For instance if my string contains - 'नमस्ते' how do I print all the unicode escape sequence for the alphabets in the string.
If you want the \u escapes for each character (what you'd type to redefine the string in pure ASCII Python code), use the unicode-escape codec:
>>> 'नमसत'.encode('unicode-escape')
b'\\u0928\\u092e\\u0938\\u0924'
If it needs to end up a str, rather than bytes, decode it back as ASCII (and remove the quoting and doubled backslashes on display by printing it):
>>> print('नमसत'.encode('unicode-escape').decode('ascii'))
\u0928\u092e\u0938\u0924
>>> s = "नमस्ते"
>>> s.encode('utf-8')
b'\xe0\xa4\xa8\xe0\xa4\xae\xe0\xa4\xb8\xe0\xa5\x8d\xe0\xa4\xa4\xe0\xa5\x87'
>>> s.encode('unicode-escape')
b'\\u0928\\u092e\\u0938\\u094d\\u0924\\u0947'
Related
I have a txt file which contains a line:
' 6: "\\351\\231\\220\\346\\227\\266\\345\\205\\215\\350\\264\\271"'
The contents in the double quotes is actually octal encoding, but with two escape characters.
After the line has been read in, I used regex to extract the contents in the double quotes.
c = re.search(r': "(.+)"', line).group(1)
After that, I have two problem:
First, I need to replace the two escape characters with one.
Second, Tell python that the str object c is actually a byte object.
None of them has been done.
I have tried:
re.sub('\\', '\', line)
re.sub(r'\\', '\', line)
re.sub(r'\\', r'\', line)
All failed.
A bytes object can be easily define with 'b'.
c = b'\351\231\220\346\227\266\345\205\215\350\264\271'
How to change the variable type of a string to bytes? I think this not a encode-and-decode thing.
I googled a lot, but with no answers. Maybe I use the wrong key word.
Does anyone know how to do these? Or other way to get what I want?
This is always a little confusing. I assume your bytes object should represent a string like:
b = b'\351\231\220\346\227\266\345\205\215\350\264\271'
b.decode()
# '限时免费'
To get that with your escaped string, you could use the codecs library and try:
import re
import codecs
line = ' 6: "\\351\\231\\220\\346\\227\\266\\345\\205\\215\\350\\264\\271"'
c = re.search(r': "(.+)"', line).group(1)
codecs.escape_decode(bytes(c, "utf-8"))[0].decode("utf-8")
# '限时免费'
giving the same result.
The string contains literal text for escape codes. You cannot just replace the literal backslashes with a single backslash as escape codes are used in source code to indicate a single character. Decoding is needed to change literal escape codes to the actual character, but only byte strings can be decoded.
Encoding a Unicode string to a byte string with the Latin-1 codec translates Unicode code points 1:1 to the corresponding byte, so it is the common way to directly convert a "byte-string-like" Unicode string to an actual byte string.
Step-by-Step:
>>> s = "\\351\\231\\220\\346\\227\\266\\345\\205\\215\\350\\264\\271"
>>> print(s) # Actual text of the string
\351\231\220\346\227\266\345\205\215\350\264\271
>>> s.encode('latin1') # Convert to byte string
b'\\351\\231\\220\\346\\227\\266\\345\\205\\215\\350\\264\\271'
>>> # decode the escape codes...result is latin-1 characters in Unicode
>>> s.encode('latin1').decode('unicode-escape')
'é\x99\x90æ\x97¶å\x85\x8dè´¹' # convert back to byte string
>>> s.encode('latin1').decode('unicode-escape').encode('latin1')
b'\xe9\x99\x90\xe6\x97\xb6\xe5\x85\x8d\xe8\xb4\xb9'
>>> # data is UTF-8-encoded text so decode it correctly now
>>> s.encode('latin1').decode('unicode-escape').encode('latin1').decode('utf8')
'限时免费'
Your text example looks like part of a Python dictionary. You may be able to save some steps by using the ast module's literal_eval function to turn the dictionary directly into a Python object, and then just fix this line of code:
>>> # Python dictionary-like text
d='{6: "\\351\\231\\220\\346\\227\\266\\345\\205\\215\\350\\264\\271"}'
>>> import ast
>>> ast.literal_eval(d) # returns Python dictionary with value already decoded
{6: 'é\x99\x90æ\x97¶å\x85\x8dè´¹'}
>>> ast.literal_eval(d)[6] # but decoded incorrectly as Latin-1 text.
'é\x99\x90æ\x97¶å\x85\x8dè´¹'
>>> ast.literal_eval(d)[6].encode('latin1').decode('utf8') # undo Latin1, decode as UTF-8
'限时免费'
I have everything working as I want it in my code, but I'm still curious. I have a string: "stación." When I convert that string to unicode, I get:
unicode('stación', 'utf-8')
>>> u'staci\xf3n'
That "\xf3" in there looks like a byte character. This is different from:
unicode('Поиск', 'utf-8')
>>> u'\u041f\u043e\u0438\u0441\u043a'
In the latter example, as with everything I've converted to unicode before, I get unicode characters starting with "\u." Normally, when I see a byte starting with "\x," I think there's a problem. What gives here? Is this because "ó" is extended ASCII?
No, it's because "ó" is a non-ASCII character within the first 255 characters. Since it's representable using a single byte, we save 2 characters in the representation. The other two representations are valid, but not required.
>>> u'\u00f3'
u'\xf3'
>>> u'\U000000f3'
u'\xf3'
u'\xf3' is not a byte; it is a Unicode string with a single Unicode codepoint (U+00f3 LATIN SMALL LETTER O WITH ACUTE).
What you see (u'\xf3') is how Python 2 chooses to represent Unicode character with Unicode ordinals (integers) in the range 0..255 that are not printable ascii characters (Python 3 would show 'ó' here, only non-printable characters use '\xhh' form there by default). As #Ignacio Vazquez-Abrams said: u'\u00f3' and u'\U000000f3' literals create exactly the same Unicode string.
You could see how the Unicode character (u'\xf3') looks like bytes in different character encodings for comparision:
>>> print(u'\xf3')
ó
>>> u'\xf3'.encode('utf-8')
b'\xc3\xb3'
>>> u'\xf3'.encode('utf-16be')
b'\x00\xf3'
>>> u'\xf3'.encode('utf-32le')
b'\xf3\x00\x00\x00'
>>> u'\xf3'.encode('cp1252')
b'\xf3'
Note: b'\xf3' and u'\xf3' are different things. The former is a bytestring that contains a single byte (an integer 243), the latter is a Unicode string that contains a single Unicode codepoint (Unicode ordinal 243). The number is the same 243 by the units are different -- 100 calories is not the same thing as 100 grams.
I have a tree structure in which keywords may contain some latin characters. I have a function which loops through all leaves of the tree and adds each keyword to a list under certain conditions.
Here is the code I have for adding these keywords to the list:
print "Adding: " + self.keyword
leaf_list.append(self.keyword)
print leaf_list
If the keyword in this case is université, then my output is:
Adding: université
['universit\xc3\xa9']
It appears that the print function properly shows the latin character, but when I add it to the list, it gets decoded.
How can I change this? I need to be able to print the list with the standard latin characters, not the decoded version of them.
You don't have unicode objects, but byte strings with UTF-8 encoded text. Printing such byte strings to your terminal may work if your terminal is configured to handle UTF-8 text.
When converting a list to string, the list contents are shown as representations; the result of the repr() function. The representation of a string object uses escape codes for any bytes outside of the printable ASCII range; newlines are replaced by \n for example. Your UTF-8 bytes are represented by \xhh escape sequences.
If you were using Unicode objects, the representation would use \xhh escapes still, but for Unicode codepoints in the Latin-1 range (outside ASCII) only (the rest are shown with \uhhhh and \Uhhhhhhhh escapes depending on their codepoint); when printing Python automatically encodes such values to the correct encoding for your terminal:
>>> u'université'
u'universit\xe9'
>>> len(u'université')
10
>>> print u'université'
université
Compare this to byte strings:
>>> 'université'
'universit\xc3\xa9'
>>> len('université')
11
>>> 'université'.decode('utf8')
u'universit\xe9'
>>> print 'université'
université
Note that the length reflects that the é codepoint is encoded to two bytes as well. It was my terminal that presented Python with the \xc3\xa9 bytes when pasting the é character into the Python session, by the way, as it is configured to use UTF-8, and Python has detected this and decoded the bytes when I defined a u'..' Unicode object literal.
I strongly recommend you read the following articles to understand how Python handles Unicode, and what the difference is between Unicode text and encoded byte strings:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!) by Joel Spolsky
The Python Unicode HOWTO
Pragmatic Unicode by Ned Batchelder
When you print a list, you get the repr of the items it contains, which for strings is different from their contents:
>>> a = ['foo', 'bär']
>>> print(a[0])
foo
>>> print(repr(a[0]))
'foo'
>>> print(a[1])
bär
>>> print(repr(a[1]))
'b\xc3\xa4r'
The output of repr is supposed to be programmer-friendly, not user-friendly, hence the quotes and the hex codes. To print a list in a user-friendly way, write your own loop. E.g.
>>> print '[', ', '.join(a), ']'
[ foo, bär ]
I have a tree structure in which keywords may contain some latin characters. I have a function which loops through all leaves of the tree and adds each keyword to a list under certain conditions.
Here is the code I have for adding these keywords to the list:
print "Adding: " + self.keyword
leaf_list.append(self.keyword)
print leaf_list
If the keyword in this case is université, then my output is:
Adding: université
['universit\xc3\xa9']
It appears that the print function properly shows the latin character, but when I add it to the list, it gets decoded.
How can I change this? I need to be able to print the list with the standard latin characters, not the decoded version of them.
You don't have unicode objects, but byte strings with UTF-8 encoded text. Printing such byte strings to your terminal may work if your terminal is configured to handle UTF-8 text.
When converting a list to string, the list contents are shown as representations; the result of the repr() function. The representation of a string object uses escape codes for any bytes outside of the printable ASCII range; newlines are replaced by \n for example. Your UTF-8 bytes are represented by \xhh escape sequences.
If you were using Unicode objects, the representation would use \xhh escapes still, but for Unicode codepoints in the Latin-1 range (outside ASCII) only (the rest are shown with \uhhhh and \Uhhhhhhhh escapes depending on their codepoint); when printing Python automatically encodes such values to the correct encoding for your terminal:
>>> u'université'
u'universit\xe9'
>>> len(u'université')
10
>>> print u'université'
université
Compare this to byte strings:
>>> 'université'
'universit\xc3\xa9'
>>> len('université')
11
>>> 'université'.decode('utf8')
u'universit\xe9'
>>> print 'université'
université
Note that the length reflects that the é codepoint is encoded to two bytes as well. It was my terminal that presented Python with the \xc3\xa9 bytes when pasting the é character into the Python session, by the way, as it is configured to use UTF-8, and Python has detected this and decoded the bytes when I defined a u'..' Unicode object literal.
I strongly recommend you read the following articles to understand how Python handles Unicode, and what the difference is between Unicode text and encoded byte strings:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!) by Joel Spolsky
The Python Unicode HOWTO
Pragmatic Unicode by Ned Batchelder
When you print a list, you get the repr of the items it contains, which for strings is different from their contents:
>>> a = ['foo', 'bär']
>>> print(a[0])
foo
>>> print(repr(a[0]))
'foo'
>>> print(a[1])
bär
>>> print(repr(a[1]))
'b\xc3\xa4r'
The output of repr is supposed to be programmer-friendly, not user-friendly, hence the quotes and the hex codes. To print a list in a user-friendly way, write your own loop. E.g.
>>> print '[', ', '.join(a), ']'
[ foo, bär ]
When I tried to get the content of a tag using "unicode(head.contents[3])" i get the output similar to this: "Christensen Sk\xf6ld". I want the escape sequence to be returned as string. How to do it in python?
Assuming Python sees the name as a normal string, you'll first have to decode it to unicode:
>>> name
'Christensen Sk\xf6ld'
>>> unicode(name, 'latin-1')
u'Christensen Sk\xf6ld'
Another way of achieving this:
>>> name.decode('latin-1')
u'Christensen Sk\xf6ld'
Note the "u" in front of the string, signalling it is uncode. If you print this, the accented letter is shown properly:
>>> print name.decode('latin-1')
Christensen Sköld
BTW: when necessary, you can use de "encode" method to turn the unicode into e.g. a UTF-8 string:
>>> name.decode('latin-1').encode('utf-8')
'Christensen Sk\xc3\xb6ld'
I suspect that it's acutally working correctly. By default, Python displays strings in ASCII encoding, since not all terminals support unicode. If you actually print the string, though, it should work. See the following example:
>>> u'\xcfa'
u'\xcfa'
>>> print u'\xcfa'
Ïa
Given a byte string with Unicode escapes b"\N{SNOWMAN}", b"\N{SNOWMAN}".decode('unicode-escape) will produce the expected Unicode string u'\u2603'.