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tkinter askdirectory doesn't work from imported module

I have been using tkinter to supply a file dialog (in python 3.6) which allows users to select a directory. It works fine when it is a sub-function within the same module, but if I move that subfunction into a separate module and then try to import it from that module, it no longer works. Instead the code just hangs when the file dialog should pop up but it never appears.
working code:
This works if I run the main function
from tkinter import Tk
from tkinter.filedialog import askdirectory
def SelectDirectory():
# start up the tk stuff to have a file directory popup
print('start')
root = Tk()
print('postroot')
root.withdraw()
print('postwithdraw')
# let the user pick a folder
basepath = askdirectory(title='Please select a folder')
print('postselection')
root.destroy()
print('postdestroy')
return basepath
def main():
ans = SelectDirectory()
print(ans)
If I instead put this in another module and import it from that module, then it will print until 'postwithdraw' and then just hang.
submod.py:
from tkinter import Tk
from tkinter.filedialog import askdirectory
def SelectDirectory():
# start up the tk stuff to have a file directory popup
print('start')
root = Tk()
print('postroot')
root.withdraw()
print('postwithdraw')
# let the user pick a folder
basepath = askdirectory(title='Please select a folder')
print('postselection')
root.destroy()
print('postdestroy')
return basepath
and then run this:
from submod import SelectDirectory
def main():
ans = SelectDirectory()
print(ans)
It never gets past 'postwithdraw' and the file dialog never pops up.
Does anyone know what I am doing wrong here? I would think it has something to do with the tkinter window not appearing since its not the main module but is there some way to get past that?

Your both versions don't work. Both give 'module' object is not callable.
You have to use
root = Tk.Tk()
instead of
root = Tk()
and then both versions works.
Maybe two Tk in Tk.Tk() seems weird but usually we use lowercase tk instead of Tk in
import tkinter as tk
and then you have
root = tk.Tk()

Getting folder path with Python Tkinter tkFileDialog

Using Python Tkinter I am trying to get the directory path of selected Folder. I do not want to load a file or navigate to a file but get the folder path like
How can I do this?
from Tkinter import *
from tkFileDialog import askopenfilename
def callback():
name= askopenfilename()
print name
errmsg = 'Error!'
Button(text='File Open', command=callback).pack(fill=X)
mainloop()
Update
from Tkinter import *
from tkFileDialog import askopenfilename
from tkinter import filedialog #for Python 3
def callback():
name= askopenfilename()
directory = filedialog.askdirectory()
print directory
errmsg = 'Error!'
Button(text='File Open', command=callback).pack(fill=X)
mainloop()

You can use askdirectory from filedialog as follows:
from tkinter import filedialog #for Python 3
directory = filedialog.askdirectory()

Ok Looks like I find the solution on my own. Putting here which might help someone else in future.
import Tkinter, tkFileDialog
root = Tkinter.Tk()
root.withdraw()
dirname = tkFileDialog.askdirectory(parent=root,initialdir="/",title='Please select a directory')
print(dirname)

Python - How to read a file that was selected from Tkinter?

This is for my assignment.
I was given a template like this... def_choosefile() :
import tkinter
from tkinter import filedialog
root_window = tkinter.Tk()
root_window.withdraw()
return filedialog.askopenfilename()
So if i get this correct, it'll prompt a dialog window, asking to select a file. And when a file is selected, the program is supposed to tell what files did it pick. Using these:
selected_file = choose_file()
print ("Selected file: {}".format (selected_file))
after that, how do i make the program read the files normally? Normally i would use:
infile = open('text')
infile.readline()

import tkinter
from tkinter import filedialog
root_window = tkinter.Tk()
root_window.withdraw()
def choose_file():
return filedialog.askopenfilename()
selected_file = choose_file()
with open (selected_file,'r') as readfile:
lines = readfile.read().splitlines()
for line in lines[0:2]:
print (line)

tkinter filedialog window persists after folder selection

I use the following sub-routine to get a path to the files I require
from tkinter import *
from tkinter import filedialog
def get_foldername(prompt):
root = Tk()
root.withdraw() # get rid of annoying little window
my_path = filedialog.askdirectory(initialdir="/Users/" + getuser(),title=prompt) + "/"
return my_path
The problem is, that the filedialog window persists until the program ends, how can I unload this window before returning to my main program routine?
The following code duplicates the persistence problem:
from getpass import getuser
from tkinter import *
from tkinter import filedialog
def get_foldername(prompt):
root = Tk()
root.withdraw() # get rid of annoying little window
my_path = filedialog.askdirectory(initialdir="/Users/" + getuser(), title=prompt) + "/"
return my_path
def main():
path_to_files = get_foldername("Choose source folder")
while True:
for idx in range(3000000):
print(path_to_files)
break
if __name__ == '__main__':
main()

Get a file's directory in a string selected by askopenfilename

I'm making a program that you use the askopenname file dialog to select a file, which I then want to save the directory to a string so I can use another function (which I already made) to extract the file to a different location that is predetermined.
My button code that opens the file dialog is this:
`a = tkinter.Button(gui, command=lambda: tkinter.filedialog.askopenfilename(initialdir='C:/Users/%s' % user))`

This should be what you want:
import tkinter
import tkinter.filedialog
import getpass
# Need this for the `os.path.split` function
import os
gui = tkinter.Tk()
user = getpass.getuser()
def click():
# Get the file
file = tkinter.filedialog.askopenfilename(initialdir='C:/Users/%s' % user)
# Split the filepath to get the directory
directory = os.path.split(file)[0]
print(directory)
button = tkinter.Button(gui, command=click)
button.grid()
gui.mainloop()

If you know where the file actually is, you could always just ask for a directory instead of the file using:
from tkFileDialog import askdirectory
directory= askdirectory()
Then in the code:
import tkinter
import tkinter.filedialog
import getpass
from tkFileDialog import askdirectory
# Need this for the `os.path.split` function
import os
gui = tkinter.Tk()
user = getpass.getuser()
def click():
directory= askdirectory()
print (directory)
button = tkinter.Button(gui, command=click)
button.grid()
gui.mainloop()