Communication between two python programs - python

please help me understand why this doesn't work and how to change it.
I basically want to be able to query values of a var of program one from program two. So here are the most basic programs:
P1:
import time
gscore = 0
def get_info():
return gscore
def main():
global gscore
score = 0
while score <10:
time.sleep(1)
score +=1
gscore = score
print(score)
if __name__ == '__main__':
main()
P2:
from functest import get_info
print(get_info())
The structure may seem a bit weird but basically I have an existing small python game and want to be able to query the score which is why I adapted it in this way. So P1 obviously counts to ten but P2 always gets 0 as a return value. I feel like I'm making a really stupid mistake here...
Thx for help :)

if __name__ == '__main__' is only executed when you run your code form a shell and not when you import your program from another program. To fix this you can modify your program as:
In you P1 modify get_info to this:
def get_info():
global gscore
return gscore
In your P2 do this:
from functest import main, get_info
main()
print(get_info())
Also, note that there are better way of doing what you are doing like using a class instead of creating a global variable.
class Score(object):
def __init__(self, gscore=0):
self.gscore = gscore
def get_info(self):
return self.gscore
def increment(self, score=0):
while score < 10:
score +=1
self.gscore = score

When you import a module in Python you are not executing the content of it.
if __name__ == "__main__": is there so that your Python files can act as either reusable modules, or as standalone programs.
If you want to execute the main() function you'll need to explicitly call it.:
from functest import main, get_info
main() # calling the main function in your functest file
print(get_info()) # calling the get_info function
this will return the value you are looking for.
Now, main will be called if you execute the functest.py file:
$ python functest.py
#=> 9

When you import a function of another program, you are importing the functionality of the program, not the actual instance of the program. What I mean by that is that your program only counts to 10 while it's running, but 10 isn't part of the code, it's a result.
What importing it allows you to do is run the bit of code you imported (In your case, running the get_info code with the gscore = 0 being the gscore that is returned, however, this is a distinct instance of your other program, so even if gscore is increasing in another program that you're running with the main method, your second program has it's own gscore that is 0. Importing is more for when you have a sort of library of functions in a program that you want access to.
What you want is to be able to, run time, read a value that the other program has generated. This can't be done with python variables, but it can be done in many other ways. A common way is to write the score to a file, then read the file in your other program. If you need information on how to read and write files, read this guide here.

Related

Function results in program crash- no crash command [duplicate]

I have this code:
import sys
def random(size=16):
return open(r"C:\Users\ravishankarv\Documents\Python\key.txt").read(size)
def main():
key = random(13)
print(key)
When I try running the script, there are no errors, but nothing appears to happen. I expected it to print some content from the key file, but nothing is printed.
What is wrong? How do I make the code run?
You've not called your main function at all, so the Python interpreter won't call it for you.
Add this as the last line to just have it called at all times:
main()
Or, if you use the commonly seen:
if __name__ == "__main__":
main()
It will make sure your main method is called only if that module is executed as the starting code by the Python interpreter. More about that here: What does if __name__ == "__main__": do?
If you want to know how to write the best possible 'main' function, Guido van Rossum (the creator of Python) wrote about it here.
Python isn't like other languages where it automatically calls the main() function. All you have done is defined your function.
You have to manually call your main function:
main()
Also, you may commonly see this in some code:
if __name__ == '__main__':
main()
There's no such main method in python, what you have to do is:
if __name__ == '__main__':
main()
Something does happen, it just isn't noticeable
Python runs scripts from top to bottom. def is a statement, and it executes when it is encountered, just like any other statement. However, the effect of this is to create the function (and assign it a name), not to call it. Similarly, import is a statement that loads the other module (and makes its code run top to bottom, with its own global-variable context), and assigns it a name.
When the example code runs, therefore, three things happen:
The code for the sys standard library module runs, and then the name sys in our own module's global variables is bound to that module
A function is created from the code for random, and then the name random is bound to that function
A function is created from the code for main, and then the name main is bound to that function
There is nothing to call the functions, so they aren't called. Since they aren't called, the code inside them isn't run - it's only used to create the functions. Since that code doesn't run, the file isn't read and nothing is printed.
There are no "special" function names
Unlike in some other languages, Python does not care that a function is named main, or anything else. It will not be run automatically.
As the Zen of Python says, "Explicit is better than implicit". If we want a function to be called, we have to call it. The only things that run automatically are the things at top level, because those are the instructions we explicitly gave.
The script starts at the top
In many real-world scripts, you may see a line that says if __name__ == '__main__':. This is not "where the script starts". The script runs top to bottom.
Please read What does if __name__ == "__main__": do? to understand the purpose of such an if statement (short version: it makes sure that part of your top-level code is skipped if someone else imports this file as a module). It is not mandatory, and it does not have any kind of special "signalling" purpose to say where the code starts running. It is just a perfectly normal if statement, that is checking a slightly unusual condition. Nothing requires you to use it in a script (aside from wanting to check what it checks), and nothing prevents you from using it more than once. Nothing prevents you from checking whether __name__ is equal to other values, either (it's just... almost certainly useless).
You're not calling the function. Put main() at the bottom of your code.

Solution to get output for python project

I am doing a simple project on my Pycharm IDE.
My code is this:
import webbrowser
import time
socialMediaUrls = ["www.google.com","www.edureka.com"]
techUrls = ["www.udacity.com","www.dailymotion.com"]
def open_tabs(url_list):
for element in url_list:
webbrowser.open_new_tab(element)
def main():
webbrowser.open("www.youtube.com",new=0,autoraise=false)
time.sleep(1)
open.tab(socialMedialUrls)
open_tabs(techUrls)
main()
but after running I am getting this message:
C:\Users\adc\AppData\Local\Programs\Python\Python36-32\python.exe
C:/Users/adc/PycharmProjects/untitled1/ur.py
Process finished with exit code 0
And I am getting same message for all my projects. What should I do?
You should call main in that way:
def main():
webbrowser.open("www.youtube.com",new=0,autoraise=false)
time.sleep(1)
open.tab(socialMedialUrls)
open_tabs(techUrls)
if __name__ == "__main__":
main()
Also I see that your code contains some other errors. For example, in Python there is False keyword, not false. Lines with open.tab and open_tabs will not work too.
Currently, no instructions are reachable in your script (besides the import statements)
in:
def main():
webbrowser.open("www.youtube.com",new=0,autoraise=false)
time.sleep(1)
open.tab(socialMedialUrls)
open_tabs(techUrls)
main()
indentation suggests that you're performing a recursive call (which isn't what you want).
Unindent main() to make sure you execute something in your script.
Or put the instructions of main at zero-indent level outside any procedure (in that case, it is executed even when importing the module, probably not important here)
(note that python programs don't need a main(), this isn't C)

Python main function not working [duplicate]

This question already has answers here:
Why doesn't the main() function run when I start a Python script? Where does the script start running (what is its entry point)?
(5 answers)
Closed 6 years ago.
I am writing a simple Python program with some functions, one of which is a main() function executes the other functions. However when I run the code below there is no output. Can someone tell me if they see an error in the structure?
def print1():
print("this is also a function")
def print2():
print("this is a function")
def main():
print1()
print2()
You need to call main(). Right now it is just a definition. What use is an entry in a dictionary if nobody uses the word?
def print1():
print("this is also a function")
def print2():
print("this is a function")
def main():
print1()
print2()
main()
It is common in Python programs to do things differently depending on if the file is being imported or run. When a file is executed, the __name__ variable is set either to '__main__' or the name of the file. It is set to '__main__' if the file is being executed as a python script, and it is set to the name of the file if it is being imported. You can use this information so that you don't actually run anything if it is just being imported instead of being run as a python script:
if __name__ == '__main__':
main()
That way, you can import the module, and use the functions without main() being called. If it is run as a python script, however, main() will be called.
Add this to the bottom of your code.
if __name__ == "__main__":
main()
See https://docs.python.org/2/library/main.html
Main needs to be called explicitly. You can do it without the if statement, but this allows your code to be either a module or a main program. If it is imported as a module, main() won't be called. If it is the main program then it will be called.
You are thinking like a C programmer. In this case python acts more like a shell script. Anything not in a function or class definition will be executed.
You need to call main() in order for it to run.
I believe what you mean to be doing is
def print1():
print("this is also a function")
def print2():
print("this is a function")
if __name__ == '__main__':
print1()
print2()
Call this script something.py and then run python something.py from your command line.

Initialize variable in loop - use global variable?

I wrote a function that makes a screenshot and checks if it's different than the old one. The example code is below. However, I wonder about pythons best practice to set the variables oldimage and image. Especially oldimage needs to be set before main() can start the first time. Do I use global variables?
def main():
image=screenGrab()
if equal(image,oldimage):
pass
else:
dosomething()
oldimage=image
while True:
main()
Using global variables is almost never the correct solution. It usually ends up causing more problems than solutions. Continuing from #MartijnPieters, I would organize your code as follows:
def main():
oldimage = loadLastImage()
while True:
image=screenGrab()
if not equal(image,oldimage):
dosomething()
saveLastImage(image) # this is the opposite of loadLastImage()
oldimage=image
# this is the more accepted way of running main
# because it still allows your code to be loaded as module
if __name__ == "__main__":
main()

Why doesn't the main() function run when I start a Python script? Where does the script start running (what is its entry point)?

I have this code:
import sys
def random(size=16):
return open(r"C:\Users\ravishankarv\Documents\Python\key.txt").read(size)
def main():
key = random(13)
print(key)
When I try running the script, there are no errors, but nothing appears to happen. I expected it to print some content from the key file, but nothing is printed.
What is wrong? How do I make the code run?
You've not called your main function at all, so the Python interpreter won't call it for you.
Add this as the last line to just have it called at all times:
main()
Or, if you use the commonly seen:
if __name__ == "__main__":
main()
It will make sure your main method is called only if that module is executed as the starting code by the Python interpreter. More about that here: What does if __name__ == "__main__": do?
If you want to know how to write the best possible 'main' function, Guido van Rossum (the creator of Python) wrote about it here.
Python isn't like other languages where it automatically calls the main() function. All you have done is defined your function.
You have to manually call your main function:
main()
Also, you may commonly see this in some code:
if __name__ == '__main__':
main()
There's no such main method in python, what you have to do is:
if __name__ == '__main__':
main()
Something does happen, it just isn't noticeable
Python runs scripts from top to bottom. def is a statement, and it executes when it is encountered, just like any other statement. However, the effect of this is to create the function (and assign it a name), not to call it. Similarly, import is a statement that loads the other module (and makes its code run top to bottom, with its own global-variable context), and assigns it a name.
When the example code runs, therefore, three things happen:
The code for the sys standard library module runs, and then the name sys in our own module's global variables is bound to that module
A function is created from the code for random, and then the name random is bound to that function
A function is created from the code for main, and then the name main is bound to that function
There is nothing to call the functions, so they aren't called. Since they aren't called, the code inside them isn't run - it's only used to create the functions. Since that code doesn't run, the file isn't read and nothing is printed.
There are no "special" function names
Unlike in some other languages, Python does not care that a function is named main, or anything else. It will not be run automatically.
As the Zen of Python says, "Explicit is better than implicit". If we want a function to be called, we have to call it. The only things that run automatically are the things at top level, because those are the instructions we explicitly gave.
The script starts at the top
In many real-world scripts, you may see a line that says if __name__ == '__main__':. This is not "where the script starts". The script runs top to bottom.
Please read What does if __name__ == "__main__": do? to understand the purpose of such an if statement (short version: it makes sure that part of your top-level code is skipped if someone else imports this file as a module). It is not mandatory, and it does not have any kind of special "signalling" purpose to say where the code starts running. It is just a perfectly normal if statement, that is checking a slightly unusual condition. Nothing requires you to use it in a script (aside from wanting to check what it checks), and nothing prevents you from using it more than once. Nothing prevents you from checking whether __name__ is equal to other values, either (it's just... almost certainly useless).
You're not calling the function. Put main() at the bottom of your code.

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