I have a following file structure:
mymodule/
__init__.py
mylib.py
test.py
File mymodule/__init__.py:
# mymodule/__init__.py
def call_me():
module = __import__('.mylib')
module.my_func()
File mymodule/mylib.py:
# mymodule/mylib.py
def my_func():
print("hi!")
File test.py:
# test.py
from mymodule import call_me
call_me()
If I run python3 test.py it fails with the error:
module = __import__('.mylib')
ImportError: No module named '.mylib'
I want to perform a relative import inside of call_me that equals to the static import from . import mylib. How can I do it?
Use importlib.import_module and specify your package from __name__ in __init__.py:
importlib.import_module(name, package=None)
Import a module.
The 'package' argument is required when performing a relative import. It
specifies the package to use as the anchor point from which to resolve the
relative import to an absolute import.
Example:
import importlib
def call_me():
module = importlib.import_module('.mylib', package=__name__)
module.my_func()
How about this,
def call_me():
mylib = __import__('mylib', globals(), locals(), [], 1)
mylib.my_func()
Please refer the doc: import
Related
below the folder structure of my software:
below the code of all the .py files:
run.py:
import modules.module_01.aa as a
a.test()
# test:
if __name__=="__main__":
pass
aa.py (module 1):
import libraries.qq as q
import libraries.zz as z
def test():
q.qq_fun()
z.zz_fun()
print("ciao")
qq.py (library used by aa.py):
def qq_fun():
pass
zz.py (library used by aa.py):
def zz_fun():
pass
my question is really simple, why when I run "run.py" Python say to me:
why "aa.py" can't import the module "qq.py" and "zz.py"? how can I fix this issue?
run.py
In run.py, the Python interpreter thinks you're trying to import module_01.aa from a module named module. To import aa.py, you'll need to add this code to the top of your file, which adds the directory aa.py is in to the system path, and change your import statement to import aa as a.
import sys
sys.path.insert(0, "./modules/module_01/")
aa.py
The same problem occurs in aa.py. To fix the problem in this file, you'll need to add this code to the top of aa.py, which adds the directory qq.py and zz.py are in, and remove the libraries. from both of your import statements.
import sys
sys.path.insert(0, "./modules/module_01/libraries")
I have a package structure like this:
- src
- src/main.py
- src/package1
- src/package1/__init__.py
- src/package1/module1.py
- src/package1/module2.py
... where module2 is a subclass of module1, and therefore module1 gets referenced by an absolute import path in module2.py.
That is, in src/package1/module2.py:
from package1.module1 import SomeClassFromModule1
The problem occurs in the main.py script:
## here the imports
def main():
# create an instance of the child class in Module2
if __name__ == "__main__":
main()
Option 1 works. That is, in src/main.py:
from package1.module2 import SomeClassFromModule2
some_name = SomeClassFromModule2()
Option 2 does not work. That is, in src/main.py:
import package1.module2.SomeClassFromModule2
some_name = package1.module2.SomeClassFromModule2()
... causes the following error.
ModuleNotFoundError: No module named 'package1.module2.SomeClassFromModule2'; 'package1.module2' is not a package
So why is there this difference between the import and from ... import idiom?
Would be glad for some clarification.
import x keyword brings all the methods and class from x in the the file it is being called.
from x import y this brings a specific method or class('y' is a method or class) from that .py file ('x' is the file here) instead of bringing all the methods it has.
In your case when you import package1.module2 the SomeClassForModule2() is being already imported and hence you need not write import package1.module2.SomeClassFromModule2
here I guess you want to access a class, so you need to create a object in order to access it.
hope this helped you
After some test, I think you cannot import a function or class by using import your_module.your_class.
It's all about package, module, function and class:
# import module
>>>import os
<module 'os' from ooxx>
#use module of module (a litte weird)
>>>os.path
<module 'posixpath' from ooxx>
#import module of module (a litte weird)
>>>import os.path
#use function
>>>os.path.dirname
<function posixpath.dirname(p)>
# you cannot import a function (or class) by using 'import your.module.func'
# 'import ooxx' always get a module or package.
>>>import os.path.dirname
ModuleNotFoundError
No module named 'os.path.dirname'; 'os.path' is not a package
# instead of it, using 'from your_module import your_function_or_class'
>>>from os.path import dirname
<function posixpath.dirname(p)>
I have dir structure like this:
Proj/
run.py
Util/
__init__.py
x.py
y.py
In x.py, I define a function:
def p():
return 1
In y.py, I define:
def q():
return 2
Currently in run.py, I'll use
from Util import *
But I have to call them using
x.p()
y.q()
But I want to call them using
p()
q()
Is there a way that I can do that? Like (as I imagine)
from Util.* import *
Bring the names up into the package namespace, by using star imports in the __init__.py:
# in util/__init__.py
from util.x import *
from util.y import *
In each submodule, define the names which you want to export by using the __all__ name:
# in x.py
__all__ = ['p']
And:
# in y.py
__all__ = ['q']
This is a pretty standard usage of the __init__.py module within a package, documented here.
I have 4 files in my project:
project/__init__.py
project/app.py
project/mod_x.py
project/mod_y.py
In mod_x.py I have a class (e.g. ModX)
In mod_y.py I have just one function.
I import modules from app.py as follows:
from .mod_x import ModX
import .mod_y
I get an error:
ImportError: No module named 'mod_y'
Before I created init.py I didn't have that kind of problems (of course, I dont put "." before module name).
How to import module which doesn't have the class inside in Python3 with init.py file inside the current directory?
Relative imports are only available for from...import syntax.
You could import that function this way:
from .mod_y import FUNCTION_NAME
Module could be imported this way:
from . import mod_y
I failed to import a module from sub directory in python. Below is my project structure.
./main.py
./sub
./sub/__init__.py
./sub/aname.py
when I run python main.py, I got this error:
Traceback (most recent call last):
File "main.py", line 4, in <module>
import sub.aname
File "/Users/dev/python/demo/sub/__init__.py", line 1, in <module>
from aname import print_func
ModuleNotFoundError: No module named 'aname'
I don't know it failed to load the module aname. Below is the source code:
main.py:
#!/usr/bin/python
import sub.aname
print_func('zz')
sub/__init__.py:
from aname import print_func
sub/aname.py:
def print_func( par ):
print ("Hello : ", par)
return
I am using python 3.6.0 on MacOS
There are several mistakes in your Python scripts.
Relative import
First, to do relative import, you must use a leading dots (see Guido's Decision about Relative Imports syntax).
In sub/__init__.py, replace:
from aname import print_func
with:
from .aname import print_func
Importing a function
To import a function from a given module you can use the from ... import ... statement.
In main.py, replace:
import sub.aname
with:
from sub import print_func
from sub import aname
aname.print_func('zz')
Probably the most elegant solution is to use relative imports in your submodule sub:
sub.__init__.py
from .aname import print_func
But you also need to import the print_func in main.py otherwise you'll get a NameError when you try to execute print_func:
main.py
from sub import print_func # or: from sub.aname import print_func
print_func('zz')