How do I make this code print the total number of bright pixels that are over 200:
from PIL import Image
img = input("File name: ")
img = Image.open(img);
for y in range(img.height):
for x in range(img.width):
pixel = img.getpixel((x, y))
if pixel >= 200:
print(pixel,"pixels are bright.")
Right now it's printing every single pixel that is over 200 on new lines, but I just want one line that prints the total like this:
File name: slippers.png
121081 pixels are bright.
You don't need loops at all for this. Simply create a mask returning which pixels are above the threshold, and sum the mask.
With numpy
You just need to convert the img from a PIL Image to a numpy array, which you can do with np.array(img). Then create a boolean mask for whenever the pixels are above your threshold, np.array(img) >= 200. This will create an array of the same size as your image with a True or False in each pixel location for whether it meets the criteria. Then if you np.sum() the resulting image, it will convert True to 1 and False to 0, so summing will give the total number of pixels which met the criteria. All of this in one line:
bright_count = np.sum(np.array(img) >= 200)
Pure PIL
For a purely PIL solution that doesn't use numpy, you can use the point() method of the Image class. See this question/answer for a good discussion of the method. The point() method takes in a function which assigns new values to a pixel. Here I've just assigned a value of 1 whenever it's above the threshold. Then I've grabbed just the data from the Image type with the getdata() method, and summed the data with the Python sum() function.
bright_count = sum(img.point(lambda pix: 1 if pix>=thresh else 0).getdata())
Just count the pixels before printing:
from PIL import Image
img = input("File name: ")
img = Image.open(img);
count = 0
for y in range(img.height):
for x in range(img.width):
pixel = img.getpixel((x, y))
if pixel >= 200:
count += 1
print(count,"pixels are bright.")
You can use the getcolors() function from PIL image, this function return a list of tuples with colors found in image and the amount of each one. I'm using the following function to return a dictionary with color as key, and counter as value.
from PIL import Image
def getcolordict(im):
w,h = im.size
colors = im.getcolors(w*h)
colordict = { x[1]:x[0] for x in colors }
return colordict
im = Image.open('image.jpg')
colordict = getcolordict(im)
# get the amount of black pixels in image
# in RGB black is 0,0,0
black_pixels_count = colordict.get((0,0,0))
# get the amount of white pixels in image
# in RGB white is 255,255,255
white_pixels_count = colordict.get((255,255,255))
You can try this one too (Python 3):
from PIL import Image
imgFile = input("File name: ")
img = Image.open(imgFile);
pixels = img.getdata()
total = len(list(filter(lambda i: i >= (200,200,200), pixels)))
print("There are %d bright pixels" % total)
You can use the getdata() method to take all pixels at once end then you can filter the ones which are above the desired value. In Python 2, you can simply write i >= 200.
Related
My goal is to generate a color per pixel in order to fill up the whole canvas however the image generated always turns out black with only one of its pixels changed color, I can't seem to figure what I'm doing wrong.
import random
from PIL import Image
canvas = Image.new("RGB", (300,300))
y = random.randint(1, canvas.width)
x = random.randint(1, canvas.width)
r = random.randint(0,255)
g = random.randint(0,255)
b = random.randint(0,255)
rgb = (r,g,b)
for i in range(canvas.width):
canvas.putpixel((x,y), (rgb))
canvas.save("test.png", "PNG")
print("Image saved successfully.")
You really should try and avoid using for loops in any Python image processing - they are slow and error-prone.
The easiest and fastest way to make a random image is using vectorised Numpy functions like this:
import numpy as np
from PIL import Image
# Create Numpy array 300x300x3 of random uint8
data = np.random.randint(0, 256, (300,300,3), dtype=np.uint8)
# Make into PIL Image
im = Image.fromarray(data)
The problem with your code is that you are not iterating over every pixel. I've modified your code to iterate over every pixel, check whether or not it is black (0,0,0), then place a pixel on that iteration with your randomly-generated rgb value. Then, I regenerate 3 new random numbers and place them back into the rgb tuple causing the next pixel in the loop to have a different rgb value.
The x and y definitions are redundant, as you want a random color for every pixel but do not want random pixels, so I have removed them. I added a declaration, pixels = canvas.load() which allocates memory for the pixels so you can iterate over them and change each individual color. I heavily relied on this similar stackoverflow question, if you want further information. Here is my code:
canvas = Image.new("RGB", (300,300))
pixels = canvas.load()
width, height = canvas.size
for i in range(width):
for j in range(height):
if pixels[i,j] == (0,0,0):
r = random.randint(0,255)
g = random.randint(0,255)
b = random.randint(0,255)
rgb = (r,g,b)
canvas.putpixel((i,j), (rgb))
canvas.save("test.png", "PNG")
print("Image saved successfully.")
Here is the output produced:
So in my coursework, I am supposed to change the different variations of colors and get an image that looks like the example provided. I have gotten halfway there, but for the life of me cannot figure out how to get the colors to change, even a little bit. Even if the code runs without errors, the colors will not change
i've tried numpy arrays, editing the pixel color, etc. I can not get anything to work.
import PIL
from PIL import Image
from PIL import ImageEnhance
from PIL import ImageDraw
from PIL import ImageFont
fnt = ImageFont.truetype('readonly/fanwood-webfont.ttf', 75)
# read image and convert to RGB
image=Image.open("readonly/msi_recruitment.gif")
image=image.convert('RGB')
drawing_object = ImageDraw.Draw(image)
# build a list of 9 images which have different brightnesses
enhancer=ImageEnhance.Brightness(image)
images=[]
x = 1
for i in range(0, 10):
pixels = img.load()
print(image.size)
x += 1
z = x
if x%3 == 1 :
z = 9
drawing_object.rectangle((0,450,800,325), fill='black')
drawing_object.text((20,350),'channel intensity o 0.{}'.format(z), font=fnt, fill=(255,255,255))
elif x%3 == 0:
z = 5
drawing_object.rectangle((0,450,800,325), fill='black')
drawing_object.text((20,350),'channel intensity o 0.{}'.format(z), font=fnt, fill=(255,255,255))
else:
z = 1
drawing_object.rectangle((0,450,800,325), fill='black')
drawing_object.text((20,350),'channel intensity o 0.{}'.format(z), font=fnt, fill=(255,255,255))
images.append(enhancer.enhance(10/10))
## create a contact sheet from different brightnesses
first_image=images[0]
contact_sheet=PIL.Image.new(first_image.mode, (first_image.width*3,first_image.height*3))
x=0
y=0
for img in images:
# Lets paste the current image into the contact sheet
contact_sheet.paste(img, (x, y) )
# Now we update our X position. If it is going to be the width of the image, then we set it to 0
# and update Y as well to point to the next "line" of the contact sheet.
if x+first_image.width == contact_sheet.width:
x=0
y=y+first_image.height
else:
x=x+first_image.width
# resize and display the contact sheet
contact_sheet = contact_sheet.resize((int(contact_sheet.width/2),int(contact_sheet.height/2) ))
display(contact_sheet)
So in general you can use OpenCVs ColorMap to change colors in your image:
import cv2
img = cv2.imread(r"<IMAGE PATH>")
img = cv2.applyColorMap(img, cv2.COLORMAP_JET) # Change colors of image with predefined colormap
# Display the new image
cv2.imshow("img", img)
cv2.waitKey()
Now if you want to create your own colormap instead of using a predefined one in OpenCV you can do it with cv2.LUT() (OpenCV Documentation)
Example Input:
Example Output:
And here would be a quick example of how to change Gamma with this approach:
def adjust_gamma(img, gamma=1.0):
assert (img.shape[0] == 1)
invGamma = 1.0 / gamma
table = np.array([((i / 255.0) ** invGamma) *
255 for i in np.arange(0, 256)]).astype("uint8")
new_img = cv2.LUT(np.array(img, dtype=np.uint8), table)
return new_img
It looks like you have a typo in your loop:
for i in range(0, 10):
# if-elses
...
images.append(enhancer.enhance(10/10))
You're enhancing the image with a factor of 1.0 at each iteration, which according to the docs:
Adjust image brightness.
This class can be used to control the brightness of an image. An enhancement factor of 0.0 gives a black image. A factor of 1.0 gives the original image.
Using z, which I suspect was your intention, will give you the tiers of brightness your comments describe:
for i in range(0, 10):
# if-elses
...
images.append(enhancer.enhance(z/10))
Edit: changed assumed value from i to z, based on the text you're writing.
I should also point out that you probably want to create a temp "watermark" image during the for-loop to apply the text/rectangle to. Since the ImageDraw objects modify the image in-place, you're applying the text on top of each other at each iteration, causing some weird text on the later images.
I am trying to increase the region of interest of an image using the below algorithm.
First, the set of pixels of the exterior border of the ROI is de termined, i.e., pixels that are outside the ROI and are neighbors (using four-neighborhood) to pixels inside it. Then, each pixel value of this set is replaced with the mean value of its neighbors (this time using eight-neighborhood) inside the ROI. Finally, the ROI is expanded by inclusion of this altered set of pixels. This process is repeated and can be seen as artificially increasing the ROI.
The pseudocode is below -
while there are border pixels:
border_pixels = []
# find the border pixels
for each pixel p=(i, j) in image
if p is not in ROI and ((i+1, j) in ROI or (i-1, j) in ROI or (i, j+1) in ROI or (i, j-1) in ROI) or (i-1,j-1) in ROI or (i+1,j+1) in ROI):
add p to border_pixels
# calculate the averages
for each pixel p in border_pixels:
color_sum = 0
count = 0
for each pixel n in 8-neighborhood of p:
if n in ROI:
color_sum += color(n)
count += 1
color(p) = color_sum / count
# update the ROI
for each pixel p=(i, j) in border_pixels:
set p to be in ROI
Below is my code
img = io.imread(path_dir)
newimg = np.zeros((584, 565,3))
mask = img == 0
while(1):
border_pixels = []
for i in range(img.shape[0]):
for j in range(img.shape[1]):
for k in range(0,3):
if(i+1<=583 and j+1<=564 and i-1>=0 and j-1>=0):
if ((mask[i][j][k]) and ((mask[i+1][j][k]== False) or (mask[i-1][j][k]==False) or (mask[i][j+1][k]==False) or (mask[i][j-1][k]==False) or (mask[i-1][j-1][k] == False) or(mask[i+1][j+1][k]==False))):
border_pixels.append([i,j,k])
if len(border_pixels) == 0:
break
for (each_i,each_j,each_k) in border_pixels:
color_sum = 0
count = 0
eight_neighbourhood = [[each_i-1,each_j],[each_i+1,each_j],[each_i,each_j-1],[each_i,each_j+1],[each_i-1,each_j-1],[each_i-1,each_j+1],[each_i+1,each_j-1],[each_i+1,each_j+1]]
for pix_i,pix_j in eight_neighbourhood:
if (mask[pix_i][pix_j][each_k] == False):
color_sum+=img[pix_i,pix_j,each_k]
count+=1
print(color_sum//count)
img[each_i][each_j][each_k]=(color_sum//count)
for (i,j,k) in border_pixels:
mask[i,j,k] = False
border_pixels.remove([i,j,k])
io.imsave("tryout6.png",img)
But it is not doing any change in the image.I am getting the same image as before
so I tried plotting the border pixel on a black image of the same dimension for the first iteration and I am getting the below result-
I really don't have any idea where I am doing wrong here.
Here's a solution that I think works as you have requested (although I agree with #Peter Boone that it will take a while). My implementation has a triple loop, but maybe someone else can make it faster!
First, read in the image. With my method, the pixel values are floats between 0 and 1 (rather than integers between 0 and 255).
import urllib
import matplotlib.pyplot as plt
import numpy as np
from skimage.morphology import binary_dilation, binary_erosion, disk
from skimage.color import rgb2gray
from skimage.filters import threshold_otsu
# create a file-like object from the url
f = urllib.request.urlopen("https://i.stack.imgur.com/JXxJM.png")
# read the image file in a numpy array
# note that all pixel values are between 0 and 1 in this image
a = plt.imread(f)
Second, add some padding around the edges, and threshold the image. I used Otsu's method, but #Peter Boone's answer works well, too.
# add black padding around image 100 px wide
a = np.pad(a, ((100,100), (100,100), (0,0)), mode = "constant")
# convert to greyscale and perform Otsu's thresholding
grayscale = rgb2gray(a)
global_thresh = threshold_otsu(grayscale)
binary_global1 = grayscale > global_thresh
# define number of pixels to expand the image
num_px_to_expand = 50
The image, binary_global1 is a mask that looks like this:
Since the image is three channels (RGB), I process the channels separately. I noticed that I needed to erode the image by ~5 px because the outside of the image has some unusual colors and patterns.
# process each channel (RGB) separately
for channel in range(a.shape[2]):
# select a single channel
one_channel = a[:, :, channel]
# reset binary_global for the each channel
binary_global = binary_global1.copy()
# erode by 5 px to get rid of unusual edges from original image
binary_global = binary_erosion(binary_global, disk(5))
# turn everything less than the threshold to 0
one_channel = one_channel * binary_global
# update pixels one at a time
for jj in range(num_px_to_expand):
# get 1 px ring of to update
px_to_update = np.logical_xor(binary_dilation(binary_global, disk(1)),
binary_global)
# update those pixels with the average of their neighborhood
x, y = np.where(px_to_update == 1)
for x, y in zip(x,y):
# make 3 x 3 px slices
slices = np.s_[(x-1):(x+2), (y-1):(y+2)]
# update a single pixel
one_channel[x, y] = (np.sum(one_channel[slices]*
binary_global[slices]) /
np.sum(binary_global[slices]))
# update original image
a[:,:, channel] = one_channel
# increase binary_global by 1 px dilation
binary_global = binary_dilation(binary_global, disk(1))
When I plot the output, I get something like this:
# plot image
plt.figure(figsize=[10,10])
plt.imshow(a)
This is an interesting idea. You're going to want to use masks and some form of mean ranks to accomplish this. Going pixel by pixel will take you a while, instead you want to use different convolution filters.
If you do something like this:
image = io.imread("roi.jpg")
mask = image[:,:,0] < 30
just_inside = binary_dilation(mask) ^ mask
image[~just_inside] = [0,0,0]
you will have a mask representing just the pixels inside of the ROI. I also set the pixels not in that area to 0,0,0.
Then you can get the pixels just outside of the roi:
just_outside = binary_erosion(mask) ^ mask
Then get the mean bilateral of each channel:
mean_blue = mean_bilateral(image[:,:,0], selem=square(3), s0=1, s1=255)
#etc...
This isn't exactly correct, but I think it should put you in the right direction. I would check out image.sc if you have more general questions about image processing. Let me know if you need more help as this was more general direction than working code.
I want to count the pixels of color intensity of [150,150,150] in an image and I have determined the shape of the image and made a loop to scan the image pixel by pixel but I have faced this error and I don't know why it appeared.
But I got the following error:
File "D:/My work/MASTERS WORK/FUNCTIONS.py", line 78, in <module>
if img[x,y] == [150,150,150]:
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()
Code:
img = cv2.imread('imj.jpg')
h ,w =img.shape[:2]
m= 0
for y in range(h):
for x in range(w):
if img[x,y] == [150,150,150]:
m+=1
print('No. of points = ' , m)
Instead of using a for loop, you should vectorize the processing using Numpy. To count the number of pixels of color intensity [150,150,150], you can use np.count_nonzero()
count = np.count_nonzero((image == [150, 150, 150]).all(axis = 2))
Here's an example. We create a black image of size [400,400] and color the bottom left corner to [150,150,150]
import numpy as np
# Create black image
image = np.zeros((400,400,3), dtype=np.uint8)
image[300:400,300:400] = (150,150,150)
We then count the number of pixels at this intensity
# Count number of pixels of specific color intensity
count = np.count_nonzero((image == [150, 150, 150]).all(axis = 2))
print(count)
10000
Finally we if wanted to change the pixels of that intensity, we can find all desired pixels and use a mask. In this case, we turn the pixels to green
# Find pixels of desired color intensity and draw onto mask
mask = (image == [150.,150.,150.]).all(axis=2)
# Apply the mask to change the pixels
image[mask] = [36,255,12]
Full code
import numpy as np
# Create black image
image = np.zeros((400,400,3), dtype=np.uint8)
image[300:400,300:400] = (150,150,150)
# Count number of pixels of specific color intensity
count = np.count_nonzero((image == [150, 150, 150]).all(axis = 2))
print(count)
# Find pixels of desired color intensity and draw onto mask
mask = (image == [150.,150.,150.]).all(axis=2)
# Apply the mask to change the pixels
image[mask] = [36,255,12]
It's not a recommended way to count the pixels having a given value, but still you can use below code for above case(same value of r, g and b):
for x in range(h):
for y in range(w):
if np.all(img[x, y]==150, axis=-1): # (img[x, y]==150).all(axis=-1)
m+=1
If you want to count pixels with different values of r, g and b, then use np.all(img[x, y]==[b_value, g_value, r_value], axis=-1), since OpenCV follows bgr order.
Alternatively, you can use np.count_nonzero(np.all(img==[b_value, g_value, r_value],axis=-1)) or simply np.count_nonzero(np.all(img==150, axis=-1)) in above case.
How fast change pixels values? In C# what i need to do is only use GetPixel() to get pixel value and SetPixel() to change it (its pretty easy to use but slow, MarshallCopy and Lock/UnlockBits is much faster).
In this code, i marking black pixels as 1 and white pixels as 0
import tkFileDialog
import cv2
import numpy as np
from matplotlib import pyplot as plt
path = tkFileDialog.askopenfilename()
bmp = cv2.imread(path) #reading image
height, width, channels = bmp.shape
if channels == 3:
bmp = cv2.cvtColor(bmp, cv2.COLOR_BGR2GRAY) #if image have 3 channels, convert to BW
bmp = bmp.astype('uint8')
bmp = cv2.adaptiveThreshold(bmp,255,cv2.ADAPTIVE_THRESH_GAUSSIAN_C,\
cv2.THRESH_BINARY,11,2) #Otsu thresholding
imageData = np.asarray(bmp) #get pixels values
pixelArray = [[0 for y in range(height)] for x in range(width)] #set size of array for pixels
for y in range(len(imageData)):
for x in range(len(imageData[0])):
if imageData[y][x] == 0:
pixelArray[y][x] = 1 #if black pixels = 1
else:
pixelArray[y][x] = 0 #if white pixels = 0
In c#, it can looks like this:
for (y = 0; y < bmp.Height-1; y++)
{
for (x = 0; x < bmp.Width-1; x++)
{
if (pixelArray[y, x] == 1)
newImage.SetPixel(x, y, Color.Black); //printing new bitmap
else
newImage.SetPixel(x, y, Color.White);
}
}
image2.Source = Bitmap2BitmapImage(newImage);
In the next step i will marking countour pixels as "2", but now i want to ask you, how to set new image in python from my specific value and then, display it? For experimental purpose, i want to invert image (from B&W to W&B) only by byte valuse. Can you help me how to do it?
EDIT1
I think i found a solution, but i have GREYSCALE image with one channel (i think thats how it works when i using cv2.cvtColor to convert 3 channels image to greyscale image). The function like this:
im[np.where((im == [0,0,0]).all(axis = 2))] = [0,33,166]
Could work pretty well, but how to make that function work with greyscale image? I want to set some black pixels (0) into White (255)
For a single channel image (gray scale image) use the following:
First create a copy of the gray image:
gray_2 = gray.copy()
Now assign black pixels to be white:
gray_2[np.where(gray == 0)] = 255