\": \"examplepass\"}"
Currently got
headers = {"accept": "application/json",
"Content-Type": "application/json-patch+json"}
data = {'\"userName\"': '\"exampleuser\"',
'\"password\"': '\"examplepass\"'}
response = requests.put(url=url, data=data, headers=headers)
print(response)
Currently getting a 401 response. Unfortunately, the curl converter does not recognise it.

In bash, you escaped the quotes of the json
In Python, you shouldn't need to
data = {'userName' : 'exampleuser',
'password': 'examplepass'}
Then, you're sending json, so do json=data instead of data=data

convert curl get to rest api to python

I have this curl command:
curl -X GET --header 'Accept: application/vnd.pagerduty+json;version=2' --header 'Authorization: Token token=y_NbAkKc66ryYTWUXYEu' 'https://api.pagerduty.com/services?time_zone=UTC&sort_by=name'
I need to convert it to python using requests library
import requests
def support(self):
services_list = requests.get('I need to convert the link to pass it here as a parameter')

import requests
def support():
headers = {
'Accept': 'application/vnd.pagerduty+json;version=2',
'Authorization': 'Token token=y_NbAkKc66ryYTWUXYEu'}
payloads = (
('time_zone', 'UTC'),
('sort_by', 'name'),)
services_list = requests.get('https://api.pagerduty.com/services', headers=headers, params=payloads)

cURL to python Requests: form with file attachment

I have the following cURL request which works successfully:
curl https://daDomain.com/v2-beta/media \
--header "Authorization: Bearer TOKEN" \
--form media=#recording.mp3 \
--form 'configuration={"configuration":{"keywords":{"groups":["data"]}}}'
Below is the python-requests version of the code, which when called returns a 400 error saying a "mediaUrl is not a valid URL".
import requests
headers = {}
headers["Authorization"] = "Bearer TOKEN"
url = "https://daDomain.com/v2-beta/media"
configuration = '{"configuration":{"keywords":{"groups":["data"]}}}'
filepath = 'recording.mp3'
files = {'media' : open('filepath.mp3', 'rb'), 'configuration' : configuration}
r = requests.post(url, headers = headers, files=files)

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